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151.

If a chord, which is not a tangent of the parabola `y^2=16 x`has the equation `2x+y=p ,`and midpoint `(h , k),`then which of the following is(are) possible values (s) of `p , ha n dk ?``p=-1,h=1,k=-3``p=2, h=3, k=-4``p=-2, h=2, k=-4``p=5, h=4, k=-3`

Answer» Parabola,`y^2-16x=0` equation of chord.`2x+y=p`
The equation of chord at given middle point(h,k) to the parabola
`T=s_1`
`ky-8(x+h)=k^2-16h`
`ky-8x+8h-k^2=0`
`2x+y-p=0`
`-8/2=k/1=(8h-k^2)/(-p)`
`2k=-8`
`k=-4`
`(-4)/(-1)=(8h-16)/(-p)`
`4p-8h=16`
`p-2h=-4-(1)`
So, correct option is B.
152.

A silver of radius `1 cm` and work function `4.7 eV` is suspended from an insulating thread in freepace. It is under continuous illumination of `200 nm` wavelength light. As photoelectron are emitted the sphere gas charged and acquired a potential . The maximum number of photoelectron emitted from the sphere is `A xx 10^(e) (where 1lt A lt 10)` The value of `z` is

Answer» Correct Answer - 7
153.

Column I gives certain situating in which a straight metallic wire of resitance R is used and Column II gives some resulting effects. Match the statements in Column I with the statements in Column II and indicate your answer by darkening appropriate bubbles in the `4 xx 4` matrix given in the ORS.

Answer» Correct Answer - A::B
154.

Two wires each carrying a steady current I are shown in four configurations in Column I. Some of the resulting effects are described in Column II. Match the statements in Column I with the statements in Column II and the indicate your answer by darkening appropriate bubbles in the `4xx4` matrix given in the ORS.

Answer» Correct Answer - A::B
155.

Column I describes some situations in which a small object moves. Column II describes some characteristics of these motion. Match the situtions in column I with the characteristics in column II.

Answer» Correct Answer - A::B
156.

The image of an object, formed by a plano-convex lens at a distance of 8 m behind the lens, is real is one-third the size of the object. The wavelength of light inside the lens is 2/3 times the wavelength in free space. The radius of the curved surface of the lens isA. 1 mB. 2 mC. 3 mD. 6 m

Answer» Correct Answer - C
157.

A steady current `I` goes through a wire loop `PQR` having shape of a right angle triangle with `PQ = 3x, PR = 4x and QR = 5x`. If the magnitude of the magnetic field at `P` due to this loop is `k((mu_(0)I)/(48 pi x))`, find the value of `K`.

Answer» Correct Answer - 7
158.

Among the following, the least stable resonance structure is :A. B. C. D.

Answer» Correct Answer - A
159.

The dissociation constant of a substituted benzoic acid at `25^(@)C` is `1.0 xx 10^(-4)`. The pH of `0.01M` solution of its salt is :

Answer» Correct Answer - 8
160.

An aqeous solution of X is added slowly to an aqueous solution of Y as shown in List-I. The variation in conductivity of these reaction in List-II. Match List-I with List-II and select the correct answer using the code given below the lists: A. `{:(P,Q,R,S),(3,4,2,1):}`B. `{:(P,Q,R,S),(4,3,2,1):}`C. `{:(P,Q,R,S),(2,3,4,1):}`D. `{:(P,Q,R,S),(1,4,3,2):}`

Answer» Correct Answer - A
161.

`P` and `Q` are isomers of dicarboxylic acid `C_(4)H_(4)O_(4)`. Bothdecolorize `Br_(2)//H_(2)O`. On heating, `P` forms the cyclic anhydride. Upon treatment with dilute alkaline `KMnO_(4),P` as well as `Q` could produce one or more than one forms `S,T` and `U`. Compounds formed from `P` and `Q` are, respectivelyA. Optically active S and optically active pair (T,U)B. Optically inactive S and optically inactive pair (T,U)C. Optically acitve pair (T,U) and optically acitve SD. Optically inactive pair (T,U) and optically inactive S.

Answer» Correct Answer - B
162.

