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1 ml = 0.001 litre 2000 ml = 2 litre 5000 ml = 5 litre 3600 ml = 3.6 litre 4050 ml = 4.05 litre

a

2764.5412764.54

b.13451340km

√3 = 1.732

Let the first installments be aGiven that the installments are in AP.Let the common difference be dHence the installments are: a, a + d, a + 2d ………..40th termRecall the nth term of AP, tn = a + (n – 1)d⇒ t40 = a + (40 – 1)d = a + 39dSum of n term of AP,

Given total debt = Rs 3600⇒ 20[2a + 39d] = 36002a + 39d = 180 → (1)It is also given that 30 installments are paid.Unpaid amount = one-third of Rs 3600 = Rs 1200Therefore total payment till 30 installments = 3600 – 1200 = Rs 2400Now, sum of 30 terms, = 15(2a + 29d)⇒ 15(2a+29d) = 24002a +29d = 160 → (2)Subtract (2) and (1), we get2a + 39d = 1802a +29d = 160-------------------- 10d = 20∴ d = 2Put d = 2 in equation (1)2a + 29(2) = 180⇒ 2a + 58 = 180⇒ 2a = 180 – 58 = 122∴ a = 618th installment, t8 = a + 7d= 61 + 7(2)= 61 + 14 = 75

natural number .............

natural numbers.....

.........natural number.....

natural number is the best answer

co primes is correct

it is simple - natural number

Two numbers having only 1 as a common factor is called co-prime number

Two numbers having only 1 as common factors are called to prime numbers

option C

angle FEG = 180-105 = 75° angle HEG = 180-75 = 105°

Answer)1000 litersExplanation:1liter=0.01m2Therefore 1m2=1000 liters

1. 9656 2. 9550 3. 9756

2)9656 2)9550 3)9756

x measures 105 degrees

180-65=115 because it is alternate angle

105° is correct answer.

105° is right answer .

the answer is option (b)

110 is correct answer

this questions ans is 105

x=105° is the answer. This is the XKaman Hal

(b)=105° receive answer

105° is the correct and right answer

105° is the correct answer h

X measures 105 degree

105 is correct answer

105 digri is correct answer

(b) 105 is the answer of this question..

X=180°-65°=105° is right answer these questions

the answer could be a or d but i havent learned that yet cuz im in 5th grade but i just made some calculations

the answer could be a or d but I haven't learned that yet cuz I'm in 5th grade but just made some calculations

B. 2.991 is the correct answer

2.991 is correct answer

B.2991 is the right answer

Sum of interior angles in a Pentagon is 540.120+100+90+110+x=540x=540-420x=120°

The nearest natural number from any negetive number is 1

so, the number to be added with -2/3 to give 1 is

-2/3 +x = 1=> x = 1+2/3 = 5/3

ANSWER - 13800 as because the nearest number of 13799 is 13800

nearest number of 13799 is 13800

13800 is right ans bcoz 13799 is only its nearest no.

13800 is right answer

the nearest number of 13799 is 13800.

composite is the answer of the following

The H.C.F of given numabers can never be less than or equal to than any of the numbers

37.composite numabers

36. more than any of the numbers37. composite numbers

more than any of the numbercomposite

404=2*2*10196=2*2*2*2*2*3HCF=2*2=4LCM=2*2*101*2*2*2*3=9696LCM*HCF=Product of two given numbers4*9696=404*9638784=38784

The price of the pencils per score = ₹96=> the price of a pencil = ₹96/20= ₹4.8the price of the ball pens per dozen = ₹50.4=> the price of a ball pen = ₹50.4/12=₹4.2the required ratio =

=(4.8×10)÷(4.2 ×10)= 48/10÷ 42/10=48/10 * 10/42=8:7

20 pencil=rs 961 pencil=96/20=4.8rs12 pens=50.4 rs1 pen=50.4/12=4.2 rsSo,pencil:pen=4.8:4.2=0.8:0.7

8:7 is the best answer

The quadratic equation=x^2-(sum of roots)X+(product of roots)=x^2-(-2/√3+√4/4)X+(-2/√3*√3/4)=x^2-(-8+√12/4√3)X+(-1/2)

770+28790+8798 will be the answer

part 1

part 2

i) 5.010010001...../7ii) 5.020020002..../7iii) 5.030030003...../7

sin 18/cos 22=cos(90-18)/sin(90-22)

=cos 72/sin 68

However, if your question is modified a little to "How many trailing zeros are there in 100!?" then we can definitely work it out.

The only trick is to remember that a zero is created by the factor pair (2,5) as 2*5 = 5*2 =10. Therefore, it is necessary to count the number of 5s and 2s. One could possibly argue that the count of 5s alone or 2s alone might give us the result. But that would actually cause a problem by giving us an exaggerated or underestimated count of 0s. As it is possible that the count of 2s is greater or lesser than the count of 5s. So, the count of 0s in the end result would rather depends on the minimum count between the count of 2s and the count of 5s.

100! represents the product of all the natural numbers up to and including 100.

Clearly, the count of 2s is more than the count of 5s. (Let me know if you could visualize it!)

To count the number of 5s, we must note that there are 20 multiples of 5 among the natural numbers up to and including 100. Only these multiples can contribute 5!!

It would be worth to note that 16 multiples of 5 would contribute one 5 each except 25, 50, 75 and 100. The reason to expel out these 4 multiples of 5 from the first group is that each of these multiples is a multiple of 25 too. That means each of these multiples contribute two 5s each.

So, the total count of 5s = 16*1 + 4*2 = 16 +8 =24

Therefore, the total number of trailing 0s in 100! is =24

Otherwise the total count of 0s in 100! is30if all the 0s , not just the trailing 0s, are to be counted.

lets multiply it by 5 so 3645×5=18225 which is square of 135so smallest number is 5.

Quadratic equation =x^2-(sum of roots)x+(product of roots)x^2-10x+10= 0this is the required equation

wrong answer

dear buddy now plx find its by solving the equation

Typical question about like increase or decrease questions

Let radius of the cylinder= r mHeight = h mGiven (r+h)=37mTotal surface area= 2*pi*r(r+h)=16282*22/7* r*37=1628r=(1628*7)/(2×22×37)After cancellationr=7 mr+h =377+h=37h=30mi) csa of the cylinder=2*pi*r*h=2*22/7*7*30=1320 m^2Voume =pi*r^2*h=22/7*7*7*30=4620m^3

4620m^3 is the right answer

Let r and h respectively be the radius and the height of the cylinder. We have:

r + h = 37 m

TSA = 1628 m2

2πr (h + r) = 1628

2πr(37) = 1628

r=(1628×7) /(2×22×37)=7m

h=37-7=30m

Volume of the cylinder =πr2h

=22/7×7×7×30=4620m³

4620 is the right answer

4620 is the right answer

∆PQR s ED || QO

.°. PD/DO = PE/EQ ( from formula )-------(1)

∆POR s DF || OR

.°. PD/DO = PF/FR ( from formula )........(2)

from (1) and (2) we get

PE/EQ = PF/FR

.°. EF || QR

5/7, 9/11 is the correct answer of the given question