InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Missing of menses is the first indication of pregnancy. |
| Answer» Due to fertilisation , corpus luteum increases in size and secretes progesterone and maintains the thickness of endometrium due to this there is no menstruation . So, missing of menses is the first indication of pregancy . | |
| 2. |
Give reasons : Surgical sterilization is a permanent method of birth control . |
| Answer» Surgical sterilization is a permanent method of birth control as the surgical intervention blocks the gamete transport and prevents pregnancy . | |
| 3. |
Give scientific reasons : (a) The pyramid of energy is always upright . (b) In an ecosystem the energy flow is always unidirectional . (c) Ozone present in the startosphere is called as " good ozone " . |
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Answer» (a) The pyramid of energy is always upright . Pyramid of energy is always upright , because energy flows from a paricular trophic level to next. Some energy is lost in the process thus it can never be inverted . (b) In an ecosystem the energy flow is always unidirectional . An energy captured by autotrophs does not go back to solar energy , i.e., which passes to herbivores does not go back to autotrophs . (c) Ozone present in the stratosphere is called as "good ozone ". As ozone absorbs UV rays from sun , which is harmful to living organism . |
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| 4. |
Solve the differential equation : ` (x + y) (dy)/(dx) = 1` . |
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Answer» Given , ` (x + y) (dy)/(dx) = 1` ` therefore (dy)/(dx) = x + y` `rArr (dx)/(dy) - x = y ` This is linear differential equation with x as dependent veriable of the from ` (dx)/(dy) + P x = Q . ` ` therefore P = - 1, Q = y ` The integrating factor , I.F. ` = e^(int" P dy" )= e^(int-1 dy) = e^(-y)` ` therefore ` The solution is , ` x (I.F.) = int Q (I.F.) dy + C ` ` rArr xe^(-y) = intye^(-y) dy + C ` ` rArr xe^(-y) = y [-e^(-y)] - int 1 (-e^(-y)) dy + C ` `rArr ex^(-y) = - ye^(-y) - e^(-y) + C ` ` rArr e^(-y) (x + y + 1) = C ` ` rArr x + y + 1 = Ce^(y)` is general solution . |
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| 5. |
Scrotal sac serves as thermo regulator. |
| Answer» Scrotal sac serves as thermoregulator as it regulates the temperature for spermatogenesis in tests . | |
| 6. |
After puberty human female shows cyclic changes in her reproductive system . Explain structural and hormonal changes in the uterus . |
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Answer» (a) Menstrual phase : When the ovum is not fertilized the high level progesterone inhibits secretion of Luteinising Hormone (LH) and LH level decreases . This results in decreases in level of progesterone from corpus luteum. When the amount of progesterone further decreases and stimulates anterior pituitary to secrete Follicle Stimulating Harmone (FSH) and proliferative phase begins the basal part of endometrium remains intact and thickness is only about 1mm. (b) Proliferative phase : In this phase the primordial follicle of the ovary develops into Graafian follicle . Many primordial follicles are present in the ovary. Changes in uterus : Oestrogen secreted by follicular cells of ovary stimulate endometrial glands . Thickness of endometrium grows to about 3 mm to 5 mm . (c) Ovulatory phase : Ovulation is the process in which there is rupture of Graafian follicle with discharge of ovum into abdominal cavity . It is uder influence of LH . A sudden rise in level of LH stimulates ovulation which occurs usually on 14 th day of menstrual cycle . (d) Secretory phase : Corpus luteun in ovary secrets progesterone . It causes further groeth of endometrial glands . Uterine gland secrets fluid which is rich in glycongen for nourishing the dividing embryo . It is also called uterine milk. Thus , further increases in thickness of endometrium takes place ( 5mm to 6 mm ) . If fertilisation occurs , embryo is implanted in thickened endometrium. |
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| 7. |
Valves are present in the veins. |
| Answer» Valves are thin walled with semilunar valves to prevent backward flow of blood . | |
| 8. |
