InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4951. |
13. Find the value of x and y,if PQRS is a rectangle.(x 3) cm3)(3y-7) cm2.x |
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| 4952. |
Cube: 3 cm x 3 cm x 3 cm |
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| 4953. |
22 5oive the following question.(any 5)1) IF 600 rupees buy 15 bunches of feed, how many will 1280 rupees buy?(10) |
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Answer» Cost of 15 punches is ₹600 In ₹ 1 we can have 15/600=1/40 bunches In ₹1280 we can have 1/40×1280 bunches =32 bunches |
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| 4954. |
The lateral surface area of a hollow cylinder is 3552 cm2. It is cut along its height and it forms a rectangularsheet of width 24 cm. Find the perimeter of the rectangular sheet. |
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Answer» LSA of a hollow cylinder = 3552 cm^2Width of the rectangular sheet formed = 24 cmLet the length of the rectangular sheet be 'l' cmArea of the sheet formed = LSA of hollow cylinder24 x l = 3552l = (3552) / (24)l = 148Length of the rectangular sheet = 148 cmPerimeter of the rectangular sheet = 2(l + b)= 2(148 + 24)= 2(172)= 344cm. |
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| 4955. |
who is grah mantri |
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Answer» Rajnath Singh is the Grah Mantri. |
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| 4956. |
6 cms om2 cm5 cm9 cm5 cmifn)2. Find the perimeter of(a) Rectangle whose length-30 cm, breadth-15 cm.(b) Square whose each side is 15 cm.m. If a girl wishes to walk around its3· The side of a square garden is 70IOT f 60 cm. If its two sides are of length 18 crt oach Sichrice, find the distance she has to cover. |
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| 4957. |
A rectangle has twice the area of a square. The length of the rectangle is 12 cm greaterd the perimeter of theand the width is 8 cm greater than a side of a square. Find perimeter of square. |
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Answer» let the side of square is a , so area = a². then area of rectangle is l*b = (a+12)(a+8) = a²+20a+96 . but rectangular area is 2 times the square .so,2a² = a² +20a +96 => a²-20a-96 = 0=> a²-24a+4a -96 = 0=> a(a-24)+4(a-24) = 0=> (a-24)(a+4) = 0 so, a = 24cm now perimeter is 4*a = 24*4 = 96cm. khud sa bhibkabhi bana liyaa karo humesa google ma sahayata mat karob let one side of the square be x then length of rectangle = 12+xand breadth = 8+xarea of sqaure = x²area of rectangle = l*b →(12+x)(8+x) given - ar( rectangle )=2* ar(square) (12+x)(8+x)=2x²96+20x +x²= 2x²x²-20x-96=0x²-24x+4x-96=0x(x-24)+4(x-24)=0(x-24)(x+4)=0x=24 ( neglecting x=-4 since lenght cannot be negative) lenght of rect- 36breadth - 32 perimeter - 2*(32+36)= 136units kabhi apna bhi brain use kar liyaa karo bewkoofo |
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| 4958. |
(9) The product of two negative rational numbersforms a negative rational number. |
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| 4959. |
Choose the correct option:The side of a square is 11 m, then its area is(a) 121 m2(b) 44 m(c) 121 cm(d) none of these2. The length and breadth of a rectangular lawn is 25 m and 20 m respectively, then itsarea is(a) 45 m(b) 500 m2 (c) 90 m2 (d) none of these3. If the sides of a triangle are 12 cm, 15 cm and 20 cm, then the perimeter of the triang|(d) none of thes(C) 50 cm(b) 49 cm(a) 47 cm4. The side of a square lawn is 20 m, then the length of the fence around it is(c) 400 m(d) none of the(a) 40 m(b) 80 m193AREA AND PERIMETER OF RECTILINEAR FL |
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Answer» 1.side of a square 11 mIt's Area Is 11² =121 m²2.Area of the rectangular lawn is 25*20 = 500 m²3.Perimeter of the triangle will be (12+15+20) = 47 cm4.the length of fence around it will be 20*20 = 400 m. 1 (a)2 (b)3 (a)4 (c) sorry 4 (b) is the correct answer of this question 1) 121m²2)500m²3)47cm4)400m 1.1212.5003.474.400 |
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| 4960. |
