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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 38101. |
Root over of 1 + Cos a upon root over of 1 - cos a |
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| 38102. |
How to solve 1-64/113/1-49/113 |
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Answer» 21/16 -63/ 113 × 113/-48 = -63 / -48 = 63/48 = 21/16 |
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| 38103. |
What are the methods of quadratic equation |
| Answer» Method of solving quadratic equation - Factoring, Completing square method, graphical method , quadratic formula a | |
| 38104. |
Find the discriminant of the quadratic equation 3x²-4x-2=0 |
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Answer» D= b^2 - 4ac = (-4)^2 - 4×3(-2) = 16+24 = 40 2√(-2) |
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| 38105. |
Plz answer quick |
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Answer» ? Question❔❔❔ |
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| 38106. |
2πr+d=perimeter of ___________ |
| Answer» triangle | |
| 38107. |
The total surface area of given solid figure is |
| Answer» Where is the figure?? | |
| 38108. |
152x-378y =-74-378x+152y = -604Solve for x and y by elimination method |
| Answer» The given equations are{tex}152x - 378y = -74{/tex} ...(i){tex}-378x\xa0+ 152y = -604{/tex}. ... (ii)Clearly, the coefficients of x\xa0and y in one equation are interchanged in the other.Adding (i) and (ii), we get{tex}(152-378)x\xa0+ (-378 +152) y = -(74 + 604){/tex}{tex}\\Rightarrow{/tex}\xa0{tex}(-226)x\xa0+ (-226)y = -678{/tex}{tex}\\Rightarrow{/tex}\xa0{tex}(-226)(x + y) = -678{/tex}{tex}\\Rightarrow \\quad ( x + y ) = \\frac { - 678 } { - 226 } \\Rightarrow x + y = 3{/tex}. ...(iii)Subtracting (ii) from (i), we get{tex}(152 + 378) x + (-378 - 152)y = (-74 + 604){/tex}{tex}\\Rightarrow{/tex}530x\xa0- 530y = 530{tex}\\Rightarrow{/tex}\xa0530(x - y) = 530 {tex}\\Rightarrow{/tex}\xa0x\xa0- y = 1. ... (iv)Adding (iii) and (iv), we get 2x = 4 {tex}\\Rightarrow{/tex}\xa0x = 2.Subtracting (iv) from (iii), we get2y = 2 {tex}\\Rightarrow{/tex} y = 1.Hence, x = 2 and y = 1 | |
| 38109. |
What is 24 carat gold? How will you convert it into 18 carat gold? |
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Answer» My pleasure Thanks secret girl I hope u got ur answer..... ☺ 24 carat gold is pure gold. Pure gold is very soft and not suitable for making jewellery. Therefore, to increase it\'s hardness , it is alloyed either with copper or silver. 18 carat gold is prepared by alloying 18 parts pure gold with 6 parts of either cooper or silver. Pure gold is defined as 24 carats or having a fineness. 24 carat gold means pure gold means 24 of 24parts of alloy is gold making it pure gold. This is a science ques. |
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| 38110. |
What is the area of cuboid? |
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Answer» Happy Birthday Deepika ji Right lucky... ?? Total surface area of cuboid=2( lb+bh+hl ) |
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| 38111. |
Divide x³+x²+3 |
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Answer» Isko tu hi karke bata de Bhai divide kisse krenge with what shud u divide |
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| 38112. |
Which guide is better for class10 English Hindi math science |
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Answer» Arihant or ncert You can take:English- all in one,maths-rs aggarwal or rd sharma and Science- dinesh publications...... |
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| 38113. |
a/x-a +b/x-b =2c/x-c |
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| 38114. |
2^m5^n(m,n£N)ends with...... |
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| 38115. |
1/a, 1/b,and 1/c are in AP show that b+b/a , c+c/a and a+b/c are also in AP |
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| 38116. |
Easy explanation of substitution |
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Answer» Substitution means subsituting the value of one variable in the other equation to find the value of other variable. For example :x+y=2 .......(1)x-y=3. ..........(2)We can write equation (2) as x=3+y. ........(3)Now put the value of x in eq. (1)x+y=2(3+y)+y=23+2y=22y=2-3y=-1/2Substituting value of y in equation 2x-y=3x-(-1/2)=3x+1/2=32x+1/2=32x+1=62x=5x=5/2Hence we get value of x and y by substituting value of x to find the value of y. Substitution is itself so easy. |
