InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1701. |
Explain ex-1.1clearly |
| Answer» | |
| 1702. |
Show that square of any positive integer is in the form of 4q or 4q+1 |
| Answer» Very easy | |
| 1703. |
5q,5q+1 or 5q+4 |
| Answer» What to do | |
| 1704. |
find hcf225&135 |
| Answer» 45 | |
| 1705. |
Prove that 1/root 2 is irrational |
| Answer» Koi bhi maths ki book khol le sub main ye sum milega | |
| 1706. |
Prove that "Sum of two irrational numbers is a rational number " |
|
Answer» Let R and I are rational number and irrational number respectively.Assume that sum of R and I is a rational number and equal to P |
|
| 1707. |
X+2x+1=0 |
| Answer» X= -1/3 | |
| 1708. |
Do you like formala |
| Answer» | |
| 1709. |
prove that n³-n is divisible by 6 and n is any postive intergers |
| Answer» n3\xa0- n = n (n2\xa0- 1) = n (n - 1) (n + 1)\xa0Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2.∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer.If n = 3p, then n is divisible by 3.If n = 3p + 1, then n – 1 = 3p + 1 –1 = 3p is divisible by 3.If n = 3p + 2, then n + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1) is divisible by 3.So, we can say that one of the numbers among n, n – 1 and n + 1 is always divisible by 3.⇒ n (n – 1) (n + 1) is divisible by 3.\xa0Similarly, whenever a number is divided by 2, the remainder obtained is 0 or 1.∴ n = 2q or 2q + 1, where q is some integer.If n = 2q, then n is divisible by 2.If n = 2q + 1, then n – 1 = 2q + 1 – 1 = 2q is divisible by 2 and n + 1 = 2q + 1 + 1 = 2q + 2 = 2 (q + 1) is divisible by 2.So, we can say that one of the numbers among n, n – 1 and n + 1 is always divisible by 2.⇒ n (n – 1) (n + 1) is divisible by 2.Since, n (n – 1) (n + 1) is divisible by 2 and 3.∴ n (n-1) (n+1) = n3\xa0- n is divisible by 6.( If a number is divisible by both 2 and 3 , then it is divisible by 6)\xa0 | |
| 1710. |
What is the syllabus for IX and X ? |
| Answer» Whole book | |
| 1711. |
All formula in mansuratio |
| Answer» | |
| 1712. |
Maths class 10 paper hoga |
|
Answer» Nhi No |
|
| 1713. |
Solve for x and y ax +by =3ab & a^2x + b^2y = a+b |
| Answer» | |
| 1714. |
First chapter which will be studied in 11 in mathematics |
| Answer» | |
| 1715. |
Result declaration kab hai. |
|
Answer» Sorry it was for the upper ques From 16th of april . u don\'t have got the time table ? Depend on CBSE |
|
| 1716. |
Natural numbers |
| Answer» All positive integers are known as natural no. Example- 1,2,5,4,5 etc | |
| 1717. |
If the zeroes of polynomial x^2-5x+k are the resiprocal of each other, find the value of k??? |
| Answer» | |
| 1718. |
find the HCF of 196 and 38220 in detail |
| Answer» 38220=196×195+0so H.C.F.(196,38220) is196because divisor at this stage is196 | |
| 1719. |
Use Euclid division Lamba to find HCF of 870 and 225 |
|
Answer» 225 is hcf ? Let us take, a=870,b=225 870=225×3+195Now take, a=225,b=195 225=195×1+30Now take, a=195,b=30 195=30×6+15Now take, a=30,b=15 30=15×2+0 So, (HCF of 870 & 225)is 15 by Euclid division lamba |
|
| 1720. |
Highest common factor of 6 and 8 |
| Answer» 2 is the HCF of 6 & 8. | |
| 1721. |
It is very good did by CBSE by applying annual system ....... |
| Answer» | |
| 1722. |
Is it hard to take commerce with maths in 11 class |
| Answer» Depend on u | |
| 1723. |
Find zeroes of polynomial x2+1/6x+2, verify relationship between zeroes of above polynomial |
| Answer» | |
| 1724. |
