InterviewSolution
Saved Bookmarks
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 5401. |
Construct a triangle abc in which bc=7cm b=75and ab ac=13 |
| Answer» Given: In {tex}\\triangle{/tex}ABC, BC = 7 cm, {tex}\\angle{/tex}B = 75o and AB + AC = 13 cm.Required: To construct the triangle ABC.Steps of construction :\tDraw the base BC = 7 cm.\t\tAt the point B construct\xa0an angle YBC = 75o.\tCut an\xa0arc from B as centre and radius equal to AB + AC = 13 cm. on the ray BY. Name it D.\tJoin DC.\tDraw the perpendicular bisector of line segment DC which intersects BD at some point name it A.\tJoin AC.\tABC is the required triangle. | |
| 5402. |
Find the coordinates of the point where the line 2 x minus y is equals to 3 minutes both the axis |
| Answer» | |
| 5403. |
ggdrjm |
| Answer» | |
| 5404. |
What is angel sum theorem |
|
Answer» Total sum of three angles in a triangle is 180 ,it is called Angel sum property. If in a traingle we have three angles so we can add all of them and equate it 180 |
|
| 5405. |
How to solve equation |
| Answer» | |
| 5406. |
Lines and angles leason |
| Answer» | |
| 5407. |
2x-90(89) |
| Answer» 2x-8010=-16020 | |
| 5408. |
What is lines angle |
| Answer» | |
| 5409. |
The common initial point of an angle is |
| Answer» vertex | |
| 5410. |
Arrange in descending order ^3√5,^6√26,^4√8,√2. |
| Answer» | |
| 5411. |
The part of the plane which lies between the rays is called |
| Answer» Inclined plane | |
| 5412. |
What is a cube root of 100 ? |
|
Answer» The first one is right 4.64158883 is the cube root of hundred√100=4.64158883 1000000 1000000 1000000 |
|
| 5413. |
What will be the answer if we add 1 +2+3+4+5+6+7+8+9+10 up to the end .dum ha to answer da ka dikhaw |
|
Answer» 55 55 55 May be 55 |
|
| 5414. |
In decimal form -4/-9 |
|
Answer» -0.444444444... -4/-9 = 4/9 = 0.444 |
|
| 5415. |
The mean of five number is 27 if one number is excluded their means is 25 find the excluded number |
| Answer» 2 | |
| 5416. |
Numbers is 27 if one number is exchanged their means is 25 find the exist number |
| Answer» 625I737D+3638O83762N8362T8K5N64O28W | |
| 5417. |
Find mirror image of -2,3 |
|
Answer» Along x axis: (-2,-3),and along y axis: (2,3). 2,-3 |
|
| 5418. |
Postulate |
| Answer» Postulates need to proof but if this question come in exam write the theorem because postulate is correct answer but in CBSE it is wrong. If you want to know about postulate, see in last page of 5 chapter of math book of ncert | |
| 5419. |
To prove ab||bc given abc perpendicular to bca |
|
Answer» No question is wrong..? |
|
| 5420. |
4x2 |
|
Answer» 8 4 x 2 =8 |
|
| 5421. |
To verify the identity of ( a -b)= |
| Answer» (a-b)=? | |
| 5422. |
Find a rational number between -2 and 4 |
|
Answer» -1, 0,1,2,3 0 2 3 4 2 3 4 2,3 |
|
| 5423. |
Find a rational number between 1/9 and 2/9 |
|
Answer» Let us take\xa04 rational number between\xa01/9 and 2/9So, 4+1=51/9 and 2/91/9x5/5=5/452/9x5/5=10/45Hence, The rational number between 1/9 and 2/9 are\xa06/45,7/45,8/45,9/45\xa0ORRational number between\xa0Are\xa0 Find a rational number between 1/9 and 2/9 |
|
| 5424. |
X=9-4√5X^-1/x^ |
| Answer» | |
| 5425. |
Simplify 81x¹² - 256y¹² |
