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2951.

If cos2A+cos2C=sin2B, then △ ABC is [MP PET 1991]

Answer»

If cos2A+cos2C=sin2B, then ABC is

[MP PET 1991]



2952.

The circle x2+y2=1 cuts the x-axis at P and Q. Another circle with centre at Q and variable radius intersects to first circle at R above the X-axis and the line segment PQ at S. The maximum area of the triangle QSR is

Answer»

The circle x2+y2=1 cuts the x-axis at P and Q. Another circle with centre at Q and variable radius intersects to first circle at R above the X-axis and the line segment PQ at S. The maximum area of the triangle QSR is


2953.

An ellipse has OB as a semi-minor axis. F and F' are its foci and the angle FBF' is a right angle. Then, the eccentricity of the ellipse is ___

Answer»

An ellipse has OB as a semi-minor axis. F and F' are its foci and the angle FBF' is a right angle. Then, the eccentricity of the ellipse is ___



2954.

Let α, β be such that π<α−β<3π.Ifsin α+sin β=2165 and cos α+cos β=−2765,then the value of cosα−β2 is

Answer» Let α, β be such that π<αβ<3π.Ifsin α+sin β=2165 and cos α+cos β=2765,then the value of cosαβ2 is
2955.

The value of tan−1√a(a+b+c)bc+tan−1√b(a+b+c)ca+tan−1√c(a+b+c)ab, where a,b,c&gt;0, is

Answer»

The value of tan1a(a+b+c)bc+tan1b(a+b+c)ca+tan1c(a+b+c)ab, where a,b,c>0, is

2956.

If the 5th term of a G.P. is 13 and 9th term is 16243, then the 4th term will be

Answer»

If the 5th term of a G.P. is 13 and 9th term is 16243, then the 4th term will be


2957.

If p is the length of perpendicular from the origin to the line whose intercepts on the axes are a and b, then show that 1p2=1a2+1b2

Answer»

If p is the length of perpendicular from the origin to the line whose intercepts on the axes are a and b, then show that 1p2=1a2+1b2

2958.

limx→∞cos2xx=

Answer»

limxcos2xx=



2959.

The equation of circle which passes through focus of parabola x2=4y and touches it at (6,9) is

Answer»

The equation of circle which passes through focus of parabola x2=4y and touches it at (6,9) is

2960.

If sinB=15sin(2A+B), then tan(A+B)tanA is equal to

Answer»

If sinB=15sin(2A+B), then tan(A+B)tanA is equal to

2961.

Trigonometric EquationsGeneral Solutions1. tan x=2P. 2nπ±2π3,n∈I2. sin x=√32Q. nπ−π4,n∈I3. cos x=−12R. nπ+(−1)nπ3,n∈I4. cot x=−1S. nπ+tan−1(2),n∈I

Answer»

Trigonometric EquationsGeneral Solutions1. tan x=2P. 2nπ±2π3,nI2. sin x=32Q. nππ4,nI3. cos x=12R. nπ+(1)nπ3,nI4. cot x=1S. nπ+tan1(2),nI



2962.

If (1+i)(1+2i)(1+3i)......(1+ni) = a+ib, then 2.5.10.....(1+n2) is equal to

Answer»

If (1+i)(1+2i)(1+3i)......(1+ni) = a+ib, then 2.5.10.....(1+n2) is equal to


2963.

The orthocentre of the triangle formed by the vertices (5,0),(0,0) and (52,5√32) is

Answer»

The orthocentre of the triangle formed by the vertices (5,0),(0,0) and (52,532) is

2964.

Two parabolas x2=4y and y2=4x intersect at two distinct points out of which one of them is origin then the other point will be

Answer»

Two parabolas x2=4y and y2=4x intersect at two distinct points out of which one of them is origin then the other point will be

2965.

If ′abcd′ is a 4 digit number where a&gt;b≥c&gt;d, then the number of such numbers are

Answer»

If abcd is a 4 digit number where a>bc>d, then the number of such numbers are

2966.

