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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

According to the Balances on steady-state processes, the accumulation is equal to?(a) 1(b) 0(c) 100(d) 2I had been asked this question by my college director while I was bunking the class.I need to ask this question from Material Balance Numericals in division Material Balance of Bioprocess Engineering

Answer»

Correct answer is (b) 0

Easy explanation: The process is said to be operating at steady-STATE when all process variables do not CHANGE with time.

The accumulation term in a balance must equal to ZERO to ENSURE that the amount/mass of material in the process do not change with time.

Steady state means accumulation = 0

Input + generation – output – CONSUMPTION = 0

Input + generation = output + consumption.

2.

Conversion of 40°C into Fahrenheit.(a) 40 F(b) 100 F(c) 4 F(d) 104 FThis question was posed to me in an online interview.I'm obligated to ask this question of Thermodynamic Preliminaries in section Material Balance of Bioprocess Engineering

Answer» RIGHT choice is (d) 104 F

Explanation: T(°F) = T(°C) × 9/5 + 32

= 40 × 9/5 + 32

= 104 F.
3.

What do you mean by material balance equation?(a) Original-Solids-in-place (OSIP)(b) Original-Gas-in-place (OGIP)(c) Original-Air-in-place (OAIP)(d) Original-Liquid-in-place (OLIP)The question was asked in an interview for internship.Question is from Material Balance Numericals in portion Material Balance of Bioprocess Engineering

Answer»

Correct answer is (d) ORIGINAL-Liquid-in-place (OLIP)

Explanation: Material balance analysis is an INTERPRETATION method used to determine original fluids-in-place (OFIP) based on production and static PRESSURE data. The general material balance equation relates the original oil, gas, and water in the reservoir to production volumes and current pressure conditions / fluid PROPERTIES.

4.

What is the COD (chemical oxygen demand) of ethanol, expressed as g COD/g ethanol?(a) 1.30 g COD/g ethanol(b) 32 g COD/g ethanol(c) 2.24 g COD/g ethanol(d) 2.09 g COD/g ethanolThe question was asked in quiz.My question is based upon Stoichiometry of Growth and Product Formation topic in division Material Balance of Bioprocess Engineering

Answer»

Right choice is (d) 2.09 g COD/g ETHANOL

The best I can explain: Ethanol (C2H5OH) has a DEGREE of reduction of 12 (MOL electrons/mol ethanol). Oxygen has a degree of reduction of -4 (mol electrons/mol oxygen)and a molecular WEIGHT of 32 g/mol, which corresponds to 8 g oxygen (=COD)/mol electrons. Multiplying 12 by 8, this results in 96 g COD/mol ethanol, or, 96/46 = 2.09 g COD/g ethanol.

5.

What is the degree of reduction of glucose?(a) 4(b) 3(c) 12(d) 24This question was posed to me during an interview.The doubt is from Stoichiometry of Growth and Product Formation topic in section Material Balance of Bioprocess Engineering

Answer»

The correct option is (d) 24

Easiest EXPLANATION: Glucose is C6H12O6. The DEGREE of reduction = 6 X (+4) + 12 x (+1) + 6 x (-2) = 24.

6.

Which of the following is the example of Reflexivity equivalence relation?(a) A ∼ A(b) A ∼ B(c) A ∼ C(d) C ∼ BI had been asked this question in quiz.Asked question is from Thermodynamic Preliminaries topic in section Material Balance of Bioprocess Engineering

Answer»

Right choice is (a) A ∼ A

Explanation: The equivalence relation is of reflexivity as an example of a reflexive relation is the relation “is equal to” on the SET of real numbers since EVERY real NUMBER is equal to itself. A reflexive relation is said to have the reflexive PROPERTY or is said to possess reflexivity. Along with symmetry and transitivity, reflexivity is one of three properties defining equivalence relations.

7.

”Bacteria have slightly higher nitrogen content than fungi”.(a) True(b) FalseI got this question in an international level competition.Question is from Stoichiometry of Growth and Product Formation in section Material Balance of Bioprocess Engineering

Answer»

The correct option is (a) True

For explanation: BACTERIA TEND to have SLIGHTLY higher NITROGEN contents (11-14%) than fungi (6.3-9.0%).

