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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 5351. |
Angle bisector Given value of x |
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| 5352. |
4√28/3√7 |
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| 5353. |
The oa,ob are opposite rays and angle aoc+angle bod=90°,find angle cod |
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| 5354. |
side side side angel diffination |
| Answer» When sides Of triangle are congrent through SSS is known as SSS congrency | |
| 5355. |
Where can i find PK for 9th ? |
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Answer» Its a practice book What is pk? Boli tread sai ki |
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| 5356. |
Find the area of triangle whose sides are respectively 150 cm, 120 cm and 200 cm |
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Answer» 8966.5 My answer is 8966.56 Let a=150cn,b=120cmand c=200cmS=a+b+c/2=150+120+200/2=235cmFrom heros formula√s(s-a×s-b×s-c)√235×85×115×35=5244676.94 8966.56 |
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| 5357. |
How to explain root11 on number line |
| Answer» √3^2+√1=√10,√10+√1=√11 | |
| 5358. |
2.369÷3.2+30_24=12.7403125 |
| Answer» 12.7403125 | |
| 5359. |
one upon root 3 + root 2 |
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| 5360. |
5upon3 plus 3upon7 plus 1upon2 |
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Answer» 130/42 119 upon 42 |
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| 5361. |
How to find solutions of linear equations |
| Answer» From solving the equations | |
| 5362. |
F-9/5+32=f=c |
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| 5363. |
If ×=√7+√6\\√7-√6 then find {×+1/×} |
| Answer» Give me answer of this ouestion | |
| 5364. |
0.32 there is a bar in 2 express this in the form p/q |
| Answer» X=0.3222----------1 10x=3.2222-------22-19x=2.9X=2.9\\9X=29\\90 | |
| 5365. |
Howmany least number of distinct points determine a unique line |
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Answer» 2 is the least no. of distinct points determine a unique line 2 |
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| 5366. |
Difference between linear pair and adjacent angles |
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Answer» Sum is 180 Linear pair have 2 uncommon arm in 2 different direction |
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| 5367. |
203×592+3.026_369=119,810.026 |
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| 5368. |
Square root of 0.9 with solution, please |
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Answer» It is a secret. So, I can\'t tell you.But I am excellent in mathematics. How did u find it? .3 0.948683 0.9486832981 = 0.94868 |
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| 5369. |
(2√3-5√2) (√3+2√2) |
| Answer» (2√3-5√2)(√3+2√2)=2√3(√3+2√2)-5√2(√3+2√2)=6+4√6-5√6-20=-12-√6 | |
| 5370. |
How can we change degree into radians |
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| 5371. |
In a triangle BD=EC,AD=AE,proove that AB=AC |
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| 5372. |
Where can i find pk garg????? |
| Answer» In mathematics ??⚘? | |
| 5373. |
Which questions can for 20 marks exam |
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Answer» Finding the zeroes of polynomials ch2 Ch? No questions |
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| 5374. |
How to prove that one line have only one mid point |
| Answer» Proof: Let us prove this statement by contradiction method. Let us assume that the line segment PT has two midpoints R and S.{tex}\\Rightarrow \\quad P R=\\frac{1}{2} P T{/tex}...........(1){tex}P S=\\frac{1}{2} P T{/tex}\xa0..........\xa0(2) ({tex}\\because{/tex}\xa0R and S are mid-points according to assumption)from (1)\xa0and (2) , we get{tex}\\Rightarrow{/tex}\xa0PR = PSBut this is possible only if R and S coincide. { which may not be possible if R and S are two different points }Therefore,Our contradiction is incorrect.i.e. there is only one mid-point of every line\xa0segment.Hence, proved | |
| 5375. |
Sir muje algebric wale sum nhi aate |
| Answer» You can refer to the books of class 6 or 7 for the basics | |
| 5376. |
Find the value of x^3 + 1/x^3 if x+1/x = √3. |
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| 5377. |
The angle of quadrilateral are in the 3:5:9:13.find the all angles of the quadrilateral |
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Answer» Find the value of x keeping their sum = 360°Multiply the given ratios by x.Angle:36,60,108,156 36,60,108,156 |
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| 5378. |
If x=5-√21/2,find the value of (1)x+1/x (2)x²+1/x² |
| Answer» Step-by-step explanation:Given ,x = (5 - √21)/21/x = 2/(5 -√21)=2(5 + √21)/(5 -√21)(5 + √21)= (5 + √21)/2hence,x + 1/x = (5 -√21)/2 + (5+√21)/2 =5x² + 1/x² = (x + 1/x)² -2x.1/x= (x + 1/x)² -2=(5)² -2= 23 | |
| 5379. |
How to factorize x²-13/24x-1/12 |
| Answer» Not possible | |
| 5380. |
What is postulate 5 explain it |
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| 5381. |
Explain quadrilateral |
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Answer» A structure of any simple closed figure which have 4 side\'s ,4vertices and 4 angles called quadrilateral A 4-sided polygon is called a quadrilateral |
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| 5382. |
Cffgg |
| Answer» Rational numbers are always real numbers | |
| 5383. |
1,2,3 ,4,5............25 |
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| 5384. |
65*96 |
