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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Arrange in ascending order 4√20,6√25,3√7 |
| Answer» 3√7,4√20,6√25 | |
| 2. |
Prove that every line segment has one and only one mid - point. |
| Answer» | |
| 3. |
The sides of a triangular plot are in the ratio of 3:7:5 and its perimeter is 300m.find the area |
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Answer» First side is 60 second side is 140 third side is 100 Take all the sides as 3x 7x5x |
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| 4. |
All 1 to 8 identities |
| Answer» see 2nd chapter summary | |
| 5. |
If p(x)=x^2+5x+2 Then find the value of p(3), p(0),and p(1) |
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Answer» P (3) = 26P (0) = 2P (1) = 8 Just put values in place of x |
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| 6. |
(64)1/2 ×(125)1/3 |
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Answer» (64)^1/2×(125)^1/3.8×5.40 40 40 May be 40 40 |
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| 7. |
Prove line segment has one and only one mid point? |
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| 8. |
find the two rational no. and two irrationl no. between root2 and root3 |
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| 9. |
X=√3+1÷√3-1,y=√3-1÷√3+1 find the value of x2+xy-y2 |
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| 10. |
If median of 17,22,38,40,x,x+8,75,95 is 48 find value of x |
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Answer» Given observation are:\xa017, 22,38, 40, x , x+ 8, 75 , 95Total number of observation i.e n = 8Given, median = 48(4th value of\xa0observation + 5th value of observation)/2 = 48(40 + x)/2 = 4840 + x = 96x = 96 - 40x = 56 May be 44 |
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| 11. |
Prove that the quadrilateral formed by angle bisector of a cyclic quadrilateral is also cyclic |
| Answer» Consider a quad. Abcd with angle bisectors of a,b,c and d meet at p,q,r and s forming a quad.Now take the angles and a=1 + 1 where 1 is an angle similarly b=2+2 nd c=3+3 nd d=4+4Now as abcd is cyclic quad. Then a+c=180° and b+d=180° now 1/2a+1/2c=90° similarly with b and d Now 1+3=90° and 3+4=90° And in ∆apd angle p=180°-(1+4)Similarly in ∆brc angle r=180°-(2+3)Add both equations nd replace the values of 1+3 nd 2+4 with 90°\'s and u will get p+r=180°Hence it is a cyclic quad. | |
| 12. |
Factorise : (a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3 |
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| 13. |
Find the value of {(23+2^2)^1/2+(140-19)^1/2}^2 |
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| 14. |
X^2-2x-8 |
| Answer» x2 - 2x - 8= x2 - 4x + 2x - 8= x (x - 4) + 2(x - 4)= (x -4) ( x + 2) | |
| 15. |
Find the probability of multiple of 3 from 1 to 100 |
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Answer» Probability(of multiple of 3 from= 33/100=0.33 33/100 |
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| 16. |
Factorise : 27p3- 1/216- 9p2/2+p/4 |
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| 17. |
In a triangle ABC, if 3angleA =4angleB=6angle, calculate the angles |
| Answer» A+b+c = 180 4+6+c= 180 10+c= 180 C=180 - 10 C=170 | |
| 18. |
Find the ratio of the volumes of a cone and of a cylinder whose base diameter and height are equal |
| Answer» 1:3 | |
| 19. |
H 4cm r 5cm h=? |
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| 20. |
Factorise by splitting the middle term.1.) y2-5y+X |
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| 21. |
If the value of x= 3+√5 , then find the value of ( x^3 + 1/x^3 ) |
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| 22. |
(√13+√4)-(√13-√2) |
| Answer» 2+ROOT2 | |
| 23. |
Write each of the following as an equation in two variables(1) 2x=3(2) 5y=2 |
| Answer» (1) x=1 (2)y=-3 | |
| 24. |
Find area of isosceles triangle whose side is x and y |
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Answer» Side x,x,y Your above data is not full fill the making question. Some things is missing |
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| 25. |
If each side ofa triangle is doubled then how many times areaif triangle in reased |
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Answer» 3 times F*** 2 times |
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| 26. |
How many cubes can be cut of side 4cm from big cube with edge 32cm |
| Answer» It would be:-(32)^3 /(4)^3 =>32,768/64 => 512 | |
| 27. |
What is the formula to find area of isosceles triangle |