Let `veca=2hati+hatj-hatk&vecb=hati+2hatj+hatk` be two vectors. Consider a vector `vecC=alphaveca+betavecb,alpha,beta in R`. If the projection of `vec c` on the vector `(veca+vecb)` is `3sqrt(2)` then the minimum value of `(vec c -(vecaxxvecb)).vec c` equal to

Answer» Correct Answer - A
`vec c=alpha(2hati+hatj-hatk)+beta(hati+2hatj+hatk)`
`impliesvec c=(2alpha+betahati+(alpha=2beta)hatj+(beta-alpha)hatk`
`(vecc.(veca+vecb))/(|veca+vecb|)=3sqrt(2)implies9(alpha+beta)=18impliesalpha+beta=2` ltBrgt `(vecc-vecaxxvecb).vecc=(alphaveca+betavecb-vecaxxvecb).(alphaveca+betavecb)=6alpha^(2)+6alphabeta+6beta^(2)=6[alpha^(2)+alpha(2-alpha)+(2-alpha)^(2)]`
`=6(alpha^(2)-2alpha+4)=min` value 18.
163.

Different possible thermal decomposition pathways for peroxyesters are shown below. Match each pathway from List I with an appropriate structure from List II and select the correct answer using the code given below the lists. A. `{:(,,"P","Q","R","S"),(,"(A)","1","3","4","2"):}`B. `{:(,,"P","Q","R","S"),(,"(B)","2","4","3","1"):}`C. `{:(,,"P","Q","R","S"),(,"(C)","4","1","2","3"):}`D. `{:(,,"P","Q","R","S"),(,"(D)","3","2","1","4"):}`

Answer» Correct Answer - A
164.

A ball is dropped from a height of 20 m above the surface of water in a lake. The refractive index of water is 4.3. A fish inside the lake, in the line of fall of the ball, is looking at the ball. At an instant, when the ball is 12.8 m above the water surface, the fish sees the speed of the ball as `[Take _(g)=10m/s^(2).]`A. 9m/sB. 12m/sC. 16m/sD. 21.33m/s

Answer» Correct Answer - C
165.

Phase space diagrams are useful tools in analyzing all kinds of dynamical problems. They are especially useful is studying the changes in motion as initial position and momentum are changed. Here we consider some simple dynamical systems in one-dimensions. For such systems, phase space is a plane in which position is plotted along horizontal axis and momentum is plotted along vertical axis. The phase space diagram is x(t) vs. p(t) curve in this plane. The arrow on the curve indicates the time flow. For example, the phase space diagram for a particle moving with constant velocity is a straight line as shown in the figure. We use sign convention in which position or momentum upwards (or to right) is positive and downwards (or to left) is negative. The phase space diagram for simple harmonic motion is a circle centered at the origin. In the figure, the two circles represent the same oscillator but or different initial conditions, and `E_(1)` and `E_(2)` are the total mechanical energies respectively. Then A. `E_(1) = sqrt(2) E_(2)`B. `E_(1) = 2 E_(2)`C. `E_(1) = 4 E_(2)`D. `E_(1) = 16 E_(2)`

Answer» Correct Answer - C
166.

Phase space diagrams are useful tools in analyzing all kinds of dynamical problems. They are especially useful is studying the changes in motion as initial position and momentum are changed. Here we consider some simple dynamical systems in one-dimensions. For such systems, phase space is a plane in which position is plotted along horizontal axis and momentum is plotted along vertical axis. The phase space diagram is x(t) vs. p(t) curve in this plane. The arrow on the curve indicates the time flow. For example, the phase space diagram for a particle moving with constant velocity is a straight line as shown in the figure. We use sign convention in which position or momentum upwards (or to right) is positive and downwards (or to left) is negative. Consider the spring-mass system, with the mass submerged in water, as shown in the figure. The phase space diagram for one cycle of this system is A. B. C. D.

Answer» Correct Answer - B
167.

A block is moving on an inclined plane making an angle `45^@` with the horizontal and the coefficient of friction is `mu`. The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down. If we define `N=10mu`, then N is

Answer» Correct Answer - 5
168.

A boy is pushng a ring of mass 2kg and radius 0.5 m with a stick as shwon in figure. The stick applies a force of 2N on the ring and rolls it without slipping with an accelertaion of `0.3 m/s^2.` The coefficinet of friction between the ground and the ring is large enough that rolling always occurs and the coefficient of friction between the stick and the ring of (P/10). The value of P is

Answer» Correct Answer - 4
169.