There are 10 points in a plane no three of which are in the same straight line, excepting 4 points, which are collinear. Find the probability that (i) number of straight lines obtained from the pairs of these points. (ii) number of triangles that can be formed with the vertices as these points.

Answer»

There are 10 points in a plane no three of which are in the same straight line, excepting 4 points, which are collinear.

Find the probability that

(i) number of straight lines obtained from the pairs of these points.

(ii) number of triangles that can be formed with the vertices as these points.

2967.

If sin B= 15sin (2A+B), thentan(A+B)tanA is equal to

Answer»

If sin B= 15sin (2A+B), thentan(A+B)tanA is equal to

2968.

limx→π2(1−tan(x2))(1−sin x)(1+tan(x2))(π−2x)3is

Answer»

limxπ2(1tan(x2))(1sin x)(1+tan(x2))(π2x)3is



2969.

4tan−115−tan−11239 is equal to

Answer» 4tan115tan11239 is equal to
2970.

Total number of particles i.e. (Zeff) in a 3-D hexagonal close packed (hcp) unit cell is

Answer» Total number of particles i.e. (Zeff) in a 3-D hexagonal close packed (hcp) unit cell is
2971.

If truth value for p→(q∨r) is false, then the truth values of p, q, r are respectively :

Answer»

If truth value for p(qr) is false, then the truth values of p, q, r are respectively :

2972.

Arun wants to predict the runs India will score in the next ball. The present score is 100 runs in 25 overs and he wants to predict the score when it is 25 overs and 1 ball. What is the sample set? (India is batting first)

Answer»

Arun wants to predict the runs India will score in the next ball. The present score is 100 runs in 25 overs and he wants to predict the score when it is 25 overs and 1 ball. What is the sample set? (India is batting first)

2973.

The sum of co-efficients of all even degree terms in x in the expansion of (x+√x3−1)6+(x−√x3−1)6,(x&gt;1) is equal to:

Answer»

The sum of co-efficients of all even degree terms in x in the expansion of (x+x31)6+(xx31)6,(x>1) is equal to:

2974.

If nC3+nC4&gt;n+1C3,then,

Answer»

If nC3+nC4>n+1C3,then,

2975.

If sinθ=nsin(θ+2α), then the value of tan(θ+α) is(where n is a constant)

Answer»

If sinθ=nsin(θ+2α), then the value of tan(θ+α) is

(where n is a constant)

2976.

If z=2+i and z3+3z2−9z+35=kz, then the value of k is

Answer» If z=2+i and z3+3z29z+35=kz, then the value of k is
2977.

For all natural numbers n, 102n−1+1 is divisible by

Answer»

For all natural numbers n, 102n1+1 is divisible by


2978.

If cos (x-y) cos(z-t) = cos(x+y) cos (z+t), then tanx tany + tanz tant is equal to

Answer»

If cos (x-y) cos(z-t) = cos(x+y) cos (z+t), then tanx tany + tanz tant is equal to


2979.

If α,β are zeroes of a polynomial 6x2 + x – 2, then the polynomial whose zeroes are 2α+3β and 3α+2β , is .

Answer»

If α,β are zeroes of a polynomial 6x2 + x 2, then the polynomial whose zeroes are 2α+3β and 3α+2β , is .

2980.

Let A be a set of 5 elements and B be a set of 2 elements. The number of subsets of A×B having 4 elements is

Answer» Let A be a set of 5 elements and B be a set of 2 elements. The number of subsets of A×B having 4 elements is
2981.

∫[1+tan xtan(x+α)]dx,is equal to

Answer» [1+tan xtan(x+α)]dx,is equal to
2982.

The value of the expression tan−1(√22)+sin−1(√55)−cos−1(√1010), is

Answer»

The value of the expression tan1(22)+sin1(55)cos1(1010), is

2983.

If a, b, c, d are in GP, prove that (a2+b2+c2)(b2+c2+d2)=(ab+bc+cd)2

Answer»

If a, b, c, d are in GP, prove that

(a2+b2+c2)(b2+c2+d2)=(ab+bc+cd)2

2984.

