InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
T1=2,t2=tn-1+5,n-2 |
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| 2. |
If triangle ABC is right angle at C then the value of sec (A+B) is |
| Answer» Sec(A+B)=Sec90°=infinityBecause, since angle C is 90° so by angle sum property angle A+B will be equal to 90° and the value of sec 90° is not defined | |
| 3. |
Find the zeroes of the polynomial ?2 − 3 |
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Answer» x²-3= 0(x)²-(√3)²=0By using identity a²-b²=(a+b)(a-b)(x-√3)(x+√3)=0x-√3=0 or x+√3=0x=√3 or x=-√3 x2 - 3 = 0x2 - (\xa0√ 3)2 =0(x - √ 3) (x + √ 3)=0x - √ 3=0 and x + √ 3=0x = √3 and x = - √3 |
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| 4. |
Asian dustbin sleep sum cm all dictum SNL |
| Answer» Kehna kya chahti ho | |
| 5. |
What is the formula for area of sphere ??? |
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Answer» 4πr square ,where r is radius 4 pie r square 4πr², where r is radius 4πr^2 |
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| 6. |
Mujhe all chapters answer chea |
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Answer» Answer batio Hello What |
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| 7. |
Show that the product of 3 consecutive numbers are divisible by 6 |
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| 8. |
Irrational number of 2 |
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| 9. |
Values of alpha,beta and gamma? |
| Answer» • a+b+c=-b/a• ab+bc+ca=c/a• abc=-d/a Here, a is alpha, b is beta & c is gamma | |
| 10. |
substituting method |
| Answer» It is the method by which the value of a variable in equation 1 is substituted in another equation and the value of the other variable in equation 2 is substituted in equation 1 or equation 3 made by equation 1.Let\'s understand it with an example:x+y=2............. eq 1x-2y=1............. eq 2In equation 1, x+y=2x=y-2............. eq 3substituting the value of x in equation 2x-y=1(y-2) -2y=1y-2-2y=1-y-2=1-y=1+2-y=3[y= -3]Substituting the value of y in equation 3x=y-2x=-3-2[x=-5]Hope you understood. | |
| 11. |
If the age of father is 3 times the age of son,if the age of son is 15.what is the age of father? |
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Answer» Age of father is 45years let age of son be = x yr old then the age of father =3x given son\'s age = x=15 yr .therefore the age of father = 3x=3(15) = 45 . yr thank you ? Age of father is 45 years Age of son = 15Age of father = 3 times age of son =3×15 = 45 years. (ans) = age of father. |
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| 12. |
Derive distance formula |
| Answer» Speed is equal to distance over timeThe ,,distance is equal Speed into distance | |
| 13. |
Is completing the square topic in the syllabus of this year? |
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Answer» Okay thank you? Yes.... |
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| 14. |
Chapter 2 all solutions |
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| 15. |
What is the role of zero in maths? |
| Answer» 0 (zero) is a number, and the numerical digit used to represent that number in numerals. It fulfills a central\xa0role\xa0in\xa0mathematics\xa0as the additive identity of the integers, real numbers, and many other algebraic structures. As a digit, 0 is used as a placeholder in place value systems. | |
| 16. |
if the distance between point (p, -5) and (2,7) is 13, the value of \'p\' is |
| Answer» Hi | |
| 17. |
Given HCF (306, 657) =9, Find the LCM(306, 657). |
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Answer» LCM = 22,338 Answer:LCM=22,338 |
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| 18. |
(x-b)(x-c)/(a-b)(b-c)+(x-c)(x-a)/(b-c)(b-a)+(x-a)(x-b)/(c-a)(c-b) |
| Answer» Are you sure it is correct? | |
| 19. |
Which is Best reference book for standard maths in cbse board examination? |
| Answer» All books are good dear....but, you just have to do hard work..? | |
| 20. |
Find the values of p so that the equation( p-4 )x²-2(p-4) x+4=0 has real roots |
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| 21. |
If an AP the sum of n term is equal to n time of first term then common difference is... |