A thin ring of mass 2kg and radius 0.5 m is rolling without on a horizontal plane with velocity 1m/s. A small ball of mass 0.1kg, moving with velocity 20 m/s in the opposite direction hits the ring at a height of 0.75m and goes vertically up with velocity 10m/s. Immediately after the collision A. the ring has pure totation about its stationary CM.B. the ring comes to a complete stop.C. friction between the ring and the ground is to the left.D. there is no friction between the ring and the ground.

Answer» Correct Answer - A::C
170.

Two ideal batteries of `emf V_(1) and V_(2)` and three resistance `R_(1)R_(2) and R_(3)` are connected The current in resistance `R_(2)` would be zero if A. `V_(1) = V_(2) and R_(1) = R_(2) = R_(3)`B. `V_(1) = V_(2) and R_(1) = 2R_(2) = R_(3)`C. `V_(1) =2V_(2) and 2R_(1) = 2R_(1) = 2R_(2) = R_(3)`D. `2V_(1) = V_(2) and 2R_(1) = R_(2) = R_(3)`

Answer» Correct Answer - A::B::D
171.

A particle is projected with speed `v_(0)` at an angle `theta(theta ne 90^(@))` with horizontal and it bounce at same angle with horizontal. If average velocity of journey is `0.8 v_(0)` where `v_(0)` is average velocity of first projectile then `alpha` is

Answer» For first projectile
=((2u_(x_(1))u_(y_(1)))/g+(2u_(x_(2))u_(y_(2)))/g+.......(2u_(x_(n))u_(y_(n)))/g)/((2u_(y_(1)))/g+....(2u_(y_(n)))/g)`
`U_(x)[(1+1/(alpha^(2))+1/(alpha^(4))+.....1/(alpha^(2n)))/(1+1/(alpha)+1/(alpha^(2))+.....+1/(alpha^(n)))]=0.8 V_(0)`
`(V_(0)[1/(1-1/(alpha^(2)))])/([1/(1-1/(alpha))])=0.8 v_(0)implies (alpha)/(1+alpha) =0.8 implies alpha=4`
172.

1 mole of Rhombic sulphur is treated with conc. `HNO_(3)` find the mass of `H_(2)O` formed

Answer» Correct Answer - 288
`32H_(2)O+S_(8)to8H_(2)SO_(4)+48H^(o+)+48e^(Theta)`
`underline([e^(Theta)+H^(o+)+HNO_(3)toNO_(2)+H_(2)O]xx48)`
`underset(1 mol)(S_(8))+48HNO_(3)to8H_(2)SO_(4)+48NO_(2)+underset(16" mol")(16H_(2)O)`
`implies` mass of `H_(2)O` formed `=(16)(18)g=288g`
173.

Mole fraction of urea in 900 gram water is 0.05 density of solution is `1.2g//cm^(3)`. Find the molarity of solution.

Answer» Correct Answer - 2.98 or 2.99
`wt_(H_(2)O)=900gimpliesn_(H_(2)O)=(900)/(18)=50`
Let moles of urea =y
`impliesx_(urea)=(y)/(y+50)=0.05`
`impliesy=(50)/(19)`
`thereforeWt_(urea)=((50)/(19))xx60=(3000)/(19)`
`thereforeWt_(solution)=(3000)/(19)+900=((201))/(19)xx100`
`rho_("solution")=1.2g//cm^(3)`
`impliesV_("solution")=(wt)/(rho)=((201)/(19))xx(100)/(1.2)`
`impliesM_(urea)=(n_(urea))/(V_(ml))xx1000=(((50)/(19))xx1000)/(((201)/(19))xx(100)/(1.2))=((500)(1.2))/(201)=(600)/(201)cong2.985`
Answer after rounding off =2.98
174.

A point charges Q is moving in a circular orbit of radius R in the x-y plane with an angular velocity `omega`. This can be considered as equivalent to a loop carrying a steady current `(Q omega)/(2 pi)`. S uniform magnetic field along the positive z-axis is now switched on, which increases at a constant rate from 0 to B in one second. Assume that the radius of hte orbit remains constant. The application of hte magnetic field induces an emf in the orbit. The induced emf is defined as the work done by an induced electric field in moving a unit positive charge around a closed loop. It si known that, for an orbiting charge, the magnetic dipole moment is proportional to the angular momentum with a porportionality constant `lambda`. The charge in the magnetic dipole moment associated with the orbit. at the end of the time interval of hte magnetic field charge, isA. `-gamma BQR^(2)`B. `gamma (BQR^(@))/(2)`C. `gamma(BQR^(2))/(2)`D. `gamma BQR^(2)`

Answer» Correct Answer - B
175.

