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class frequency

20-30 6

30-40 F1

40-50 16

50-60 13

60-70 f2

70-80 2

total 50

YOUR ANSWER IS F1=9 and F2=4

FULL SOLUTION IS ATTACHED WITH IMAGE ☝☝☝

won 75%matches

so they lost 25% of matches25/100×20=5

surface area is 6a^2=600cm^2hence a^2=100hence a=10cm

Given surface area is 1200 cm²Surface area of cube = 6×(Side)²1200 = 6 × (side)²(side)² = 200side = √(200)side = 10√2 cm

wrong

Let the distance covered by the peacock be AC = x mHence the distance covered by the snake is DC = x mIn right ΔABC, by Pythagoras theorem we haveAC^2= AB^2+ BC^2x^2= 9^2+ (27 – x)^2⇒ x^2= 81 + 729 – 54x + x^2⇒54x = 810∴x = 15

In 1000 person net increase is 75

Therefore in 8000 net increase=75\1000×8000=600

Net increase in one year is 600 then net increase in two year=600×2=1200

Therefore total population after 2year is 8000+1200=9200

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5)Given,∠1:∠2=3:2Solution:∠1 and ∠2 are supplementary angles.So, ∠1+∠2=180°=>3x+2x=180°=>5x=180°=>x=36°so, ∠1=3x=3*36=108°and ∠2=2x=2*36=72°

Now, ∠1=∠3 and ∠2 =∠4 (vertically opposite)so, ∠3=108°∠4=72°

∠4=∠6 and ∠3=∠5 ( alternate interior angles)so, ∠6=72° and ∠5=108°and finally,

∠5=∠7 and ∠6=∠8 ( vertically opposite)so, ∠7=108° and ∠8=72°

1+1-(1/√3)2-1/√32√3-1/√3

what is this

this is the answer to that question

this is wrong

this is right just do the rationalization

yes all these are zeros of the equation

76metre in 4secHence in 1sec=76/4=19mHence in m/s=19m/sfor km/hr multiply the speed value by 3.6hence 19*3.6=68.4m/s

Probability=frequency of multiple of 3/total outcome =(20+18)/100 =19/50

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Let pencil be x and let pen be y5x+7y=507x+5y=46multiply first equation by 735x+49y = 350multiply second equation by 535x+25y=230solving them we get 24y=120 which gives y is 5 rupeessubstituting in second equation we get x is 3 rupees

Let the cost of pencil be x and the cost of the pen be y

5x + 7y = 50 . . . . . (1)7x + 5y = 46 . . . . . (2)

(1) × 7

35x + 49y = 350 . . . . . (3)

(2) × 5

35x + 25y = 230 . . . . . (4)

(3) - (4)

24y = 120 y = 5

substituting in (2) we get

x = 3

Therefore, Cost of pencil = ₹3Cost of pen = ₹5

let cost(in RS) of one pencil = x cost (in RS) of one pen = yTherefore , according to question 5x+7y = 50 ........ (1) 7x + 5y = 46 .........(2)Multiply equation 1 by 7 equation by 5 we get 7(5x+7y)= 7*50 35x +49y = 350 .......(3) 5(7x +5y) = 5*46 35x +25y = 230 ....... (4)

Subtract equation 4 from equation 3 , we get 35x + 49y - 35x - 25y= 350 -230 49y -25y = 120 24y = 120 y = 120 /24 y= 5Substitute y=5 in equation 1 , we get 5x + 7*5 =50 5x+35 =50 5x = 50 - 35 5x =15 x= 15/5 x=3

Hence Cost of One Pencil = x =3 Cost of One Pen =y =5

correct answer is (i) >(ii) =(iii) >(iv) <(v) =

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(i)>ii)=iii)>iv)<v)=

i. )>ii.)=iii)>iv) <v) =

i)>ii)=iii)>iv)<v)=

1) -14+11+5=16-14=214-11-5= 14-16= -2-14+11+5>14-11-52) 30(-5)+(-8) 30-13=17(-5=+(-8)+30= -13+30=1730+(-5)+(-8)= (-8)+(-5)+30

3)7+11+(-5)=18-5=13*-7)+-11+5=-18+5= -137+11+(-5)>(-7)+(-11)+5

4)(-14)+11+(-12)=11-25= -1414+11+13=38(-14)+11+(-11)<14+11+13

i)>ii)=iii)>iv)<v)=

hope it helps u

1] > 2] =3] >4] <5] =

(i) -14+11+5( )14-11-5 -14+16. ( )14-16 2. ( ) -2 >

1. >2. = 3. >4. <5. =

Let the ratio of sides be x so sides are

3x, 4x, 5x

So, observe this

(3x)² + (4x)² = (5x)²

9x² + 16x² = 25x²

25x² = 25x²

25 = 25,

This shows pythaogras theorem applicable hence given is right angled triangle

put x = 0 x²-2x = 0²-2×0 = 0yes x=0 is root of polynomialput x = 2x²-2x= 2²-2×2 = 4-4 = 0yes x=2 is also zero polynomial

if we put x=2 2^2-2*2=4-4=0if we put x=0 0^2-0=0so roots are 0 and 2