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5151.

Find all the zeros of the polynomial-+ ar -4, if two of its zeros are /2 and-2.

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5152.

9. In the following data the median of the runs scored by 60 top batsmernof the world in one-day international cricket matches is 5000. Find themissing frequencies x and y.ens scored 09500- 500450- 500500-6500/500 7500/7500-$500Number ofbatsmen122

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5153.

68. The area of a right-angled triangle is 165 sq metres. Determine its beand altitude if the latter exceeds the former by 7 metres.

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Let the base and altitude be x and x+7 respectively.Area of triangle=1/2×base×height165=1/2×x×(x+7)330=x(x+7)X^2+7x-330=0(X-15)(x+20)=0X=15. Or x=-20(rejected because it is negative)

So, x=15And,x+7=22

So the base and height are 15m and 22m respectively.

5154.

as Bolve the following1 What must be added to 4283 to get 609372 Find a number which is 3860 less than 9000

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5155.

Madhu's flower garden is now a square. If she enlarges it by increasing the width lmetre and the length 3 metres, the area will be 19 sq metres more than the presentarea. What is the length of a side now?

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Let the side of the garden(square) is x m. Then the are is x² m².The new length is (x+3) m and the new width is (x+1) m. Then the new area will be, (x+3)(x+1) m².By the given question,(x+3)(x+1)=x²+19or, x²+3x+x+3=x²+19or, 4x+3=19or, 4x=19-3or, 4x=16or, x=4 m

5156.

15, Madhu's flower garden is now a square. If she enlarges it by increasing n 0.metre and the length 3 metres, the area will be 19 sq metres more than the presentarea. What is the length of a side now ?

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Let the side of the garden(square) is x m. Then the are is x² m².The new length is (x+3) m and the new width is (x+1) m. Then the new area will be, (x+3)(x+1) m².By the given question,(x+3)(x+1)=x²+19or, x²+3x+x+3=x²+19or, 4x+3=19or, 4x=19-3or, 4x=16or, x=4 m

5157.

rnotheierb60. The length of a hall is 3 metres more than itsbreadth. If the area of thehall is 238 sq metres, calculate its length and breadth.

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5158.

7. The sum of the radius of the base and the height of a solid cylinder37 metres. If the total surface area of the cylinder be 1628 sq metres. Find its volume.

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thanks

5159.

The sum of the radius of the base and the height of a solid cylinder37 metres. If the total surface area of the cylinder be 1628 sq metres,findits volume.is

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5160.

7. The sum of the radius of the base and the height of a solid cylinder is37 metres. If the total surface area of the cylinder be 1628 sq metres, findits volume.2

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5161.

.A rectangular water tank has 16200 litres of water. The floor of the water tank is 4.5 m x 3 m. Find theheight of water in the tank.

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Volume of Reactangular water tank = 162800 lit or 162.8 m^3I litre =.001 m^3

Let height of water in tank = hWe know, volume = l*b*h

Then,l*b*h = 162.84.5*3*h = 162.8h = 162.8/13.5h = 12.05 m

Therefore height of water in tank is 12.05 m

5162.

VIALS:Ex. Find 7 rational numbers between 1 and

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5163.

ofwater.Thewaterisemptied3. A cylindricalwater tank of diameter 42 cm and height 12 cm, is fulltank orectangular tank of length 44 cm and breadth 42 cm. Find the height to which water risein the tank.

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5164.

A rectangular tank contains 35000 litres Ul WaUtank if the base of the tank is 7 m x 2.5 m.A cylindrical water tank of diameter 42 em and height 12 cm, is full of water. The water is emptiedinto a rectangular tank of length 44 cm and breadth 42 cm. Find the height to which water risesin the tank.m and height 12 cm, is full of water. The water is emptiedd 100 meters wide is flowing at the rate of 4.5 km per hour. Find how

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5165.

¢ L b kL1क ट+ दर 2 "89 न १ kRS =q+7 2 ‘79

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(a+b)^2= a^2+b^2-2ab(5)^2= a^2+b^2-2(6)25-12= a^2+b^2= 13thanks

please like the solution 👍 ✔️

5166.

lg] ¢h3IbE bhobb e k2R |4 klie *heछह | नस kL |l bR 2h |12 dh bk मोनिका पक कप हु. (हि)

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समुच्चय होगा

Rolling Two Dice

When rolling two dice, distinguish between them in some way: a first one and second one, a left and a right, a red and a green, etc. Let (a,b) denote a possible outcome of rolling the two die, with a the number on the top of the first die and b the number on the top of the second die. Note that each of a and b can be any of the integers from 1 through 6. Here is a listing of all the joint possibilities for (a,b):

(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

5167.

