1333 + Interview Questions in HYDROGEN IN GENERAL AWARENESS Page 25 InterviewSolution

1201.	Describe the commercial preparation methods for the manufacture of hydrogen?
Answer» 1 by electrolysis of water: H₂O -----> +OH At cathode: H⁺ + e---------> H H + H-----------------> H₂ At anode: 4OH- -----------> 2H₂O +O₂ Thus by this method Hydrogen is produced at cathode and oxygen is produced at anode.

1201.

Describe the commercial preparation methods for the manufacture of hydrogen?

Answer»

1 by electrolysis of water:

H₂O -----> +OH

At cathode: H⁺ + e---------> H

H + H-----------------> H₂

At anode: 4OH- -----------> 2H₂O +O₂

Thus by this method Hydrogen is produced at cathode and oxygen is produced at anode.

Discussion

1202.	Who discovered hydrogen?
Answer» Henry Cavendish discovered hydrogen in 1766.

Discussion

1203.	Write one laboratory method of preparation of hydrogen gas.
Answer» Generally prepared by the reaction of granulated zinc with dilute hydrochloric acid as under Zn(s)+2HCl --->ZnCl₂ +H₂ (g)

1203.

Write one laboratory method of preparation of hydrogen gas.

Answer»

Generally prepared by the reaction of granulated zinc with dilute hydrochloric acid as under

Zn(s)+2HCl --->ZnCl₂ +H₂ (g)

Discussion

1204.	what do you understand by “Non stoichiometric hydrides”? Do you think this type of hydrides to be formed by alkali metals? Justify your answer.
Answer» Hydrides which are deficient in hydrogen and in which the ratio of hydrogen to metal is fractional are called non-stoichiometric hydrides. This type of hydrides are formed by d-and f-block element. Since alkali metals are highly reducing, they transfer their own electron to H atom thereby forming H- ion. Therefore the ratio of metal to hydrogen is always fixed and they form only stoichiometric hydrides. In other words alkali metals do not form non-stoichiometric hydrides.

1204.

what do you understand by “Non stoichiometric hydrides”? Do you think this type of hydrides to be formed by alkali metals? Justify your answer.

Answer»

Hydrides which are deficient in hydrogen and in which the ratio of hydrogen to metal is fractional are called non-stoichiometric hydrides. This type of hydrides are formed by d-and f-block element.

Since alkali metals are highly reducing, they transfer their own electron to H atom thereby forming H- ion. Therefore the ratio of metal to hydrogen is always fixed and they form only stoichiometric hydrides. In other words alkali metals do not form non-stoichiometric hydrides.

Discussion

1205.	In which group hydrogen is placed on the basis of electronic configuration?
Answer» The electronic configuration of hydrogen is 1s¹. On this basis, hydrogen is placed in group 1.

Discussion

1206.	What is ortho-hydrogen?
Answer» The hydrogen in which rotation of proton or nucleus is in same direction is called ortho-hydrogen.

Discussion

1207.	Which of the isotopes of hydrogen is radioactive?
Answer» Tritium (³₁H) is radioactive isotope of hydrogen.

Discussion

1208.	Write the name of isotopes of hydrogen and write the number of proton, electron and neutron in these.
Answer» Isotopes of hydrogen (a) Hydrogen (protium) ¹₁H No. of protons = 1 No. of electrons = 1 No. of neutrons 1 – 1 = 0 (b) Deutrium ²₁H No. of protons = 1 No. of electrons = 1 No. of neutrons = 2 – 1 = 1 (c) Tritium ³₁H No. of protons = 1 No. of electrons = 1 No. of neutrons = 3 – 1 = 2.

1208.

Write the name of isotopes of hydrogen and write the number of proton, electron and neutron in these.

Answer»

Isotopes of hydrogen
(a) Hydrogen (protium) ¹₁H
No. of protons = 1
No. of electrons = 1
No. of neutrons 1 – 1 = 0

(b) Deutrium ²₁H
No. of protons = 1
No. of electrons = 1
No. of neutrons = 2 – 1 = 1

(c) Tritium ³₁H
No. of protons = 1
No. of electrons = 1
No. of neutrons = 3 – 1 = 2.

