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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
A Sum Of Rs.4800 Is Invested At A Compound Interest For Three Years, The Rate Of Interest Being 10% P.a., 20% P.a. And 25% P.a. For The 1st, 2nd And The 3rd Years Respectively. Find The Interest Received At The End Of The Three Years? |
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Answer» Let A be the amount received at the end of the THREE years. A = 4800[1 + 10/100][1 + 20/100][1 + 25/100] A = (4800 * 11 * 6 * 5)/(10 * 5 * 4) A = Rs.7920 So the interest = 7920 - 4800 = Rs.3120 Let A be the amount received at the end of the three years. A = 4800[1 + 10/100][1 + 20/100][1 + 25/100] A = (4800 * 11 * 6 * 5)/(10 * 5 * 4) A = Rs.7920 So the interest = 7920 - 4800 = Rs.3120 |
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| 52. |
Find The Compound Interest Accrued On An Amount Of Rs.14,800 At 13.5% P.a At The End Of Two Years. (round Off Your Answer To Nearest Integer) |
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Answer» CI = 14800{ [ 1 + 13.5/100]2 - 1 } = 14800 { [1 + 27/200]2 - 1 = 14800 { 2 + 27/200}{27/200} = (74)[2 + 27/200](27) = 1998[2 + 27/200] = 3996 + 269.73 = RS. 4266. CI = 14800{ [ 1 + 13.5/100]2 - 1 } = 14800 { [1 + 27/200]2 - 1 = 14800 { 2 + 27/200}{27/200} = (74)[2 + 27/200](27) = 1998[2 + 27/200] = 3996 + 269.73 = Rs. 4266. |
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| 53. |
A Property Decreases In Value Every Year At The Rate Of 6 1/4% Of Its Value At The Beginning Of The Year Its Value At The End Of 3 Years Was Rs.21093. Find Its Value At The Beginning Of The First Year? |
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Answer» 6 1/4% = 1/16 X *15/16 * 15/16 * 15/16 = 21093 x = 25600.24. 6 1/4% = 1/16 x *15/16 * 15/16 * 15/16 = 21093 x = 25600.24. |
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| 54. |
Two Pipes Can Separately Fill A Tank In 20 And 30 Hours Respectively. Both The Pipes Are Opened To Fill The Tank But When The Tank Is Full, A Leak Develops In The Tank Through Which One-third Of Water Supplied By Both The Pipes Goes Out. What Is The Total Time Taken To Fill The Tank? |
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Answer»
1 + 1/3 = 4/3 1 --- 12 4/3 --- ? 1/20 + 1/30 = 1/12 1 + 1/3 = 4/3 1 --- 12 4/3 --- ? 4/3 * 12 = 16 hrs. |
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| 55. |
Two Pipes A And B Can Fill A Tank In 4 And 5 Hours Respectively. If They Are Turned Up Alternately For One Hour Each, The Time Taken To Fill The Tank Is? |
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Answer» 1/4 + 1/5 = 9/20 20/9 = 2 2/9 9/20 * 2 = 9/10 ---- 4 hours WR = 1 - 9/10 = 1/10 1 H ---- 1/4 ? ----- 1/10 1/4 + 1/5 = 9/20 20/9 = 2 2/9 9/20 * 2 = 9/10 ---- 4 hours WR = 1 - 9/10 = 1/10 1 h ---- 1/4 ? ----- 1/10 2/5 * 60 = 24 = 4 hrs 24 min. |
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| 56. |
The Average Of 11 Numbers Is 10.9. If The Average Of First Six Is 10.5 And That Of The Last Six Is 11.4 The Sixth Number Is? |
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Answer»
1 to 6 = 6 * 10.5 = 63 6 to 11 = 6 * 11.4 = 68.4 63 + 68.4 = 131.4 – 119.9 = 11.5 6TH number = 11.5. 1 to 11 = 11 * 10.9 = 119.9 1 to 6 = 6 * 10.5 = 63 6 to 11 = 6 * 11.4 = 68.4 63 + 68.4 = 131.4 – 119.9 = 11.5 6th number = 11.5. |
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| 57. |
The Equal Amounts Of Money Are Deposited In Two Banks Each At 15% Per Annum For 3.5 Years And 5 Years Respectively. If The Difference Between Their Interests Is Rs.144, Find The Each Sum? |
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Answer» <P>(P*5*15)/100 - (P*3.5*15)/100 = 144 75P/100 – 52.5P/100 = 144 22.5P = 144 * 100 => P = Rs.640. (P*5*15)/100 - (P*3.5*15)/100 = 144 75P/100 – 52.5P/100 = 144 22.5P = 144 * 100 => P = Rs.640. |
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| 58. |
4000 Was Divided Into Two Parts Such A Way That When First Part Was Invested At 3% And The Second At 5%, The Whole Annual Interest From Both The Investments Is? |
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Answer» (X*3*1)/100 + [(4000 - x)*5*1]/100 = 144 3x/100 + 200 – 5x/100 = 144 2x/100 = 56 è x = 2800. (x*3*1)/100 + [(4000 - x)*5*1]/100 = 144 3x/100 + 200 – 5x/100 = 144 2x/100 = 56 è x = 2800. |
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| 59. |
Rs.1170 Is Divided So That 4 Times The First Share, Thrice The 2nd Share And Twice The Third Share Amount To The Same. What Is The Value Of The Third Share? |
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Answer» A+B+C = 1170 4A = 3B = 2C = x A:B:C = 1/4:1/3:1/2 = 3:4:6 6/13 * 1170 = Rs.540. A+B+C = 1170 4A = 3B = 2C = x A:B:C = 1/4:1/3:1/2 = 3:4:6 6/13 * 1170 = Rs.540. |
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| 60. |
