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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 5251. |
Verify whether cos hx is an odd function or an even function. |
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Answer» it is an even function as f(-x) = f(x) |
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| 5252. |
Verify whether x-isa solution of the equation l-x +-= 2x4 |
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Answer» Explanation : 1 1/4*x + 1/2 = 2x - 1/2 If we put x = 4/3 in the equation and both sides are equal then its the solution of our equation. 5x/4 + 1/2 = 2x - 1/2 L.H.S = 5x/4 + 1/2 = 5/4*4/3 + 1/2 = 5/3 + 1/2 = 13/6 R.H.S. = 2x - 1/2 = 2*4/3 - 1/2 = 8/3 - 1/2 = (16-3)/6 = 13/6 L.H.S. = R.H.S. Solution : Yes, it is the solution of an equation. If you find this answer helpful then like it |
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| 5253. |
Verify whether the points (1,5), (2,3) and (-2,-1) are collinear or not. |
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| 5254. |
e 5: Verify whether 2 and 0 are zeroes of the polynomial x2 â 2x. |
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Answer» To check whether 2 and 0 are zeroes of x² - 2x, substitute x = 2, 0 when x = 2 (2)² - 2(2) = 4 - 4 = 0 when x = 0 (0)² - 2(0) = 0 - 0 = 0 Therefore, 2 and 0 are zeroes of x² - 2x when we put both the values the answer is 0 so 2 and 0 are the zeroes of the given equation |
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| 5255. |
W T N सर -...el R ey o e Tt - P नें a= 37’ b= |
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Answer» a = bq + ra = 37, b = 4, r = 1, q =? Then, 37 = 4*q + 137 - 1 = 4q4q = 36q = 9 |
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| 5256. |
1. निम्नलिखित भिन्नों को दशमलव रूप में लिखिए और बताइए कि प्रत्येक काकिस प्रकार का है :| 36 1 Le की 42.& ) 45gl 2 329®™ 33 Wi " Zo0-t — o2... आप जानते हैं कि द = 0142857 Siarad A, W s R e war s ]n |
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Answer» aap inka divide kardo 1st questions ka 1st ka ans. 0.36 aayega |
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| 5257. |
Verify, whether points P(6, -6), Q(3,-7) and R(3, 3) are collinear. |
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| 5258. |
Verify whether -2,1 are the zeroes of the cubic polynomial, P(x)-2x' +x-5x +2, alsoverify the relationship between the zeroes and the co-efficients. |
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| 5259. |
G. An aeneplane, when000 mgnour al pobes vertically above aroth n cuoplane a+an Ä°nstartthe veialldlistance between thu aroplaneat the instant Clake 3-13) |
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Answer» Please like the solution 👍 ✔️👍 |
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| 5260. |
Ta graticule is prepared on the polar Zenithalequidistant projection for the north polar region, then() what will be the extent or error in the area of thezone lying between 65°N and 75°N latitude, and (h)what will be the error in the scale along 65°N |
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Answer» Zenithal projections (also known as azimuthal projections) are a class of projections in which the surface of projection is a plane. The native coordinate system is such that the polar axis is orthogonal to the plane of projection, whence the meridians are projected as equispaced rays emanating from a central point, and the parallels are mapped as concentric circles centered on the same point. The projection is therefore defined by R$\scriptstyle \theta$ and A$\scriptstyle \phi$ as in the following diagram: zenithal projection are a class of projectio Zenithal projections(also known asazimuthal projections) are a class of projections in which the surface of projection is a plane. The native coordinate system is such that the polar axis is orthogonal to the plane of projection, whence the meridians are projected as equispaced rays emanating from a central point, and the parallels are mapped as concentric circles centered on the same point. zenithal projections are a class of projections with plane surface of projection please 1 question is show Zenithal projection (also known as azimuthal projection) are a class of projections in which the surface of projection is a plane.The native coordinate system is such that the polar axis is orthogonal to the plane of projection,whence the meridians are projected as equispaced rays emanating from a central point,and the parallels are mapped as concentric circles centered on the same point.The projection is therefore defined by R$\scriptsyls\theta$ and A$ scriptstyle\phi$ as in the following diagram. 9 12 14 16 18 22 20 24 26 28 30 32 34 26 zenithal projection also know as azimuthal projection are a class of projection |
