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Find the zeroes of the polynomial ?2 − 3 |
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Answer» x²-3= 0(x)²-(√3)²=0By using identity a²-b²=(a+b)(a-b)(x-√3)(x+√3)=0x-√3=0 or x+√3=0x=√3 or x=-√3 x2 - 3 = 0x2 - (\xa0√ 3)2 =0(x - √ 3) (x + √ 3)=0x - √ 3=0 and x + √ 3=0x = √3 and x = - √3 |
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