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1301.

Which of the following will not liberate dihydrogen ?A. `Zn + H_(2)SO_(4)` (di.)B. `Zn + NaOH(aq)`C. `Cu + H_(2)SO_(4)`(conc.)D. `F_(2) + H_(2)O`

Answer» Correct Answer - C::D
1302.

Aluminium reacts with boiling water to liberate dihydrogen gas along with the formation ofA. Aluminium oxideB. aluminium hydroxideC. aluminium suboxideD. aluminium superoxide.

Answer» Correct Answer - A
1303.

Write the Uses  of Dihydrogen.

Answer»

Uses of Dihydrogen 

In the synthesis of ammonia / in the manufacture of vanaspati fat / in the manufacture of bulk organic chemicals /used for the preparation of hydrogen chloride/ In metallurgical processes,/.Atomic hydrogen and oxy-hydrogen torches find use for cutting and welding / used as a rocket fuel/ used in fuel cells for generating electrical energy.

1304.

Choose the correct statement about the given figures. A. (II) represents solid state while (III) represents liquid state.B. (II) represents liquid state while (III) represents solid state.C. (I) represents solid state while (III) represents liquid state.D. (I) represents liquid state While (III) represents solid state.

Answer» Correct Answer - B
In liquid state water molecules are hydrogen bonded while in solid state water molecules are arranged in tetrahedral manner with molecules are arranged in tetrahedral manner with open cage ctructure.
1305.

What happens when an alkaline solution of potassium ferricyanide is reacted with `H_(2)O_(2)`?A. Potassium ferricyanide is oxidised to potassium ferrocyanide becomes colourless and `H_(2)O_(2)` is oxidised.B. Potassium ferricyanide becomes colourless and `H_(2)O_(2)` is oxidised to `O_(2)`.C. Potassium ferricyanide is reduced to ferric hydroxide and `H_(2)O_(2)` is oxidised to `H_(2)O`.D. Potassium ferricyanide is reduced to potassium ferrocyanide and `H_(2)O_(2)` is oxidised to `O_(2)`.

Answer» Correct Answer - D
`{:(2K_(3)[Fe(CN)_(6)]+2KOH to 2K_(4)[Fe(CN)_(6)]+H_(2)O+[O]),(" "H_(2)O_(2)+[O]to H_(2)O+O_(2)),(ulbar(2K_(3)[Fe(CN)_(6)]+2KOH+H_(2)O_(2)to 2K_(4)[Fe(CN)_(6)]+2H_(2)O+O_(2))):}`
1306.

Can distilled water be called as deionized water.

Answer»

Yes, distilled water does not contain any cations and anoins.

1307.

Name a process which can remove both temporary and permanent hardness of water.

Answer»

A process which can remove both temporary and permanent hardness of water is Permutite.

1308.

Radioactive elements emit `alpha, beta` and `gamma` rays and are characterised by their half-lives. The radioactive isotope of hydrogen isA. protiumB. deuteriumC. tritiumD. hydronium

Answer» Correct Answer - C
Nuclides with n/p (neutron-proton) ratio gt 1.5 are usually radioactive. For, tritium (n = 2, p =1), it is 2.
1309.

Radioactive elements emit α, β and γ rays and are characterised by their halflives. The radioactive isotope of hydrogen is(i) Protium(ii) Deuterium(iii) Tritium(iv) Hydronium

Answer»

(iii) Tritium

1310.

Complete the reaction:Fe(s) + H2O(g) →

Answer»

3Fe(s) + 4H2O(g) → Fe3O4(s) + 4H2 (g).

1311.

Complete the reaction : Fe(s) + H2O(g) →

Answer»

3Fe(s) + 4H2O(g) → Fe3O4(s) + 4H2(g)

1312.

Which of the following is the correct statement?A. Hydrogen has the same I.E. as that of alkali metalsB. Hydrogen has strong tendency to gain one electron same as that of alkali metalsC. Hydrogen molecule is diatomic so are the halogensD. Electron affinity of hydrogen is same as that of halogens

Answer» Correct Answer - C
1313.

A sample of hard water is allowed to pass through and anion exchanger. Will it produce lather with soap easily?

Answer»

Na, Ca2+ and Mg2+ ions are still present and these will react with soap to form to form curdy while precipitate. Therefore, it will not produce lather with soap solution easily.

1314.

The isotope of hydrogen which is radioactive isA. ProtiumB. TritiumC. DeuteriumD. Neutron

Answer» Correct Answer - B
1315.

Radioactive elements emit `alpha, beta and gamma` rays and are characterised by their half-lives. The radioactive isotope of hydrogen isA. Protium 0B. DueteirumC. TritiumD. Hydronium

Answer» (C ) Tritium is the radioactive isotopes of hydrogen
1316.

Which isotope of hydrogen is radioactive in nature?