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| 38117. |
Y= √x+2√x+2√...... |
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| 38118. |
Y = √1+2√1+2√1+2√.... |
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| 38119. |
Prove that 0/0=equal to 2HOW?? |
| Answer» never | |
| 38120. |
Which book we read during board exam except ncert |
| Answer» Full marks guide | |
| 38121. |
Make graph for (x^2+1)&(x^3+1) |
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| 38122. |
ax +by = cbx + ay = 1+ cBy elimination method |
| Answer» The given pair of equations isax + by = c ...(1)bx + ay = 1 + c ...(2){tex}\\Rightarrow{/tex} ax + by - c = 0 ...(3){tex}\\Rightarrow{/tex} bx + ay - (1 + c) = 0 ...(4)To solve the equations by the cross multiplication method, we draw the diagram below:Then,{tex}\\frac{x}{{(b)( - (1 + c)) - (a)( - c)}}{/tex}{tex} = \\frac{y}{{( - c)(b) - ( - (1 + c))(a)}}{/tex}{tex} = \\frac{1}{{(a)(a) - ({b})(b)}}{/tex}{tex}\\Rightarrow \\frac{x}{{ - b - bc + ac}} = \\frac{y}{{ - bc + a + ac}} = \\frac{1}{{{a^2} - {b^2}}}{/tex}{tex} \\Rightarrow x = \\frac{{ - b - bc + ac}}{{{a^2} - {b^2}}}{/tex}{tex}y = \\frac{{ - bc + a + ac}}{{{a^2} - {b^2}}}{/tex}Hence, the solution of the given pair of linear equations is{tex}x = \\frac{{ - b - bc + ac}}{{{a^2} - {b^2}}},\\;y = \\frac{{ - bc + a + ac}}{{{a^2} - {b^2}}}{/tex}Verification, Substituting{tex}x = \\frac{{ - b - bc + ac}}{{{a^2} - {b^2}}},\\;y = \\frac{{ - bc + a + ac}}{{{a^2} - {b^2}}}{/tex}We find that both the equations (1) and (2) are satisfied as shown below:ax + by {tex} = a\\left( {\\frac{{ - b - bc + ac}}{{{a^2} - {b^2}}}} \\right) + b\\left( {\\frac{{ - bc + a + ac}}{{{a^2} - {b^2}}}} \\right){/tex}{tex} = \\frac{{ - ab - abc + {a^2}c - {b^2}c + ab + abc}}{{{a^2} - {b^2}}} = c{/tex}bx + ay {tex}= b\\left( {\\frac{{ - b - bc + ac}}{{{a^2} - {b^2}}}} \\right) + a\\left( {\\frac{{ - bc + a + ac}}{{{a^2} - {b^2}}}} \\right){/tex}{tex}= \\frac{{ - {b^2} - {b^2} + abc - abc + {a^2} + {a^2}c}}{{{a^2} - {b^2}}}{/tex}This verifies the solution. | |
| 38123. |
S-t=3 solve by substitute method |
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Answer» Either this question is wrong or this is solved by any value of s or t It can\'t be solved |
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| 38124. |
Solve the pair of linear equation37x+43y=123,43x+37y=117 |
| Answer» The given equations are37x\xa0+ 43y = 123 ... (i)43x\xa0+ 37y = 117. ... (ii)Clearly, the coefficients of x\xa0and y in one equation are interchanged in the other.Adding (i) and (ii), we get(37x\xa0+ 43y) + (43x\xa0+ 37y) = 123 + 117(37 + 43)x+ (43 + 37)y = (123 +117){tex} \\Rightarrow{/tex}80x + 80y = 240{tex} \\Rightarrow{/tex}80(x\xa0+ y) = 240{tex} \\Rightarrow{/tex} x + y = 3 ....... (iii)Subtracting (i) from (ii), we get(37x\xa0+ 43y) - (43x\xa0+ 37y) = 123 - 1176x\xa0-\xa06y = -6{tex}\\Rightarrow{/tex}\xa06 (x - y) = -6{tex}\\Rightarrow{/tex}\xa0x\xa0- y = -1\xa0... (iv)Adding (iii) and (iv), we get(x + y) + (x - y) = 3 + (-1){tex}\\Rightarrow{/tex} x + y + x - y = 2{tex}\\Rightarrow{/tex} 2x\xa0= 2{tex}\\Rightarrow{/tex}\xa0x\xa0= 1.Subtracting (iv) from (iii), we get(x + y) - (x - y) = 3 - (-1){tex}\\Rightarrow{/tex}x + y - x + y = 4{tex}\\Rightarrow{/tex}2y = 4{tex}\\Rightarrow{/tex} y = 2.Hence, x\xa0= 1 and y = 2. | |
| 38125. |
Explain why 7×11×13+13 and 7×6×5×4×3×2×1+5 are composite number. (Real numbers) |
| Answer» Numbers are of two types - prime and composite.Prime numbers can be divided by 1 and only itself, whereas composite numbers have factors other than 1 and itself.It can be observed that7 × 11 × 13 + 13 = 13 × (7 × 11 + 1)= 13 × (77 + 1)= 13 × 78= 13 ×13 × 6The given expression has 6 and 13 as its factors.Therefore, it is a composite number.7 × 6 × 5 × 4 × 3 × 2 × 1 + 5= 5 ×(7 × 6 × 4 × 3 × 2 × 1 + 1)= 5 × (1008 + 1)= 5 ×10091009 cannot be factorized furtherTherefore, the given expression has 5 and 1009 as its factors.Hence, it is a composite number. | |
| 38126. |
a,a2,a3,a4To find common difference |
| Answer» 2a-a= a so, the common difference between each no. is [a] ( II - I)=( IV - III) | |
| 38127. |
