This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(xii) 8760057(xiv) 99395055(xv) 100001010x for which the number 71x is divisible by 3. Also.Find all the possible values ofsuch numbers |
|
Answer» when a number is divisible by 3 then sum of digits must be divisible by 3.so here 71x = 7+1+x = 8+x = so possible of x are 1, 4, 7. |
|
| 2. |
Example 1 : A picnic is being planned in a school for Class Vâ Ą. Girls are 60% of thetotal number of students and are 18 in number. |
| Answer» | |
| 3. |
(v) (2 kg 250 g): (3 kg) |
|
Answer» As 1 kg = 1000g 2 kg 250 g = 2250 g 3 kg= 3000g Ratio = 2250:3000=3:4 ( HCF of 2250 and 3000 is 750) |
|
| 4. |
/=6 XV-6 =7 |
|
Answer» -6 |
|
| 5. |
Out of 3000 students in a school, 2400 went for the picnic. Find the percentage of students who did nogo for picnic? |
|
Answer» a man income is ₹ 960 it saves 25 how much does he saves |
|
| 6. |
2. Out of 3000 students in a school, 2400 went for the picnic. Find the percentage of students who did nogo for picnic? |
|
Answer» No of students in school 30000No of students went for picnic 24000no of students didn't go 6000percentage of students 6000/30000*100= 20% |
|
| 7. |
Out of 3000 students in a school, 2400 went for the picnic. Find the percentage of students who did notgo for picnic?2. |
|
Answer» total students 30000Students went for picnic 24000Students didn't go for picnic 6000Percentage of students who didn't go for picnic 6000/30000*100= 20% thanks |
|
| 8. |
5 children of a school have to go on a picnic. They have to go by buses in each ofwhich only 22 children can travel. How many buses will be needed?9. 30 |
|
Answer» To find this divide the number of childrenhence 305/22=13.86Hence nearest whole number is 14 hence 14 buses are required. |
|
| 9. |
In a battle 70% of the combatants lost one eye, 80% an ear,75% an arm, 85% a leg, x% lost all the four limbs. Theminimum value of x is |
|
Answer» Let us start with 70% who lost one eyeConsider 80% lost one ear.This means 20% did not lose one ear.Suppose this 20% all lost one eye as well.This means 70% - 20% = 50% lose one eye and one leg Consider 75% lost arm next.This means 25% did not lose arm.Suppose this 25% all lose one eye and one ear.This means 50% - 25% = 25% lose ear, one eye and one arm Consider 85% lost a legThis means 15% did not lose leg.Suppose this 15% all lose ear, one eye and one arm.This means 25% - 15% = 10% lost all 4 limbs.Now, it is given that x% lost all four limbs. So, x=10 |
|
| 10. |
In a battle 70% of the combatants lost one eye, 80% an ear,75% an arm, 85% a leg, x% lost all the four limbs. Theminimum value of x is(a) 10(c) 15(b) 12(d) none of these |
| Answer» | |
| 11. |
(zg+ x - fig) - xv âT |
|
Answer» 4x - (3y - x + 2z) = 4x - 3y + x - 2z = 5x - 3y - 2z If you find this answer helpful then like it. |
|
| 12. |
a toge lag ClogsXXV |
| Answer» | |
| 13. |
Wi x1000Mg xVHIRA M = |
| Answer» | |
| 14. |
(v) (2 kg 250 g) : (3 kg) |
|
Answer» As 1 kg = 1000g 2 kg 250 g = 2250 g 3 kg= 3000g Ratio = 2250:3000=3:4 ( HCF of 2250 and 3000 is 750) |
|
| 15. |
Q.1) Find the value of V (5-2A) 1/25(B) 5 (C) 0.5(D) 0.2 |
| Answer» | |
| 16. |
is the centre of the circle.IOAB 40° and 2OCB 30, find ZAOC.(i) In Figure (2), A, B and Carethree points on the circle withcentre O such that ZAOB 90and CAOC = 110". FindZBAC. B- 90-Ita |
| Answer» | |
| 17. |
X. Evaluate v(-25) xV(-49). |
|
Answer» √(-25)*√(-49) = 5i*7i = 35i² We know i² = -1 = -35 Like my answer if you find it useful! |
|
| 18. |
2. Find the value of :(1) -53 - (-23)(iii) 176 + (-323) + (-176) + 123(v) - 25 + 35 + (-10) - (- 65).(ii) 20-12-25(iv) - 16-(-28) - (-70) - 82croond.879. |
|
Answer» 1) -53+23=30 2)20-12-25=8-25=-17 (i)=30(ii)=-17(iii)=-200(iv)=0(v)=65 0 -200 65 -170 |
|
| 19. |
An integer from 100 through 999, inclusive, is to bechosen at random. What is the probability that thenumber chosen will have 0 as at least 1 digit?A 19/900B.81/900C. 90/900D.171/900E.271/1,000 |
|
Answer» Option D |
|
| 20. |
The sum of two rational numbers is 2. If one of the numbers is -, find the other. |
| Answer» | |
| 21. |
. The product of two rational numbers isIf one of the-3518numbers is ,find the oser.12 |
|
Answer» (5/12)x=-35/18x=-14/3 |
|
| 22. |
3. The product of two rational numbers is 0. Ifone of the numbers is find the other. |
|
Answer» let number be x. then x*7/8=0x=0 |
|
| 23. |
29) ABCD is a square, if<PQR= 90° and PBQCDR, Prove that QBRCPQ = QR and QPR = 450 |
| Answer» | |
| 24. |
15The sum of two rational numbers is 8. If one of the numbers is, find the other. |
|
Answer» Pura |
|
| 25. |
3. The product of two rational numbers is -16 If one of the numbers isfind the other. |
