InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 6551. |
1/(1+a+b^-1)+1/(1+b+c^-1)+1/(1+c+a^-1) |
| Answer» Question: If abc =1,then show that 1/(1+a+ b^(-1) )+ 1/(1+b+ c^(-1) )+ 1/(1+c+ a^(-1) ) = 1Answer:\xa0 | |
| 6552. |
Find the median of first 10natural numbers. Is it is equal |
|
Answer» formula of median is sum of given number divide by total number.....so we add number and after divide.....1+2+3+4+5+6+7+8+9+10=55......we divide 55 by 10 because total numbers are 10.....55/10=5.5.....so,answer is 5.5 5.5 Median = 1,2,3,4,5,6,7,8,9,10Therfore median =5+6/2=5.5Mean 1+2+3+4+5+6+7+8+9+10=55/10 =5.5 Therefore median is equal to their mean that is 5.5=5.5 |
|
| 6553. |
What are quarters |
| Answer» The coordinates axes divided the plane into 4 parts which are known as quarters | |
| 6554. |
What is the coordinates of a point on x - axis or y-axis? |
|
Answer» ??????-? The\xa0coordinates of a point\xa0on the\xa0x-axis\xa0are of the form (x, 0) and that of the\xa0point\xa0on the\xa0y-axis\xa0are (0,\xa0y). The\xa0coordinates\xa0of the origin are (0, 0). |
|
| 6555. |
What is the coordinates of origin |
|
Answer» The coordinates of origin are(0,0) The\xa0coordinates of a point\xa0on the\xa0x-axis\xa0are of the form (x, 0) and that of the\xa0point\xa0on the\xa0y-axis\xa0are (0,\xa0y). The\xa0coordinates\xa0of the origin are (0, 0). The coordinates of origin are (0,0) |
|
| 6556. |
? ???????? ???????? ???×?.???×?.???.???? ???? ?? ??? ?????? ?? ? ?????? ?????????? ?? ???? ?????? |
| Answer» Volume of a matchbox = 4 x 2.5 x 1.5 cm3\xa0= 15 cm3∴ Volume of a packet containing 12 such boxes = 15 x 12 cm3\xa0= 180 cm3. | |
| 6557. |
2x +1/3x =12 |
| Answer» 2x+1 / 3x =122x+1 = 12 × 3x2x+1 = 36x2x-36x = -1-34x = -134x = 1x = 1/34 | |
| 6558. |
A,b and c,are side of the triangle.the off sides are a =4cm b=8cm and c=10cm then semi_ perimeter s= |
|
Answer» a = 4 cm, b = 8 cm and c = 10cmSemi-perimeter s = (a + b+ c)/2= (4 + 8 + 10)/2 = 22/2 = 11 cm\xa0 Hi |
|
| 6559. |
Is there is any changes in syllabus |
| Answer» No | |
| 6560. |
67 table |
| Answer» | |
| 6561. |
How many multiples of 4 are there in between 10 and 250 |
| Answer» the numbers between\xa010\xa0and\xa0250\xa0which are multiple of\xa04\xa0are\xa012,16,20,...,248.\xa0This is an AP with first term\xa0a=12, common difference\xa0d=4.Let there be\xa0n\xa0terms in this AP, thenan\u200b=248⇒a+(n−1)d=248⇒12+(n−1)×4=248⇒(n−1)=59⇒n=60 | |
| 6562. |
Why we learn maths |
|
Answer» We learn maths to deal with the daily situations occurring in our daily life related to calculations, and everywhere you see Maths??????????✂️?✅️❌️? why you ask why we learn maths??Maths very helpful in our life in nowdays.May be you don\'t like maths .if you like maths you comments me |
|
| 6563. |
AB parallel to CD, angel BDC =40 and angel BAD =75 , find x, y, z |
| Answer» 65 | |
| 6564. |
how can i get the explanatiom |
| Answer» | |
| 6565. |
Sciy |
| Answer» Qqw | |