Discussion

1209.	Identify the isotopes of hydrogen.(a) Has no neutron. (b) Radioactive in nature.
Answer» (a) Protium₁H¹ e^- =1, p⁺ =1,n⁰ =0 (b) Tritium ₁H³ e^- =1, p⁺ =1,n⁰ =2 Hence n/p>1.25

1209.

Identify the isotopes of hydrogen.(a) Has no neutron. (b) Radioactive in nature.

Answer»

(a) Protium₁H¹ e^- =1, p⁺ =1,n⁰ =0

(b) Tritium ₁H³ e^- =1, p⁺ =1,n⁰ =2 Hence n/p>1.25

Discussion

1210.	Which one is not an isotope of hydrogen ?A. TritiumB. DeuteriumC. Ortho hydrogenD. None of these
Answer» Correct Answer - C Ortho hydrogen is not the isotope of hydrogen but it is isomer of hydrogen.

Discussion

1211.	Which of the following statements are correct ?A. `H_(2)O_(2)` reduces `MnO_(4)^(-)` both in acidic and basic mediaB. `H_(2)O_(2)` oxidises `Fe^(2+)` ions both in acidic and basic mediaC. `H_(2)O_(2)` oxidises `Mn^(2+) ` to `Mn^(4+)` ions in basic mediumD. `H_(2)O_(2)` liberates `I_(2)` from acidified KI solution and reduces `I_(2)` to `I^(-)` ions in basic medium.
Answer» Correct Answer - A::B::C::D

Discussion

1212.	The reagents used fro softening of the temporary hardness of water is/areA. `Ca_(3)(PO_(4))_(2)`B. `Ca(OH)_(2)`C. `Na_(2)CO_(3)`D. `NaOCl`
Answer» Correct Answer - B::C `Ca(OH)_(2) and Na_(2)CO_(3)` react with bicarbonates of Ca and Mg present in temporary hard water to form the corresponding insoluble carbonates which upon filtration give soft water. `Ca(HCO_(3))_(2) + Ca(OH)_(2) to 2CaCO_(3) darr + 2H_(2)O` `Ca(HCO_(3))_(2) + Na_(2)CO_(3) to CaCO_(3) darr + 2NaHCO_(3)`

Discussion

1213.	Hydrogen peroxide can be preapared by the action of dil. `H_(2)SO_(4)` or `H_(3)PO_(4)` on barium peroxide or by bubbling peroxide . On an industrial scale, it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% `H_(2)SO_(4)` or an equimolar mixture of `H_(2)SO_(4)` and ammonium sulphate . The strength of `H_(2)O_(2)` solution can be expressed in a number of ways namely normality , molarity , percentage strength and volume strength . Volume strength refers to the volume of `O_(2)` produced at N.T.P. by decomposition of 1 mL of `H_(2)O_(2)` solution. `H_(2)O_(2)` acts as an oxidising as well as reducing agent both in acidic and basic media. Hydrolysis of one mole of peroxodisulphuric acid producesA. two moles of sulphuric acidB. two moles of peroxomonosulphuric acidC. one mole of sulphuric acid and one mole of peroxomonosulphuric acidD. one mole of sulphuric acid, one mole of peroxomonosulphuric acid and one mole of hydrogen peroxide
Answer» Correct Answer - c `HO-underset("Peroxodisulpuric acid ")(S0_(2)-O-O-SO_(2))-OH+H_(2)O to underset("Sulphuric acid")(HOSO_(2)OH)+underset("Peroxomono-sulphuric acid")(HOOSO_(2)OH)`

Discussion

1214.	Hydrogen peroxide can be preapared by the action of dil. `H_(2)SO_(4)` or `H_(3)PO_(4)` on barium peroxide or by bubbling peroxide . On an industrial scale, it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% `H_(2)SO_(4)` or an equimolar mixture of `H_(2)SO_(4)` and ammonium sulphate . The strength of `H_(2)O_(2)` solution can be expressed in a number of ways namely normality , molarity , percentage strength and volume strength . Volume strength refers to the volume of `O_(2)` produced at N.T.P. by decomposition of 1 mL of `H_(2)O_(2)` solution. `H_(2)O_(2)` acts as an oxidising as well as reducing agent both in acidic and basic media. The correct increasing order of the acidity of `CO_(2), H_(2)O and H_(2)O_(2)` isA. `CO_(2) lt H_(2)O_(2) lt H_(2)O`B. `H_(2)Olt H_(2)O_(2) lt CO_(2)`C. `H_(2)O lt H_(2)O_(2) gt CO_(2)`D. `H_(2)O_(2) gt CO_(2) gt H_(2)O`
Answer» Correct Answer - b A strong acid displaces a weaker acid from its salts `BaO_(2) + underset("Stronger acid")ubrace (H_(2)O+CO_(2))to BaCO_(2) + underset("Weaker acid")(H_(2)O_(2))` i.e. `CO_(2)` is a stronger acid from `H_(2)O_(2)` `therefore ` option (b) is correct