8.

What is the combined feed ratio from the following?(a) Quantity of mixed feed stream to the quantity of fresh feed stream(b) Quantity of recycle stream to the quantity of fresh feed stream(c) Quantity of fresh feed stream to the quantity of recycle stream(d) Quantity of fresh feed stream to the quantity of mixed feed streamThe question was posed to me in class test.The query is from Material Balances with Recycle, By topic in chapter Material Balance of Bioprocess Engineering

Answer»

The CORRECT answer is (a) Quantity of MIXED feed STREAM to the quantity of FRESH feed stream

Best EXPLANATION: Combined feed ratio is the ratio of the quantity of mixed feed stream to the quantity of fresh feed stream.

Combined feed ratio = M/F.

9.

Each year 80,000 people move into a city, 70,000 people move out, 18,000 are born, and 11,000 die. Write a balance on the population of the city.(a) 17,000 P/yr(b) 15,000 P/yr(c) 20,000 P/yr(d) 22,000 P/yrI got this question in semester exam.I need to ask this question from Material Balance Numericals in division Material Balance of Bioprocess Engineering

Answer»

The correct answer is (a) 17,000 P/yr

Explanation: LET P denotes people,

INPUT + GENERATION – Output – Consumption = accumulation

80,000 P/yr + 18,000 P/yr – 70,000 P/yr – 11,000 P/yr = A(P/yr)

A = 17,000 P/yr

Each YEAR the city’s population increases by 17,000 P/yr.

10.

In the fluid, when the flow velocity is constant at each point over time. Which term is applicable over this condition?(a) Thermodynamic equilibrium(b) Osmotic equilibrium(c) Hydrostatic equilibrium(d) Water pressure equilibriumThis question was addressed to me in an internship interview.The query is from Thermodynamic Preliminaries in portion Material Balance of Bioprocess Engineering

Answer»

The CORRECT option is (c) Hydrostatic equilibrium

Explanation: In fluid mechanics, a fluid is said to be in hydrostatic equilibrium or hydrostatic balance when it is at rest, or when the FLOW velocity at each point is constant over time. This occurs when external forces such as GRAVITY are balanced by a PRESSURE gradient FORCE.

11.

Which of the following is an example of neither intrinsic nor extrinsic property?(a) Mass(b) Electrical resistance (Series)(c) Electrical resistance (Parallel)(d) TemperatureI have been asked this question in class test.This key question is from Thermodynamic Preliminaries in chapter Material Balance of Bioprocess Engineering

Answer»

Correct answer is (c) Electrical resistance (Parallel)

To explain: When TWO wires with electrical resistances R1 and R2 are connected in series than the TOTAL resistance is an extensive quantity Rtotal = R1 + R2, but when the wires are connected in parallel the total resistance is not extensive 1/Rtotal = 1/R1 + 1/R2. THEREFORE, electrical resistance is not an extensive nor INTENSIVE quantity.

12.

A process unit involves 3 chemical components. How many mass balances can be written?(a) 3(b) 5(c) 6(d) 4I had been asked this question in an online interview.I'd like to ask this question from Material Balance Numericals in section Material Balance of Bioprocess Engineering

Answer»

The CORRECT option is (d) 4

The best explanation: We can write 4 BALANCE equations: A TOTAL balance equation and 3 component balance equations.

Independent balances: Not all balances are independent SINCE the total balance is the SUM of all of the component balances.

Thus, the number of independent balances we can write = the number of components.

13.

2SO2+O2 → 2SO3. What is the stoichiometric ratio of SO2 to SO3?(a) 3(b) 1(c) 2(d) 0I have been asked this question in unit test.My question is taken from Law of Conservation of Mass in section Material Balance of Bioprocess Engineering

Answer» CORRECT choice is (b) 1

To elaborate: stoichiometric RATIO of SO2 to SO3 = (2 mole of SO2 reacted)/(2 mole of SO3 produced) = 1.
14.