| Answer» | |
| 26. |
22. In the given figure if ABProve that BQ-QC.AC then |
| Answer» | |
| 27. |
(i) Which one of the following is an irrationalnumber?16(A)(B) 5 (C) D196V 25 |
| Answer» | |
| 28. |
13. The curved surface area of a (、linder is 4400 cm2 and the circumferenceof its base is 110 cm. Find the height and the volume of the cylinder |
| Answer» | |
| 29. |
109. The curved surface area of a cylinder is 4400 cm2 and the circumference of its base is 110 cm. Find thevolume of thę cylinder. |
| Answer» | |
| 30. |
The curved surface area of a cylinder is 4400 cm2 and the circumferenceof its base is 110 cm. Find the height and the volume of the cylinder |
| Answer» | |
| 31. |
in a school of 1500 student 900 are girls find the ratio of boys to all the students? |
| Answer» | |
| 32. |
The curved surface area of a cylinder is 4400 cmsquare and the circumference of its base is 110 cm. Find the height and the volume of the cylinder. |
|
Answer» Galat Hai bhai |
|
| 33. |
9 The area of the curved surface of a cylinder is 4400 cm2, and the circumienence of isbase is 110 cm. Find(0 the height of the cylinder(ai) the volume of the cylinder. |
| Answer» | |
| 34. |
terms of an A.P4. In the given figure, two line segments AC and BD intersecteach other at the point P such that PA 6 cm, PB 3 cm,PC = 2.5 cm, PD = 5 cm, LAPB 50° and <CDP-300,then find the measure of ZPBA. |
| Answer» | |
| 35. |
70% of the students in a school are boys and the number of girls is 504, Finboys in the school., |
| Answer» | |
| 36. |
19. Find one rational numbers between |
| Answer» | |
| 37. |
A triangle having sides a, b and c. Ifs-a 4 cm, s-ibb and c.Find one rational and one irrational number between 2 anSimplify: (5+v7)(2+v5 |
|
Answer» (5+√7)(2+√5)=10+2√7+5√5 +√35 |
|
| 38. |
70% ofthe students in a school are boys and the number of girls is 540, find the number of boys injhe school? |
| Answer» | |
| 39. |
P and Q are points on sides AB and AC re-spectively of A ABC. If AP 3 cm, PB-6em, AQ 5 cm and QC 10 cm, show thatBC 3PQ |
| Answer» | |
| 40. |
xpress 8232 as produci cf iis prime factors. |
| Answer» | |
| 41. |
Check whether ( Iis a fuctor of the polynomial. xx +x-5x,Justily your answer |
|
Answer» thanks |
|
| 42. |
HINT: A sDUn an examination 17% of the students fail, what percentage o students paae? Howany students will pass if 900 students sppear in the examination? |
|
Answer» 17% students failed so 83% students passednow total 900 so passed students are (900×83)/100=747 |
|
| 43. |
ACISE -1.uclid's algorithm to find the HCF ofOand 270 (ii) 196 and 38220 (iii)ithm to show that any positive od |
|
Answer» 38220 =196*195 +0 Hence, HCF of 196 and 38220 =196. |
|
| 44. |
अकरानैटिस गुणन का प्रयोग करके निम्नलिखित मेंक) 136 x 115घ) 385 x 122- विक्ष |
|
Answer» i) 136 x 115=15,640, iii) 385 x 122 = 46, 970 136 × 115-------- 680+ 1360+13600-------- 15640 385×122-------- 770+ 7700+38500---------- 46970 1564046970 is the correct answer of the given 136×115=15640385×122=46970 136×115----------15640 385×122---------46970 1ans-365×115-15640 2ans-385×122-46970 1.ans=156402.ans=46970 1st question answer is 16640and 2nd answer is 46970 ¡) 136 × 115=15,640, ¡¡¡) 383 ×122=46,970 correct answer is 136 × 115 = 15640385 × 122 = 46970 15,64046,970 is the right answer. 136×115=15640385×122= 46970is correct 15,640 46,970is the correct answer ¡) 136 × 115=15,640 ¡¡¡)385 × 122 = 46,970 136. ×115= 15640 385×122= 46970 |
|
| 45. |
11. The curved surface area of acylindcr is 4400 cm2 and the circumference of iis base 1s110 cm. Find the volume of the cylinder. |
| Answer» | |
| 46. |
ling verhicallostha hon nerser o0srotect himzell latom the rain |
|
Answer» thanks |
|
| 47. |
13. Find the value of x.136 124째141째132째129째158xo 116 |
|
Answer» Given figure is octagon.We know sum of all interior angles in octagon is 1080° So, 136+124+141+158+116+x+129+132=1080 x + 936 = 1080° x = 1080° - 936° x = 144° Please hit like if you find my solution useful |
|
| 48. |
20. Find one rational and one irrational no between 5 and 5 |
|
Answer» Rational no. 987/10500.Irrational numbers are those numbers which can't be represented in the from ofp upon qand which are non-terminating and non-repeating. We know that, √3 = 1.732 and √5 = 2.236 So, three irrational numbers between √3 and √5 are: 1.798779856479841.., 2.010010001001991... , 2.121212121212312... Like my answer if you find it useful! |
|
| 49. |
l one-thiard of anumbes twhenуг.eguqls-one-EiPhof-the-nymberincreased Find the numbersea yqls one-fifhaf the number |
|
Answer» but answers is 75 |
|
| 50. |
1.Write 4 log 4+ 2 log 5 -log 15 as a single logarithm. |
| Answer» | |