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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1701. |
If the solubility product of lead iodide `(Pbl_(2))` is `3.2 xx 10^(-8)`, then its solubility in moles/litre will beA. `2 xx 10^(-3)`B. `4 xx 10^(-4)`C. `1.6 xx 10^(-5)`D. `1.8 xx 10^(-5)` |
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Answer» Correct Answer - A `K_(sp) = 4S^(3)` `4S^(3) = 3.2 xx 10^(-8), S = 2 xx 10^(-3) M`. |
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| 1702. |
Assertion (A ) `:` The degree of ionization of water is small at `25^(@)C` , only about one of every `10^(7)` molecules in pure water is ionized at any instant Reason (R ) `:` In pure water at `25^(@)C ` the molar concentration of water is essentially constant.A. Both A and R true and R is the correct explanation of AB. Both A and R are true but R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true |
| Answer» Correct Answer - B | |
| 1703. |
A buffer solution of `pH =9` can be prepared by mixingA. `CH_(3)COONa` and `CH_(3)COOHs`B. NaCl and NaOHC. `NH_(4)Cl` and `NH_(4)OH`D. `KH_(2)PO_(4)` and `K_(2)HPO_(4)` |
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Answer» Correct Answer - C A basic buffer `(pH=9)` is formed by mixing a solution of a weak base and its salt with a strong acid. Therefore, correct choice is (C ) i.e., `NH_(4)OH` and `NH_(4)Cl` |
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| 1704. |
Which one of the following curves represents the graph pH during the titration of `NaOH` and HCl(aq)A. B. C. D. |
| Answer» Correct Answer - A | |
| 1705. |
One litre of water contains `10^(-7)` mole hydrogen ions. The degree of ionization in water will beA. `1.8 xx 10^(-7)%`B. `0.8 xx 10^(-9)%`C. `3.6 xx 10^(-7)%`D. `3.6 xx 10^(-9)%` |
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Answer» Correct Answer - A 1 litre of water contains 1000/18 mole. So degree of ionization `= (10^(-7) xx 18)/(1000) = 1.8 xx 10^(-7)%` |
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| 1706. |
A buffer solution with pH 9 is to be prepared by mixing `NH_(4)Cl` and `NH_(4)OH`. Calculate the number of moles of `NH_(4)Cl` that should be added to one litre of `1.0 M NH_(4)OH`. `[ K_(b) = 1.8 xx 10^(-5)]`A. 3.4B. 2.6C. 1.5D. 1.8 |
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Answer» Correct Answer - D `pH = -log K_(b) + log. (["Salt"])/(["Acid"])` `pH = -log[1.8 xx 10^(-5)] + log.(["Salt"])/(1.0)` `9 = 4.7 + log.(["Salt"])/(1.0)` `log.(["Salt"])/(1.0) = 9 - 4.7 = 4.3` `(["Salt"])/(1.0) = "Antilog" (1)/(4.3), ["Salt"] = 1.8`. |
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| 1707. |
When a solid `KCI` is added to a saturated solution of `AgCI "in" H_(2)O`,A. Nothing happens.B. Solubility of `AgCI` decreases.C. Solubility of `AgCI` increases.D. Solubility product of `AgCI` increases. |
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Answer» Correct Answer - B `AgCI harr Ag^(o+) +CI^(Theta)` `KCI rarr K^(o+) +CI^(Theta)` Due to common ion effect of `CI^(Theta)`, the supression of ionisation of `AgCI`, takes place and solubility of `AgCI` decreases. |
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| 1708. |
For an acid buffer solution the `P^(H)` is `3`. The `p^(H)` can be increased byA. Increasing the concentration of saltB. Increasing the concentration of acidC. Decreasing the concentrationpf saltD. Independent of concentration of acid & salt |
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Answer» Correct Answer - A `P^(H) = P^(Ka) + "log" (["salt"])/(["acid"])` |
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| 1709. |
50 mL of 2N acetic acid mixed with 10 mL of 1N sodium acetate solution will have an approximate pH of `(K_(a)=10^(-5))`:A. 4B. 5C. 6D. 7 |
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Answer» Correct Answer - A Meq.of acetic acid `=50xx2=100` Meq.of `CH_(3)COONa=10xx1=10` `pH= -log K_(a)+log([Sal t])/([Acid])` or `pH= -log 10^(-5)+log (10)/(100)=4` |