| 6566. |
Ghahshgdjska |
|
Answer» Hahahagsgsgsfhgfff Fggftcfggfg Wuug Rstefdvhy |
|
| 6567. |
If x=2+√3,Find the value of x power3+1/x power3 |
| Answer» Question :\xa0If x=2-√3, find the value of (x-1/x) of power 3Answer :x = 2 - √3--( 1 )1/x = 1/( 2 - √3 )= ( 2 + √3 ) / [ ( 2 - √3 )(2 + √3 ) ]= ( 2 + √3 ) / [ 2² - ( √3 )² ]= ( 2 + √3 ) / ( 4 - 3 )= 2 + √3 ----( 2 )x - 1/x= 2 - √3 - ( 2 + √3 )= 2 - √3 - 2 - √3= - 2√3 ---( 3 )Therefore ,( x - 1/x )³ = ( - 2√3 )³= - 24√3 | |
| 6568. |
Zero is a odd number or even number |
|
Answer» Even Even number Zero is a even number |
|
| 6569. |
P(x)=3x_2 |
| Answer» + | |
| 6570. |
State Euclid\'s fifth postulate |
| Answer» If a straight line falling on two straight lines makes the interior angles on the same side of it taken together less than two right angles, then the two\xa0straight lines, if produced indefinitely, meet on that side on which the sum of angles is less than two right angles. | |
| 6571. |
Find five rational number between 1.101101110........ and 1.10110122012220122220...... |
| Answer» | |
| 6572. |
Show that [x^a/x^6]a^2+ab+b^2×(x^b/x^c)b^2+bc+c^2×(x^c/x^a)c^2+ac+a^2=1 |
| Answer» | |
| 6573. |
Express the following in a rational denominator 7√3/√3+10-2√5/√6+√5-3√2/√15+3√2 |
| Answer» | |
| 6574. |
2+2+3+4+5+6+7+8+9+0+1-24-12-12 |
|
Answer» Answer is -1 -1 2+2+3+4+5+6+7+8+9+0+1-24-12-12= 11 +18 + 18 - 24 - 24= 47\xa0- 24 - 24= 23 - 24= -1 |
|
| 6575. |
4^2 |
|
Answer» 4^2= 16 16 4 into 4=16 |
|
| 6576. |
If a=1-root2 find (a-1÷a)cube |
| Answer» Answer :The value of\xa0\xa0is 8 .To find : The value of\xa0Solution :Given :Therefore,Thus, the value of\xa0\xa0is\xa08. | |
| 6577. |
Sir exercise 2.5 |
| Answer» See in books | |
| 6578. |
Solve (-7+√7(4)-3√7) |
| Answer» | |
| 6579. |
7x-1/4-1/3 (2x+x-1/2)=6 1/3 |
| Answer» The answer of given equation is 5.Step-by-step explanation:Given: The given equation isThe solution is given in following steps\xa0The answer of\xa0the\xa0given equation is 5. | |
| 6580. |
In which of the quadrant does (-3,-2) lies |
|
Answer» In third quadrant Quadrant III(-3, -2)\xa0lies\xa0in\xa0Quadrant 3. |
|
| 6581. |
2x+5(y-1)=15 |
| Answer» | |
| 6582. |
Gsi |
| Answer» Ahdhjddjdj | |
| 6583. |
To verify that the sum of any two sides of a triangles is always greater than the third side |
| Answer» Given ΔABC, extend BA to D such that AD = AC.Now in ΔDBC∠ADC = ∠ACD [Angles opposite to equal sides are equal]Hence ∠BCD > ∠ BDCThat is BD > BC [The side opposite to the larger (greater) angle is longer]Þ AB + AD > BC\xa0∴ AB + AC > BC [Since AD = AC)Thus sum of two sides of a triangle is always greater than third side. | |
| 6584. |
Find the rationalising factor of the following surds5÷√33÷√141÷3√37÷2√52÷3√6 |
| Answer» | |
| 6585. |
I WANT THE CUBE IDENTITY |
| Answer» 1. (a+ b)^3 = a^3 - b^3 - 3ab( a+b )2. (a- b)^3 = a^3 - b^3 - 3ab ( a- b)3. (a^3 + b^3) = ( a+b) (a^2 + ab+ b^2)4. (a^3-b^3) = (a- b) (a^2 + ab + b^2) | |