baata 3456.7 +e235 kya hota hai |
| Answer» btate ni kiya bigadh lega | |
| 1725. |
5+4 |
|
Answer» 5+4=4+5 9 9 9 9 9 .e sala cup namde 9 |
|
| 1726. |
932>213 |
| Answer» Yes | |
| 1727. |
38220>196 find the hcf |
| Answer» By euclid lemma the hcf of 38220 ,196 is 196.A=bq+r | |
| 1728. |
Solve the following systems of equations:-√2x - √3y = 0√3x - √8y = 0 |
| Answer» | |
| 1729. |
√Ab=√a√b |
| Answer» | |
| 1730. |
Ex-3.4 Q1 |
| Answer» | |
| 1731. |
Uvb |
| Answer» | |
| 1732. |
2x+3y+5=03x-2y-12=0 |
|
Answer» What we have to find here? What exactly u want to know?? Can u please justify ur question |
|
| 1733. |
Show that n square- 1 divisible by 8 if n is positive odd integer |
| Answer» | |
| 1734. |
Algorithm |
| Answer» | |
| 1735. |
What are imaginary numbers |
| Answer» √-2 | |
| 1736. |
What is 10×7 |
| Answer» 70 | |
| 1737. |
If 15 tan square Φ + 4sec square Φ=23, then find the value of(sec Φ + cosecΦ)square -sin square Φ. |
| Answer» | |
| 1738. |
Find the number nearest to 110000 But greater than100000 which is exactly divisible by each 8,15,21 |
| Answer» L.C.M of 8, 15 and 21.8 = 2 {tex}\\times{/tex}\xa02 {tex}\\times{/tex}\xa0215 = 3 {tex}\\times{/tex}\xa0521 = 3 {tex}\\times{/tex}\xa07L.C.M of 8, 15 and 21 = 23{tex}\\times{/tex}\xa03 {tex}\\times{/tex}\xa05 {tex}\\times{/tex}\xa071= 840If we divide 110000 by 840, we will find out that it is not exactly divisible and we get 800 as remainder.Thus the number nearest to 110000 but greater than 100000 which is exactly divisible by 840 and also divisible by 8, 15 and 21 is = 110000 - 840 = 109200Hence 109200 is exactly divisible by 8, 15 and 21. | |
| 1739. |
Relationship between x and y if (1,2) (7,0) and (x,y) are colliner? |
| Answer» 2X+6Y=13 | |
| 1740. |
1,12,18,25,?,52 |
| Answer» | |
| 1741. |
Find the coordinate of the poibt on y-axis whuch is nearest to the point |
| Answer» The point on y-axis that is nearest to the point(-2,5) is (0,5). | |
| 1742. |
1÷sinA= |
| Answer» Cosec A | |
| 1743. |
In figure ab=5 3cm,dc=4cm and bd=3cm .find.α |
| Answer» | |
| 1744. |
What is transportation |
| Answer» Transportation is the movement of humans, animals and goods from one location to another. | |
| 1745. |
What is AP mean |
| Answer» arithmetic progression | |
| 1746. |
Chapter AP exercise 5.4 question number 3 |
| Answer» Check NCERT Solutions here :\xa0https://mycbseguide.com/ncert-solutions.html | |
| 1747. |
What is cirlce |
| Answer» A circle is a simple closed shape. It is the set of all points in a plane that are at a given distance from a given point, the centre, equivalently it is the curve traced out by a point that moves so that its distance from a given point is constant. | |
| 1748. |
Date sheet of class 10th 2018 examinations |
| Answer» Check datesheet of examination here :\xa0https://mycbseguide.com/cbse-datesheet.html | |
| 1749. |
If 4m+8,2m²+3m+6 & 3m² + 4m +4 are 3 concecutive terms of an AP. Find m. |
| Answer» First term = 4m+8Second term =\xa0{tex}2m^2+3m+6{/tex}Third term =\xa0{tex}3m^2+4m+4{/tex}Common Difference d = second term - first termd =\xa0{tex}(2m^2+3m+6) - (4m+8){/tex}d =\xa0{tex}2m^2-m-2{/tex}Common Difference = third term - second term\xa0d =\xa0{tex}(3m^2+4m+4)-(2m^2+3m+6){/tex}d =\xa0{tex}m^2+m-2{/tex}So,\xa0{tex}2m^2-m-2 = m^2+m-2{/tex}{tex}m^2-2m=0{/tex}m(m-2)= 0This gives m= 0 and m-2=0m=0 or m=2\xa0 | |
| 1750. |
2/2 |
| Answer» The answer is 1. | |