The acidic hydrolysis of ether (X) shown below is fastest when. A. one phenyl group is replaced by a methyl groupB. one phenyl group is replaced by a para-methoxyphenyl groupC. two phenyl groups are replaced by two para-methoxyphenyl groups.D. no structural change is made to X.

Answer» Correct Answer - C
176.

A tertiary alcohol (H) upon acid-catalysed dehydration gives a product (I). Ozonolysis of (I) leads to compounds (J) and (K). Compound (J) upon reaction with KOH gives benzyl alcohol and a compound (L), whereas (K) on reaction with KOH gives only (M). The structurer of compound (I) is:A. B. C. D.

Answer» Correct Answer - A
177.

The `beta`-decay process, discovered around `1900`, is basically the decay of a neutron `(n)`, In the laboratory, a proton `(p)` and an electron `(e^(-))` are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a tro-body dcay process, it was observed that the electron kinetic energy has a continuous spectrum. Considering a three-body decay process i.e., `n rarr p + e^(-)+overset(-)v_(e )`, around `1930`, Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino `(overset(-)V_(e ))` to be massless and possessing negligible energy, and neutron to be at rest, momentum and energy conservation principles are applied. From this calculation, the maximum kinetic energy of the electron is `0.8xx10^(6)eV`. The kinetic energy carried by the proton is only the recoil energy. What is the maximum energy of the anti-neutrino?A. `0 le K le 0.8xx10^(6) eV`B. `3.0 eV le K le 0.8 xx 10^(6) eV`C. `3.0 eV le K le 0.8 xx 10^(6) eV`D. `0 le K lt 0.8 xx 10^(6) eV`

Answer» Correct Answer - D
178.

In the mac. Arthur process of extraction `Auoverset(NaCN,Q)toRunderset("with "Y)overset("extracted")toZ`A. R is `[Au(CN_(4))]^(Theta)`B. Z is `[Zn(CN)_(4)]^(2-)`C. Q is `O_(2)`D. Y is Zn

Answer» Correct Answer - B::C::D
`Auoverset(NaCN+O_(2))to[Au(CN_(4))]^(Theta)overset(Zn)to[Zn(CN)_(4)]^(2-)+Au`
179.

A planet of radius `R=(1)/(10)xx(radius of Earth)` has the same mass density as Earth. Scientists dig a well of depth`(R )/(5)` on it and lower a wire of the same length and a linear mass density `10^(-3) kg m(_1)` into it. If the wire is not touching anywhere, the force applied at the top of the wire by a person holding it inplace is (take the radius of Earth`=6xx10^6m` and the acceleration due to gravity on Earth is `10ms^(-2)`A. 96NB. 108NC. 120ND. 150N

Answer» Correct Answer - B
180.

A metal is illumimated by light of two different wavelength `248nm` and `310 nm` . The maximum speeds of the photoelectrons corresponding in these wavelength are `u_(1) and u_(2)` respectively . If the ratio `u_(1) : u_(2) = 2 : 1` and `hc = 1240 eVnm `, the work function of the meal is nearlyA. `3.7 eV`B. `3.2 eV`C. `2.8 eV`D. `2.5 eV`

Answer» Correct Answer - A
181.

The species which by definition has zero standard molar enthalpy of formation at `298K` isA. `Br_2 (g)`B. `Cl_2 (g)`C. `H_(2)O (g)`D. `CH_(4)(g)`

Answer» Correct Answer - B
182.

`I=(2)/(pi) int_(-pi//4)^(pi//4) (dx)/((1+e^(sinx))(2-cos2x))` then find `27I^(2)`