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| 5261. |
Use Euclid's algorithm to find the HCF of 117 and 65 and then express it in the fom117 m +65 n where m and n are integers. |
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Answer» Euclid's Division Lemma :-a = bq +r 117 > 65 117 = 65 × 1 + 52 ----> [ 2 ] 65 = 52 x 1 + 13 -----> [1] 52 = 13 x 4 + 0 HCF = 13 13 = 65m + 117n From [ 1] ,13 = 65 - 52 x 1 From [2] ,52 = 117 - 65 x 1 ----> [3] Hence , 13 = 65 - [ 117 - 65 x 1 ] ------> from [3] = 65 x 2 - 117 = 65 x 2 + 117 x [-1 ] m = 2n = -1 |
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| 5262. |
of n, n+2, n+4 is divisibleby3.2. Find the HCF of 65 and 117 and expressit as a linear combination of 65 and 117. |
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| 5263. |
a dice is rolled 1oo times and its outcomes are as followsoutcomes 1 2 3 4 5 6frequency 12 15 20 14 21 18find the probability of gettinga multiple of 3. |
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Answer» Favourable outcomes = (20+18) = (38) Total outcomes = 100Probability of getting a multiple of 3 = 38/100 =0.38 |
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| 5264. |
c)A fair die is tossed 720 times. Use(i) The central limit theoremto findthe true probability; and(i) Chebyshev's inequality to find a lower boundFor the probability of getting 100 to 140 sixes. Use Ń (2-0.9772 |
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| 5265. |
12. A dice is rolled 100 times and its outcomes are as follows4,142118OutcomesFrequency 121520 |
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Answer» total frequency is 100 frequency of multiple of 3 = frequency of 3 + frequency of 6 = 20 + 18 = 38 so probability = 38/100 = 0.38 |
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| 5266. |
12. A dice is rolled 100 times and its outcomes are as followsOutcomes 1Frequency 12Find the probability of getting1520142118a. A multiple of 3. |
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Answer» total frequency is 100 frequency of multiple of 3 = frequency of 3 + frequency of 6 = 20 + 18 = 38 so probability = 38/100 = 0.38 |
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| 5267. |
A dice is rolled 100 times and its outcomes are as follows215320414618Outcomes21Frequency 12Find the probability of getting.A multiple of 3 |
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| 5268. |
12. A dice is rolled 100 times and its outcomes are as followsOutcomes 1Frequency 12Find the probability of gettinga. A multiple of 3.1514 212018 |
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Answer» Probability = possible outcomes/ total outcomes If dice is rolled 100 times then total outcomes = 100*6 = 600 possible outcomes for multiple of 3 = 20 + 16 = 36 Probability of multiple of 3= 36/600 = 6/100 =.06 |
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| 5269. |
12 A dice is rolled 100 times and its outcomes are as followsFrequency 12152014"2118Fiad the probability of gettinga A multiple of 3. |
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Answer» tqsm |
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| 5270. |
12. A dice is rolled 100 times and its outcomes are as follows6Outcomes 1Frequency 1215Find the probability of gettinga. A multiple of 320 14 21 18 |
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Answer» Multiples of 3 are 3 and 6hence total frequency 20+18=38hence probability will be 38/100=0.38 |
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| 5271. |
Represent the marks of the students of both tRe eclIOfrequeney polygons. From the two polygons compare the performancesections.of tThe runs scored by two teams A and B on the first 60 balls in a cbelow:7.Number of ballsTeam ATeam B7-1213-1819-2425-3031-3637-4243-4849-5455-602910510210Represent the data of both the teams on the same graph by frequencyHint: First make the class intervals continuous.] |
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| 5272. |
3. Tick (~) the correct one.10 million = 1 crorect number |
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Answer» 1 million = 10 lakh10 million = 100 lakh (b) yes yes no is the correct yes........................ b is the right answer b is the right.......... b is the right answer.... (b) is the right answer option b yes 10 million =1 crore. yes10 million equal to 1 crore Yes is the right answer yes is the correct answer no is the correct answer of the given question b is the correct answer B is the right answer |
