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6651.

a^1/a=b^1/b=c^1/c & a^bc+b^ac+c^ab=729 find a^1/a

Answer» Thanks
\xa0Let sayTaking power ABC each side then\xa0\xa0Hence
6652.

(2a-b-c)^3

Answer»
6653.

Find the zeroes of polynomialf(x)= x²+5x–14

Answer»
6654.

1+2+3=??

Answer» Obviously 6
6
6
6
6655.

write 2 rational no between √2 and √3

Answer» We know that,√2 = 1.4142135.....√3 = 1.73205080......As we know that rational numbers are those decimal numbers which are either terminating or repeating.So, you can given any terminating or repeating decimal number between 1.4142135 ...... and 1.73205080 ....... as your answer.Thus your answer can be any of the following rationals:1.415, 1.416, 1.417, 1.532, 1.582, 1.60, 1.62, 1.70, 1.72 etc
√2 ≈ 1.414 and √3 ≈ 1.732 . Then we have a rational number 1.5 and 1.6 which is in between √2 and √3.
6656.

Wht is radius

Answer» *half of dimeter*
Half of the diameter
The half of the diameter
Hello Ritika
\xa0When we connect a point on the circumference of a circle to the exact centre, then the line segment made is called the\xa0radius\xa0of the ring. The distance between the center of the circle to its circumference is the radius.\xa0
6657.

Polynomial ch-2 ex-2.4 Q-4 point-2

Answer» Q. 2x² + 7x +3 Ans.... By splitting the middle term 2x² + (6+1)x +3 2x² + 6x + x + 3 2x(x+3) +1( x+3)(x+3)(2x+1)
6658.

1.232332333

Answer» Irrational number
It is an irrational no.
6659.

1, 1, 4, 8, 9, 27, 16, 64, 25, ?

Answer» 125
125
1sq,1cub.,2sq,2qb.,3sq,3qb.,4sq,4qb.,5sq,_answer__5qb_=125_.
125
125
6660.

Find the value of \'s\' if the perimeter is 32cm

Answer» Side of square = 8cm
The perimeter of square =4 x side. 4 x side =32. Side =32/4. Side =8
32/2=16
The perimeter of square = 4 × side\xa04 × side = 32side = 32/4side = 8 cm\xa0
Perimeter of square = 4*sideP=32cm32cm = 4*side32/4= side8cm = side of square
6661.

Thickness of a paper is 0.08m write these numbers in standard form

Answer» 8.000 ×10-2
2/25m
6662.

Identify the irrational no.1. √7 - √3 2. 9.98 bar3. √1694. 6.056

Answer» \xa0(2) 9.98 bar.Since 9.98 bar. is a non-terminating and recurring (repeating) decimal.So, it is a rational number.\xa0(3) 169 = 13 * 13 = 132\xa0So, 169\xa0is a perfect square.\xa0Thus, √169 is a rational number.(4) 6.056Since 6.056 is a terminating decimal,\xa0So, it is a rational number.
6663.

AB and AC are opposite rays

Answer» Incomplete question
6664.

36 degrees 27\'46\'\'+angle 28degree 43\'39\'\'

Answer» Answer= 64°70\'85"
6665.

Factorise: (a – b)3 + (b – c)3 + (c – a)3

Answer» 2 (a-b-c)3
6666.

Trinomial of degree 6

Answer» √5x⁶+3x+2 is a trinomial of degree 6
√2x-1
6667.

To become engineer we can choose biology subject

Answer» No
No
No
6668.

5+5+5+5+

Answer» 5+5+5+5=20
20
5+5+5+5 =20
20
6669.

Rationalise the denominator of 1/root5+root3

Answer» 1/√5+√3= 1/√5+√3×√5-√3/√5-√3= √5-√3/(√5)^2-(√3)^2 {(a+b)(a-b)= (a)^2-(b)^2}=√5-√3/5-3=√5-√3/2 ans...Do you satisfied to my given answer????
=1× root 5 - root 3/root 5 + root 3× root 5 - root 3 =Root 5 - root 3/ root 5 square - root 3 square =Root 5 - root 3 / 5 - 3 = Root 5 - root 3/2 Ans.
6670.