| Answer» 1 | |
| 22. |
Write the measure at adjacent , side opposite side and hypotenus of angle |
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| 23. |
Solve for x and y 5/x+y + 1/x-y =2 15/x+y -5/x-y =-2 |
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| 24. |
2(56+56)4 |
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Answer» 896 2(112)4=224×4=896 Or koi questions 8(56+56) =448+448 =896 |
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| 25. |
By using euclid\'s algorithm find the latgest number which divides 650 and 1170 |
| Answer» 1170=650 multiply 1+520650=520 multiply 1+130520=130multiply 4+0130 is the answer | |
| 26. |
Exercise 4.4 problem 5 .10th NCERT solution |
| Answer» 5. Is it possible to design a rectangular park of perimeter 80 metres and area 400\xa0m2. If so, find its length and breadth.Ans.\xa0Let length of park =\xa0x\xa0metresWe are given area of rectangular park =\xa0Therefore, breadth of park =\xa0\xa0metres{Area of rectangle = length ×\xa0breadth}Perimeter of rectangular park = 2 (length\xa0+\xa0breath) =\xa0metresWe are given perimeter of rectangle = 80 metresAccording to condition:=>\xa0⇒\xa0⇒\xa0⇒\xa0⇒\xa0Comparing equation,\xa0\xa0with general quadratic equation\xa0, we get\xa0a\xa0= 1,\xa0b\xa0= −40 and\xa0c\xa0= 400Discriminant =\xa0\xa0(1) (400) = 1600 – 1600 = 0Discriminant is equal to 0.Therefore, two roots of equation are real and equal which means that it is possible to design a rectangular park of perimeter 80 metres and area\xa0.Using quadratic formula\xa0\xa0to solve equation,Here, both the roots are equal to 20.Therefore, length of rectangular park = 20 metresBreadth of rectangular park =\xa0 | |
| 27. |
Exercise 6.3 Question no. 10 |
| Answer» 10. CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of ΔABC and ΔEFG respectively. If ΔABC ~ ΔFEG, Show that:(i) CD/GH = AC/FG(ii) ΔDCB\xa0~\xa0ΔHGE(iii) ΔDCA ~ ΔHGFSolution:Given, CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of ΔABC and ΔEFG respectively.(i) From the given condition,ΔABC ~ ΔFEG.∴ ∠A = ∠F, ∠B = ∠E, and ∠ACB = ∠FGESince, ∠ACB = ∠FGE∴ ∠ACD = ∠FGH (Angle bisector)And, ∠DCB = ∠HGE (Angle bisector)In ΔACD and ΔFGH,∠A = ∠F∠ACD = ∠FGH∴ ΔACD ~ ΔFGH (AA similarity criterion)⇒CD/GH = AC/FG(ii) In ΔDCB and ΔHGE,∠DCB = ∠HGE (Already proved)∠B = ∠E (Already proved)∴ ΔDCB ~ ΔHGE (AA similarity criterion)(iii) In ΔDCA and ΔHGF,∠ACD = ∠FGH (Already proved)∠A = ∠F (Already proved)∴ ΔDCA ~ ΔHGF (AA similarity criterion) | |
| 28. |
Prove that 3+root 2 is a irrational number |
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Answer» Let us consider that 3√2 is a rational number. It can be written in the form p/q (p and q are co-primes). →p/q = 3√2. →p/3q = √2. Now, p/3q = integer/integer = rational number. But, this contradicts the fact that √2 is irrational. Therefore, our assumption that 3√2 is rational is WRONG. Hence, 3√2 is an irrational number. HoPe It HeLpS yOu?? Let us consider that 3root2 is a rational number. It can be written in the form p/q (p and q are co primes)p/q = 3root2p/3q = root2Now,p/3q = integer/interger= rational numberBut, this contradicts the fact that root2 is irrational.Therefore, our assumption that 3root2 is rational is WRONG.Hence, 3root2 is an irrational number. |
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| 29. |
The list of numbers-10,-6,-2,2,..... which is AP or not |
| Answer» a=-10Common difference=4 | |
| 30. |
The roots of the quadratic equation x2 - 0.04 = 0 are |
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Answer» 0.04 or 0 hope it will help you 0.04and 0 |
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| 31. |
Find all other trigonometrical ratios in triangle PQR, angle Q=90degree and tan=3/4 |
| Answer» If Tan A\xa0=\xa03/4, then find the other trigonometric ratio of angle\xa0A.sol) Tan A\xa0=\xa0Opposite side\xa0=\xa03 Adjacent side 4.^., opposite side : adjacent side = 3:4For angle\xa0A,\xa0opposite side\xa0=\xa0BC=3kAdjacent side\xa0=AB=4k(where\xa0k\xa0is any +ve no)Now, we have in triangle\xa0ABC(\xa0by Pythagoras theorem)\xa0\xa0AC^2\xa0=\xa0AB^2 + BC^2=>(3k)^2 + (4k)^2\xa0=\xa025k^2AC\xa0=\xa0√25k^2=> 5k\xa0=\xa0Hypotenuse\xa0Now,we can easily write the other ratios of trigonometrysin A\xa0=\xa03k\xa0=\xa03 5k 5cos A\xa0=\xa04k\xa0=\xa04 5k 5cosec A\xa0=\xa0 1 = 5 sin A 3sec A\xa0=\xa0 1 = 5 cos A 4cot A\xa0=\xa0 1 = 4 tan A 3 | |