| 6586. |
x=3+√8 then the value of x²+1/x² |
|
Answer» x = 3+ √8x = (3+√8)(3-√8) / (3-√8)x = (9 -8) / (3-√8)x = 1/ (3 -√8)Or we can write\xa01/x = (3-√8)Put the value and find outx² +(1/x²) = x² + (1/x)²So x² + 1/ x² = (3 +√8)² + (3 -√8)²= 9+6√8+8 + 9–6√8+8=\xa034.\xa0 (3+ under root 8)^2 + 1/(3+ under root 8)^2 |
|
| 6587. |
3x plus 5/7is equal to -8/5Solve this as linear equation in one variable |
| Answer» | |
| 6588. |
In triangle ABC, A=100⁰ and angleAB=AC find angle B and C |
| Answer» 40 each | |
| 6589. |
27-2/3 |
| Answer» 27 -2/3= (81 - 2)/3= 79/3 | |
| 6590. |
The line 2x+ 3y=6 cuts the x axis at & at y axis |
| Answer» At x axis = 2x+3y=6 2x+3(0)=6 2x=6 x=3Add y axis = 2x+ 3y= 6 2(0) + 3 Y =6 3 y = 6 y=2 | |
| 6591. |
Degree of a zeroed polynomial is what |
| Answer» A zero polynomial is the one where all the coefficients are equal to zero. So, the degree of the zero polynomial is either undefined, or it is set equal to -1. | |
| 6592. |
(25)1/3 * (5)1/3 |
| Answer» 25)1/3 × (5)1/3=(5)2×1/3 × (5)1/3= (5)2/3 × (5)1/3= (5)2/3+1/3 ( same base powers are added)= (5)3/3= 51= 5 | |
| 6593. |
Explain factor theorem in a very simple way. |
| Answer» In algebra a factor theorem is a theorem linking Factors and zeros of a polynomial. | |
| 6594. |
Bhhhggggccc |
|
Answer» Jcdkdkfkrkcdjjffj There is no meaning in this question .so,dont use it personally. What do you mean? |
|
| 6595. |
What is the value of 9/30-1/56+9/8 |
| Answer» 1.41 or 1.40714285714 | |
| 6596. |
Factorise:Q x^2-2√5-15 |
| Answer» x^2-3√5+1√5x-15. =x(x-3√5)+√5(x-3√5). =(x+√5)(x-3√5) | |
| 6597. |
ab+2ab-cd |
| Answer» | |
| 6598. |
Ex.4.3 question 3 If the point (3, 4) lies on the graph of the equation, find the value of\xa0a. |
|
Answer» Since, the point (x = 3, y = 4) lies on the equation 3y = ax + 7, then the equation will be , satisfied by the point.Now, put x = 3 and y = 4 in given equation, we get3(4) = a (3)+7⇒\xa012 = 3a+7⇒\xa03a = 12 – 7⇒\xa03a = 5Hence, the value of a is 5/3. Sorry This question is wrong |
|
| 6599. |
(√5+3)(√5-3) |
|
Answer» =(√5+3)(√5−3)=(√5)²-(3)² {a²-b² formula}=5-9=-4 ans. It is to multiply u have division or is it division 3+✓5 / 3 - ✓5=> 3 + ✓5 / 3 - ✓5 × 3 + ✓5/ 3 + ✓5=> ( 3 + ✓5) ( 3 + ✓5) / ( 3 - ✓5) ( 3 + ✓5)=> ( 3 + ✓5)² / (3)² - ( ✓5)²=> (3)² + ( ✓5)² + 2 × 3 × ✓5 / 9 -5=> 9 + 5 + 6✓5 / 4=> 14 + 6✓5/4=> 2 ( 7 + 3✓5 ) /4=> 7 + 3✓5/2 5-9=-4 |
|
| 6600. |
Prove sum of interior angle of a triangle is 180 |
| Answer» In order to prove that the sum of angles of a triangle is 180, you must know the theorems of angles of a triangle.We know that, alternate interior angles are of equal magnitude.This\'ll help us get the answer. Let us assume a triangle ABC. Now we have to substitute the angles.∠PAB + ∠BAC + ∠CAQ = 180°. where PQ line parallel to side BC touching vertex A.∠PAB = ∠ABC & ∠CAQ = ∠ACB BECAUSE alternate interior angles are congruent..\xa0Hence we get, ∠ABC + ∠BAC + ∠ACB = 180° [Proved] | |