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| 1710. |
One litre of water contains `10^(-7)` mole `H^(+)` ions. Degree of ionisation of water is:A. `1.8xx10^(-7)%`B. `1.8xx10^(-9)%`C. `3.6xx10^(-7)%`D. `3.6xx10^(-9)%` |
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Answer» Correct Answer - A `alpha= ("Number of mole dissociated")/("Total mole present")` `=(10^(-7))/(1000//18)=1.8xx10^(-9)=1.8xx10^(-7)%` (Total mole of `H_(2)O` in litre `=(1000)/(18)`) |
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| 1711. |
For the buffer solution containing `NH_(4)OH` and `NH_(4)Cl, P^(H)` of the buffer solution can be increased byA. Adding some more `H_(2)O`B. Adding some more `NH_(4)OH`C. Removing `NH_(4)Cl`D. Both 2 and 3 |
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Answer» Correct Answer - D `P^(H) = 14-P^(kb) - "log" [("salt")/("base")]` |
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| 1712. |
Which of the following is least likely to behave is Lewis baseA. `OH^(-)`B. `H_(2)O`C. `NH_(3)`D. `BF_(3)` |
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Answer» Correct Answer - D `BF_(3)` is an electron deficient species. |
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| 1713. |
The best indicator for the detection of the end point in the titration of a weak acid and a strong base isA. Methy1 orange `(pH` range `3 to 4)`B. Methy1 red `(pH` range `4 to 6)`C. Thymol blue `(pH` range `8 to 3)`D. Phemolphethalein `(pH` range `8 to 10)` |
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Answer» Correct Answer - D Indicator used for the titration of `WA` and `SB` is phenolphtaleim. Since the `pH` range near the end point is `8` to `10`. |
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| 1714. |
The best indicator for the detection of the end point in the titration of a weak acid and a strong base isA. Methyl orange (`3.1` to `4.4`)B. Methyl red (`4.2` to `6.3`)C. Bromothymol blue (`6` to `7.6`)D. Phenolphthalein (`8.2` to `10`) |
| Answer» Correct Answer - D | |
| 1715. |
Which of the following molecules acts as a Lewis acidA. `(CH_(3))_(3)B`B. `(CH_(3))_(2)O`C. `(CH_(3))_(3)P`D. `(CH_(3))_(3)N` |
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Answer» Correct Answer - A `(CH_(3))_(3)B` - is electron deficient. |
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| 1716. |
The best indicator for the detection of the end point in the titration of a weak acid and a strong base isA. Methy1 orange `(3 to 4)`B. Methy1 red `(5 to 6)`C. Bromothymol blue `(6 to 7.5)`D. Phenolphtalein `(8 to 9.6)` |
| Answer» Correct Answer - D | |
| 1717. |
According to Lewis concept acid isA. Proton donorB. Electron pair donorC. Electron pair acceptorD. Proton acceptor |
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Answer» Correct Answer - C According to Lewis concept, acid is a lone pair acceptor. |
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| 1718. |
According to Lewis concept which one of the following is not a baseA. `OH^(-)`B. `H_(2)O`C. `Ag^(+)`D. `NH_(3)` |
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Answer» Correct Answer - C It is electron accepter so Lewis acid. |
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| 1719. |
The `pK_(a)` of acteylsalicylic acid (aspirin) is `3.5`. The pH of gastric juice in human stomach is about `2-3` and the pH in the small intestine is about 8. Aspirin will be:A. Unionised in the small intestine and in the stomach.B. Completely ionised in the small intestine and in the stomach.C. Ionised in the stomach and alomost unionised in the small intestine.D. Ionised in the small intestine and almost unionised in the stomach. |
| Answer» Correct Answer - D | |
| 1720. |
According to Lewis concept, an acid is a substance whichA. Accepts protonsB. Donates protonsC. Accepts a lone pair of electronsD. Donates a lone pair of electrons |
| Answer» Correct Answer - C | |
| 1721. |
Which of the following is not a Lewis acidA. `BF_(3)`B. `FeCl_(3)`C. `SiF_(4)`D. `C_(2)H_(4)` |