The wall of left ventricle is thicker than right ventricle. |
| Answer» Left ventricle has thickest wall as it has to pump blood to all parts of the body. | |
| 9. |
Monocytes are called scavengers. |
| Answer» Monocytes circulate in the blood and become macrophages in the tissues . These cells are very important in alerting the immune system about an infection . Macrophages are scavengers whose job is to engulf infecting germs and even infected cells . | |
| 10. |
Lymphatic vessels are milky in appearance. |
| Answer» They come from intestine and contains absorbed fats which are directly absorbed in the intestine , hence they are milky in appearance . | |
| 11. |
Define pollution . " Industries are pouring poison in water" - Expalin. |
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Answer» Substances present in air , water or soil produced by the activity of mankind in concentration suffficient to cause harmful effect to the health , vegetables , property or to interface with the enjoyment of his property is called as pollution . (a) Most of the chemicals of industrial wastes have been toxic to humans as well as animals and may bring about death or sub - lethal pathology of the liver, kidneys, reproductive systems , respiratory systems . (b) In japan illness and even death occured in 1950 s among fisherman who ingested fish , crab and shell fish contaminated with methyl mercury poisoning produced a cripling and often a fatal disease called Minamata disease. |
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| 12. |
Define apiculture . Name the products obtained from it . |
| Answer» Rearing of honey bee is known as apiculture . Products obtained from it are honey , wax, venon and royal jelly. | |
| 13. |
Give the role of plasmids in bacterial cell. |
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Answer» (a) Plasmids in bacteria carry genes related to metabolic activity and allow the carrier bacterium to survive and reproduce under unfavourable conditions . (b) Plasmids also act as vector . |
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| 14. |
What is Sinus arrhythmias ? |
| Answer» During inspiration the heart rate increases and during expiration it decrease. This phenomenon is known as sinus arrhythmias . | |
| 15. |
By which process ammonia is converted into urea in liver ? |
| Answer» By ornithing cycle ammonia is converted into urea in liver. | |
| 16. |
Define Respiratory Quotient (RQ) and calculate the respiratory quotient of carbohydrate. |
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Answer» Ratio of volume of `CO_(2)` evolved to the volume of `O_(2)` consumed in respiration is known as Respiratory Quotient (RQ). When carbhoydrates are used as respiratory substrate and are completely oxidized , the RQ is 1 , because volume of `CO_(2)` evolved is equal to the volume of `O_(2)` consumed . RQ for carbohydrate is : `RQ = (6CO_(2))/( 6 O_(2)) = 1*0` `C_(6)H_(12)O_(6)+6 O_(2) to 6 CO_(2) + 6 H_(2)O` + energy. |
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| 17. |
Light and dark reactions are interdependent. Explain |
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Answer» Products of light reaction i.e., ATP and `NADPH_(2)` (assimilatory power ) are required for dark reaction i.e., for reduction of `CO_(2)` into gluocse. During dark reaction ADP, iP and NADP get regenerated and are required for synthesis of ATP and `NADPH_(2)` during light interdepent. |
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| 18. |
If three numbers are added , their sum is 2 . If two times the second number is subtracted from the sum of first and third numbers we get 8 and if three times the first number added to the sum of second and third numbers we get 4 . Find the numbers using matrices . |
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Answer» Let , x,y, z be three numbers. Then according to given conditions , we get the following equations : ` x + y + z = 2 ` ` x - 2y + z = 8 ` and ` 3x + y + z = 4 ` Now , putting these equations is matrix method we get , `[(1,1,1),(1, -2, 1),(3,1,1)][(x),(y),(z)] = [(2),(8),(4)] ` i .e. AX = B Now using , ` R_(2) - R_(1) , R_(3) - 3R_(1) ` , we get `[(1,1,1),(0,-3,0),(0,-2,-2)][(x),(y),(z)] = [(2),(6),(-2)] ` ` therefore x + y + z = 2 `...(i) ` - 3y = 6` `rArr y = - 2 ` and ` - 2 (y + z) = - 2 ` `rArr y + z= 1` ` rArr - 2 + z = 1 " "[ because y = - 2] ` ` rArr z = 3 ` Putting the values of y and z in equations (i) we get , ` x - 2 + 3 = 2 ` ` rArr x + 1 = 2 ` ` rArr x = 1 ` ` therefore ` Three numbers are ` x = 1 , y = - 2 and z = 3 ` . |