18. The perimeter of the rectangle and square are same.Length and breadth of the rectangle are 10 cm and 8cm respectively. What is the area of the square?(B) 36 sa, cm |
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| 4961. |
area, the circle or the square? (Take)10. From a circular card sheet of radius 14 cm, two circles of radius 3.5 em and ao orectangle of length 3 cm and breadth I cm are removed. (as shown in the adjoiningfigure). Find the area of the remaining sheet. (Take |
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| 4962. |
ple 8: The perimeter ULUon : To find the area, we need the sideSide of the square = Perimeter -= 12 cm = 4 =. Area = side x side = 3 cm x 3kercise 12CFind the length of the rectangle whose(a) Area = 352 sq cm and breadth = 22 cm |
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Answer» Length is 12 cm because area= length×breadth Area=352sq cmBreadth=22 cmArea of rectangle =length × breadth ⇒352=Length ×22⇒Length =352/22=16 cm∴ length of the rectangle is 16 cm area of the rectangle=length x breadth352=lx22l=352/22l=16 cm length= 16 cm is the correct answer of the given question |
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| 4963. |
10. The length of a rectangle is 8 cm more than itswidth. If the perimeter of the rectangle is 44 cm.Find the length and breadth of the rectangle. |
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Answer» Let the breadth be xlet the length be x+8perimeter of rectangle=2 (length +breadth)so, 2 (x+x+8)=44cm=2 (2x+8)=44=4x + 16=44 =4x= 44-16=4x= 28=x = 28÷4=x= 7therefore, breadth is 7 (x)length is 7+8 (x+8)=15 |
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| 4964. |
Find Quadratic equation roots are 1,2 and -4,-5 |
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| 4965. |
2] ABC and Î1QR are eq vilateral triangles thencorrespondence between them is /are similarity(b) 4(c) 6(d) 8 |
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Answer» ABC and PQR are equivalent triangles then 6 correspondence between them is/are similarity. 3 are of sides and 3 are of angles correspondence If you find this answer helpful then like it. |
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| 4966. |
classmateDatePage.+) 2 2 १/ ४/ ८. Cहैं . १* 7:/3० ८ ६ ६०|१४६स24/। ।- ० *४ ॐ।० |
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Answer» answer is definitely right 2nd no = LCM× HCF/1st no = 180×6/38 =5×6=30 |
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| 4967. |
DatePage2 |
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Answer» 2^(x-1) * 2^(x+2) = 4^2 2^(x-1) * 2^(x+2) = (2)^4 (x - 1) + (x + 2) = 4 2x + 1 = 4 2x = 3 x = 3/2 |
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| 4968. |
EXCELLENCEDatePage2 |
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Answer» sin30=1/2cos45=1/√2tan30=1/√3sin90=1cos90=0Now put in equation1/4*1/2+4/3+1/2-0+1/25=1/8+4/3+1/2+1/25=3+12/24+27/50=15/24+27/50=5/8+27/50=250+216/500=466/500 |
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| 4969. |
classmateDatePage2. |
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Answer» Pot your entire question please! what is the problem. |
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| 4970. |
DATE: 20PAGE:2. |
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Answer» hit the like button if u like the solution. |
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| 4971. |
325—165+44—186 |
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Answer» 18 is the answer of this question 325 - 165+44-186 325+44=369_165_186= _351369_351=18 325-165+44-186=(325+44)+(-165-186)=369-351=18 is the answer 18 is Answers in this questions 325-165+44-186 = 18 18 is the correct answer to this question. 325-165+44-186=18 is the correct answer 325 - 165 + 44 - 186 = 18 =325-165+44-186=369-351=18.IT IS THE CORRECT ANSWER 👍 only "18" is the correct answer to these question 18 is a correct answer 325-165=160+44=204-186=18 18 is correct answer in this questions 325 - 165 + 44 - 186 = 18 |
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| 4972. |
DatePage No.2TAX |
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| 4973. |
r=02.DatePage |