Two irrational number between 1/7 and 1/9

Answer» Infinite rational number
What is Matter?
6671.

Is maths ncert lesson 8 included in exams?? Pls reply me soon

Answer» Yes
Yes
6672.

How to represent √7 on number line???

Answer» 2.64
Draw a\xa0number line\xa0and mark 0, 1, 2, 3, ....etc.Mark 0 as point O and 2 as B.Now from B, draw a perpendicular AB of length 1 unit.Join OA. ...Again From A, draw a perpendicular AC of length 1 unit.Join OC. ...Again From C, draw a perpendicular CD of length 1 unit.Join OD.
6673.

Give the equation of two line passing through (2,14) . How many such line are there and why ?

Answer» x+y=163x+y=20there are infinetly many solutions passing through a line
The equations of two lines passing through (2, 14) can be taken asx + y= 16and\xa07x – y = 0.There are infinitely many such lines because through a point an infinite number of lines can be drawn.
6674.

Maths chapter 1 EXERCISES 1.1

Answer»
6675.

Give the construction to find a centre of a circle

Answer» Do it yourself
6676.

abcd is a parallelogram find 2 angle abc - angle adc and angle c is 70 class 9

Answer» Angle adc=70,Angle acd=110
6677.

To go in Google we have to choose which engineering

Answer» Computer engineering
Computer engineering and civil engineering
6678.

What is the question paper of Math class 9

Answer»
6679.

0.7 lies between which quadrant

Answer» (0, 7) lies on y -axis
6680.

5x_4x+3

Answer» Ok I write full question
Write full questions
6681.

Four solutions of 2x+y=7

Answer» -1, 90, 71, 52, 3
Given equation is:2x+y=7For x = - 1, we get−2+y=7⇒y=9\xa0∴\xa0(-1, 9) is a solution.\xa0For x = 0, we get⇒0+y=7⇒y=7\xa0∴\xa0(0, 7) is a solution.\xa0For x = 1, we get⇒2+y=7⇒y=5∴\xa0(1, 5) is a solution.\xa0For x = 2, we get⇒4+y=7⇒y=3\xa0∴\xa0(2, 3) is a solution.\xa0Hence, we have four solution\xa0(−1,9),(0,7),(1,5)and(2,3)
6682.

Rd sarma book

Answer»
6683.

if x=0 and y=k is a solution of equation 5x-3y=3 find the value of k.

Answer» 5x-3y=3It is given that x=0&y=kThen, 5(0)-3(k)=3(5×0)-(3×k)=30-3k=3-3k=3K=3÷(-3)K=-1So the answer is -1
5x-3y=3put x = 0 and y = k5 (0) - 3 (k) = 3-3k = 3k = 3/-3k = -1
6684.

In a trapezium if non-parallel sides are are equal, then it is called a _____ trapezium.

Answer» Isoceles
Isosceles
6685.

Write an equation of a line parallel to x-axis and passing through the point (3,2)

Answer» We know that The equation of line which is parallel to x-axis is y = k.Given that, Equation of line passes through (3,2) so, y = 2 , x = 3.So, The equation of line is y = 2 .
6686.

Factorise: 8p cube+12/5p square+6/25p+1/125.

Answer» Answer:Step-by-step explanation:/*\xa0By\xa0algebraic\xa0identity:a³+3a²b+3ab²+b³\xa0=\xa0(a+b)³\xa0*/Therefore,
6687.