Which of the following represents the figure corresponding to the stream?(a) Recycle system(b) By-pass system(c) Purge system(d) Recover streamI got this question in final exam.My question is from Material Balances with Recycle, By topic in chapter Material Balance of Bioprocess Engineering

Answer»

The correct answer is (b) By-pass system

To elaborate: A by-pass is one where a portion of the inlet to a process unit is split from the feed and instead of entering the process is combined with the outlet from that process. This practice is far less common than RECYCLE, but may be USED if your ultimate goal is a material with PROPERTIES” in-between” the UNTREATED reactant and the process outlet product.

15.

Which of the following system follows the differential equation?(a) Semi- Batch process(b) Batch process(c) Fed- Batch process(d) Continuous processThis question was addressed to me during an interview.I would like to ask this question from Law of Conservation of Mass topic in portion Material Balance of Bioprocess Engineering

Answer»

The correct choice is (d) Continuous process

Explanation: Amounts of mass entering and leaving the system are specified USING flow rates, a mass balance based on rates is called a differential balance. WHEREAS, each term of the mass-balance equation in this case is a quantity of mass, not a RATE. This type of balance is called an integral balance. Differential balances for continuous SYSTEMS operating at steady state and integral balances for batch and semi-batch systems between INITIAL and final states are used.

16.

Calculate the degree of reduction for ethanol, where the degree of reduction of C=4, H=1, O=-2.(a) γ = 9(b) γ = 6(c) γ = 3(d) γ = 2This question was addressed to me in an online quiz.The query is from Law of Conservation of Mass topic in portion Material Balance of Bioprocess Engineering

Answer»

Correct option is (b) γ = 6

To elaborate: Ethanol (C2H5OH) = 2(4) + 6(1) + 1(-2) = 12,

γ = 12/2 = 6

As, the number of equivalents of available ELECTRONS per GRAM atom C is the measure of degree of reduction.

17.

If the reactant Magnesium reacts with Reactant Hydrochloric acid to form the product Magnesium chloride + Hydrogen, then what will be the atomic mass of both the product?(a) 90(b) 97(c) 80(d) 87This question was posed to me during a job interview.This question is from Law of Conservation of Mass topic in chapter Material Balance of Bioprocess Engineering

Answer»

Correct OPTION is (b) 97

Easiest explanation: Mg (Magnesium) + 2 HCL (Hydrochloric acid) = MgCl2 (Magnesium chloride) + H2 (HYDROGEN),

Atomic masses: Mg = 24, H = 1, Cl = 35.5

one atom of Mg, 2 atoms of H and 2 atoms of Cl on both sides of the equation,

Law of conservation of mass balance: 24 + 2 × (1+ 35.5) = 24+ (2 × 35.5) + (2×1) = 97 (Both equal 97)

Note the subscript 2 after the Cl in magnesium chloride or the 2 after the H in the hydrogen MOLECULE, means two atoms of that element.

The 2 before the HCl doubles the number of hydrochloric acid molecules.

18.

A continuous process is set up for treatment of wastewater. Each day, 10^3 kg cellulose and 10^5 kg bacteria enter in the feed stream, while 10^2 kg cellulose and 1.5 x 10^2 kg bacteria leave in the effluent. The rate of cellulose digestion by the bacteria is 8 x 10^2 kg d^-1. The rate of bacterial growth is 4x 10^2 kg d^-l; the rate of cell death by lysis is 6 x 10^2 kg d^-1. Write balances for cellulose and bacteria in the system.(a) 1× 10^3 kg, 9 × 10^3 kg(b) 1× 10^2 kg, 9.965 × 10^4 kg(c) 1× 10^3 kg, 9.964 × 10^4 kg(d) 1× 10^2 kg, 9 × 10^3 kgI had been asked this question in class test.The above asked question is from Law of Conservation of Mass topic in division Material Balance of Bioprocess Engineering

Answer» RIGHT answer is (B) 1× 10^2 kg, 9.965 × 10^4 kg

Easiest explanation: Cellulose is not generated by the process, only consumed. Using a basis of 1 DAY, the cellulose balance in kg is :

(10^3 – 10^2 + 0 – 8 x 10^2) = accumulation

Therefore, 1× 10^2 kg cellulose accumulates in the SYSTEM each day.