Discussion

1215.	Hydrogen peroxide can be preapared by the action of dil. `H_(2)SO_(4)` or `H_(3)PO_(4)` on barium peroxide or by bubbling peroxide . On an industrial scale, it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% `H_(2)SO_(4)` or an equimolar mixture of `H_(2)SO_(4)` and ammonium sulphate . The strength of `H_(2)O_(2)` solution can be expressed in a number of ways namely normality , molarity , percentage strength and volume strength . Volume strength refers to the volume of `O_(2)` produced at N.T.P. by decomposition of 1 mL of `H_(2)O_(2)` solution. `H_(2)O_(2)` acts as an oxidising as well as reducing agent both in acidic and basic media. Which of the following substances on treatment with `H_(2)O_(2)` gives `MnO_(2)`A. acidified `KMnO_(4)`B. alkaline `KMnO_(4)`C. alkaline `MnSO_(4)`D. both (b) and (c)
Answer» Correct Answer - d

Discussion

1216.	Hydrogen peroxide can be preapared by the action of dil. `H_(2)SO_(4)` or `H_(3)PO_(4)` on barium peroxide or by bubbling peroxide . On an industrial scale, it can be prepared by hydrolysis of peroxodisulphuric acid obtained by electrolysis of 50% `H_(2)SO_(4)` or an equimolar mixture of `H_(2)SO_(4)` and ammonium sulphate . The strength of `H_(2)O_(2)` solution can be expressed in a number of ways namely normality , molarity , percentage strength and volume strength . Volume strength refers to the volume of `O_(2)` produced at N.T.P. by decomposition of 1 mL of `H_(2)O_(2)` solution. `H_(2)O_(2)` acts as an oxidising as well as reducing agent both in acidic and basic media. The volume of 10 volume `H_(2)O_(2)` solution that decolourises 200 mL of 2N `KMnO_(4)` solution in acidic medium is :A. 112 mLB. 336 mLC. 200 mLD. 224 mL
Answer» Correct Answer - d

Discussion

1217.	Which of the following is used as rocket fuel?A. Liquid `O_(2)`B. liquid `NH_(3)`C. Liquid `N_(2)`D. Liquid `H_(2)`
Answer» Correct Answer - D

Discussion

1218.	The reaction of `H_(2)S+H_(2)O_(2) rarr S+2H_(2)O` manifestsA. Acidic nature of `H_(2)O_(2)`B. Alkaline nature of `H_(2)O_(2)`C. Oxidising nature of `H_(2)O_(2)`D. Reduciing action of `H_(2)O_(2)`
Answer» Correct Answer - c `underset(-2)(H_(2)S)+H_(2)O_(2)rarr underset(0)(S)+2H_(2)O` In this reaction `H_(2)O_(2)` shows oxidising nature.

Discussion

1219.	`H_(2)O_(2)` is used as `:`A. antisepticB. bleaching agentC. propellantD. all
Answer» Correct Answer - d `H_(2)O_(2)` can be used as antiseptic, bleaching agent and propellant.

Discussion

1220.	On burning hydrogen in air the colour of flame isA. greenB. light bluishC. yellowD. none of these
Answer» Correct Answer - B

Discussion

1221.	Surface water contains.A. suspended impuritiesB. organic impuritiesC. saltD. salt and organic compound
Answer» Correct Answer - A

Discussion

1222.	Match the column I with column II and mark the appropriate choice. A. `(A) to (i), (B) to (ii), (C ) to (iii), (D) to (iv)`B. `(A) to (iii), (B) to (i), (C ) to (ii), (D) to (iv)`C. `(A) to (iii),(B) to (ii), (C ) to (iv), (D) to (i)`D. `(A) to (iii),(B) to (ii), (C ) to (i), (D) to (iv)`
Answer» Correct Answer - B