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| 19. |
Membrance bound receptors and hormones produce second messengers like .......A. ReninB. `IP_(3)`C. ANFD. GHRF |
| Answer» Correct Answer - B | |
| 20. |
Give the types of blood proteins and human hormones produced by recombinant DNA - technique. |
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Answer» Blood proteins : Erythropiotein , Factor VII , VIII,IX . Tissue plasminogen activator ( TPA) , Urokinase . Human hormones : Epidermal growth factor Follicle stimulating hormone , Insulin roth hormone or Somatotrophic harmone . |
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| 21. |
During double fertilization second male gamete fuses with....A. antipodal cellB. egg cellC. secondary nucleusD. synergids |
| Answer» Correct Answer - C | |
| 22. |
As the base sequence present on one stand of DNA decides the base sequence of other strand , this strand is considered as ......A. Descending strandB. Leading strandC. Lagging strandD. Complimentary strand |
| Answer» Correct Answer - D | |
| 23. |
Evaluate : `int_(0)^((pi)/(2)) sin^(2) x dx `. |
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Answer» `int_(0)^((pi)/(2)) sin^(2) x *dx = int_(0) ^((pi)/(2)) ((1 - cos 2x)/(2)) dx ` ` [ because cos 2x = 1 - 2 sin^(2) x] ` `= (1)/(2) int_(0)^((pi)/(2)) (1- cos 2x )dx` ` = (1)/(2) [ x - (sin 2x)/(2)]_(0) ^((pi)/(2))` ` = (1)/(2) [(pi)/(2) - (sin pi)/(2)]` `therefore int_(0)^((pi)/(2)) sin^2 x. d x = 1/2xxpi/2=pi/4` |
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| 24. |
In ` Delta ABC ` , prove that : ` sin ((B - C)/(3)) = ((b -c)/(a)) cos ((A)/(2))` |
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Answer» In `Delta ABC ` , ` a/(sinA) = b/(sinB)= c/(sin C)" "` (by sine rule) By equal ratio theorem we can write . ` (a) /(sin A) = (b - c)/(sin B - sinC )` ` rArr (a)/(b-c) = (sin A)/(sin B - sin C)` ` rArr (b - c)/(a) = (sin B sin C)/(sin A)` `rArr (b-c)/(a) = (2 sin ((B - C)/(2)). cos ((B + C)/(2)))/(sin A)` ` = (2 sin ((B - C)/(2)). cos ((pi - A)/(2)))/(sinA)` (` because A + B + C = pi ` , sum of all angles of triangle) ` = (2 sin ((B-C)/(2)) . sin ((A)/(2)))/(2 sin ((A)/(2)) . cos ((A)/(2)))` ` rArr (b-c)/(a) = (sin ((B - C)/(2)))/(cos((A)/2))` ` rArr ((b - c)/(a)) . cos ((A)/(2)) = sin ((B - C)/(2)) ` |
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| 25. |
Discuss the continunity of the funcation `f(x) = (log (2 + x) - (log (2 - x)))/(tan x ) "for x " ne 0 ` = 1 for x = 0 at the point x= 0 |
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Answer» f (x) is continuous at x = 0 if ` underset(x to 0 ) ("lim") f (x) = f(0) `. But , ` R.H.S = f (0) = 1 " "` …(Given) L.H.S `= underset(x to 0 ) (lim) f (x) ` `= underset(x to 0) lim (log (2+ x ) - log (2 - x))/(tan x )` ` = underset(x to 0)lim (log ((2 + x)/(2 -x)))/(tan x)` ` = underset(x to 0)lim (1)/(x) (log ((2 + x)/(2 -x)))/((tan x)/(x))` ... (Dividing both Nr and Dr by x ) ` = underset(x to 0)lim (log ((2 + x)/(2 -x))^(1//x))/((tan x)/(x))` ` = underset(x to 0)lim (log [(1 + (x)/(2))/(1 - (x)/(2))])/((tan x//x))` ` underset(x to 0)lim (log[({(1 + (x)/(2))^(1//2)})/({(1 - (x)/(2))^(-1//2)})])/(underset(x to 0)lim ((tanx)/(x)))` ` therefore L.H.S = (log ((e^(1//2))/(e^(-1//2))))/(1) = log e^(1//2 + 1//2)` = log e = 1 ` therefore` L.H.S . = R.H.S hence , f(x) is continuous at x = 0 . |
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| 26. |
`int(dx)/(9x^(2) +1)`A. ` (1)/(3) tan^(-1) (2x) + c`B. `(1)/(3) tan^(-1) x + c `C. `(1)/(3) tan^(-1) (3x) + c`D. `(1)/(3) tan^(-1) (6x) + c ` |
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Answer» Correct Answer - c `(1)/(3) tan^(-1) (3x) + c ` |
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| 27. |
The equation of line is ` 2x - 2 = 3y + 1 = 6z - 2 ` find its direction ratios and also find the vector equation of the line . |