| 32. |
Write five Indian mathematician names and their contribution |
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Answer» Thanks And please tell their contribution Aryabhata. ...Brahmagupta. ...Srinivasa Ramanujan. ...P.C. Mahalanobis. ...C.R. Rao. ...D. R. ...Harish Chandra. ... |
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| 33. |
Siddh Kijiye ki Bindu (1 - 1) ,(5,2),(9,5) |
| Answer» Let A(1,-1),B(5,2) and C(9,5)Area of Triangle=1/2[X1(Y2-Y3)+X2(Y3-Y1)+X3(Y1-Y2)] =1/2[1(2-5)+5(5+1)+9(-1-3)]=1/2[-3+30-36]=1/2*(-9)=4.5 unit sq.(AREA CANNOT BE NEGATIVE) | |
| 34. |
(Sin 30°+cos 30 °) - (sin 60 °+cos60 °) |
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Answer» answer is 1 \xa0A n s w e r :=> (sin30+cos30) - (sin60+cos60)\xa0sin30 = 1/2\xa0sin60= √3/2\xa0cos30= √3/2\xa0cos60= 1/2\xa0=> (1/2+√3/2) - (√3/2+1/2)\xa0=> 1+√3/2 - √3+1/2\xa0=> 1+1+√3-√3 /2\xa0=> 2/2\xa0=>1 |
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| 35. |
Three numbers in A.P. have sum 24. The middle term is-(a) 6 (b) 8 (c) 3 (d) 2 |
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Answer» how can we consider 8 as a middle term can please give step by step explanation We will consider 8 as a middle term |
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| 36. |
22 ×5 |
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Answer» 110 110 110 110 110 |
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| 37. |
I want to buy this but in rs 200 |
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Answer» What\'s your question???Pls write properly.. What do you want to buy |
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| 38. |
Solve 2x+3y = 11 and 2x-4y=-24 and hence find the value of M for which y=Mx+3 |
| Answer» We have,2x + 3y = 11 ….(1)2x – 4y = – 24 ….(2)From (1), we have 2x = 11 – 3ySubstituting 2x = 11 – 3y in (2), we get11 – 3y – 4y = –24⇒ –7y = – 24 – 11⇒ –7y = – 35⇒ y = 5Putting y = 5 in (1), we get2x + 3 × 5 = 112x = 11 – 15⇒ x = –4/2 = – 2Hence, x = – 2 and y = 5Again putting x = – 2 and y = 5 in y = mx + 3, we get5x = m(–2) + 3⇒ –2m = 5 – 3⇒ m = – 1 | |
| 39. |
Sec²a/tan²a |
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| 40. |
Simplyfy the equation x*2 |
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| 41. |
if sum of a number and its square root is 90 find number |
| Answer» Let the positive square root be \'x\'The number is x^2x^2 +x = 90x^2+x-90=0x^2 +10x-9x-90= 0x(x+10)-9(x+10) =0X=9, x=-10x cannot be -10 because square root is positive number.there x = 9The number is 81.\xa0 | |
| 42. |
Bhai t.s. ka full form bata de yar |
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Answer» If u r asking about t.c. then it is transfer certificate. If not thenpls write your question again. from which book u r asking.can u tell me that |
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| 43. |
X3+Y3= ? |
| Answer» X³+Y³= (x+y) (x²-xy+y²) | |
| 44. |
Determine if the points (1,5),(2,3)and (-2,-11) are collinear ? |
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Answer» Determine if the points (1, 5), (2, 3) and (– 2, – 11) are collinear Let the given points be A( 1, 5), B(2, 3) and C(-2, -11). ThenHere, we see that AB + BC ≠ AC, BC + AC ≠ AB and AB + AC ≠ BC.Hence, the points A, B and C are not collinear. |
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| 45. |
Find the roots of following :X - 1/x =3 |
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| 46. |
TanA=1/root 5. Cosec^2A-Sec^2A/cosec^2A+sec^2A |
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| 47. |
0%0=? |
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| 48. |
Can anyone can send 2020 semester 1 paper |
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| 49. |
express 5005 as a product of its prime factors |
| Answer» 5005 = 5 × 7 × 11 × 13 | |
| 50. |
Ifα and β are the zeroes of the polynomial x²-3x+2,then the value of 1/α^2+1/β^2 ??? |
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