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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
7. The ages of Hari and Harry are in the ratio 5:7. Four years from now the ratio of their ages will be 3:4. Find their present ages. The denominator of a rational number is greater than its numerator by 8. f the numerator is increased by 17 and the denominator is decreased by 1, the number obtained is Find the rational number. |
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Answer» Let the rational number be=a/b `b=a+8` `(a+17)/(b-1)=3/2` `2a+34=3b-3` `3(a+8)-2a=37` `3a+24-2a=37` `a=13` `b=a+8=21` `a/b=13/21`. |
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| 2. |
`75(x+y)^2 - 48(x-y)^2` |
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Answer» `75(x+y)^2-48(x-y)^2` `75x^2+75y^2+150xy-48x^2-48y^2+96xy` `27x^2+27y^2+246xy`. |
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| 3. |
The digits of a two-digit number differ by 3 If the digits are interchanged and the resulting number is added to the original number we get 143 What can be the original number |
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Answer» Let first number be x Other number will be x+3 According to question 10x+(x+3)+10(x+3)+x=143 10x+x+10x+x+3+30=143 22x=110 x=5 digit will be 58 |
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| 4. |
If you subtract `1/2` from a number and multiply the result by `1/2` you get `1/8`. What is the number? |
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Answer» `(x-1/2)*1/2=1/8-(1)` `(x-1/2)=2/8=1/4` `x-1/2=1/4` `x=3/4` putting this value in equation 1 `(3/4-1/2)*1/2=1/4*1/2=1/8` |
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| 5. |
Solve the equation and check your result. `2 y + 5/3 = (26)/3 - y` |
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Answer» `2y+5/3=26/3-y` `3y=21/3` `y=7/3`. |
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| 6. |
Amina thinks of a number and subtracts `5/2` from it. She multiplies the result by 8. The result now obtained is 3 times the same number she thought of. What is the number? |
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Answer» Let the required number is `x`. Then, `8(x-5/2) = 3x` `8x-20= 3x=>5x = 20` `x = 4` So, number thought by Amina is `4`. |
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| 7. |
The perimeter of a rectangle is 13 cm and its width is `(2) 3/4 cm .` Find its length. |
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Answer» We know the perimeter`(P)` of a rectangle is `2(l+b)`, where l is length and b is breadth or width. Here, `P = 13cm` `b = 2 3/4 cm = 11/4cm` So, `13 = 2(11/4+l)` `=> l = 13/2-11/4 = 15/4cm = 3 3/4cm` |
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| 8. |
Sum of two numbers is 95. If one exceeds the other by 15, find the numbers. |
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Answer» Let two numbers be x and y According to Question x+y=95-(1) x-y=15-(2) adding equation 1 and 2 2x=110 x=55 y=40. |
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| 9. |
`(2x-13)/5 - (x-3)/11` = `(x-9)/5 + 1` |
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Answer» `(2x-13)/5 - (x-3)/11 = (x-9)/5+1` `=>1/55(22x-143-5x+15) = 1/5(x-9+5)` `=>17x-128 = 11(x-4)` `=>17x-128 = 11x-44` `=> 6x = 84=> x = 14` |
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| 10. |
Solve the equation. `6=z+2` |
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Answer» 6=z+2 subtracting 2 both sides z=4 |
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| 11. |
There is a narrow rectangular plot, reserved for a school, in Mahuli village. The length and breadth of the plot are in the ratio 11:4. At the rate Rs100 per metre it will cost the village panchayat Rs 75000 to fence the plot. What are the dimensions of the plot? |
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Answer» Let length of the rectangular plot in meters ` = 11x` The, breadth of the rectangular plot in meters ` = 4x` `:. ` Perimeter of the rectangular plot in meters `(P) = 2(11x+4x) = 30x` Total cost of fencing the plot ` = 75000` RsRate of cost ` = 100` Rs per meter So, perimeter`(P) = 75000/100 = 750` meter `:. 30x = 750` `=> x = 25` `:.` Length of the rectangular plot ` = 11**25 = 275m` Breadth of the rectangular plot ` = 4**25 = 100m` |
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| 12. |
Solve the equation. `6x=12` |
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Answer» 6x=12 dividing 6 both sides x=2. |
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| 13. |
Solve the equation. `1.6 = y/15`, `(2x)/3=18`,`7x-9=16` |
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Answer» 1)1.6=y/15 multiplying 15 both the sides. 1.6*15=y y=24. 2)2x/3=18 multiplying 3 both sides 2x=54 dividing 2 both the sides x=27. 3)7x-9=16 adding 9 both the sides 7x=25 dividing 7 both sides x=25/7. |
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| 14. |
Solve the equation. `t/5=10` |