| Answer» 6240 | |
| 5385. |
if the length of a median of an equilateral triangle is x cm, then find it\'s area |
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Answer» Solution:In an equilateral triangle, the height and the median are considered to be of same length. Hence we can say that, Height of an equilateral triangle is equal to Median of the same equilateral triangle.We know that, can be calculated as:Here, \'a\' denotes the side of an equilateral triangle.Now we know that area of an equilateral triangle can be calculated as:Substituting the value of \'a\' we get, Area is (x^2)/√3 cm^2 |
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| 5386. |
A^4+A^2+5 |
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| 5387. |
P(x)=2x⁴ -6x²+2x² -x+2andg(x)=x+2 |
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Answer» 16 -32 16 -4 |
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| 5388. |
Extra questions |
| Answer» Explain epithelial tissues | |
| 5389. |
What is tangent? |
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Answer» Tanget means 90 Tangent to a circle is a line which intersects the circle in exactly one point.At a point of a circle there is one and only one tangent.The tangent at any point of a circle is perpendicular to the radius through the point of contact.The lengths of tangents drawn from an external point to a circle are equal.Centre of the circle lies on the bisector of the angle between the two tangents. |
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| 5390. |
If m=1+root2 finxd value of mpower4 -1÷mpower4 |
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| 5391. |
10+√20+√40+√60 |
| Answer» √2+√3+√5 | |
| 5392. |
What is congerent triangle |
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Answer» A congruent triangle is in which when we have 2 triangles these will satisfy each other completely called congruent triangle Do you mean congruent triangle? |
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| 5393. |
Factorise 8a cube+b cube+12a square b+6ab square |
| Answer» In this we will use identify of (a+b)^3If the equation is 8a^3+b^3+12a^2b+6ab^2 Then a is 2a and b is b So after putting identity the answer is (2a+b)^3 or (2a+b)(2a+b)(2a+b) | |
| 5394. |
Show that if daigonals of parralelogram bisect each at right angles , then it is a rhombus |
| Answer» Given: Diagonals of quadrilateral intersect each other at right angles.To Prove: Quadrilateral is a rhombus.Proof : In {tex}\\triangle{/tex}AOB and {tex}\\triangle{/tex}AOD,AO = AO . . . [Common]OB = OD . . . [Given]{tex}\\angle{/tex}AOB = {tex}\\angle{/tex}AOD . . .[Each 90o]{tex}\\therefore{/tex}\xa0{tex}\\angle{/tex}AOB\xa0{tex}\\cong{/tex}\xa0{tex}\\triangle{/tex}AOD . . . [By SAS property]{tex}\\therefore{/tex}\xa0AB = AD . . . [c.p.c.t.] . . . . (1)Similarly, we can prove thatAB = BC . . . . (2)BC = CD . . . . (3)CD = AD . . . . (4)From (1), (2), (3) and (4)AB = BC = CD = DASince opposite sides of quadrilateral ABCD are equal, it can be said that ABCD is a parallelogram. Since all sides of a parallelogram ABCD are equal, it can be said that ABCD is a rhombus. | |
| 5395. |
Five postulate of Euclid |
| Answer» . A straight line segment can be drawn joining any two points.2. Any straight line segment can be extended indefinitely in a straight line.3. Given any straight line segment, a circle can be drawn having the segment as radius and one endpoint as center.4. All right angles are congruent.5. If two lines are drawn which intersect a third in such a way that the sum of the inner angles on one side is less than two right angles, then the two lines inevitably must intersect each other on that side if extended far enough. This postulate is equivalent to what is known as the parallel postulate. | |
| 5396. |
Chapter 8 all theorem proof |
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Answer» Written in NCERT See in your maths book |
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| 5397. |
Prove that if the diagonal of the quadrilateral bisect each other at 90degree then it is a rhombus. |
| Answer» Given: Diagonals of quadrilateral intersect each other at right angles.To Prove: Quadrilateral is a rhombus.Proof : In {tex}\\triangle{/tex}AOB and {tex}\\triangle{/tex}AOD,AO = AO . . . [Common]OB = OD . . . [Given]{tex}\\angle{/tex}AOB = {tex}\\angle{/tex}AOD . . .[Each 90o]{tex}\\therefore{/tex}\xa0{tex}\\angle{/tex}AOB\xa0{tex}\\cong{/tex}\xa0{tex}\\triangle{/tex}AOD . . . [By SAS property]{tex}\\therefore{/tex}\xa0AB = AD . . . [c.p.c.t.] . . . . (1)Similarly, we can prove thatAB = BC . . . . (2)BC = CD . . . . (3)CD = AD . . . . (4)From (1), (2), (3) and (4)AB = BC = CD = DASince opposite sides of quadrilateral ABCD are equal, it can be said that ABCD is a parallelogram. Since all sides of a parallelogram ABCD are equal, it can be said that ABCD is a rhombus. | |
| 5398. |
Sas congruency theorem |
| Answer» SAS congruence criterion: If\xa0two sides and included an angle of one triangle are equal to the corresponding two sides and included angle of another triangle then the two triangles are said to be congruent.Consider {tex}\\triangle{/tex}ABC, {tex}\\triangle{/tex}PQRhere AB = PQ, AC = PR and {tex}\\angle{/tex}A = {tex}\\angle{/tex}PHence {tex}\\triangle{/tex}ABC {tex}\\cong{/tex}\xa0{tex}\\triangle{/tex}PQR by SAS congruence criterion. | |
| 5399. |
(5-4)(6+4) |
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Answer» 10 1 10 10 |
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| 5400. |
,the three angle of a quadrilateral are65 |
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