Answer» Correct Answer - 4
`I=(2)/(pi)underset(-(pi)/(4))overset(pi//4)int(dx)/((1+e^(sinx))(2-cos2x))` ..(i)
by a+b-x property
`I=(2)/(pi)underset(-(pi)/(4))overset(pi//4)int(dx)/((1+e^(-sinx))(2-cos2x))=(2)/(pi)overset(-(pi)/(4))overset(pi//4)int(e^(sinx)dx)/((1+e^(sinx))(2-cos2x))dx` ...(ii)
adding (1) and (2)
`2I=(2)/(pi)underset(-(pi)/(4))overset(pi//4)int((1+e^(sinx)))/((1+e^(sinx))(2-cos2x))dximpliesI=(1)/(pi)underset(-(pi)/(4))overset(pi//4)int(1)/(2(2cos^(2)x-1))dx=(1)/(pi)underset(-(pi)/(4))overset(pi//4)(sec^(2)x)/(3sec^(2)x-2)dx`
put `tanx=t.sec^(2)xdx=dt`
`=(2)/(pi)int_(0)^(1)(dt)/(3t^(2)+1)=(2)/(3pi)(1)/(((1)/(sqrt(3))))(tan^(-1)((t)/(1//sqrt(3))))_(0)^(1)=(2)/(3pi)(tan^(-1)(sqrt(3))-tan^(-1)(0))=(2)/(sqrt(3)pi)((pi)/(3))=(2)/(3sqrt(3))`
Now `27I^(2)=27xx(4)/(27)=4`
183.

A wire, which passes through the hole in a small bead, is bent in the form of quarter of a circle. The wire is fixed vertically on ground as shown in the figure. The bead is released from near the top of the wire and it slides along the wire without friction. As the bead moves from A to B, the force it applies on the wire is A. always radially outwardsB. always radially inwardsC. radially outwards initially and radially inwards later.D. radially inwards initially and radially outwards later.

Answer» Correct Answer - D
184.

What `omegane1` be a cube root of unity. Then minimum value of set `{|a+bomega+comega^(2)|^(2)`, a,b,c are distinct non zero intergers) equals

Answer» Correct Answer - 3
`|a+bomega+comega^(2)|^(2)=a^(2)+b^(2)+c^(2)-ab-bc-ca=(1)/(2){(a-b)^(2)+(b-c)^(2)+(c-a)^(2)}`
it will be minimum when `a=1,b=2,c=3`
so minimum value is 3.
185.

An infinitely long hollow conducting cylinder with inner radius `(r )/(2)` and outer radius `R` carries a uniform current ra density along its length . The magnitude of the magnetic field , ` | vec(B)|` as a function of the radial distance `r` from the axis is best represented byA. B. C. D.

Answer» Correct Answer - D
186.

Electrons with de-Broglie wavelength `lambda` fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray isA. `lamda_0 = ( 2mc lamda ^(2))/( h )`B. ` lamda_0 = ( 2h ) /( mc )`C. `lamda _0 = ( 2 m^(2) c ^(2) lamda ^(3))/(h^(2)) `D. `lamda _0 = lamda `

Answer» Correct Answer - A
187.

Statement-1: The total translational kinetic energy of fall the molecules of a given mass of an ideal gas is 1.5 times the product of its pressure and its volume because. Statement-2: The molecules of a gas collide with each other and the velocities of the molecules change due to the collision.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.C. Statement-1 is True, Statement-2 is FalseD. Statement-1 is False , Statement-2 is True

Answer» Correct Answer - B
188.

Two trains `A and B` moving with speeds `20m//s` and `30m//s` respectively in the same direction on the same straight track, with `B` ahead of `A`. The engines are at the front ends. The engine of train `A` blows a long whistle. Assume that the sound of the whistle is composed of components varying in frequency from `f_(1) = 800 Hz` to `f_(2) = 1120 Hz`, as shown in the figure. The spread in the frequency (highest frequency - lowest frequency) is thus `320 Hz`. The speed of sound in still air is `340 m//s`. (4) The speed of sound of the whistle isA. 340m/s for passengers in A and 310 m/s for passengers in BB. 360 m/s for passengers in A and 310 m/s for passengers in BC. 310 m/s for passengers in A and 360 m/s for passengers in BD. 340 m/s for passengers in both the trains

Answer» Correct Answer - B
189.

Two trains `A and B` moving with speeds `20m//s` and `30m//s` respectively in the same direction on the same straight track, with `B` ahead of `A`. The engines are at the front ends. The engine of train `A` blows a long whistle. Assume that the sound of the whistle is composed of components varying in frequency from `f_(1) = 800 Hz` to `f_(2) = 1120 Hz`, as shown in the figure. the spread in the frequency (highest frequency - lowest frequency) is thus `320 Hz`. the speed of sound in still air is `340 m//s`. (5) The distribution of the sound intensity of the whistle as observed by the passengers in train `A` is best represented byA. B. C. D.