| Answer» Correct Answer - D | |
| 1722. |
The compound that is not a Lewis acid isA. `BF_(3)`B. `AlCl_(3)`C. `BeCl_(2)`D. `SnCl_(4)` |
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Answer» Correct Answer - D Sn in `SnCl_(4)` has its octet completed while the central atoms in other molecules have incomplete octet. |
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| 1723. |
The `pK_(a)` of acetylsalicylic acid (aspirin) is 3.5. The pH of gastric juice in human stomach is about 2-3 and the pH in the small intestine is about 8. Aspirine will beA. Unionised in the small intestine and the stomachB. Completely ionised in the small intestine and in the stomachC. Ionised in the stomach and almost unionised in the small intestineD. Ionised in the small intestine and almost unionised in the stomach |
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Answer» Correct Answer - D Under strong acidic conditions present in stomach (pH 2-3), weak acids such as acetylsalicylic acid with `pK_(a) = 3.5` remains unionized but under basic conditions (pH 8) present in small intestine, it is ionized. Thus option (d) is correct. |
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| 1724. |
`0.1` mole of `CH_(3)CH (K_(b) = 5 xx 10^(-4))` is mixed with `0.08` mole of HCl and diluted to one litre. What will be the `H^(+)` concentration in the solutionA. `8 xx 10^(-2) M`B. `8 xx 10^(-11) M`C. `1.6 xx 10^(-11) M`D. `8 xx 10^(-5) M` |
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Answer» Correct Answer - B `CH_(3)NH_(2) + HCl rarr CH_(3)NH_(3)^(+)Cl^(-)` `{:(0.1,0.08,0),(0.02,0,0.08):}` (Basic buffer solution) `[OH^(-)] = K_(b) xx ("Base")/("Salt")` `= 5 xx 10^(-4) xx (0.02)/(0.08) x= (10^(-14))/(1.25 xx 10^(-4))` `= 8 xx 10^(-11) M` |
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| 1725. |
0.1 mole of `CH_(3)NH_(2)(K_(b) = 5 xx 10^(-4))` is mixed with 0.08 mole of HCl and diluted to one litre. What will be the `H^(+)` concentration in the solutionA. `8 xx 10^(-2)M`B. `8 xx 10^(-11) M`C. `1.6 xx 10^(-11) M`D. `8 xx 10^(-5) M` |
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Answer» Correct Answer - B `{:(CH_(3)NH_(2),+,HCl,rarr,CH_(3)NH_(3)^(+)Cl^(-)),(0.1,,0.08,,0),(0.02,,0,,0.08):}` As it is a basic buffer solution. `pOH = pK_(b) + log.(0.08)/(0.02) = - log5 xx 10^(-4) + log 4` `= 3.30 + 0.602 = 3.902` `pH = 14 - 3.92 = 10.09`, `[H^(+)] = 7.99 xx 10^(-11) = 8 xx 10^(-11) M` |
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| 1726. |
0.1 mole of `CH_(3)NH_(2) (K_(b) = 5 xx 10^(-4))` is mixed with 0.08 mole for HCl and diluted to one litre. What will be the `H^(+)` concentration in the solutionA. `8 xx 10^(-2)M`B. `8 xx 10^(-11)M`C. `1.6 xx 10^(-11)M`D. `8 xx 10^(-5) M` |
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Answer» Correct Answer - B `{:(CH_(3)NH_(2)+,HCl, rarr, CH_(3)NH_(3)^(+)Cl^(-)),(0.1, 0.08,, 0),(0.02, 0,, 0.08):}` (Basic buffer solutions) `[OH^(-)] = K_(b) xx ("Base")/("Salt") = 5 xx 10^(-4) xx (0.02)/(0.08) = 1.25 xx 10^(-4)` `:. [H^(+)] = (10^(-14))/([OH^(-)]) = (10^(-14))/(1.25 xx 10^(-4)) = 8 xx 10^(-11) M`. |
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| 1727. |
Which are strong acids ? (P)HI, (Q)`HNO_3` , (R)`H_2SO_3`A. Q onlyB. P and Q onlyC. Q and R onlyD. P,Q and R |
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Answer» Correct Answer - B |
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| 1728. |
What is the conjugate base of `HSO_4^-` ?A. `H^+`B. `H_2SO_4`C. `OH^-`D. `SO_4^(2-)` |
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Answer» Correct Answer - D |
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| 1729. |
What is maximum pH required to prevent the precipitation of ZnS in a solution that is 0.01 M `ZnCl_(2)` and saturated with 0.10M `H_(2)S`? [Given : `K_(sp)(ZnS)=10^(-21),` `K_(a_(1))xxK_(a_(2))` (of `H_(2)S`)=`10^(-20)`]A. `0`B. `1`C. `2`D. `4` |