If x/y + y/x=-1( where x,y is not equal to 0) then find the value of xcube - ycube

Answer» \xa0We know that,x3\xa0- y3\xa0= (x - y)(x² + xy + y²) ....(i)Given that, x/y + y/x = -1(x² + y²)/xy = -1x² + y² = -xyx² + y² + xy = 0(x² + xy + y²) = 0Multyplying by (x - y) on both sides we get,(x - y)(x² + xy + y²) = (x - y) × 0x3\xa0- y3\xa0= 0 using (i)
6688.

Which whole number represents the y coordinate of any point lying on the x axis?

Answer» 0If a\xa0point lies on the x-axis\xa0then its\xa0y-coordinate\xa0is 0. Similarly, a\xa0point\xa0on the\xa0y-axis\xa0has its\xa0x-coordinate\xa00. The origin has\xa0coordinates\xa0(0,0). On the right you see an example of a (Cartesian)\xa0coordinate\xa0plane with some\xa0points\xa0sketched in it.
6689.

Examine whether x+2 is a factor of x3 + 3x2 + 5x + 6.

Answer» Ok
{tex}P(x)=x^3+3x^2+5x+6{/tex}g(x)=x+2 x=-2put x=-2 in p(x){tex}p(-2)=(-2)^3+3(-2)^2+5(-2)+6{/tex} =-8+12-10+6 =0since p(x) is zero\xa0x+2 is a factor of\xa0{tex}x^3+3x^2+5x+6{/tex}
6690.

I want to know the line that are drawn near to dA/dr from application of derivative chapter

Answer»
6691.

find five rational number between 3/5 4/5

Answer» 3/5 , 4/5 3*5/5*5. , 4*5/5*515/25. , 20/2515/25. , 16/25. , 17/25. ,18/25. , 19/25. , 20/25
Question -3 Find five rational numbers between 3/5 and 4/5.Solution:\xa0Since we want five numbers, we write 3/5 and 4/5 So multiply in numerator and denominator by 5+1 =6 we get
6692.

3 aur aur 4 ke bich ki parimay sankhya gyat Karen

Answer»
6693.

Visualise 4.26 on the number line,up 4 decimal places.

Answer»
6694.

Visualise 3.765 on the number line, successive magnification.

Answer»
6695.

find the two rational between 5/7 and6/7

Answer» Solution :-
6696.

Find the value of (2.7)³ - (1.6)³ - (1.1)³ using a suitable identity

Answer» {tex}2.7^3-1.6^3{/tex}{tex}=(2.7-1.6)^3+3(2.7)(1.6)(2.7-1.6){/tex}{tex}=(1.1)^3+3(2.7)(1.6)(1.1){/tex}{tex}=(1.1)^3+14.256{/tex}{tex}2.7^3-1.6^3-1.1^3{/tex}{tex}=(1.1)^3+14.256-(1.1)^3{/tex}{tex}=14.256{/tex}
6697.

Factorise : 8x³ - 27y³ + 125z³ + 90xyz

Answer» 8x3−27y3+125z3+ 90xyzUsing,a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)\xa0Here,a=2xb=−3yc=5z,Therefore,=>(2x)3+(−3y)3+(5z)3−3×2x×(−3y)×5z=(2x−3y+5z)(4x2+9y2+25z2+6xy+15yz−10xz)
6698.

Find five rational numbers between 3/5and 4/5

Answer» Find five rational numbers between 3/5 and 4/5.Solution:\xa0Since we want five numbers, we write 3/5 and 4/5 So multiply in numerator and denominator by 5+1 =6 we get
6699.

Expand each of the following using suitable identities (-2x+5y-3z)²

Answer» We know that(a+b+c)² = a² + b² + c² + 2(ab + bc + ca)So,(-2x + 5y - 3z)²= (-2x)² + (5y)² + (-3z)² + 2 [ (-2x)*5y + 5y*(-3z) + (-3z)*(-2x) ]= 4x² + 25y² + 9z² + 2 [ (-10xy) + (-15yz) + 6xz ]= 4x² + 25y² + 9z² - 20xy - 30yz + 12xz
6700.

solutions for CBSE mathematics 2020 code 30/3/3

Answer»