Performing the same balance for bacteria:

(10^5 – 1.5 x 10^2 + 4 x 10^2 – 6 x 10^2) = accumulation

Therefore, 9.965 × 10^4 kg bacterial cells accumulate in the system each day.
19.

Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt% methanol and the second contains 70.0 wt% methanol. If 200 kg of the first mixture is combined with 150 kg of the second, what are the mass and composition of the product (Total balance, Methanol balance, Physical constraint)?(a) 350 kg, 0.529, 0.471(b) 320 kg, 0.529, 0.521(c) 360 kg, 0.620, 0.471(d) 350 kg, 0.690, 0.760The question was posed to me in unit test.My question comes from Law of Conservation of Mass topic in section Material Balance of Bioprocess Engineering

Answer»

Right answer is (a) 350 kg, 0.529, 0.471

To ELABORATE: Material Balances (Steady-State, Non-Reactive Process) :

Total Balance: m1 + M2 = m3

Methanol-Balance: m1xM1 + m2xM2 = m3xM3

Water-Balance: m1xw1 + m2xw2 = m3xw3

(choose only 2 equations since one of them is no longer independent)

Physical Constraint (applied to mixture 3):

xM3 + xW3 = 1.00

Always START with the equation with the least NUMBER of unknowns if possible and minimize solving equations simultaneously.

Total Balance (m3)



Methanol Balance (xM3)



Physical Constraint (xW3)

Total balance:

m3 = (200 kg) + (150 kg)

m3 = 350 kg

CH3OH balance:

(200 kg)(0.40) + (150 kg)(0.70) = (350 g)xM3

xM3= 0.529

Physical constraint:

xW3 = 1.00 – xM3 = 1 – 0.529

xW3 = 0.471.

20.

From the following type of processes, which type depends on the steady-state condition?(a) Batch process(b) Fed-Batch process(c) Semi-Batch process(d) Continuous processI got this question during an interview.The query is from Thermodynamic Preliminaries in section Material Balance of Bioprocess Engineering

Answer»

The correct answer is (d) Continuous process

The explanation is: If all properties of a SYSTEM, such as temperature, pressure, concentration, volume, MASS, etc. do not vary with time, the process is said to be at steady state. Continuous processes MAY be either steady state or transient. It is USUAL to RUN continuous processes as close to steady state as possible; however, unsteady-state conditions will exist during start-up and for some time after any change in operating conditions.

21.

The fresh feed to an ammonia synthesis reactor contains nitrogen, hydrogen and 2.0 mole per cent inerts. The molar ratio of H2:N2 is 3:1. The product stream consists of pure ammonia. Since conversion in the reactor is only 15%, a recycle stream is used and in order to avoid build-up of inerts, a purge stream is withdrawn. The rate of purge stream is adjusted to keep inert concentration in the recycle stream at 8 mole per cent. For a fresh feed rate of 100 moles/hr. Note that recycle stream contains only nitrogen, hydrogen and inerts. The N2:H2 ratio of 1:3 is maintained in every process stream, and calculate the number of moles, moles of inerts and moles of hydrogen in the recycle stream?(a) 437 moles/hr, 35 moles/hr, 301.5 moles/hr(b) 237 moles/hr, 30 moles/hr, 200 moles/hr(c) 567 moles/hr, 35 moles/hr, 205 moles/hr(d) 347 moles/hr, 30 moles/hr, 500 moles/hrThe question was posed to me in an interview.My doubt is from Material Balances with Recycle, By topic in chapter Material Balance of Bioprocess Engineering

Answer»

Right option is (a) 437 moles/hr, 35 moles/hr, 301.5 moles/hr

To explain I would say: TOTAL NUMBER of moles in the RECYCLE STREAM = 100.50×4/0.92 = 437 moles/hr

Moles of inerts in the recycle stream = 437 – 100.50×4=35 moles/hr

Moles of hydrogen in the recycle stream = 100.50×3 = 301.50 moles/hr.

22.