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Answer» Correct Answer - B `K_(sp) = [Zn^(2+)][S^(2-)]` `[S^(2-)] = (10^(-21))/(0.01) = 10^(-19)` for `K_(a_(1)), K_(a_(2)) = ([H^(+)]^(2)[S^(2-)])/([H_(2)S])` `10^(-20) = ([H^(+)]^(2) xx 10^(-19))/(0.1) rArr [H^(+)] = 0.1` or `pH = 1` |
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| 1730. |
Which of the following is a Lewis baseA. `CH_(4)`B. `C_(2)H_(5)OH`C. AcetoneD. Secondary amine |
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Answer» Correct Answer - B::D Presence of lone pair of electron and they donate two electron pairs. |
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| 1731. |
In the equilibrium `CH_(3)COOH + HF hArr CH_(3)COOH_(2)^(+) + F^(-)`A. `F^(-)` is the conjugate acid of `CH_(3)COOH`B. `F^(-)` is the conjugate base of HFC. `CH_(3)COOH` is the conjugate base of `CH_(3)COOH_(2)^(+)`D. `CH_(3)COOH_(2)^(+)` is the conjugate base of `CH_(3)COOH` |
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Answer» Correct Answer - B `CH_(3)COOH + HF hArr CH_(3)COOH_(2)^(+) + F^(-)`. HF gives `H^(+)` to the `CH_(3)COOH`. So it is a conjugate base of HF. |
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| 1732. |
Conjugate base of a strong acid isA. a weak baseB. a strong baseC. neutralD. a weak acid |
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Answer» Correct Answer - A A strong acid has a weak conjugate base. |
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| 1733. |
Which one of the following compound is not a protonic acidA. `SO_(2)(OH)_(2)`B. `B(OH)_(3)`C. `PO(OH)_(3)`D. `SO(OH)_(2)` |
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Answer» Correct Answer - B `B(OH)_(3)` not have `H^(+)`. |
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| 1734. |
Acidity of diprotic acids in aqueous increases in the orderA. `H_(2)Te lt H_(2)S lt H_(2)Se`B. `H_(2)Se lt H_(2)Te lt H_(2)S`C. `H_(2)S lt H_(2)Se lt H_(2)Te`D. `H_(2)Se lt H_(2)S lt H_(2)Te` |
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Answer» Correct Answer - C Bond length increases from `H_(2)S` to `H_(2)Te`. |
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| 1735. |
You are given `10^(-5)MNaCl` solution and `10^(-8)MAgNO_(3)` solution.They are mixed in `1:1` volume ratio predict whether `AgCl` will be precipitated or not ,if solubility product `(Ksp)` of `AgCl=10^(-10)` |
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Answer» Upon mixing equal volumes ,volume of solution will get doubled.so concentreation of each ion will get halved from original value. ionic product `K_(lp)=[Ag^(+)][Cl^(-)]_("upon mixing")=(10^(-5))/(2)xx(10^(-5))/(2)=25xx10^(-15)( ltK_(sp))` Hence ,no precipitaion will take place. |
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| 1736. |
Calculate `K_(sp)` of `Fe_(4)[Fe(CN)_(6)]_(3)` at a particular temperature where solubility in water =smol//L |
| Answer» `K_(Sp)=4^(4).3^(3).(s)^(3+4)=6912s^(7)` | |
| 1737. |
The solubility of `Fe(OH)_(3)` would be maximum in :A. 0.1 M NaOHB. 0.1 M HClC. 0.1 M KOHD. 0.1M `H_(2)SO_(4)` |
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Answer» Correct Answer - d |
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| 1738. |
Which of the following is the strongest base?A. `C_(2)H_(5)^(-)`B. `C_(2)H_(5)COO`C. `C_(2)H_(6)O^(-)`D. `OH^(-)` |
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Answer» Correct Answer - A Acidic stength `C_(2)H_(6) lt C_(2)H_(5)OH lt C_(2)H_(5)COOH` Weakest acid wil have strongedt conjugate base. |
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| 1739. |
Which of the following is the strongest base ?A. `C_2H_5^-`B. `C_2H_5COO^-`C. `C_2H_5O^-`D. `OH^-` |
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Answer» Correct Answer - A |
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| 1740. |
Which of the following is the strongest baseA. `C_(2)H_(5)^(-)`B. `C_(2)H_(5)COO^(-)`C. `C_(2)H_(5)O^(-)`D. `OH^(-)` |
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Answer» Correct Answer - A `C_(2)H_(5)^(-)` is a strongest base. |
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| 1741. |