Discussion

1223.	Match the reactions of column I with their types given in column II and mark the appropriate choice. A. `(A) to (ii), (B) to (i), (C ) to (iii), (D) to (iv)`B. `(A) to (iii), (B) to (ii), (C ) to (iv), (D) to (i)`C. `(A) to (i), (B) to (ii), (C ) to (iv), (D) to (iii)`D. `(A) to (iii), (B) to (iv), (C ) to (i), (D) to (ii)`
Answer» Correct Answer - D

Discussion

1224.	The maximum number of hydrogen bonds formed by a water molecule in ice isA. 4B. 1C. 2D. 3
Answer» Correct Answer - A

Discussion

1225.	Number of `H-`bonds formed by a water molecule is:A. 2B. 8C. 1D. 4
Answer» Correct Answer - D

Discussion

1226.	An element reacts with hydrogen to form a compound A which on treatment with water liberates hydrogen gas. The element can beA. NitrogenB. ChlorineC. SeleniumD. Calcium.
Answer» Correct Answer - D `Ca+H_(2)toCaH_(2)overset(2H_(2)O)toCa(OH)_(2)+2H_(2)`

Discussion

1227.	The maximum possible number of hydrogen bonds a water molecule can form isA. 1B. 2C. 3D. 4
Answer» Correct Answer - D

Discussion

1228.	Statement-I: `D_(2)` molecules is more stable than `H_(2)`. Statement-II: The bond dissociation energy of `D_(2)` is more than of `H_(2)`.A. If both Statement-1 `&` Statement-II are True `&` the Statement-II is not a correct explanation of the Statement I.B. If both Statement-I `&` Statement-II are True but Statement-II is not a correct explanantion of the Statement-I.C. If Statement-I is True but the Statement-II is False.D. If Statement-I is False but the Statement-II is True.
Answer» Correct Answer - A

Discussion

1229.	Hydrogen can be prepared by the action of dil `H_(2)SO_(4)` onA. copperB. ironC. leadD. mercury
Answer» Correct Answer - B `Cu(E_(Cu^(2+)//Cu)^(@)=+0.34 V)` and `Hg(E_(Hg^(2+)//Hg)^(@)=+0.80 V)` lie above `H_(2)` in the electrochemical series and hence do not react with dil. `H_(2)SO_(4)` to evolve `H_(2)` gas . Although `Pb(E_(Pb^(2+)//Pb)^(@)=-0.13V)` lies below `H_(2)` in the electrochemical series, it reacts with dil. `H_(2)SO_(4)` in the begining to evolves `H_(2)` gas but `PbSO_(4)` produced during the reaction forms a `Pb+ H_(2)SO_(4)("dil.") to underset("In soluble")(PbSO_(4))(s) + H_(2)(g)` protective layer around the unreacted Pb and the reaction stops. Only iron `(E_(Fe^(2+)//Fe)^(@)==0.44V)` reacts readily with dil. `H_(2)SO_(4)` to evolve `H_(2)` gas.

Discussion

1230.	Positron is -A. A nucleus with one neutron and one protonB. A nucleus with two protonC. A helium nucleusD. Electron with `+ve` charge
Answer» Correct Answer - D Positively charged `e^(-)` is known as positron.

Discussion

1231.	When treated with nitric acid which of the following liberates hydrogen ?A. ZincB. CopperC. MagnesiumD. Mercury
Answer» Correct Answer - C `Mg+2HNO_(3)rarrMg(NO_(3))_(2)+H_(2)`

Discussion

1232.	Pick out the correct statementA. By decreasing the temperature pura parahydrogen can be obtainedB. By increasing the temperature pura orthohydrogen can be obtained.C. By decreasing the temperature pura orthohydrogen can be obtained.D. By increasing the temperature pura parahydrogen can be obtained.
Answer» Correct Answer - A

Discussion

1233.	Pick out the correct statementA. By decreasing the temperature pure para`-` hydrogen can be obtainedB. By increasing the temperature pure ortho`-` hydrogen can be obtainedC. By decreasing the temperature pure ortho `-` hydrogen can be obtainedD. By increasing the temperature pure para `-` hydrogen can be obtained
Answer» Correct Answer - b b

Discussion

1234.	Pick the odd one outA. Sodium borohydride reacts very slowly with cold water toB. Sodium borohydride reacts very violently with cold water to produce `H_(2)`C. Solubility of sodium borohydride in water at `25^(@)`C is `10*05` g/mLD. Melting point of sodium borohydride is `500^(@)C`.
Answer» Correct Answer - B Reaction of `NaBH_(4)` with cold water is very slow. All other statements except (B) are correct.