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| 4974. |
iv) 25:70v) 186: 403 |
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Answer» so ratio of 186 and 403 is186/403= 6/13 no divide ve karne aaa please specify your question last question |
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| 4975. |
नि ८८ क 186, 252 ard 334 byGuckidd Qiuisen ahgasiton) |
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| 4976. |
>2)नजाजा2186+76'+ 50+ 9t - २८० । |
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Answer» 240+x=360x=360-240x=120 |
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| 4977. |
The H.CE of 186 and 496 is 62, What is their L.С.М.? |
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| 4978. |
You have studied in Class IX, that a median of a triangle divides it into two triangles of equal areas.Verify this result for A4BC whose vertices are A(4,-6), B(3.-2) and C(5, 2) |
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| 4979. |
correspondencestate the test and meof vertices by which the trianglesare congruent. |
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Answer» triangle man congruent to triangle bpn and the congruent is RHS |
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| 4980. |
What is the ratio of areas of the similar triangles whose sides are in the ratio 3:4 |
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Answer» Ratio=3:4k=3/4Ratio of area will be k^2=Area of triangle A/ Area of triangle B=(3/4)^2=9/16 |
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| 4981. |
3) Prove that the point (3,0).(6, 4) and (-1,3) are the vertices of a night angled isosceles tianele.ot a nnA and RB. |
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| 4982. |
6. A shopkeeper sold a sack of rice for685.20 and made a profit of R 120.80. What wahis cost price ? |
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Answer» Selling price = cost price + profit685.20 = Cost price + 120.80Cost price = 685.20 - 120.80 = Rs 564.40 hit like if you find it useful |
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| 4983. |
26. An article is sold at a loss of 20% for Rs.8000. If it is soldat20% profit, then what would be the selling price of the article? |
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| 4984. |
1517+7412 |
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Answer» 1517 + 7412 = 8929 is the answer |
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| 4985. |
Find the area of the triangles whosevertices are (-5, 1), (93,-5) and is, a). |
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Answer» what are you written the second point Plz answer this question |
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| 4986. |
Sarikapurchased 45 dozens of pens for3,510. She sells 20 dozens at a profit of 15%and the remaining for 10% loss. What is her total loss% or profit%? |
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Answer» Profit of 20 dozen = 15%loss of 25 dozen = 10%total profit = 15 - 10 = 5the profit 5%at 3500= 1% of 3500 = 3500 ÷ 100 = 35total = 35 × 5 = 175the profit is 175 or. the profit is 20% thanks |
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| 4987. |
4, Sarika purchased 45 dozens of pens for3,510. She sells 20 dozens at a profit of 15%Horsand the remaining for 10% loss. What is her total loss% or prof |
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Answer» THANKYOU VERYMUCH |
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| 4988. |
22. Shabana bought 16 dozen ball bens and sold them at a loss equal to S.P. of 8 ball pens.Find(i) her loss percent(ii) S.P. of 1 dozen ball pens, if she purchased these 16 dozen ball pens for Rs 576. |
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| 4989. |
2. A man purchased a T.V. for 6,000 and sold it at a loss 15%. Find the S.P. of the T.V. set.3. The cost of 12 pens is equal to the S.P. of 15 pens. Find the loss percent. |
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| 4990. |
By selling 90 ball pens for Rs. 160, person losses 20%. How many ball pens he sold at Rs. 96 so as to have a profit of 20 %? |
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| 4991. |