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| 5273. |
ballsinacicketmatchaare given7. The runs seored by two teams A and B on the first 60belowTeam BTeam ANumber of balls1-67-1213-1819-2425-3031-3637-4243-4849-5455-6010410410Represent the data of both the teams on the same graph by frequency polygons.Hint: First make the class intervals continuous.] |
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| 5274. |
Let f: R- R be defined as f(x) 3x. Choose the correct answer.(A) fis one-one onto(C) fis one-one but not ontoR-> R be defined as fCr)(B) fis many-one onto(D) fis neither one-one nor onto. |
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| 5275. |
(viii) If O is the angle between two vectors a and , then a. 720only when :(A) 0<o<img(B) Osos(C) 0<0<(Choose the correct one)(D) 030sTurn Over |
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| 5276. |
FREEVYRIR111 LUIUI!22. The probability of winning of a game is x /12. If the probability of losing thegame is 1/3. Find the value of x. |
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| 5277. |
In a competition 3 points areawarded for each game won and1 point is deducted for every gamelost. A competitor attempted 15games and got 33 points. Howmany games did he win? |
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Answer» Total number of games = 15For each won points awarded = 3For each lost points deducted = 1 For 15 games won points should be 45 Thus, 3x - (15-x) = 334x = 33 + 154x = 48x = 48/4 = 12 So number of games won = 12number of games lost = 3 |
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| 5278. |
3. सिद्ध कीजिए कि ,/3 एक अआर्पाg e |
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Answer» सबसे पहले इसका उलटा मान लेते हैं; यानि मान लेते हैं कि √3 एक परिमेय संख्या है।ऐसी संख्या के लिये a और b दो ऐसी संख्या होंगी जहाँ b ≠ 0 तथा a और b कोप्राइम होंगे, ताकि;√3 = a/bया, b√3 = a दोनों तरफ का वर्ग करने पर यह समीकरण मिलता है;3b2= a2इसका मतलब है कि a23 से डिविजिबल होगा और इसलिये a भी 3 से डिविजिबल होगा।लेकिन यह हमारी पहले के मान का विरोधी है कि a और b कोप्राइम हैं, क्योंकि हमें 3 के रूप में a और b का कम से कम एक कॉमन फैक्टर मिल गया है।यह हमारे पहले मानी हुई संभावना कि b√3 प्रमेय संख्या है का भी विरोधाभाषी है।इसलिए एक b√3 अप्रमेय संख्या है सिद्ध हुआ |
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| 5279. |
EXERCISE 1.3Find each of the following products:(a) 3×(-1)c) (-21) x (-30)) ((b)(d)(f)(-1) x 225(-31 6) × (-1 )(-12) × (-11)×(10)15) × ○ × (-18)9×(-3) × (-6) |
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| 5280. |
1. Look at the table given below:11-20 21-3021-30Marks0-1031-40No. of students6The true lower limit of the class 21-30 is |
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| 5281. |
game |
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Answer» khel for mind fresh ohkkkkkkk |
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| 5282. |
3e+x=(g- g+ x (nâ= =t |
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| 5283. |
60, 4-10-{12-(5-4-31河丽(c) 6(a) 5(b) 4 |
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Answer» 4-[6-{12-(5-(-1))}]=4-[6-{12-6}]=4-[6-6]=4-0=4 |
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| 5284. |
d the product, using suitable proper(a) 26x (-48) + (-48) × (-36)(c) 15 × (-25) × (-4) × (-10)Evaluate(a) (-31)÷[(-30) + (-1) |
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Answer» a) -48(26-36) = -48*(-10) = 480b) 15*(-25)*(-4)*(-10) = -15000 |
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| 5285. |
\left. \begin{array} { c c c } { 1 - 10 } & { 11 - 20 } & { 21 - 30 } & { 31 - 40 } & { 41 - 50 } \\ { \vdots } & { 4 } & { 10 } & { 20 } & { 1 } & { 3 } \end{array} \right. |
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Answer» what to find mean, median or mode |
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| 5286. |
( 5 ro e v 0 3 )जम | e दर o {;' AL ".I‘ ALy nolynd muodo 4 3 .4 L 5 %13 ठहर Ao o k oPO lyno pral |
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| 5287. |
a) 2 pens and 3 note books togethercosts Ro. 66. Whersas 3 ponsand 2 note books together costs Rs. 54. What is the total costof 5 pens and 2 note books. |
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| 5288. |
EXERCISE 8.11. If the cost of 18 pens is 423, find the cost of 25 such pens2. A car travel 432 km in 48 l of netrol ou 5 |
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Answer» Cost of 18 pens is ₹423 So, cost of 1 pen is ₹423/18 = ₹ 23.5 Cost of 25 pens is ₹ 23.5 × 25 = ₹ 587.5 thank you so much |