Discussion

1235.	Cosider the reactions (i) `H_(2)O_(2) + 2HI to I_(2) + 2H_(2)O` (ii) `HOCl + H_(2)O_(2) to H_(3)O^(+) + Cl^(-) + O_(2)` Which of the following statements is correct about `H_(2)O_(2)` with reference to these reactions ? Hydrogen peroxide is â€¦â€¦â€¦A. an oxidising agent in both (A) and (B)B. an oxidising agent in (A) and reducing agent in (B)C. a reducing agent in (A) and oxidising agent in (B)D. a reducing agent in both (A) and (B)
Answer» Correct Answer - B (A) `H_(2)O_(2)+2H overset(-1)(I)to overset(0)(I_(2))+2H_(2)O` Iodine is oxidised from -1 to 0 oxidation state thus, `H_(2)O_(2)` acts as an oxidising agent and itself gets reduced. (B) `HO overset((+1))(Cl)+H_(2)O_(2)to H_(2)O^(+)+Cl^(-)+O_(2)` Chlorine is reduced from +1 to -1 oxidation state thus, `H_(2)O_(2)` acts as a reducing agent and itself gets oxidised.

Discussion

1236.	Boiling point of water is high due to presence ofA. H-bondingB. its bend structureC. It high dielectric constantD. None
Answer» Correct Answer - A Water contain intermolecular H-bonding as intermolecular force that why it is having higher boiling point.

Discussion

1237.	6 volume sample of `H_(2)O_(2)`A. would given 6 volumes of oxyen per unit volume of `H_(2)O_(2)` sample at STPB. will contain ` 6% V//V` of `H_(2)O_(2)`C. will contain `6 % W//V ` of `H_(2)O_(2)`D. would give 6 volumes of oxygen per unit weight of `H_(2)O_(2)` sample at STP
Answer» Correct Answer - A 6 volume sample of `H_(2)O_(2)` means 6 volumes of oxygen are given out per unit volume of `H_(2)O_(2)` sample at STP.

Discussion

1238.	The boiling points of water is high becauseA. Water molecular is linerB. Water molecule is not linearC. Water molecule possess covalent bond between H and OD. Water molecules associate due to H-bonding
Answer» Correct Answer - D Water molecules are associated with H-boiling , due to which boiling of H-bond.

Discussion

1239.	A sample of water contains sodium chlorde. It isA. hard waterB. soft waterC. moderately hard D. None.
Answer» Correct Answer - B NaCl does not make water hard.

Discussion

1240.	Brackish water mostly containsA. calcium chlorideB. barium sulphateC. sodium chlorideD. mineral acids.
Answer» Correct Answer - C Brackish water containing sodium chloride is soft water.

Discussion

1241.	Which of the following statement is incorrectA. Gemination of seeds in heavy water stops or slowdownB. The growth of plant is slowdown in heavy waterC. Small fish die in heavy waterD. In heavy water, NaCl solubility is more than normal water.
Answer» Correct Answer - A

Discussion

1242.	A sample of water contains sodium chlorde. It isA. hard waterB. soft waterC. moderately hardD. None.
Answer» Correct Answer - B NaCl does not make water hard.

Discussion

1243.	Which is true statement?A. the layer of ice on the surface of river in the winter acts as a thermal insulator between the water below and the air aboveB. the fish and other marine organism are enabled to survive long periods of freezing water due to the fact that ice is lighter than waterC. both correctD. none is correct
Answer» Correct Answer - C

Discussion

1244.	A sample of water contains sodium chlorde. It isA. Hard waterB. Soft waterC. Moderately hardD. None of these
Answer» Correct Answer - B

Discussion

1245.	Hydrogen is evolved the action of cold dilute `HNO_(3)` on `:`A. `Fe`B. `Mn`C. `Cu`D. `Al`
Answer» Correct Answer - b `Mn+2HNO_(3)(dil.) rarr Mn (NO_(3))_(2)+H_(2)`

Discussion

1246.	Action of water or dilute mineral acdis on metal can give `:`A. monohydrogenB. tritiumC. dihydrogenD. trihydrogen
Answer» Correct Answer - c `2Na+2H_(2)Orarr 2NaOH+H_(2),Mg+H_(2)Orarr MgO+H_(2),` `Mg+H_(2)SO_(4) rarr MgSO_(4)+H_(2)`

Discussion

1247.	Action of water or dilute mineral acids on metals can giveA. MonohydrogenB. TritiumC. DihydrogenD. `D_(2)`.
Answer» Correct Answer - C Action of water on dil. Mineral acids `(HCl,H_(2)SO_(4))` can given dihydrogen.