Answer» Correct Answer - Tritium.
1317.

A sample of hard water is allowed to pass through an anion exchanger. Will it produce lather with soap easily?

Answer»

No, it will not produce lather with soap easily because Ca2+ ang Mg2+ ions are still present in hard water.

1318.

Name the isotope of hydrogen which is radioactive in nature.

Answer»

Tritium \(^3_1H\) is radioactive in nature.

1319.

The inorganic compound obtained by the auto oxidation of 2-alkylanthraquinol isA. `H_(2)O`B. `H_(2)O_(2)`C. `H_(2)`D. `O_(2)`

Answer» Correct Answer - B
1320.

A mixture of hydrazine and H2O2 with Cu(II) catalyst is used as a rocket propellant. Why?

Answer»

The reaction between hydrazine and hydrogen peroxide is highly exothermic So, this mixture is used as a rocket propellant.

NH2NH2 (l) + 2H2O2 (l) \(\overset{Cu(II)}{\rightarrow}\) N2 (g) + 4H2O (g)

1321.

A mixture of hydrazine and `H_(2)O_(2)` with Cu(II) catalyst is used as a rocket prepellant . Why ?

Answer» The reaction between hydrazine and `H_(2)O_(2)` is highl exothermic and is accoumpanied by a large increase in the volume of the products and hence this mixture is used as a rocket propellant.
`NH_(2)NH_(2)(l) + 2H_(2)O_(2)(l) overset( Cu (II))to N_(2)(g)uarr + 4H_(2)O(g) uarr`
1322.

Give reasons:(i) Lakes freeze from top towards bottom.(ii) Ice floats on water.

Answer»

i) During severe winter, the temperature of water in the lake keeps on decreasing. Since cold water is heavier, it keeps on going into the interior of the lake while warm water keeps on coming to the surface of the lake. This process continues till the temperature of entire water of lakes becomes 4°C. Since density of water is maximum at 277 K, any further decrease in the temperature will decrease its density. As a result, the temperature of the surface water keeps on decreasing and it ultimately freezes. Now, any further decrease in the temperature will decrease the temperature of water below 4°C. This process continues and as a result, the lakes keep on freezing from top to bottom.
(ii) Density of ice is less than water due to presence of empty spaces created because of H-bonding between H2O molecules. Hence, ice floats on water. 

1323.

Why do lakes freeze from top towards bottom?

Answer»

The upper surface of lake is in contact with the cold environment and starts to freeze. The density of ice is less than that of liquid water. Therefore, ice floats on the surface. Thus, the ice layer at lower temperature floats over the water below it. Due to this the freezing of water into ice occurs continuously from top towards bottom.

1324.

What do you understand by (i) electron-deficient,(ii) electron-précise and (iii) electron precise hydrides. Provide justification with suitable examples.

Answer»

Electron-deficient: the hydrides which contain less than eight electron in their outmost shell are called electron- deficient for exam B2H6 

Electron- precise: These hydrides contain exact number of electron to form covalent bonds and hence are called as electron-precise hydrides for example: CH4, SIH4,GeH4,SnH4 

Electron-rich: these have more electron than required to form nomal covalent bond and are called as electron rich hydrides. For example NH3,PH3,H2O,H2S.

1325.

Given reasons (i) Lakes freeze form top towards bottom. (ii) Ice floats on water.

Answer» (i) During severe winter, the temperature of water in the lake keeps on decreasing . Since cold water is heavier, therefore, it keeps on going into the interior of the lake while warm water from inside the lake keeps on coming to the surface of the lake. This process continues till the temperature of entire water of the lakes becomes 277 K. Since denisty of water is maximum at 277 K , therefore, any further decrease in the temperature of the surface water will decrease its density . As a result , the temperature of the surface water keeps on decreasing and ultimately freezes while the temperature of water underneath the surface remains at 277 K . Further decrease in the temperature of ice on the surface will decrease the temperature of water below 277 K lying underneath the surface of water. This decrease in temperature continues till it freezes. This process continues and as a result , the lakes keeps on freezing from top to bottom.
1326.

With the increasesA. orthoB. metaC. paraD. None.

Answer» Correct Answer - A
With the increase in temperature the proportion of ortho form of `H_(2)` increases till its proportion reaches `75%`.
1327.

Consider the following reaction I.`H_(2)(g) +X_(2)(g) to 2HX(g)(X= F, Cl, Br,l)` II. `2H_(2)(g)+O_(2)(g) =underset("heating")overset("Catalyst")to 2H_(2)O(l)` III. `3H_(2)(g)+N_(2)(g) =underset("Fe")overset("673 K. 200atm")to 2NH_(3)(g)` IV.`H_(2)(g) + Pd^(2+) (aq) to Pd(s)+2H^(+) (aq)` The correct reactions are .A. II, III and IVB. IV and VC. I, II and IVD. All of these

Answer» Correct Answer - D
All reactions are correct.
1328.