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Answer» `t/5 = 10` `=>t = 10**5=> t = 50`` |
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| 15. |
The base of an isosceles triangle is `4/3 cm.` The perimeter of the triangle is `(4) 2/(15) cm.` What is the length of either of the remaining equal sides? |
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Answer» Let any of the remaining side of the isosceles triangle is `x` cm in length. Then, Perimeter of triangle, ` = x+x+4/3 = 2x+4/3` cm `=>2x+4/3 = 4 2/15`( Perimeter is `4 2/15`) `=>2x+4/3 = 62/15=>2x = 62/15-4/3` `=> 2x = 42/15 => x = 14/10 = 7/5 = 1 2/5` cm So, Required sides of given triangles are `1 2/5` cm each. |
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| 16. |
The number of boys and girls in a class are in the ratio 7:5. The number of boys is 8 more than the number of girls. What is the total class strength? |
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Answer» Let the number of boys in the class is `7x`. Then, the number of girls will be `5x`. We are given, `7x = 5x+8` `=>2x = 8 => x = 4` Total strength of class ` = 7x+5x = 12x = 12**4 = 48` |
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| 17. |
Solve the equation. `7x-9=16` |
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Answer» `7x-9 = 16` `=> 7x = 16+9` `=> 7x = 25=>x = 25/7` |
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| 18. |
Simplify and solve the linear equations. `3(t-3)=5(2t+1)` |
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Answer» 3(t-3)=5(2t+1) 3t-9=10t+5 7t=-14 t=-2. |
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| 19. |
Solve the equation. `3/7 + x = 17/7` |
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Answer» `3/7+x = 17/7` `x = 17/7 -3/7` `=>x = 14/7 => x =2` |
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| 20. |
Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers. |
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Answer» Let Those consecutive numbers be x,x+1,x+2 According to Question 2x+3(x+1)+4(x+2)=74 2x+3x+4x+11=74 9x=63 x=7 those 3 consecutive numbers are 7,8,9. |
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| 21. |
The sum of three consecutive multiples of 11 is 363. Find thesemultiples. |
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Answer» x be the multiple of 11 first number=x second number=x+11 third number=x+22 According to question x+(x+11)+(x+22)=363 3x+33=363 3x=330 x=110 first number=110 second number=121 third number=132. |
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| 22. |
Simplify and solve the linear equations. `15 (y - 4) - 2 (y - 9 ) + 5 (y + 6 ) =0` |
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Answer» `15(y-4)-2(y-9)+5(y+6) = 0` `=>15y -60 -2y +18 +5y +30 = 0` `=>18y = 12=> y = 12/18 = 2/3` |
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| 23. |
The present age of Sahil’s mother is three times the present age of Sahil. After 5 years their ages will add to 66 years. Find their present ages. |
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Answer» Assume present age of sahil be x Present age of his mother will be 3x after 5 years sahil age=x+5 his mothers age =3x+5. According to question (x+5)+(3x+5)=66 4x+10=66 4x=56 x=14 sahil present age=14 years his mother present age= 42 years. |
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| 24. |
Solve the linear equations. `x + 7 - (8 x)/3 = (17)/6 - (5 x)/2` |
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Answer» `x+7-(8x)/3 = 17/6 - (5x)/2` `=>x+(5x)/2 -(8x)/3 = 17/6-7` `=>(6x+15x-16x)/6 = (17-42)/6` `=>5x = -25=>x = -5` |
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| 25. |
Lakshmi is a cashier in a bank. She has currency notes of denominations Rs 100, Rs 50 and Rs 10, respectively. The ratio of the number of these notes is 2:3:5. The total cash with Lakshmi is Rs 4,00,000. How many notes of each denomination does she have? |
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Answer» Let the number of 100 rupees note `= 2x` Then, the number of 50 rupees note ` = 3x` Then, the number of 10 rupees note ` = 5x` We are given, `100(2x)+50(3x)+10(5x) = 400000` `=>200x+150x+50x = 400000` `=>400x = 400000` `=>x = 1000` So, the number of 100 rupees note ` = 2000` The number of 50 rupees note ` = 3000` The number of 10 rupees note ` = 5000` |
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| 26. |
Deveshi has a total of Rs 590 as currency notes in the denominations of Rs 50, Rs 20 and Rs 10. The ratio of the number of Rs 50 notes and Rs 20 notes is 3:5. If she has a total of 25 notes, how many notes of each denomination she has? |
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Answer» Let 50 Rs note be 3x 20 Rs note will be 5x 10 Rs note willbe(25-8x) Total denomination=590 According to question 50(3x)+20(5x)+10(25-8x)=590 150x+100x-80x+250=590 170x=340 x=2 50 Rs note are 3x=3*2=6 20 Rs note are 5x=5*2=10 10 Rs note are 25-16=9. |
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