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Answer» Given equation is ` 2x - 2 = 3y + 1 = 6z - 2 ` i.e. `(x -1)/((1)/(2)) = (y + (1)/(3))/((1)/(3)) = (z - (1)/(3))/((1)/(6))` The line passes through the point whose position vector is ` bar a ` . ` therefore vara = hati - (1)/(3) hatj + (1)/(3) hatk ` and direction ratios of line are ` (1)/(2), (1)/(3), (1)/(6) or 3,2,1`. ` therefore barb = 3hati + 2hatj + hatk ` Hence , vector equation of line is ` barr = bara + lambda barb ` `therefore barr = (hati - (1)/(3) hatj +(1)/(3) hatk) + lambda (3 hati + 2hatj + 3hatk)` . |
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| 28. |
If ` f(x) = (1 + 2x)^(1//x), for x ne 0` is continous at x = 0 , then f(0) = ………..A. eB. `e^(2)`C. 0D. 2 |
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Answer» Correct Answer - b `e^(2)` |
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| 29. |
Write the equation of the plane ` 3x + 4y - 2z = 5 ` in the vector form . |
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Answer» Given , the equation of the plane ` (3x + 4y - 2z = 5 )` Let `barr = xhati + yhatj + zhatk` be any vector in the plane and 3, 4, -2 are direction rations of `barn ` , which is normal to the plane . ` rArr barn = 3hati + 4hatj - 2hatk ` ` rArr (xhati + yhatj + zhatk) . (3hati + 4hatj - 2hatk) = 5 ` `rArr barr. (3hati + 4hatj - 2hatk) = 5` which is the required form . |
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| 30. |
Direction ratios of the line which is perpendicular to the lines with direction ratios (-1,2,2) and (0,2,1) areA. ` - 2 , - 1 , - 2 `B. `2, 1, 2 `C. `2, - 1, -2`D. `- 2, 1, - 2 ` |
| Answer» 2, - 1, 2 (All given options are incorrect ). | |
| 31. |
Find P and k if the equation `px^(2)-8xy+3y^(2)+14x+2y+k=0` represents a pair of perpendicular lines. |
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Answer» Given , `px^(2) - 8xy + 3y^(2) + 14x + 2y + q = 0 ` represents pair of perpendicular lines . Compaing it with ` ax^(2) + 2hxy + by^(2) + 2gx + 2fy + c = 0 ` ` therefore ` we get , a = p , 2h = - 8 (h = - 4), b = 3 , 2g = 14 , (g = 7) 2f = 2, (f = 1) and c = q The equation represents a pair of lines ` therefore abc + 2fgh - af^(2) - bg^(2) - ch^(2) = 0 ` Now put the values ` therefore 3pq + 2xx 1 xx 7 (-4) -p (1)^(2) - 3 (7)^(2) - q (-4)^(2) = 0 ` ` therefore 3 pq - 56 - p - 147 - 16q = 0 ` ...(i) Since , lines are perpendicular ` therefore a + b = 0 ` ` therefore p + 3 = 0 ` ` therefore p = - 3 ` Put the value of p in equation (i) , we get ` rArr " we get ", - 9q - 65 + 3 - 147 - 16 q = 0 ` ` rArr - 25 q - 200 = 0 ` `rArr - 25 q = 200` `rArr q = - 8 ` Hence , p = - 3 and q = -8` . |
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| 32. |
The acute angle between the two planes ` x + y + 2z` = 3 and 3x - 2y + 2z = 7 ` is …….A. ` sin^(-1) ((5)/(sqrt(102)))`B. ` cos^(-1) ((5)/(sqrt(102)))`C. ` sin^(-1) ((15)/(sqrt(102)))`D. ` cos^(-1) ((15)/(sqrt(102)))` |
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Answer» Correct Answer - b `cos^(-1) ((5)/(sqrt(102)))` |
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| 33. |
Find the principal solution of `cotx=-sqrt(3)`A. `(pi)/(6), (5pi)/(6)`B. `(5pi)/(6), (7pi)/(6)`C. `(5pi)/(6), (11pi)/(6)`D. `(pi)/(6), (11pi)/(6)` |
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Answer» Correct Answer - C `(5pi)/(6) , (11pi)/(6)` |
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| 34. |
Write the truth values of the following statement ` 2 + 3 = 5 or sqrt(2) + sqrt(3) = sqrt(5)` |
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Answer» Let ` p = 2 + 3 = 5 ` which is T ` q = sqrt(3) + sqrt(3) = sqrt(5)` which is F `therefore ` Truth value of given statement is T `vv` T F = T |
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| 35. |
Find the volume of the parallelopiped, if the coterminus edges are given by the vectors ` 2hati + 5hatj - 4hatk . 5hati + 7hatj + 5hatk , 4hati + 5hatj - 2hatk` |
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Answer» Let ` baca = 2hati + 5hatj - 4hatk , barb = 5hati + 7hatj + 5hatk` ` barc = 4hati + 5hatj - 2hatk ` `therefore bara . (baraxxbarc) = |{:(2,5,-4),(5,7,5),(4,5,-2):}|` ` = 2(-14 - 25 ) - 5 (- 10 - 20 ) - 4 (25 - 28) ` ` = - 78 + 150 + 12 = 84 ` ` therefore ` Volume of parallelopiped is 84 cubic units. |
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