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| 5289. |
. Arjit Sharma generally wears his father's coat. Unfortunately, his cousin Shaurya poked him one daythat he was wearing a coat of length more than hisheight by 15%. If the length of Arjit's father's coatis 120 cm then find the actual length of his coat. |
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Answer» the actual length of arjit coat is =15×100/120= 12.5 120-12.5=107.5 therefore arjits coat length is 107.5cm. 107.5 cm is the correct answer of the given question |
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| 5290. |
CELL...LL26. From a stationary shop, Archana bought two pencils and three pens for 40 and Indu bought onepencil and two pens for 25. Find the price of one pencil and one pen graphically. |
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Answer» 12 for pens and 2 for pencil 5 pencil 10 pen is the correct answer of the given question is |
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| 5291. |
10 A coat was sold by a shopkeeper at a gain of 5%. If it had been sold for1650 less, he would have suffered a loss of 5%. Find the cost price. |
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| 5292. |
(6) The total cost of 6 books and 7 pens is 79 rupees and the total cost of 7 books and 5 pensis 77 rupeess. Find the cost of 1 book and 2 pens. |
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Answer» Let the cost of the book be xAnd the cost of pen be yThen the cost of 6 books n 7 pens is6x+7y = 79And 7x+6y = 77Now let us add both equations13x + 13y = 156X+y = 12Let us subtract both equations-x + y = 2Now let us add the equations so obtained thenX-x + y +y = 12 + 22y = 14y = 7Substitute in one equation thenX + 7 = 12X = 5So the cost of one book is 5And one pen is 7So the cost of 1 book and 2 pens isX + 2y = 5 + 2(7) = 5 + 14 = 19 |
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| 5293. |
12:2 tables and 3 chairs together cost & 2000 whereas 3 tables and 2 chairs together cost t 2500.the total cost of I table and 5 chairs.ind |
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Answer» Let the cost of a table is Rs t and cost of a chair is Rs c. Given 2t + 3c = Rs 2000 ----------------1 And 3t + 2c = Rs 2500 -----------------2 Solve these two linear equations Multiply eqn 1 by 3 and eqn 2 by 2 6t + 9c = 6000 -----------3 6t + 4c = 5000------------4 Subtract Eqn 4 from 3 5c = 1000 c = 200 Substitute the value of c in eqn 1 2t + 3*200 = 2000 2t + 600 = 2000 2t = 1400 t = 700 The cost of a table is Rs 700 and Cost of 5 chairs = 5 * 200= Rs 1000. |
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| 5294. |
2 tables and 3 chairs toseparately,and 3 chairs together cost 2000 whereas 3 tables and 2 chairs together cost 2500d the total cost of 1 table and 5 chairs.Tooth |
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Answer» Let the cost of a table is Rs t and cost of a chair is Rs c. Given 2t + 3c = Rs 2000 ----------------1 And 3t + 2c = Rs 2500 -----------------2 Solve these two linear equations Multiply eqn 1 by 3 and eqn 2 by 2 6t + 9c = 6000 -----------3 6t + 4c = 5000------------4 Subtract Eqn 4 from 3 5c = 1000 c = 200 Substitute the value of c in eqn 1 2t + 3*200 = 2000 2t + 600 = 2000 2t = 1400The cost of a table is Rs 700 and Cost of 5 chairs = 5 * 200 = Rs 1000. |
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| 5295. |
The perimeter of a square painting is 8, m. How long is its each side? |
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Answer» Perimeter of a square= 4a = 8 4a=8a=2So it's side is 2 m long. |
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| 5296. |
EXERCISE 3Es and 4 tables together cost 2800 while 4 chairs and 3 tablest2170. Find the cost of a chair and that of a table.2 37 pens and 53 pencils tocoth |
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| 5297. |
What ghaul d be added to4 x^{2} y+5 x^{3}-6 x+0-6 x^{3}-2 x^{2} y+8 x-8 |
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| 5298. |
Three chairs and two tables cost * 700 and five chairs and three tables cost 1100.What is the total cost of 2 chairs and 3 tables? |
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| 5299. |
3 chairs and 2 tables cost Rs. 700/- while 5chairs and 3 tables cost Rs. 1100/-. Find outthe cost of 2 chairs and 1 table. |
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| 5300. |
(iii) 3 chairs and 4 tables cost 18,000, 4 chairsand 3 tables cost 15,600. Find the cost of achair and a table.Solution : |
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