(ii) 3860 l into kl

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1 kiloliter = 10^3liter.

3860 l=3.86 kl

5168.

Votbll Sk 13 bhlie T kL Do हे धयल् के *IS हक] अर हू e 1 LD Blle b Dbl < e L I EM\"

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5169.

16. An aeroplane at an altitude of 250 m observes the angleof depression of two boats on the opposite banks ofa river to be 45° and 60° respectively. Find the widthof the river. Write the answer correct to the nearestwhole number

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Let A be the position of the airplane and let BC be the river. Let D be the point in BC just below the airplane. B and C be two boats on the opposite banks of the river with angles of depression 60° and 45° from A.

tan 45= AD/ DCy= 250= DCin ADB tan 60= AD/BD√3= 250/xx= BD= 144.3mBC= BD+DC144.3+ 250394.3m= width

5170.

(1JDIdcelsius for x-axis and fallelIr the temperature is 30 °C, what is temperaturefahrenheit?norature is 95 °F, what is the temperature

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(30°C× 9/5) + 32 = 86°F

5171.

Find the minimum length in cm and correct tonearest whole number of the thin metal sheetrequired to make a hollow and closed cylindricalbox of diameter 20 cm and height 35 cm.Given that the width of the metal sheet is 1 m.Also, find the cost of the sheet at the rate of56 per m.

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Let length of metal sheet be l and breadth be bBreadth b = 1m = 100 Cm

radius of cylindrical box r = 10 Cmand Height h = 35 Cm

Thus area of of closed cylindrical box = 2pi r h + 2 pi r^2= 2*3.14*10*35 + 2*3.14*100= 2198 + 628 = 2826 Cm sq Thus

Area of box = area of Sheet

2826 = l * b l = 2826/100 l = 28.26 CmThus length of sheet is 28.26 Cm

Cost of 1 msq of sheet = 56 RsCost of 10000Cm Sq = 56/10000 RsCost of 2826 Cmsq = 56 * 0.2826 Rs = 15.8256 RsThus total cost of sheet is 15.8256 Rs

5172.

\tan 72 ^ { \circ } = \tan 18 ^ { \circ } + \tan 54 ^ { \circ }

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tan54 = tan(72-18)

= tan54 =( tan72-tan18)/1+tan72.tan18

= tan54 = ( tan72-tan18)/1+tan(90-18).tan18

= tan54 =( tan72-tan18)/1+cot18.tan18

= tan54 =( tan72-tan18)/2

= tan72-tan18 = 2tan54

=(tan72 = tan18+2tan54)

tanq

5173.

8.Estimate the value of the following numbers to the nearest whole mure( 197 ( 250 (ii) 780

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(i)Square root of 97 to the nearest whole number -10

(ii)Square root of 250 to the nearest whole number-16

(iii) Square root of 780 to the nearest whole number-28.

is the best answer.

√97=10√250=16√780=28

is the correct answer.

(1)=10(2)=16(3)=28 hope this will help you

like my answer

97 = 10250=16 780=28like my answer iF u want to score 100 marks in exams

5174.

Two poles stand on the opposite sides of a road, 10 m wide. Theheights of the two poles are 7 m and 9 m respectively. Estimate thedistance between their tops, nearest to the whole number of metres.

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5175.

Solve:cot 18°tan 720

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=cot 18/ tan 72= tan 72/tan 72= 1

5176.

32/50+3) (+5) (15+3 2)7133/22 (D) 3

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5177.

MathEXFind the gain or loss per cent when:(i) CP 620 and SP- 713iii) CP345 and SP372.60

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5178.

\begin{array} { l } { \text { Find the gain or loss per cent when: } } \\ { \text { (i) } C P = 620 \text { and } S P = 713 } \end{array}

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profit % = s.p - c.p / c.p ×100 =93/620×100 =0.15 ×100 =15%

As SP>CP so there is gainGain = SP - CP = 93gain% = (93/620) × 100 = 15%

5179.

42960876औरकाg14..13. भिन्न571311लगाया जाए, तो दूसरे क्रमांक पर कौन(a) 11अंश तथा हर 1 केकथन क्या प्रदर्शित11..14. 1536 का 1,1450 के 1 से कितन(a) 894 (b) 908 (cहैVt. 15. 11+22+32 का मान है।WIN+1all24___(a) 713(c)711-*1616. एक परीक्षा में एक छात्र से किसी निगया था, लेकिन गलती से उसने उमान सही उत्तर से 150 अधिक थ(a) 260 (b) 280

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9/8+8/3+15/4(27+64+90)/24181/24 is the right answer

9/8+8/3+15/4(27+64+90)/24181/24

a) is the right answer

181/24 is the right answer

5180.

