Saved Bookmarks
This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
\frac { x ^ { 3 } + 12 x } { 6 x ^ { 2 } + 8 } = \frac { y ^ { 3 } + 27 y } { 9 y ^ { 2 } + 27 } \cdot \text { Using componendo, find } x ; y |
| Answer» | |
| 2. |
AP 7, 13, 19, ... 205 में कितने पद हैं। जे |
| Answer» | |
| 3. |
The unit digit in the product (784 x 618 x 917 x 463) is:a) 2(b) 3(c) 4 |
| Answer» | |
| 4. |
81.If 618 + 418 is divided by 50, then remainder is(2) 2(4) 4(3) 3 |
|
Answer» 1 answercyclic nature |
|
| 5. |
11 Find the least number which must be added to eadkfollowing numbers so as to get a perfect square. Afind the square root of perfect square so obtained. (A)S(i) 525v 1825(ii) 1750(iii) 252(v) 6412 |
| Answer» | |
| 6. |
0) 7, 13, 19,..., 205AP, 11, 8, 5, 2 . . . |
| Answer» | |
| 7. |
Q. 3. Find the number of terms in each of the following A.P.:(i) 7, 13, 19, 205so |
| Answer» | |
| 8. |
Which term of A. P. 7, 13, 19is 205? |
|
Answer» a = 7 d = 13 - 7 = 6 nth term = a + (n-1)d 205 = 7 + (n-1)6 (n-1)6 = 198 n-1 = 33 n = 34 34th term is 205 If you find this answer helpful then like it. |
|
| 9. |
5.Find the number of terms in each of the following APs:0 7, 13, 19,..., 205(i) 18, 15,13,... |
| Answer» | |
| 10. |
Which term of the AP: 3, 8, TFind the number of terms in each of the following7, 13, 19,...205frrm of the AP: 11, 8 |
|
Answer» no then what is the answer |
|
| 11. |
-36*x*y %2B x^3 - 8*y^3 - 216 |
| Answer» | |
| 12. |
1000*a^3 %2B 27*b^6 |
|
Answer» 1000a^3 + 27b^6 = (10a)^3 + (3b^2)^3 Now using identity,a^3 + b^3 = (a + b) (a^2 - ab + b^2) = (10a + 3b^2)[(10a)^2 - 10a*3b^2 + (3b^2)^2] = (10a + 3b^2)(100a^2 + 30ab^2 + 9b^4) I am post photo witt |
|
| 13. |
-45*a^4*b^2 %2B 27*(a^3*b^3) |
|
Answer» 27a³b³-45a⁴b² =9a²b²(3ab-5a²) =9a³b²(3b-5a) |
|
| 14. |
\begin{array} { l } { \text { Given } x = \frac { \sqrt { a ^ { 2 } + b ^ { 2 } } + \sqrt { a ^ { 2 } - b ^ { 2 } } } { \sqrt { a ^ { 2 } + b ^ { 2 } } - \sqrt { a ^ { 2 } - b ^ { 2 } } } } \\ { \text { Use componendo and dividendo to prove that: } } \\ { b ^ { 2 } = \frac { 2 a ^ { 2 } x } { x ^ { 2 } + 1 } } \end{array} |
| Answer» | |
| 15. |
36*(a*b^2) - 54*a^2*b %2B 27*a^3 - 8*b^3 |
| Answer» | |
| 16. |
4 ( a ^ 2 - \frac 2 3 b ^ 2 ) ( \frac 3 4 a ^ 2 %2B 3 b ^ 2 ) |
| Answer» | |
| 17. |
a) How many non-square numbers are there between 132 and 1423 |
|
Answer» so, there are27 non square numbersbetween 13² and 14². |
|
| 18. |
b^2 - 2*a*b %2B b^2 - a*b %2B a^2 %2B b^2 |
|
Answer» = (a²+b²–ab+b²–2ab+b²) = a²+b²–ab+b²–2ab+b²= a²+3b²–3ab= a²+3b(b–a) answer...... |