Complete the following chemical reactions: `(i) PbS(s) + H_(2)O_(2) (aq) to (ii) MnO_(4)^(-) (aq0 + H_(2)O_(2)(aq) to ` `(iii) CaO (s) + H_(2)O (g) to (iv) AlCl_(3) (g) + H_(2)O(l) to (v) Ca_(3)N_(2)(s) + H_(2)O(l) to ` Classify the above into (a) hydrolysis, (b) redox and (c) hydration reactions.

Answer» `(i) PbS(s) + 4H_(2)O_(2) (aq) to PbSO_(4) (s) + 4H_(2)O (l)`
`(ii) 2MnO_(4)^(-) (aq) + 5H_(2)O_(2) (l) + 6H^(+) (aq) to 2Mn^(2+)(aq) + 8 H_(2)O(l) + 5O_(2)(g)`
`(iii)CaO (s) + H_(2)O (g) to Ca(OH)_(2)(aq)`
`(iv) AlCl_(3) (g) + 3H_(2)O(l) to Al(OH)_(3)(s) + 3HCl (aq)`
`(v) Ca_(3)N_(2) (s) + 6H_(2)O(l) to 3Ca(OH)_(2) (aq) + 2NH_(3)(aq)`
(a) Hydrolysis reactions : (iii), (iv), (v). (b). Redox reactions : (i) and (ii).
1329.

Complete the following reactions : `(i) PbS(s) + H_(2)O_(2)(aq) to " "(ii) CO(g) + 2H_(2) underset("Catalyst")overset("Cobalt")to `

Answer» (i) `PbS(s) + 4H_(2)O_(2)(aq) to PbSO_(4) + 4H_(2)O " "(ii) CO(g) + 2H_(2)(g) underset("Catalyst")overset("Cobalt")to CH_(3)OH(l)`
1330.

Which of the following species is reduced by `H_(2)O_(2)`A. `|Fe(CN)_(6)|^(4-)`B. `|Fe(CN)_(6)|^(3-)` in alkaline mediumC. `NO_(2)^(-)`D. `I^(-)//HCl`.

Answer» Correct Answer - B
`|Fe(CN)_(6)|^(3-)"is reduced to"|Fe(CN)_(6)|^(4-) "in alkaline solution".
2|Fe(CN)_(6)|^(3-)+2OH^(-)+H_(2)O_(2)to2|Fe(CN)_(6)|^(4-)+2H_(2)O+O_(2)`
1331.

Complete the following reactions : `(i) H_(2)(g) + M_(m)O_(o)(s) overset(Delta)to" "(ii) CO(g) + H_(2)(g) underset("catalyst")overset(Delta)to ` (iii)` C_(3)H_(8)(g) + 3H_(2)O(g) underset("Catalyst")overset(Delta)to " "(iv) Zn(s)+ NaOH(aq) overset("heat")to`

Answer» `(i) oH_(2)(g) + M_(m)O_(o)(s) overset(Delta)mM(s) + oH_(2)O(l) " "(ii) CO(g)+ 2H_(2)(g)underset("Catalyst")overset(Delta)to underset("Methanol")(CH_(3)OH(l))`
`(iii) C_(3)H_(8)(g) + 3H_(2)O(g) overset(Ni,1270K)to 3CO(g) + 7H_(2)(g)`
`(iv) Zn(s) + 2NaOH (aq) overset("heat")to underset("Sod. zincate")(na_(2)ZnO_(2)(aq))+ H_(2)(g)`
1332.

If `100 mL` of acidified `2NH_(2)O_(2)` is allowed to react with `KMnO_(4)` solution till there is light tinge of purples colour, the volume of oxygen produced at `STP` is :A. `2.24 L`B. `1.12 L`C. `3.36 L`D. `4.48 L`

Answer» Correct Answer - A
Volume of `O_(2)` at `STP`
`=100mLxx11.2mL` volume strength
`=1120 mL` of `O_(2)at STP`
Since `1N=5.6` volume strength of `H_(2)O_(2)`
`2N=11.2` volume strength of `H_(2)O_(2)`
Volume of `O_(2)` produced by `H_(2)O_(2)=1120 mL`
Same volume of `O_(2)` will be produced by `KMnO_(4)`, i.e., `1120 mL`
1333.

Ethylene and `H_2O_2` react to giveA. `CO_(2),H_(2)O`B. `CO,H_(2)O`C. Ethylene oxideD. Ethylene glycol

Answer» Correct Answer - D
`H_(2)C=CH_(2)+H_(2)O_(2)tounderset("Ethylene")underset(OH)underset(|)(H_(2)C)-underset("glycol")underset(OH)underset(|)(CH_(2))`