| Answer» (9x^6 )^2 -(16y^6)^2(9x^6+16y^6)(9x^6-16y^6)(9x^6+16y^6)[(3x^3)^2-(4y^3)^2](9x^6+16y^6)(3x^3+4y^3)(3x^3-4y^3) | |
| 5426. |
In the figure AB||CD find x |
|
Answer» Wtf 24 |
|
| 5427. |
X cube minus 3 x square - 9 x minus 5 |
| Answer» X^3-3X^2-9X-5=(X+1)(X+1)(X+5) | |
| 5428. |
Represent under root 11 on number line |
| Answer» | |
| 5429. |
(2+6)-(6-8)×(6+5) |
|
Answer» (2+6)-(6-8)*(6+5) » (8) - (-2)*(11) »8+2*(11) » 10*11 » 110 2+6-6+8×6+5=2+6-6+48+5=61-6=55 (2+6)-(6-8)×(6+5)=2+6-6+8×6+5=2+6-6+48+5=55 |
|
| 5430. |
9^3/2-3*2^0-(1/81)^1/2 |
| Answer» | |
| 5431. |
If x is a vatriate assuming a constant show that E(x)=C |
| Answer» | |
| 5432. |
5 x to the power 2 + 3 x + 1 is divided by 2x |
| Answer» | |
| 5433. |
What is the cofficient of 2+x |
|
Answer» 1 1 Coefficient of X is 1 cofficient of X is 1 |
|
| 5434. |
What is congruency rule |
| Answer» | |
| 5435. |
6x +5x-6 |
| Answer» 11x- 6 | |
| 5436. |
Two adjacent complementary angles are equal ,then angles are |
| Answer» | |
| 5437. |
Find six rational number between 7/4 and 3/5 |
| Answer» 7/4×5/5=35/20;3/5×4/4=12/20;So, six rational numbers between 7/4 and3/5 are:-13/20,14/20,15/20,16/20,17/20,and 18/20. | |
| 5438. |
What is the area of equilateral triangle |
|
Answer» half into base intonheight An equilateral triangle is a triangle in which all three sides are equal.Area of Equilateral Triangle Formula: A = 3√4 a2where, “a” denoted the sides of an Equilateral Triangle |
|
| 5439. |
Brize course |
| Answer» | |
| 5440. |
Pyramid in addition |
| Answer» | |
| 5441. |
How to know that number is rational or irrational |
| Answer» All\xa0numbers\xa0that are not\xa0rational\xa0are considered\xa0irrational. An\xa0irrational number\xa0can be written as a decimal, but not as a fraction. An\xa0irrational number\xa0has endless non-repeating digits to the right of the decimal point. | |
| 5442. |
3root40 |
| Answer» 3.41 | |
| 5443. |
What is pgt |
| Answer» pgt is the short form of pythagoras theorem | |
| 5444. |
In triangle abc, B=45,angle C=55 and bisector of angle A meets BC at a point D. Find angle ADC. |
| Answer» ANGLE ADC = 40° | |
| 5445. |
If 2*x=952 so what is 3*x=? |
| Answer» 2*x=952=> x=952/2=> x=476•: 3*476=1428 | |
| 5446. |
Difference between ASA, AAS and RHS |
| Answer» Aas- angle angle side Aas- angle angle sideRhs- right angle hypotenuse side | |
| 5447. |
Root x plus root y plus root z find the value of x plus y plus z |
| Answer» | |
| 5448. |
(2a-y)¾ |
| Answer» | |
| 5449. |
Solve the following 4/18+8/16 |
| Answer» LCM of 18 and 16 is 144(4×8)/(18×8)+(8×9)/(16×9)(32+72)/144104/14413/18 | |
| 5450. |
How a³+b³+c³-3abc = (a+b+c )(a²+b²+c²-ab-bc-ca) |
| Answer» First of all you should be know thatformulaa³ + b³ + c³ -3abc = ( a + b + c)(a² + b² + c² - ab - bc - ca).LHS = a³ + b³ + c³ - 3abc= ( a³ + b³ ) + c³ - 3abc= ( a + b)³ - 3ab( a + b) +c³ - 3abc= ( a + b)³ - 3a²b - 3ab² + c³ - 3abc= {(a + b)³ + c³ } -3a²b - 3ab² - 3abc= ( a + b + c)³ - 3c(a + b) ( a + b + c ) -3ab(a + b+ c)= ( a + b + c){ ( a + b + c)² -3c(a +b) - 3ab }= ( a + b + c){ a² + b² + c² +2ab +2bc+ 2ca -3ca - 3bc - 3ab }= ( a + b + c)( a² + b² + c² - ab - bc -ca) = RHSLHS = RHSHence, Proved | |