|
| 19. |
(a %2B b)^2 %2B (a %2B b)^2 |
|
Answer» (a + b)^2 + (b + a)^2 = 2(a + b)^2 = 2(a^2 + b^2 + 2ab) = 2a^2 + 2b^2 + 4ab |
|
| 20. |
-2*a*b(-a %2B b) %2B 6*(a^2*(-b^2 %2B b)) - 3*b^2*(2*a^2 - a) |
| Answer» | |
| 21. |
-4*a^2*b^2 %2B (-4*c^2 %2B a^2 %2B b^2)^2 |
|
Answer» (a^2 + b^2 - 4c^2)^2 - 4a^2b^2 [using a^2 - b^2 = (a + b)(a - b)] = (a^2 + b^2 - 4c^2 + 2ab)(a^2 + b^2 - 4c^2 - 2ab) = [(a + b)^2 - 4c^2][(a - b)^2 - 4c^2] = (a + b + 2c)(a + b - 2c)(a - b + 2c)(a - b - 2c) |
|
| 22. |
(a %2B b)^2=b^2 %2B a^2 %2B 2*(a*b) |
|
Answer» (a+b)^2=(a+b)(a+b)=a^2+b^2+ab+ab=a^2+b^2+2ab |
|
| 23. |
In Δ ABC, right-angled at B, AB-24 cm, BC-7 cm. Determine0) sin A, cos A(Gi) sin C, cos C |
| Answer» | |
| 24. |
. Findthe number of terms in each of the following APs:0 7, 13, 19,, 205(Gi) 18, 1513,2 |
| Answer» | |
| 25. |
a) 576 x 70 (b) 618 x 216(c) 573 x 47We know that 0 x 0 -0. Is there any other whole number which when multiplied by itself, giqual of the number itself? What is that number? |
|
Answer» 0×0=0Similarly1×1=1Thus the 1 when multipled by itself is equal to the number itself 0×0=0Similarly,1×1=1.Hence the answer is 1×1=1 |
|
| 26. |
5 :2400 का 5/8 का 74% क्या होगा! |
|
Answer» 2400×5/8=1500now,1500×74/100=15×74= 1110(ans). |
|
| 27. |
what will be added to 700 to get 2400 |
|
Answer» first to be substract 2400-700 = 1,7001,700+700 get 2400 first you have to subtract 2400 from700=2400-700=1,700 so on adding 1,700 by 700 you will get 2,400 1700 had to be added to get 2400 to 700 1700 is the best answer🏆🏆🏆 2400-700=17001700+700=24001700 Answer.... |
|
| 28. |
13. For what value of *,*° - 2x2 - 2x - 3 and*? - 2x - 3 becomes equal to zero?(a) 3(d) 1(6) 4(c) |
|
Answer» x^2 - 2x - 3 = 0x^2 - 3x + x - 3 = 0x(x - 3) + 1(x - 3) = 0(x +1)(x - 3) = 0 x^3 - 2x^2 - 2x - 3 = 0x^3 - 3x^2 + x^2 - 3x + x - 3 = 0x^2(x - 3) + x(x - 3) + 1(x - 3) = 0(x - 3)(x^2 + x + 1) = 0 As both the equations have common zero 3. Therefore for x = 3 both given equations will be equal to 0. (a) is correct option |
|
| 29. |
48*(a*b) - (4*a - 3*b)^2 %2B (4*a %2B 3*b)^2 |
|
Answer» (4a + 3b)^2 - (4a - 3b)^2 + 48ab = 16a^2 + 9b^2 + 24ab - (16a^2 + 9b^2 - 24ab + 48ab = 16a^2 + 9b^2 + 24ab - 16a^2 - 9b^2 + 24ab + 48ab = 48ab + 48ab = 96ab 96ab is the correct answer of the given question using identities of (a+b)^2 and (a-b)^2 ok and get 24ab+24ab and + with 48ab and 96ab is final ans96ab |
|
| 30. |
64*a^3 %2B 27*(b^3*(b*y(4*a %2B 3*b))) |
| Answer» | |
| 31. |
-b^3 %2B 3*(a*b^2) %2B a^3 - 3*a^2*b |