When pure carbon is burned in air, some of it oxidizes into CO2 and some to CO. The molar ratio of N2 to O2 is 7.18 and the ratio of CO to CO2 is 2.0 in the product gas. What is the percent excess air used? The exit gases contain only N2, O2, CO and CO2.(a) 50 %(b) 60 %(c) 40 %(d) 20 %The question was asked by my college professor while I was bunking the class.This interesting question is from Material Balance Numericals topic in chapter Material Balance of Bioprocess Engineering

Answer»

Right choice is (c) 40 %

Easiest explanation: The process involves TWO reactions:

R1 = C + O2 = CO2

R2 = C + 1/2 O2 = CO

As the product (output) gas composition is specified more clearly, we may USE it as starting point.

TAKE N2 in the product as nN2 = Take N2 in the product as, then O2 = 1 mol

N2 as an inert gas: input = output = 7.18 mol

O2 input with AIR = 7.18 (21/79) = 1.91 mol

Total O2 consumption = 1.91-1 = 0.91 mol

If R1 uses n1 mol O2, generating n1 mol CO2, R2 uses 0.91-n1 mol O2, generating 2

(0.91-n1) mol CO.

Since CO/CO2 in the product gas = 2, 2 (0.91-n1)/n1 = 2

n1 = 0.91/2 = 0.455 mol

Therefore, total moles of C input = 3 n1 = 1.365 mol

O2 required for COMPLETE combustion of 1.365 mol C = 1.365 mol (for R1 only)

O2 excess % = (1.91 -1365)/1.365 x 100% = 39.9% = 40% .

23.

Which of the following is the example of extensive properties?(a) Color(b) Temperature(c) Mass(d) SolubilityThis question was addressed to me during an internship interview.The above asked question is from Thermodynamic Preliminaries in division Material Balance of Bioprocess Engineering

Answer»

Right answer is (c) Mass

To elaborate: THERMODYNAMIC properties are divided into two BROAD types: intensive properties and EXTENSIVE properties. An extensive property is any property that depends on the size (or extent) of the system under consideration. An intensive property is a bulk property, meaning that it is a physical property of a system that does not DEPEND on the system size or the amount of material in the system. Mass and volume are extensive properties.

24.

A solution of common salt in water is prepared by adding 20 kg of salt to 100 kg of water, to make a liquid of density 1323 kg/m^3. Calculate the concentration of salt in this solution as a (a) weight fraction, (b) weight/volume fraction, (c) mole fraction, (d) molal concentration.(a) 15.7%, 23.1%, 0.058, 3.88 moles in m^3(b) 14.5%, 22.4%, 0.059, 2.88 moles in m^3(c) 16.7%, 22.1%, 0.058, 3.77 moles in m^3(d) 14.7%, 23.1%, 0.059, 2.77 moles in m^3I had been asked this question by my college director while I was bunking the class.Enquiry is from Law of Conservation of Mass in division Material Balance of Bioprocess Engineering

Answer»

Right answer is (c) 16.7%, 22.1%, 0.058, 3.77 moles in m^3

To explain I would SAY: (i) Weight fraction:

20/(100+20) = 0.167; %weight/weight = 16.7%

(II) Weight/volume:

A DENSITY of 1323kg/m^3 means that lm^3 of solution weighs 1323kg, but 1323kg of salt solution CONTAINS

(20×1323kg of salt) / (100+20) = 220.5 kg salt/m^3

1 m^3 solution contains 220.5 kg salt.

Weight/volume fraction = 220.5 / 1000 = 0.2205

And so weight / volume = 22.1%

(III) Moles of water = 100 / 18 = 5.56

Moles of salt = 20 / 58.5 = 0.34

Mole fraction of salt = 0.34 / (5.56 + 0.34) = 0.058

(iv) The molar concentration (M) is 220.5/58.5 = 3.77 moles in m^3.

25.

Consider the following labeled flowchart for a simple chemical process based on reaction A -> B and predict the overall and single-pass conversion of the process?(a) 100%, 70%(b) 100%, 50%(c) 100%, 75%(d) 100%, 55%I have been asked this question by my school principal while I was bunking the class.Question is taken from Material Balances with Recycle, By in chapter Material Balance of Bioprocess Engineering

Answer»

Right choice is (c) 100%, 75%

Explanation: Overall conversion: Based on the streams that enter and LEAVE the overall process.