Discussion

1248.	In which of the solution hydrogen peroxide neither acts as oxidising agent nor reducing agent ?A. `Na_(2)CO_(3)+H_(2)O_(2)to`B. `PbS+H_(2)O_(2)to`C. `Cr_(2)O_(7)^(2-)+H^(+)+H_(2)O_(2)to`D. `SO_(3)^(-)+H_(2)O_(2)to`
Answer» Correct Answer - A `Na_(2)CO_(3)+H_(2)O_(2)toNa_(2)O_(2)+CO_(2)+H_(2)O` Here `H_(2)O_(2)` behaves as an acid.

Discussion

1249.	In which of the solution hydrogen peroxide neither acts as oxidising agent nor reducing agent ?A. `PbS+H_(2)O_(2)rarr`B. `SO_(3)+H_(2)O_(2)rarr`C. `PbO_(2)+H_(2)O_(2)rarr`D. `Na_(2)CO_(3)+H_(2)O_(2)rarr`
Answer» Correct Answer - D `H_(2)O_(2)` behaves as an acid when reacts with `Na_(2)CO_(3)`. `Na_(2)CO_(3)+H_(2)O_(2)rarrNa_(2)O_(2)+CO_(2)+H_(2)O`

Discussion

1250.	Assertion. On adding Zinc pieces to aqueous `FeCl_(3)` solution, colour changes from deep yellow to light green Reason. Aqueous `FeCl_(3)` is acidic and on adding zinc, nascent hydrogen is produced which reduces deep yellow `FeCl_(3)` solution to light green `FeCl_(2)` solution.
Answer» Correct Answer - A

Discussion

Explore topic-wise InterviewSolutions in .

Describe the commercial preparation methods for the manufacture of hydrogen?

Who discovered hydrogen?

Write one laboratory method of preparation of hydrogen gas.

what do you understand by “Non stoichiometric hydrides”? Do you think this type of hydrides to be formed by alkali metals? Justify your answer.

In which group hydrogen is placed on the basis of electronic configuration?

What is ortho-hydrogen?

Which of the isotopes of hydrogen is radioactive?

Write the name of isotopes of hydrogen and write the number of proton, electron and neutron in these.

Identify the isotopes of hydrogen.(a) Has no neutron. (b) Radioactive in nature.

Which one is not an isotope of hydrogen ?A. TritiumB. DeuteriumC. Ortho hydrogenD. None of these

The reagents used fro softening of the temporary hardness of water is/areA. `Ca_(3)(PO_(4))_(2)`B. `Ca(OH)_(2)`C. `Na_(2)CO_(3)`D. `NaOCl`

Which of the following is used as rocket fuel?A. Liquid `O_(2)`B. liquid `NH_(3)`C. Liquid `N_(2)`D. Liquid `H_(2)`

The reaction of `H_(2)S+H_(2)O_(2) rarr S+2H_(2)O` manifestsA. Acidic nature of `H_(2)O_(2)`B. Alkaline nature of `H_(2)O_(2)`C. Oxidising nature of `H_(2)O_(2)`D. Reduciing action of `H_(2)O_(2)`

`H_(2)O_(2)` is used as `:`A. antisepticB. bleaching agentC. propellantD. all

On burning hydrogen in air the colour of flame isA. greenB. light bluishC. yellowD. none of these

Surface water contains.A. suspended impuritiesB. organic impuritiesC. saltD. salt and organic compound

Match the column I with column II and mark the appropriate choice. A. `(A) to (i), (B) to (ii), (C ) to (iii), (D) to (iv)`B. `(A) to (iii), (B) to (i), (C ) to (ii), (D) to (iv)`C. `(A) to (iii),(B) to (ii), (C ) to (iv), (D) to (i)`D. `(A) to (iii),(B) to (ii), (C ) to (i), (D) to (iv)`

The maximum number of hydrogen bonds formed by a water molecule in ice isA. 4B. 1C. 2D. 3

Number of `H-`bonds formed by a water molecule is:A. 2B. 8C. 1D. 4

An element reacts with hydrogen to form a compound A which on treatment with water liberates hydrogen gas. The element can beA. NitrogenB. ChlorineC. SeleniumD. Calcium.

