

InterviewSolution
Saved Bookmarks
1. |
if specific heat capacity of mercury is 0.033 cal `g^(-1)" ".^(@)C^(-1)`, how much heat is gained by 0.05 kg of mercury when its temperature rises from `68^(@)F` to 313K? |
Answer» The initial temperature `=68^(@)F` `[(5)/(9)(68-32)].^(@)C=20C^(@)` Final temperature `=313K=(313-273).^(@)C=40^(@)C` Mass of mercury given `=0.05kg=50g` Specific heat capacity of mercury =0.033 cal `g^(-1).^(@)C^(-1) I.e., heat gained by 1 g of mercury for `1^(@)C` rise =0.033 cal hence, gained by 1 g of mercury for `1^(@)C` rise =0.033`xx50=1.65cal` `therefore` hear gained by 50 g mercury for `20^(@)C` rise =33 cal |
|