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Answer» Given answer is wrong the right answer is b/4√4a^2-a^2 with side a,a,b a/2(√4b^2-a^2)/2 1/2*base*height |
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| 28. |
How to construct a right angled isosceles triangle? |
| Answer» One right angle | |
| 29. |
How to prove any figure |
| Answer» First of all we can\'t prove any figure with out knowing that what has been given and what we have to prove. So according to given question we can solve that problem. | |
| 30. |
(-9)-(-1) |
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Answer» To start using Jio data services, please configure APN by going to Settings -> Cellular Networks -> Access Point -> Click on Reset DefaultThank you,Team Jio -9+1=-8 |
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| 31. |
How many circles can be drawn through three collinear points |
| Answer» No any circle can be drow | |
| 32. |
Find the value of (63)1/2*(125)1/3 |
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Answer» 8*5=40 is the answer There shoulbe 64 in the place of 63 Wrong qiestion |
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| 33. |
If m parallel n and angel a ratio angle b 2 ratio 3 then what will be the measure of angle h? |
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Answer» Incomplete question Write question |
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| 34. |
F = 9 / 5 c +32Draw a graph of the given equation taking c along x-axis and f along y-axis |
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| 35. |
If xa/b =1find the value of a |
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Answer» xa/b = 1xa=ba=b/x b/x I ....... Know ................................. Lol!!!!!!!!!! |
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| 36. |
What is the TSA of cone |
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Answer» Pie×r(l+r) Pie ×radius (l+r) |
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| 37. |
Simplify: underroot72+800-18 |
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| 38. |
Find a= b |
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| 39. |
X - y = 2 and x -y = 4. Find the value of x and y |
| Answer» y=1;X=1;x=3 | |
| 40. |
8a³+√27b³ |
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Answer» (2a)^3+(√3b)^3.It can factorized with the formula a^3+b^3=(a+b)(a^2-ab+b^2).So,(2a-√3b)(4a^2-2√3ab+3b^2) (2a+√3b)³ Dont no |
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| 41. |
If 25 raise to x-1= 5 raise to 2x-1-100, find the value of x |
| Answer» Answer 6 | |
| 42. |
Exercise 1.3 question no 2 |
| Answer» Multiply the value of 1/7 into each of number such as 2×142857 | |
| 43. |
6(6(76(8796_5_4&5--+ |
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| 44. |
If 2 X + K Y is equal to 10 K intersect x-axis at(2,0) . Find k |
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Answer» Ye question mere exam me aaya tha The value of x and y is 2 and 02x+ky=10k Put the value of x and y 2(2)+k(0)=10k4+0=10kK=10/4K=2.5 2x+ky=10k ,(x=2,y=0),2(2)+k(0)=10k,4+0=10k,k=4/10,k=0.4 Given interesting poin (2,0).\'. X=2 and Y=0By putting the value of x and y in the equation (2x+ky=10k)We get, (2×2)+(k×0)=10k 4+0=10k => K=4/10=0.4 Hence the value of K is 0.4 |
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| 45. |
If a point O lies between two points P and R such that PO =OR , then prove that PO =1/2PR |
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Answer» Given that PO=OR......eq 1.Since,A.T.Q.,PR=PO+ORPR=PO+PO(using eq 1).PR=2POPO=1/2PR Using euclid\'s axiom |
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| 46. |
The two consecutive class marks of a distribution are 52 and 57.Find the class limit |
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| 47. |
A cube of side 5cm containba spere touching its side . Find the volume of the gap in between |
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| 48. |
Factorise (2a+3b)³-(2b-3b) ³ |
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Answer» Same answer ?? Step by step solution :Step 1 : \xa01.1 Evaluate : (2a+3b)3 = 8a3+36a2b+54ab2+27b3 1.2 Evaluate : (2a-3b)3 = 8a3-36a2b+54ab2-27b3\xa0Step 2 :Pulling out like terms :\xa02.1 Pull out like factors\xa0: 72a2b + 54b3 = 18b\xa0•\xa0(4a2\xa0+ 3b2)\xa0Final result : 18b • (4a2 + 3b2) |
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| 49. |
In the given figure show that XY parallel to EF |
| Answer» Show figure ? | |
| 50. |
Degree of x2h |
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Answer» Power me to Koi number hi nahi he??? 2 1 2 |
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