Answer» Correct Answer - A
190.

`._(92)^(238)Uoverset(x_(1))to._(90)^(234)Thoverset(x_(2))to._(91)^(234)Paoverset(x_(3))to.^(234)Zoverset(x_(4))to._(90)^(230)Th` `x_(1),x_(2),x_(3),x_(4)`, `x_(1),x_(2),x_(3),x_(4)`, are either particles or radiation. ThenA. `x_(1)` is deflected toward negatively charged plate.B. `x_(2)` is `beta^(-)` particleC. `x_(3)` is `gamma`-radiationD. z is isotope of `.^(238)U`

Answer» Correct Answer - A::B::D
`x_(1)=alpha`
`X_(2)=beta`
`X_(3)=beta`
`X_(4)=alpha`
191.

Sodium stearete is a strong electrolyte. Which of the following plot is correct regarding its conductanceA. B. C. D.

Answer» Correct Answer - B
192.

A ray of light travelling in water is incident on its surface open to air. The angle of incidence is `theta`, which is less than the critical angle. Then there will beA. only a reflected ray and no refracted rayB. only a refracted ray and no reflected rayC. a reflected ray and a refracted ray and the angle between them would be less than `180^(@)-2theta`.D. a reflected ray and a refracted ray and the angle between them would be greater than `180^(@)-2theta`

Answer» Correct Answer - C
193.

A light inextensible string that gas over a smoth fixed polley as shown in the figure connect two blocks of mases it `0.36` kg and `0.72` kg Taking `g = 10 ms^(-2)` , find the work done by the string on the block of mass ` 0.36` kg doring the first second after the system is refosed from rest ,

Answer» Correct Answer - 8
194.

Two metallic rings ` A and B`, identical in shape and size but having different reistivities `rhoA and rhoB`, are kept on top of two identical solenoids as shown in the figure . When current `I` is switched on in both the solenoids in identical manner, the rings ` A and B` jump to heights `h_(A) and h_(B)`, repectively , with ` h_(A) gt h_(B)` . The possible relation(s) between their resistivities and their masses `m_(A) and m_(B)` is(are) A. `rho_(A) gt rho_(B) and m_(A)=m_(B)`B. `rho_(A) lt rho_(B) and m_(A)=m_(B)`C. `rho_(A) gt rho_(B) and m_(A)gtm_(B)`D. `rho_(A) lt rho_(B) and m_(A) lt m_(B)`

Answer» Correct Answer - B::C
195.

Electrical resistance of certain materials, known as superconductors, changes abruptly from a nonzero value of zero as their temperature is lowered below a critical temperature `T_(C) (0)`. An interesting property of super conductors is that their critical temperature becomes smaller than `T_(C) (0)` if they are placed in a magnetic field, i.e., the critical temperature `T_(C) (B)` is a function of the magnetic field strength B. The dependence of `T_(C) (B)` on B is shown in the figure. . In the graphs below, the resistance R of a superconductor is shown as a function of its temperature T for two different magnetic fields `B_1`(solid line) and `B_2` (dashed line). If `B_2` is larget than `B_1` which of the following graphs shows the correct variation of R with T in these fields?A. B. C. D.

Answer» Correct Answer - A
196.

Match gases under specified condition listed in Column I with their proerties/laws in Column II.

Answer» Correct Answer - A::B::C
197.

The work function `(phi)` of some metals is listed below . The number of metals which will show photoelectric effect when light of 300 nm wavelength falls on the metal is :

Answer» Correct Answer - 4
198.

Match the transformation in column I with appropriate options in column II

Answer» Correct Answer - A: p, r and s B : r and s C : t D: p, q and t
199.

Schemes 1 and 2 describe sequential transformation of alkynes M and N. Consider only the major products formed in each step for both the schemes. The correct statement with respect to product Y isA. It gives a positive Tollens test and is a functional isomer of X.B. It gives a positive Tollens test and is a geometrical isomer of X.C. It gives a positive iodoform test and is a functional isomer of X.D. It gives a positive iodoform test and is a geometrical isomer of X.

Answer» Correct Answer - C
200.

All the compounds listed in Column I react with water. Match the result of the respective reactions with the appropriate options listed in Column II.

Answer» Correct Answer - A::B::C::D