how we can study maths more easily ??? |
| Answer» By practicing | |
| 38128. |
Why we cant have common factors in √5 |
| Answer» Root 5 is irrational because irrational has no common factors | |
| 38129. |
What is positive or negative integer\'s |
| Answer» -2 ,-3 etc are negative whereas 1,2,3 etc are positive integers | |
| 38130. |
Slove the pair of linear equationpx+qy=p_qqx_py=p+q |
| Answer» The given pair of equations ispx + qy = p - q .....(1)qx - py = p + q ....(2)Multiplying equation (1) by p and equation (2) by q, we getp2x + pqy = p2 - pq....(3)q2x - pqy = pq + q2.....(4)Adding equation (3) and equation (4), we get(p2 + q2)x = p2 + q2{tex}\\Rightarrow \\;x = \\frac{{{p^2} + {q^2}}}{{{p^2} + {q^2}}} = 1{/tex}Substituting this value of x in equation (1), we getp(1) + qy = p - q{tex}\\Rightarrow{/tex} qy = -q{tex}\\Rightarrow \\;y = \\frac{{ - q}}{q} = - 1{/tex}So, the solution of the given pair of linear equations is x = +1, y = -1.Verification, Substituting x = 1, y = -1,We find that both the equations (1) and (2) are satisfied as shown below:px + qy = p(1) + q(-1) = p - qqx - py = q(1) - p(-1) = q + p = p + qThis verifies the solution. | |
| 38131. |
g(s)=4s |
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| 38132. |
Prove that root8 is irrational |
| Answer» Let root 8be a rational no. So it can be written asRoot8=a/b {where a and b are co prime and rational}Squaring both side (root8) ^2=(a/b)^28=a^2 /b ^28b^2=a^2.....(1)Since 8 divides a^2, Then it divides a alsoFor some integer c8c=aPut the value of a=8c in equation (1)So,8b^2 = 64c^2B^2 =8cSince 8divides b^2Then it also divides bThat means a and b have 8 as common factor other than 1..that means a and b are not co-primeThis contradiction arises because of wrong assumption Hence root 8 is an irrational number. | |
| 38133. |
What Is the quadratic equation of x+a x + y |
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| 38134. |
If sin a√3/2 then find the value of sin 3a |
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| 38135. |
Find zeros of x cube -19 X + 30 |
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| 38136. |
Show that √6 is a irrational? |
| Answer» if a is even and b is even, then they have a common divisor (2). Then our initial assumption must be false, so the square root of 6 cannot be rational. There you have it: a rational proof of irrationality | |
| 38137. |
Please give me syllabus of annual |
| Answer» | |
| 38138. |
135 and 255 find the hcf |
| Answer» 15 | |
| 38139. |
x2-2x-8 |
| Answer» x2 - 4x +2x - 8 x(x-4) + 2 (x-4)(x+2) (x-4)Hence x = -2 , 4 | |
| 38140. |
0÷0=2,prove it |
| Answer» We can write 0/0 =100 -100/100 -100 =(10×10-10×10)/10 (10-10) =(10+10)(10 +10)/10 (10+10) =20/10 =2Hence proved | |
| 38141. |
Why do we study trignometry what is the application of this and where it is used? |
| Answer» You will find this Ans in net | |
| 38142. |
The sum of two rational no is -2. if one of them is 7,Find the other. |
| Answer» Other number is -9 | |
| 38143. |
Solve the following pair of linear equation by the substitution method x+y =14 and x_y=4 |
| Answer» X=8 & y=6 | |
| 38144. |
2 - 2 |
| Answer» 0 | |
| 38145. |
Find the coordinates of the point which divides the join of (-1,7)and(4,-3)in the ratio 2:3. |
| Answer» Let the coordinates of the required point be (x, y). Then,{tex}x = \\frac{{{m_1}{x_2} + {m_2}{x_1}}}{{{m_1} + {m_2}}}{/tex}{tex}= \\frac{{(2)(4) + (3)( - 1)}}{{2 + 3}}{/tex}{tex}= \\frac{{8 - 3}}{5} = \\frac{5}{5} = 1{/tex}{tex}y = \\frac{{{m_1}{y_2} + {m_2}{y_1}}}{{{m_1} + {m_2}}}{/tex}{tex} = \\frac{{(2)( - 3) + (3)(7)}}{{2 + 3}}{/tex}{tex} = \\frac{{ - 6 + 21}}{5} = \\frac{{15}}{5} = 3{/tex}Hence, the required point is (1, 3). | |
| 38146. |
Is half yearly exam will be or notOnly final exam |
| Answer» Only final exam will be evaluated but school can take periodic tests and compress them to specific limit. | |
| 38147. |
Prove that X^ 0= 1 |
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| 38148. |
Value of Alpha - beta |
| Answer» 23 | |
| 38149. |
1+tanA/2 /1-tanA/2=secA+tanA prove that |
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| 38150. |
How many shape |
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Answer» Countless ..................... Many shapes ...... |
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