Overall conversion =(moles of reactants in FRESH feed-moles in the output of the overall process)/(moles of reactant in fresh feed)

Therefore, the overall conversion of A is from equation:

Overall conversion = ((75 mol A/min)in –(0 mol/min)out)/((75 mol A/min)out) × 100% = 100%

Single-pass conversion: Based on streams that enter and leave the reactor.

Overall conversion = (moles of the reactants FED into the reactor-moles that exiting the reactor)/(moles of reactant fed into reactor)

Therefore, the single-pass conversion from equation is:

((100 mol A/min)in-(25 mol A/min)out)/((100 mol A/min)in) × 100% = 75%.

26.

What do you mean by the splitting point?(a) The two streams split with different composition(b) The two streams split with equal composition(c) Assuming it’s not a reactor and there’s only 2 streams(d) Assuming it’s not a reactor and there’s only 1 streamThis question was addressed to me in a job interview.The doubt is from Material Balances with Recycle, By topic in division Material Balance of Bioprocess Engineering

Answer»

Right answer is (B) The two STREAMS split with equal composition

Easy EXPLANATION: Splitting POINT: 6 variables – 2 mass balances – 1 knowing compositions are the same – 1 splitting ratio = 2 DOF (Degree of freedom). The splitting point is SPECIAL because when a stream is split, it generally is split into two streams with equal composition.

27.

From which of the following processes, only the input of the material is allowed but not output?(a) Batch process(b) Fed-Batch process(c) Semi-Batch process(d) Continuous processThis question was posed to me in an internship interview.Asked question is from Thermodynamic Preliminaries in section Material Balance of Bioprocess Engineering

Answer»

The CORRECT option is (b) Fed-Batch process

The best I can EXPLAIN: In fed-batch process, nothing is removed from the reactor during the process, but one SUBSTRATE component is added in order to control the reaction RATE by its CONCENTRATION. In a fed-batch process, a basal medium supports initial growth and production, and a feed medium prevents depletion of nutrients and sustains the production phase.

28.

Two metal strips that constitute a thermostat must necessarily differ in their _______________(a) Mass(b) Length(c) Resistivity(d) Coefficient of linear expansionI got this question during an interview.Enquiry is from Thermodynamic Preliminaries in division Material Balance of Bioprocess Engineering

Answer»

The correct choice is (d) Coefficient of linear expansion

To explain: Thermostat is used in electric apparatus LIKE a refrigerator, Iron etc for automatic CUT off. THEREFORE for metallic STRIPS to BEND on heating their coefficient of linear expansion should be different.

29.

The fresh feed to an ammonia synthesis reactor contains nitrogen, hydrogen and 2.0 mole per cent inerts. The molar ratio of H2:N2 is 3:1. The product stream consists of pure ammonia. Since conversion in the reactor is only 15%, a recycle stream is used and in order to avoid build-up of inerts, a purge stream is withdrawn. The rate of purge stream is adjusted to keep inert concentration in the recycle stream at 8 mole per cent. For a fresh feed rate of 100 moles/hr. Note that recycle stream contains only nitrogen, hydrogen and inerts. The N2:H2 ratio of 1:3 is maintained in every process stream, and calculate the moles of nitrogen entering the reactor and in the recycle stream?(a) 125 moles/hr, 100.50 moles(b) 135 moles/hr, 50 moles(c) 125 moles/hr, 50 moles(d) 185 moles/hr, 100.50 molesI had been asked this question by my college director while I was bunking the class.The query is from Material Balances with Recycle, By topic in portion Material Balance of Bioprocess Engineering

Answer»

The correct answer is (a) 125 moles/hr, 100.50 moles

The best I can EXPLAIN: Moles of NITROGEN ENTERING the reactor = (37.50/2)/0.15 = 125 moles/hr

Therefore there are 125 – 24.50 = 100.50 moles of nitrogen in the recycle stream.

30.

