Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

401.

e1 and e2 are the eccentricities of two conics S and S1. If e12+e22 = 3 then both S and S1 can be

Answer»

e1 and e2 are the eccentricities of two conics S and S1. If e12+e22 = 3 then both S and S1 can be



402.

The number of solutions of the equation z2 + ¯z = 0 is

Answer»

The number of solutions of the equation z2 + ¯z = 0 is


403.

An event A has the outcomes w1 , w2 , w3 , and w4 with probabilities 112,112,16and13.If the probability of event A is P(A),find 24 P(A).

Answer»

An event A has the outcomes w1 , w2 , w3 , and w4 with probabilities 112,112,16and13.If the

probability of event A is P(A),find 24 P(A).

404.

|∫1910sin x dx1+x8| is less then

Answer» |1910sin x dx1+x8| is less then
405.

A real 4×4 matrix A satisfies the equation A2=I, where I is the 4×4 identity matrix. The positive eigen value of A is.

Answer» A real 4×4 matrix A satisfies the equation A2=I, where I is the 4×4 identity matrix. The positive eigen value of A is.
406.

For log2xx2−1 to be defined,

Answer»

For log2xx21 to be defined,

407.

21. Let M be the maximum value of (6x−3y−8z), subject to 2x²+3y²+4z²= 1.Find [M].

Answer» 21. Let M be the maximum value of (6x−3y−8z), subject to 2x²+3y²+4z²= 1.Find [M].
408.

Which term of the A.P - 53, -47, -41, is the first positive term. __

Answer»

Which term of the A.P - 53, -47, -41, is the first positive term.


__
409.

A juggler throws balls up at regular time interval of second so that at the most 8 balls are in air. Find the maximum height upto which a ball goes (Take g = 10 m/s2)

Answer» A juggler throws balls up at regular time interval of second so that at the most 8 balls are in air. Find the maximum height upto which a ball goes (Take g = 10 m/s2)
410.

If R={(x,y)|x,y∈Z,x2+y2≤4} is a relation in Z, then domain of R is

Answer»

If R={(x,y)|x,yZ,x2+y24} is a relation in Z, then domain of R is

411.

Number of 4 digit numbers of the form N=a b c d, which satisfy following conditions :(i) 4000≤N<6000(ii) N is a multiple of 5(iii) 3≤b<c≤6 is equal to

Answer»

Number of 4 digit numbers of the form

N=a b c d, which satisfy following conditions :

(i) 4000N<6000

(ii) N is a multiple of 5

(iii) 3b<c6 is equal to

412.

For the given sequence loga,log(ab),log(ab2), where a,b,c&gt;0, the 10th term is

Answer»

For the given sequence loga,log(ab),log(ab2), where a,b,c>0, the 10th term is

413.

If the (r+1)th term in the expansion of (3√a√b+√b3√a)21 has the same power of a and b, then value of r is

Answer»

If the (r+1)th term in the expansion of (3ab+b3a)21 has the same power of a and b, then value of r is


414.

Check whether the following probabilities P(A) and P(B) are consistently defined (i) P(A)=0.5,P(B)=0.7,P(A∩B)=0.6 (ii) P(A)=0.5,P(B)=0.4,P(A∪B)=0.8

Answer»

Check whether the following probabilities P(A) and P(B) are consistently defined
(i) P(A)=0.5,P(B)=0.7,P(AB)=0.6
(ii) P(A)=0.5,P(B)=0.4,P(AB)=0.8

415.

The sum of the squares of perpendicular on any tangent of the ellipse x2a2+y2b2 = 1 from two Points on the minor axis each one at a distance of units from the centre is

Answer»

The sum of the squares of perpendicular on any tangent of the ellipse x2a2+y2b2 = 1 from two Points on the minor axis each one at a distance of units from the centre is


416.

6. In a group of 60 students, 31 can speak Hindi, 23 can speak English and 14 speak neitherHindi nor English. Determine the number of students who speak both Hindi & English.(2) 6(3) 7(4) 8

Answer» 6. In a group of 60 students, 31 can speak Hindi, 23 can speak English and 14 speak neitherHindi nor English. Determine the number of students who speak both Hindi & English.(2) 6(3) 7(4) 8
417.

The value of limn→∞3n+2n3n−2n is

Answer»

The value of limn3n+2n3n2n is

418.

Let P(A)=P(B), prove that A=B

Answer»

Let P(A)=P(B), prove that A=B

419.

The equation of chord to the parabola y2=4x whose sum of ordinates and product of abscissas of the endpoints of the chord is 4 and 9 respectively, is :

Answer»

The equation of chord to the parabola y2=4x whose sum of ordinates and product of abscissas of the endpoints of the chord is 4 and 9 respectively, is :

420.

sin4 π8+sin4 3π8+sin4 5π8+sin4 7π8=

Answer» sin4 π8+sin4 3π8+sin4 5π8+sin4 7π8=
421.