1. Convert the following temperature in the Celsius Scale.(a) 41°F(c) 95°F(e) 32°F

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(°F− 32) × 5/9 = °Chencea)41°F(41-32)*5/9=5°Cb)95°F(95-32)*5/9=35°Cc)32°F(32-32)*5/9=0°C

5181.

id. T0.14OT9 In Fig. 10.141, ABC is a triangle in which B 24C. D is a point on side BC such thatAD bisects ZBAC and AB CD. BE is the bisector of ZB. The measure of ZBAC is(a) 72°b) 730(c) 74°(d) 95°Fig. 10.141[Hint: ΔΑΒΕΔDCE ]

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5182.

19. A solution is to be kept between 86°F and 95° F what is the range of temperature in degreeelsius, if FC+32

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5183.

(f)35 k|95 into litres.

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5184.

If the temperature is 95 F, what is the temperature in celcius.

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5185.

(3) If the temperature is 95 F what is the temperaturecelsius?

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5186.

wat one may be to the other as 2:7.ratio of the price of pencil to that of ball pen. if pencils cost Rs 16 per19. Find the ratencils cost Rs 16 per score and ballens cost Rs 8.40 per dozen.

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Price of Pencil=16per scoreSo,16/20=4/5=.8rs per penPrice of pen=8.40 per dozen8.40/12=.7 per penSo,ratio=.8/.7=8/7

5187.

12What is the electric flux through a cube of side 1 cm which encloses an electric dipole[Del

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It will be zero. electric flux =( total charged enclosed)/(permittivity of free space). Since net charge of a dipole is zero. Therefore, flux through the cube will be zero.

5188.

1 in the adjoining figure. ABCD s aparallelogram in which LA獬724, Calculate

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5189.

3. If one dozen pencils cost,21, find the cost of one score pencils

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1 dozen = 12 pencils1 score = 20 pencils

Cost of 12 pencils = Rs 21

Therefore cost of one score pencils= Rs(21*20/12) = Rs 35

Hence, cost of one score pencils be is Rs 35.

5190.

यदि 721 + 722 + 723 + 724 को 25 से विभाजित किया जाता| है, तो शेष क्या बचेगा ?(A) 77(B) 17| (C) 5(D) 0 ।

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7^21(1+7+49+343)/25=7^21×400/25; whatever the value of 7^21 be, multiplying it by 400, remainder =0

5191.

Question 3.(a) Without using trigonometric tables, evaluatek wsin2 34o+ sin2 56 +2 tan 18 tan 72 - cor 30

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5192.

end. Rakesh is coming to our home forAsk your mom to make arrangementsach home with Rakesh and his famil24724

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24+24=48is a correct answer

24+24=48. v

24 + 24 = 4848 is the correct answer

24+ 24= 48.

24+24=48 is the answer

24+24=48is a correct answer

24+24=48

5193.

of the following is the7.1x3.8533. Which one of the 1best approximation of9.09(1) 74371310713(2)724(4)71410

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7.1x3.85/9.09=7×4/9=(3)

option 3 is the correct answer of the given

5194.

, lind other zeroes.fthe polynomial x -16r -26x + 10 is divided by another polynomial x th x anein ander comes out to be x + a, find k and α.chap

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5195.

9. Divide the polynomial f(x)-6x + 11x2 -39x -65 by the polynomialx)1+x. Also,find the quotient and remainder.

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5196.

anindita purchased 10pens for 120 she sold each pen for 17.find her total profit or loss

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CP = 120 SP = 17×10 = 170 PROFIT = 170 - 120 = 50

5197.

10. Check whether x-3 is a zero of polynomial x-3x +x-311. Write the degree of the polynomial 7

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11. x²-3x+x-3

Given x = 3

= 3² -2(3)-3

= 9-6-3

= 0

Yes, 3 is a zero of the polynomial

12. √7 = 7^(1/2)

Degree = 1/2

Like my answer if you find it useful!

5198.

\begin{array} { l } { \text { On dividing the polynomial } x ^ { 3 } - 5 x ^ { 2 } + 6 x - 4 \text { by a polynomial } g ( x ) , \text { quota } } \\ { \text { remainder are } ( x - 3 ) \text { and } ( - 3 x + 5 ) \text { respectively. Find } g ( x ) } \end{array}

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5199.

Find the coefficient ofin the polynomial (x - 1)(x-2)(x-3)(x-4)........ (x - 100).

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5200.

te per hour is it travelling?amp-posts are placed 30 metres apart along a road. How long will a car travelling at 45 km anur take to pass 6 lamp-posts, not counting the first of them?ih are lced 16 metres apart alonaside a railwav track at

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