The fresh feed to an ammonia synthesis reactor contains nitrogen, hydrogen and 2.0 mole per cent inerts. The molar ratio of H2:N2 is 3:1. The product stream consists of pure ammonia. Since conversion in the reactor is only 15%, a recycle stream is used and in order to avoid build-up of inerts, a purge stream is withdrawn. The rate of purge stream is adjusted to keep inert concentration in the recycle stream at 8 mole per cent. For a fresh feed rate of 100 moles/hr. Note that recycle stream contains only nitrogen, hydrogen and inerts. The N2:H2 ratio of 1:3 is maintained in every process stream. Calculate the moles of ammonia produced.(a) 38.90 moles/hr(b) 28.90 moles/hr(c) 37.50 moles/hr(d) 27.50 moles/hrI had been asked this question by my college director while I was bunking the class.This interesting question is from Material Balances with Recycle, By in division Material Balance of Bioprocess Engineering

Answer»

Right CHOICE is (c) 37.50 moles/hr

To EXPLAIN I would say: The concentration of inerts in the PURGE stream is 8 mole percent. The amount of inerts must be 2 moles/hr in order to PREVENT accumulation of inerts. Therefore the flow rate of purge stream is 25 moles/hr.

The flow rate of NITROGEN and hydrogen in the purge stream is 23 moles/hr (5.75 nitrogen, 17.25 hydrogen). Therefore moles of ammonia produced:

(24.50 – 5.75) x 2 = 37.50 moles/hr of ammonia.

31.

Convert 800 mmHg into bars.(a) 1.064 bars(b) 1.066 bars(c) 1.054 bars(d) 1.055 barsI had been asked this question during an interview for a job.I want to ask this question from Material Balance Numericals in division Material Balance of Bioprocess Engineering

Answer»

The correct option is (b) 1.066 bars

Easiest EXPLANATION: 1 mm HG = 133.322 Pa and 1 BAR = 10^5 Pa

Therefore,

bars = 800 mm Hg × \(\FRAC{133.322 \,Pa}{1 \,mm \,Hg} × \frac{1 \,bar}{10^5 \,Pa}\) = 1.066 bar.

32.

Conversion of 40 K into Celsius.(a) -233.15 °C(b) 233.15 °C(c) –245 °C(d) 245 °CThe question was asked during an interview.My question is taken from Thermodynamic Preliminaries in section Material Balance of Bioprocess Engineering

Answer» RIGHT CHOICE is (a) -233.15 °C

To ELABORATE: T(°C) = T(K) – 273.15

= 40 – 273.15

= -233.15 °C.
33.

If the matter flows through a pipe with constant velocity, is this the condition of thermodynamic equilibrium.(a) True(b) FalseThis question was posed to me in class test.Question is taken from Thermodynamic Preliminaries in portion Material Balance of Bioprocess Engineering

Answer»

Right option is (b) False

For explanation: The flow through a pipe at a CONSTANT VELOCITY, clearly there is flow of MATTER and so it is not in thermodynamic EQUILIBRIUM, however since the velocity does not change with time it is in a steady state.

34.

Which of the following is not the application of recycle system?(a) Increased reactant conversion(b) Decreased reactant conversion(c) Continuous catalyst regeneration(d) Circulation of the working fluidThis question was posed to me during an interview.This intriguing question originated from Material Balances with Recycle, By in portion Material Balance of Bioprocess Engineering

Answer»

The correct choice is (b) DECREASED reactant CONVERSION

The explanation is: The most COMMON application of recycle for systems INVOLVING chemical reaction is the recycle of reactants, an application that is USED to increase the overall conversion in a reactor and not the decreased reactant conversion.

35.

If the Reactant iron is combined with Reactant Sulfur to form the product Iron sulfide, then what will be the atomic mass of the product?(a) 88(b) 44(c) 22(d) 80I have been asked this question in exam.This is a very interesting question from Law of Conservation of Mass topic in portion Material Balance of Bioprocess Engineering

Answer» RIGHT choice is (a) 88

To explain: FE (iron) + S (Sulfur) = FeS (Iron sulfide),

Atomic masses: Fe = 56, S = 32

One atom of each ELEMENT on each side of the equations

Law of conservation of MASS balance: 56 + 32 = 88.