The domain of the function f(x)=1√x+|x|, is

Answer»

The domain of the function f(x)=1x+|x|, is

422.

For real x, the function (x−a)(x−b)(x−c) will assume all real values provided

Answer» For real x, the function (xa)(xb)(xc) will assume all real values provided
423.

If (10)9+2(11)1(10)8+3(11)2(10)7+……+10(11)9=k(10)9, then k is equal to

Answer»

If (10)9+2(11)1(10)8+3(11)2(10)7++10(11)9=k(10)9, then k is equal to

424.

In the xy plane, the segment with end points (3, 8) and (–5, 2) is the diameter of the circle. The point (k, 10) lies on the circle for

Answer»

In the xy plane, the segment with end points (3, 8) and (–5, 2) is the diameter of the circle. The point (k, 10) lies on the circle for

425.

Let z be those complex number which satisfy |z+5|≤4 and z(1+i)+¯z(1−i)≥−10,i=√−1. If the maximum value of |z+1|2 is α+β√2, then the value of (α+β) is

Answer» Let z be those complex number which satisfy |z+5|4 and z(1+i)+¯z(1i)10,i=1. If the maximum value of |z+1|2 is α+β2, then the value of (α+β) is
426.

The straight lines joining origin and the point of intersections of the curve y2 =4x with the line x+y+n = 0 are perpendicular. Find the value of n2. __

Answer»

The straight lines joining origin and the point of intersections of the curve y2 =4x with the line x+y+n = 0 are perpendicular. Find the value of n2.


__
427.

Let F1(x1,0) and F2(x2,0), where, x1&lt;0 and x2&gt;0 be the foci of the ellipse x29+y28=1 suppose a parabola having vertex at the origin and focus at F2 intersects the ellipse at point M in the first quadrant and at point N in the fourth quadrant.If the tangents to the ellipse at M and N meet at R and the normal to the parabola at M meets the X-axis at Q then the ratio of area of ΔMQR to area of the quadrilateral MF1NF2 is

Answer»

Let F1(x1,0) and F2(x2,0), where, x1<0 and x2>0 be the foci of the ellipse x29+y28=1 suppose a parabola having vertex at the origin and focus at F2 intersects the ellipse at point M in the first quadrant and at point N in the fourth quadrant.

If the tangents to the ellipse at M and N meet at R and the normal to the parabola at M meets the X-axis at Q then the ratio of area of ΔMQR to area of the quadrilateral MF1NF2 is



428.

What is the equation of chord joining 2 points of a parabola given by parameters t1 and t2.

Answer»

What is the equation of chord joining 2 points of a parabola given by parameters t1 and t2.


429.

Let f=[(x,x21+x2):x ϵ R] be a function from R into R. Determine the range of f.

Answer»

Let f=[(x,x21+x2):x ϵ R] be a function from R into R. Determine the range of f.

430.

Out of the following which is a skew- symmetric matrix

Answer»

Out of the following which is a skew- symmetric matrix

431.

number of solutions of inequalities mod(2^x -1) + mod(4- 2^x) < 3 are

Answer» number of solutions of inequalities mod(2^x -1) + mod(4- 2^x) < 3 are
432.

For all real permissible values of m, if the straight line y=mx+√9m2−4 is tangent to a hyperbola, then equation of the hyperbola can be

Answer»

For all real permissible values of m, if the straight line y=mx+9m24 is tangent to a hyperbola, then equation of the hyperbola can be

433.

How many triangles can be formed by joining 10 points on a circle? __

Answer»

How many triangles can be formed by joining 10 points on a circle?


__
434.

The vertices of the ellipse (x+1)225+(y−3)216 = 1 is

Answer»

The vertices of the ellipse (x+1)225+(y3)216 = 1 is



435.

The probability that a teacher will give an unannounced test during any class meeting is 15.If a student is absent twice, the probability that he will miss atleast one test, is

Answer»

The probability that a teacher will give an unannounced test during any class meeting is 15.If a student is absent twice, the probability that he will miss atleast one test, is

436.

If the third term in the binomial expansion of (1+xlog2x)5 equals 2560, the a possible value of x is :

Answer»

If the third term in the binomial expansion of (1+xlog2x)5 equals 2560, the a possible value of x is :

437.