|
Answer» (a-b)^3 this is the answer |
|
| 32. |
51.Simplify:(+(40° +36-6) |
|
Answer» -(3 + (40^2 + 9^2)^1/2) + (3 of 6 - 6) = - (3 + (1600 + 81)^1/2) + (3*6 - 6) = - (3 + (1681)^1/2) + (18 - 6) = - (3 + 41) + 12 = - 44 + 12 = - 32 |
|
| 33. |
8*(b^3*b^3) %2B 12*(a*b^2) %2B a^3 %2B 6*(a^2*b) |
|
Answer» (a+2b)^3 is the simplified version of this equation |
|
| 34. |
-5*b - 5*a %2B (a %2B b)^2 %2B 6 |
|
Answer» (a+b-3) (a+b-2) solution |
|
| 35. |
2. How many non perfect square numbersaretherebetween15^2 and16^2 |
| Answer» | |
| 36. |
TRY THESEI. Find the perfect square numbers between (i) 30 and 40 (ii) 50 and 60 |
| Answer» | |
| 37. |
1) 4024000Find the lcast number which must be added to each of the following numbersto get a perfect square. Also find the square root of the perfect square so oblains0 525Gi) 1750(ii) 252(rv) 1825 |
| Answer» | |
| 38. |
drequalsx logx |
| Answer» | |
| 39. |
= 2400 + 1200 = |
|
Answer» 2400 + 1200 equals to 3600 3600 is the answer of this question |
|
| 40. |
explain the using identi(3x+2y+4z)² |
| Answer» | |
| 41. |
3. The numerator of a fraction is 6 less than the denominator. If 3 is added to thenumerator, the fraction becomes equal to Find the original fraction. |
|
Answer» Suppose numerator is x-6sox-6/xnowx-6+3/x= 2/3x-3/x= 2/33x-9= 2xx= 9x-6= 3 Let denominator=xNumerator=x-6If 3 is added to numeratorFraction=x-6+3/x =x-3/x = 2/3 =(x-3)3/2x =3x-9/2x Or,3x-9=2x 3x-2x=9 X=9So fraction=numerator/denominator=x-6/x=9-6/9=3/9=1/3 |
|
| 42. |
4z+3=6+2z |
|
Answer» Ans :- 4z + 3 = 6 + 2z 4z - 2z = 6 - 3 2z = 3 z = 3/2 |
|
| 43. |
(i) (x+ 2y +4z) |
| Answer» | |
| 44. |
5. Find the solution set of inequation21.1⏠R. |
| Answer» | |
| 45. |
(a+b)^{2}-5 a-5 b+6 |
|
Answer» (a + b)² - 5a - 5b + 6(a + b)² - 5 ( a + b) + 6(a + b) ( a + b - 5) +6 |
|
| 46. |
( a + b ) ^ { 2 } - 5 a - 5 b + 6 |
| Answer» | |
| 47. |
3 a %2B 5 b = 26 ; a %2B 5 b = 22 |
|
Answer» 3a+5b=26...........13a+15b=66.........2 subtracting eqn 1 and 210b= 40b=4 3a+20=263a=6a=2 |
|
| 48. |
divide rupees 3000 into two parts such that the simple interest on the first part for 4 years at 8% per annum is equals to the simple interest on the second part for 2 years at 9% per annum |
|
Answer» where you live and study in which school. sorry I've send this by mistake. |
|
| 49. |
Find the solution set and represent it on a number line |
|
Answer» PLEASE HIT THE LIKE BUTTON |
|
| 50. |
30% of income of 'A' is equals to 20% of 3/5 ofB'S income is Rs 2400/- then find A's income. |
| Answer» | |