By selling 90 ball pens for Rs. 160 person losses 20%. How many ball pens he sold at Rs. 96 so as to have a profit of 20%? |
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| 4992. |
A merchant bought 15 dozens at Rs. 10 per dozen. He sold them at Rs. 1.50 each. Find profit and loss percent? |
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| 4993. |
The price of 357 apples is 7 1517.25. What will be the approximaleprice of 49 dozens of such apples?15 |
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Answer» 1 dozen = 12 units. Price of 357 apples = ₹ 1517.25Price of 1 apple = (1517.25/357)= ₹ 4.25Price of one dozen = 4.25*12= ₹ 51. Price of 49 dozens = 51*49= ₹ 2499 Please hit the like button if this helped you |
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| 4994. |
7. Find the area of the given figure.+20 cm20 cm -15 cm-16 cm-30 cm |
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Answer» Here, area of the given figure will be:Area of two trapeziums + area of 1 trapezium + area of rectangle First, height(h) of both trapeziums will be 30cm. - 16cm. = 14cm. Now, height(h) of each trapezium = 14/2 = 7cm. Now, area of both trapeziums = 2 × h(a + b)/2 [Where a and b are parallel sides of the trapeziums] = h(a + b)= 7cm.(20 + 5)cm.= 7cm. × 25cm.= 175cm² Similarly, area of another trapezium = 4cm.(16 + 30)cm.= 4cm. × 46cm.= 184cm² Now, area of rectangle = l × b5cm. × 16cm. = 80cm² Now, adding all the areas, we get439cm² Thus, area of the given figure = 439cm² |
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| 4995. |
Find the boundary lengths (Perimeters) of triangles whose sides are(a) 16 cm, 16 cm, 16 cm(b) 18 cm, 20 cm, 20 cm(c) 380 m, 610 m, 500 mcm: cm |
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| 4996. |
20-_4ICSE Mathematics for Class 95 cm5 cm6 cm6 cm13. From a 20 cm x 16 cm piece of wood, a block in the shapeof the letter M is made. Find the area of the wood leftover.20 cm6 cm10 cm10 cm |
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Answer» piece of the wood is 20 centimetre piece of wood b is 16 centimetre shape of the letter M is made by a and b is 20 into 16 is equal to 320 |
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| 4997. |
why we celebrate world mathematical day |
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Answer» In India, the NationalMathematics Day isobserved on December 22 every year. Itis celebratedin order tohonor the birth anniversary of the famous mathematicianSir Srinivasa Ramanujan. He was theworldfamous mathematicianwho made remarkable contributions in different fields and branches of the subjectmathematics |
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| 4998. |
Prove that (2n + 3)2 - (2n-3) is a multiple of 8using relevant method of proof. |
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Answer» (2n+3)²- (2n-3)² [ (2n +3) - (2n - 3) ] [ (2n + 3) + (2n - 3) ] = [ 6 ] [ 4n ] = 24n = 8 [ 3n ] This is a multiple of 8 (2n + 3)^2 - (2n - 3)^2 = (4n^2 + 9 + 12n) - (4n^2 + 9 - 12n) = 4n^2 + 9n + 12n - 4n^2 - 9 + 12n = 24n = 8*3n Hence, on solving we get 24n which is multiple of 8 |
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| 4999. |
In each of the following question, one term in the numberseries is wrong. Find out the wrong term.11 42 214 1045 4148 12417 |
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Answer» After 11,each and every number is formed by a definite pattern in calculation • 11 × 7 – 7 × 5 = 42 • 42 × 6 – 6 × 6 = 216 (Which is not the same number given in the series.) • 216 × 5 – 5 × 7 = 1045 • 1045 × 4 – 4 × 8 = 4148 • 4148 × 3 - 3 × 9 = 12417 So all the numbers in the series follow the same pattern in the calculation except 214. Therefore, Wrong term in series is 214. |
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| 5000. |
Erections (Q. 56 - 57): In each of the following questions, one term in theries is wrong. Find out the wrong term.- 24, 27, 31, 33, 36a) 33b) 31d) 24C) 27 |
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Answer» 31 out the wrong term |
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