The maximum possible number of hydrogen bonds a water molecule can form isA. 1B. 2C. 3D. 4

Hydrogen can be prepared by the action of dil `H_(2)SO_(4)` onA. copperB. ironC. leadD. mercury

Positron is -A. A nucleus with one neutron and one protonB. A nucleus with two protonC. A helium nucleusD. Electron with `+ve` charge

When treated with nitric acid which of the following liberates hydrogen ?A. ZincB. CopperC. MagnesiumD. Mercury

Pick out the correct statementA. By decreasing the temperature pura parahydrogen can be obtainedB. By increasing the temperature pura orthohydrogen can be obtained.C. By decreasing the temperature pura orthohydrogen can be obtained.D. By increasing the temperature pura parahydrogen can be obtained.

Pick the odd one outA. Sodium borohydride reacts very slowly with cold water toB. Sodium borohydride reacts very violently with cold water to produce `H_(2)`C. Solubility of sodium borohydride in water at `25^(@)`C is `10*05` g/mLD. Melting point of sodium borohydride is `500^(@)C`.

Boiling point of water is high due to presence ofA. H-bondingB. its bend structureC. It high dielectric constantD. None

6 volume sample of `H_(2)O_(2)`A. would given 6 volumes of oxyen per unit volume of `H_(2)O_(2)` sample at STPB. will contain ` 6% V//V` of `H_(2)O_(2)`C. will contain `6 % W//V ` of `H_(2)O_(2)`D. would give 6 volumes of oxygen per unit weight of `H_(2)O_(2)` sample at STP

The boiling points of water is high becauseA. Water molecular is linerB. Water molecule is not linearC. Water molecule possess covalent bond between H and OD. Water molecules associate due to H-bonding

A sample of water contains sodium chlorde. It isA. hard waterB. soft waterC. moderately hard D. None.

Brackish water mostly containsA. calcium chlorideB. barium sulphateC. sodium chlorideD. mineral acids.

Which of the following statement is incorrectA. Gemination of seeds in heavy water stops or slowdownB. The growth of plant is slowdown in heavy waterC. Small fish die in heavy waterD. In heavy water, NaCl solubility is more than normal water.

A sample of water contains sodium chlorde. It isA. hard waterB. soft waterC. moderately hardD. None.

A sample of water contains sodium chlorde. It isA. Hard waterB. Soft waterC. Moderately hardD. None of these

Hydrogen is evolved the action of cold dilute `HNO_(3)` on `:`A. `Fe`B. `Mn`C. `Cu`D. `Al`

Action of water or dilute mineral acdis on metal can give `:`A. monohydrogenB. tritiumC. dihydrogenD. trihydrogen

Action of water or dilute mineral acids on metals can giveA. MonohydrogenB. TritiumC. DihydrogenD. `D_(2)`.

In which of the solution hydrogen peroxide neither acts as oxidising agent nor reducing agent ?A. `Na_(2)CO_(3)+H_(2)O_(2)to`B. `PbS+H_(2)O_(2)to`C. `Cr_(2)O_(7)^(2-)+H^(+)+H_(2)O_(2)to`D. `SO_(3)^(-)+H_(2)O_(2)to`

In which of the solution hydrogen peroxide neither acts as oxidising agent nor reducing agent ?A. `PbS+H_(2)O_(2)rarr`B. `SO_(3)+H_(2)O_(2)rarr`C. `PbO_(2)+H_(2)O_(2)rarr`D. `Na_(2)CO_(3)+H_(2)O_(2)rarr`

Assertion. On adding Zinc pieces to aqueous `FeCl_(3)` solution, colour changes from deep yellow to light green Reason. Aqueous `FeCl_(3)` is acidic and on adding zinc, nascent hydrogen is produced which reduces deep yellow `FeCl_(3)` solution to light green `FeCl_(2)` solution.