The rational term(s) in the expansion of (√2+(3)15)10 is/are

Answer»

The rational term(s) in the expansion of (2+(3)15)10 is/are

2985.

limh→0{1h3√8+h−12h}is equal to

Answer»

limh0{1h38+h12h}is equal to


2986.

In △ABC, if A,B and C represent the angles of a triangle, then the maximum value of cosA+cosB+cosC is

Answer»

In ABC, if A,B and C represent the angles of a triangle, then the maximum value of cosA+cosB+cosC is

2987.

The side length of the square whose area is equal to the 7th term of the sequence 2,√8,4,…, is

Answer»

The side length of the square whose area is equal to the 7th term of the sequence 2,8,4,, is

2988.

If the arithmetic mean and harmonic mean between two numbers are 27 and 12 respectively, then the geometric mean of those two numbers is

Answer»

If the arithmetic mean and harmonic mean between two numbers are 27 and 12 respectively, then the geometric mean of those two numbers is

2989.

If ∫cosxsin3x(1+sin6x)2/3dx=f(x)(1+sin6x)1/λ+c, where c is a constant of integration, then λf(π3) is equal to :

Answer»

If cosxsin3x(1+sin6x)2/3dx=f(x)(1+sin6x)1/λ+c, where c is a constant of integration, then λf(π3) is equal to :

2990.

Which of the following statements is/are true about an even function f(x)?

Answer»

Which of the following statements is/are true about an even function f(x)?



2991.

Find the general solution of each equation: (i)√3cot x+1=0 (ii)cosec x+√2=0

Answer»

Find the general solution of each equation:

(i)3cot x+1=0

(ii)cosec x+2=0

2992.

Find the value of ∑∞i=1 ∑∞j=1 ∑∞k=1 12i2j2k.

Answer»

Find the value of i=1 j=1 k=1 12i2j2k.


2993.

Given 3 points with position vectors ¯p1,¯p2 and ¯p3 which form the vertices of a triangle with side lengths a=|¯p2−¯p1|,b=|¯p3−¯p2|,c=|¯p1−¯p3|. Then the in-centre is given by

Answer»

Given 3 points with position vectors ¯p1,¯p2 and ¯p3 which form the vertices of a triangle with side lengths a=|¯p2¯p1|,b=|¯p3¯p2|,c=|¯p1¯p3|. Then the in-centre is given by

2994.

sin2025∘ is equal to

Answer» sin2025 is equal to
2995.

The coefficient of 1x in the expansion of (1+x)n(1+1x)n is:

Answer»

The coefficient of 1x in the expansion of (1+x)n(1+1x)n is:


2996.

From the top of a building 21 m high, the angle of elevation and depression of the top and the foot of another buillding are 30∘ and 45∘ respectively. The height of the second building is

Answer»

From the top of a building 21 m high, the angle of elevation and depression of the top and the foot of another buillding are 30 and 45 respectively. The height of the second building is

2997.

If (2,1,3),(3,2,5),(1,2,4) are the mid points of the sides BC,CA,AB of △ABC respectively, then vertex A is:

Answer»

If (2,1,3),(3,2,5),(1,2,4) are the mid points of the sides BC,CA,AB of ABC respectively, then vertex A is:

2998.

If f'(x)=|x|−{x} where x denotes the fractional part of x, then f(x) is decreasing in

Answer»

If f'(x)=|x|{x} where x denotes the fractional part of x, then f(x) is decreasing in

2999.

Let (a,b) be a point on a circle which passes through (−3,1) and touches the line x+y=2 at the point (1,1). If maximum possible value of a is α, then a quadratic equation with rational coefficients whose one root is α, is

Answer»

Let (a,b) be a point on a circle which passes through (3,1) and touches the line x+y=2 at the point (1,1). If maximum possible value of a is α, then a quadratic equation with rational coefficients whose one root is α, is

3000.

The set of values of m for which f(x)=x2−(m−3)x+m intersects the positive direction of x−axis atleast once, is

Answer»

The set of values of m for which f(x)=x2(m3)x+m intersects the positive direction of xaxis atleast once, is