The solubility product of `Mg(OH)_(2)` is `1.2 xx 10^(-11)`. The solubility of this compound in gram per `100 cm^(3)` of solution isA. `1.4 xx 10^(-4)`B. `8.16 xx 10^(-4)`C. 0.816D. 1.4 |
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Answer» Correct Answer - B `{:("Mg"(OH)_(2),hArr,"Mg"^(2+)+,2OH^(-)),(,,(S),(2S)^(2)):}` `K_(sp) = 4S^(3) rArr S = 3sqrt((K_(sp))/(4)) = 3sqrt((1.2 xx 10^(-11))/(4))` `S = 1.44 xx 10^(-4) mol L^(-1) = 58 xx 1.44 xx 10^(-4) g L^(-1)` (mol. mass of `Mg(OH)_(2) = 50`) `= 83.52 xx 10^(-4) g L^(-1) = 8.35 xx 10^(-4)g//100c c`. |
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| 1742. |
A sample of water has a hardness expressed as 80 ppm of `Ca^(2+)`.This sample is passed through an ion exchange column and the `Ca^(2+)` is replaced by `H^+` What is the pH of the water after it has been so treated ? [Atomic mass of Ca=40]A. 3B. 2.7C. 5.4D. 2.4 |
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Answer» Correct Answer - d |
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| 1743. |
The pH of 0.1 M solution of the following salts increases in the orderA. `NaCl gt NH_(4)Cl lt NaCN lt HCl`B. `HCl lt NH_(4)Cl lt NaCl lt NaCN`C. `NaCN lt NH_(4)Cl lt NaCl lt HCl`D. `HCl lt NaCl lt NaCN lt NH_(4)Cl` |
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Answer» Correct Answer - B The characteristics of the given solutions are: NaCl neutral solution `NH_(4)Cl` slightly acidic due to the reaction `NH_(4)^(+) + H_(2)O hArr NH_(4)OH + H^(+)` NaCN slightly alkaline due to the reaction `CN^(-) + H_(2)O hArr HCN + OH^(-)` HCl highly acidic The pH of the solution will follow the order highly acidic `lt` slightly acidic `lt` neutral `lt`slightly alkaline i.e., `HCl lt NH_(4)Cl lt NaCl lt NaCN`. |
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| 1744. |
In the above question identify the true (T) and false (F) statement is `Hi` is replaced with `C_(2)H_(5)NH_(2)` in each statement .A. `TFFFT T`B. `TFFFFT`C. `FFT TFF`D. `FT T TFF` |
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Answer» Correct Answer - B Lewis base denotes a lone pair to an electron deficient species.Arrhenious base released `OH` Bronsted base accepts `H^(+)` from a species. |
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| 1745. |
Ammonium ion is :A. Lewis acidB. Lewis baseC. Bronsted acidD. Bronsted base |
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Answer» Correct Answer - C `NH_(4)^(+)rarr NH_(3)+H^(+) rArr "Bronsted Acid"` |
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| 1746. |
Assertion :- A solution of `NH_(4)Cl` in water is acidic in nature. Reacon : - Ammonium ions undergo hydroysis to from `NH_(4)OH` .A. AB. BC. CD. D |
| Answer» Correct Answer - 1 | |
| 1747. |
Ammonium ion isA. Neither an acid nor baseB. Both an acid and a baseC. A conjugate acidD. A conjugate base |
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Answer» Correct Answer - C `NH_(4)^(+)` is a conjugate acid `NH_(4)^(+) hArr NH_(3) + H^(+)`. |
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| 1748. |
Ammonium ion isA. a conjugate acidB. a conjugate baseC. neither an acid nor a baseD. both an acid and a base |
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Answer» Correct Answer - A `NH_(4)^(+)` is a conjugate acid of base `NH_(3)` |
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| 1749. |
Water is aA. photophobic solventB. protophilic solventC. amphiprotic solventD. aprotic solvent |
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Answer» Correct Answer - C Water is an amphiprotic solvent as it can accept protons as well as give protons. |
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| 1750. |
An example of salt that will not hydrolyse isA. `NH_(4)Cl`B. `KCl`C. `CH_(3)COONH_(4)`D. `CH_(3)COOK` |
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Answer» Correct Answer - B KCl is a salt of strong acid and strong base, so it cannot hydrolyse. |
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