From the sets given below, select equal sets : A = {2, 4, 8, 12}, B = {1, 2, 3, 4}, C = {4, 8, 12, 14}, D = {3, 1, 4, 2}, E = {-1, 1}, F = {0, a} G = {1, -1}, H = {0, 1}

Answer»

From the sets given below, select equal sets :

A = {2, 4, 8, 12}, B = {1, 2, 3, 4},

C = {4, 8, 12, 14}, D = {3, 1, 4, 2},

E = {-1, 1}, F = {0, a}

G = {1, -1}, H = {0, 1}

438.

The distance between the origin and the tangent to the curve y=e2x+x2 drawn at the point x=0 is

Answer»

The distance between the origin and the tangent to the curve y=e2x+x2 drawn at the point x=0 is

439.

If z1 and z2 are complex numbers and u=√z1z2, then ∣∣∣z1+z22+u∣∣∣+∣∣∣z1+z22−u∣∣∣ is equal to

Answer»

If z1 and z2 are complex numbers and u=z1z2, then z1+z22+u+z1+z22u is equal to

440.

(1+cosπ8)(1+cos3π8)(1+cos5π8)(1+cos7π8) is equal to

Answer» (1+cosπ8)(1+cos3π8)(1+cos5π8)(1+cos7π8) is equal to
441.

The mean and variance of 7 observations are 8 and 16 respectively. If five of the observations are 2, 4, 10, 12, 14, find the remaining two observations.

Answer»

The mean and variance of 7 observations are 8 and 16 respectively. If five of the observations are 2, 4, 10, 12, 14, find the remaining two observations.

442.

If A(z1),B(z2),C(z3) be the vertices of triangle ABC in which |ABC–––––– = π4 and ABBC = √2 then z2 is equal to

Answer»

If A(z1),B(z2),C(z3) be the vertices of triangle ABC in which |ABC–––– = π4 and ABBC = 2 then z2 is equal to


443.

nCr+2nCr−1+nCr−2 =

Answer»

nCr+2nCr1+nCr2 =


444.

If the ratio of the 5th term from the beginning to the 5th term from the end in the expansion of (4√2+14√3)n is √6:1, then the value of n is

Answer»

If the ratio of the 5th term from the beginning to the 5th term from the end in the expansion of (42+143)n is 6:1, then the value of n is

445.

Question 8 ABCD is a rectangle formed by points A (-1,-1), B(-1,4), C(5,4) and D(5,-1). P, Q, R, and S are mid-points of AB, BC, CD, and DA respectively. Is the quadrilateral PQRS a square, rectangle or rhombus? Justify your answer.

Answer»

Question 8

ABCD is a rectangle formed by points A (-1,-1), B(-1,4), C(5,4) and D(5,-1). P, Q, R, and S are mid-points of AB, BC, CD, and DA respectively. Is the quadrilateral PQRS a square, rectangle or rhombus? Justify your answer.



446.

Find the real values of x and y for which (x−iy)(3+5i) is the conjugate of (-6-24i).

Answer» Find the real values of x and y for which (xiy)(3+5i) is the conjugate of (-6-24i).
447.

Let z be a complex number satisfying z+z−1=1. A possible value of n when zn+z−n is minimum, is

Answer»

Let z be a complex number satisfying z+z1=1. A possible value of n when zn+zn is minimum, is

448.

Show that the points A(0, 7, 10), B(-1, 6, 6) and C(-4, 9,6) form an isosceles right-angled triangle.

Answer» Show that the points A(0, 7, 10), B(-1, 6, 6) and C(-4, 9,6) form an isosceles right-angled triangle.
449.

Draw the graph of logarithm function y= logax When x&gt;0and a&gt;1.

Answer»

Draw the graph of logarithm function y= logax When x>0and a>1.


450.

List I has four entries and List II has five entries. Each entry of List I is to be correctly matched with one or more than one entries of List II. List IList II (A)Let f:A→B be a function defined by (P)−1 f(x)=log(x2−7|x|+12). If C=Z−A is a set, then an element in C is (B)A solution of the inequation(Q)0∣∣∣2x−4∣∣∣&gt;1 is(C)If f(x)=log(1−|x||x−2|), then an(R)1integer which is not in the domainof f, is(D)An element in the domain of the (S)2function f(x)=ex−4x2√4x−x2 is(T)3Which of the following is the only CORRECT combination?

Answer» List I has four entries and List II has five entries. Each entry of List I is to be correctly matched with one or more than one entries of List II.



List IList II (A)Let f:AB be a function defined by (P)1 f(x)=log(x27|x|+12). If C=ZA is a set, then an element in C is (B)A solution of the inequation(Q)02x4>1 is(C)If f(x)=log(1|x||x2|), then an(R)1integer which is not in the domainof f, is(D)An element in the domain of the (S)2function f(x)=ex4x24xx2 is(T)3



Which of the following is the only CORRECT combination?