The Ratio Of The Number Of Ladies To Gents At A Party Was 1:2 But When 2 Ladies And 2 Gents Left, The Ratio Became 1:3. How Many People Were At The Party Originally? |
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Answer» X, 2x (x-2):(2x-2) = 1:3 3x-6 = 2x-2 x = 4 x+2x = 3x x, 2x (x-2):(2x-2) = 1:3 3x-6 = 2x-2 x = 4 x+2x = 3x => 3*4 = 12. |
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| 61. |
The Ratio Of Two Numbers Is 2:3 And The Sum Of Their Cubes Is 945. The Difference Of Number Is? |
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Answer» 2x.....3x 35x cube = 945 X cube = 27 => x = 3. 2x.....3x 8x cube + 27x cube = 945 35x cube = 945 x cube = 27 => x = 3. |
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| 62. |
A And B Can Do A Work In 5 Days And 10 Days Respectively. A Starts The Work And B Joins Him After 2 Days. In How Many Days Can They Complete The Remaining Work? |
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Answer» WORK done by A in 2 DAYS = 2/5 REMAINING work = 3/5 Work done by both A and B in ONE day = 1/5 + 1/10 = 3/10 Remaining work = 3/5 * 10/3 = 2 days. Work done by A in 2 days = 2/5 Remaining work = 3/5 Work done by both A and B in one day = 1/5 + 1/10 = 3/10 Remaining work = 3/5 * 10/3 = 2 days. |
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| 63. |
A Can Do A Piece Of Work In 12 Days. He Worked For 15 Days And Then B Completed The Remaining Work In 10 Days. Both Of Them Together Will Finish It In? |
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Answer»
1/25 + 1/25 = 2/25 25/2 = 12 1/2 DAYS. 15/25 + 10/x = 1 => x = 25 1/25 + 1/25 = 2/25 25/2 = 12 1/2 days. |
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| 64. |
9 Men And 12 Boys Finish A Job In 12 Days, 12 Men And 12 Boys Finish It In 10 Days. 10 Men And 10 Boys Shall Finish It In How Many Days? |
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Answer» 9M + 12B ----- 12 days 12M + 12B ------- 10 days 10M + 10B -------? 108M + 144B = 120M +120B 18B + 12B = 30B ---- 12 days 20B + 10B = 30B -----? => 12 days. 9M + 12B ----- 12 days 12M + 12B ------- 10 days 10M + 10B -------? 108M + 144B = 120M +120B 24B = 12M => 1M = 2B 18B + 12B = 30B ---- 12 days 20B + 10B = 30B -----? => 12 days. |
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| 65. |
A Is Thrice As Efficient As B And Is, Therefore, Able To Finish A Piece Of Work 10 Days Earlier Than B. In How Many Days A And B Will Finish It Together? |
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Answer» WC = 3:1 WT = 1:3 1/x – 1/3x = 1/10 x = 20/3 3/20 + 1/20 = 1/5 => 5 days. WC = 3:1 WT = 1:3 x ............3x 1/x – 1/3x = 1/10 x = 20/3 3/20 + 1/20 = 1/5 => 5 days. |
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| 66. |
A Can Do A Piece Of Work In 30 Days. He Works At It For 5 Days And Then B Finishes It In 20 Days. In What Time Can A And B Together It? |
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Answer» 5/30 + 20/X = 1 x = 24 1/30 + 1/24 = 3/40 5/30 + 20/x = 1 x = 24 1/30 + 1/24 = 3/40 40/3 = 13 1/3 days. |
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| 67. |
How Many Seconds Will A Train 100 Meters Long Take To Cross A Bridge 150 Meters Long If The Speed Of The Train Is 36 Kmph? |
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Answer» D = 100 + 150 = 250 S = 36 * 5/18 = 10 MPS T = 250/10 = 25 sec. D = 100 + 150 = 250 S = 36 * 5/18 = 10 mps T = 250/10 = 25 sec. |
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| 68. |
Two Trains Of Equal Length, Running With The Speeds Of 60 And 40 Kmph, Take 50 Seconds To Cross Each Other While They Are Running In The Same Direction. What Time Will They Take To Cross Each Other If They Are Running In Opposite Directions? |
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Answer» RS = 60 -40 = 20 * 5/18 = 100/18 T = 50 D = 50 * 100/18 = 2500/9 RS = 60 + 40 = 100 * 5/18 RS = 60 -40 = 20 * 5/18 = 100/18 T = 50 D = 50 * 100/18 = 2500/9 RS = 60 + 40 = 100 * 5/18 T = 2500/9 * 18/500 = 10 sec. |
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| 69. |
Two Trains Each 250 M In Length Are Running On The Same Parallel Lines In Opposite Directions With The Speed Of 80 Kmph And 70 Kmph Respectively. In What Time Will They Cross Each Other Completely? |
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Answer» D = 250 m + 250 m = 500 m RS = 80 + 70 = 150 * 5/18 = 125/3 T = 500 * 3/125 = 12 sec. D = 250 m + 250 m = 500 m RS = 80 + 70 = 150 * 5/18 = 125/3 T = 500 * 3/125 = 12 sec. |
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| 70. |
Two Cars Cover The Same Distance At The Speed Of 60 And 64 Kmps Respectively. Find The Distance Traveled By Them If The Slower Car Takes 1 Hour More Than The Faster Car? |
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Answer» 60(X + 1) = 64x X = 15 60 * 16 = 960 KM. 60(x + 1) = 64x X = 15 60 * 16 = 960 km. |
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