InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 5401. |
If the length of the shadow of a vertical pole and theheight of the pole is equal. Find the altitude of sun at thatpoint. |
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| 5402. |
(If the length of the shadow of a vertical pole andthe height of tyhe pole is equal. Find the altitude of sun atthat point.) |
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| 5403. |
Prove that the angle between the internal bisector of one base angleand the external bisector of the other is equal to one haif of thevertical angle. |
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| 5404. |
. Fill in the blanks:(a) 1m3Litres.ä¸âŚ |
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Answer» 1m3 =100×100×100=1000000 1000 litres or 10000 litres |
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| 5405. |
In an isosceles triangle with base a, the vertical angle is 10 times any of the base angles. Find the length of the equal sides of the triangle. |
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| 5406. |
v 17 If a, b, c, d are integers, then what 4-digit number abcd satisfies the equation 4 x abcd = dcba?HOTS] |
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Answer» 4 x abcd = dcbaa should be 1 or 2a is multiple of 4 so should be even so a = 2d>= 8 but being multiple of 4d = 84bc +3 = cbb is odd or must be 1 or 2 so b = 1Last digit of4bc+3is1, so the last digit of4bcis8andc=2orc=7. Hencec=7abcd = 2178 ans thanks now I understand the problem |
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| 5407. |
6.I.Write the fractions. Are all these fractions equivalent?7.1000011000||()âä¸ 11 o lbe |
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Answer» a)1/2,2/4,3/6,4/8 yes all these fractions equivalent |
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| 5408. |
ABCD is a parallelogram and ABEF is a rectangle show that ∆AFD =~{congruent} ∆BEC. |
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Answer» Seg AD=seg BCangle FAD=angle CBE.seg AF =seg BE. ............... property of parallel linesBy SAS test∆ AFD=∆BEC |
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| 5409. |
(İftan A= 1/V3, then value ofcos A)-A)½B) 2C) 2/N3D) 3/2 |
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| 5410. |
find the angle of a parallelogram ABCD in which ∆A=2∆B |
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Answer» Given : angle A = 2 angle B We know in parallelogram the adjacent angles have sum 180°. A and B are adjacent angles So, angle A + angle B = 180° 2B + B = 180° 3B = 180 B = 60° A = 2 × 60° = 120° A = C = 120° ( opposite angle of parallelogram) B = D = 60° ( opposite angle of parallelogram) |
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| 5411. |
6b â 8(4b â9) +3b |
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Answer» 6b - 8(4b - 9) + 3b = 6b - 32b + 72 + 3b = 72 - 23b Expand the bracket, add like terms. |
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| 5412. |
N59. ABCD is a parallelogram with vertices A (x1,y), B (x2 , y ) and C(x3,y3)Find thecoordinates of the fourth vertex D in terms of xi, X2, X3, yl , ½ and â |
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Answer» If you like the solution, Please give it a 👍 |
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| 5413. |
X6 â9 + Ay â4x9 (p) |
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Answer» 6xy - 4y + 6 - 9x 2y( 3x - 2) -3( 3x - 2) ( 2y - 3)(3x - 2) |
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| 5414. |
10. The mean of six numbers is 30. if one number is excluded, the mean is 29. Find the valuewhich is excluded. |
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Answer» thanks |
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| 5415. |
The mean of 10 observations is 15.3. If twoobservations 6 and 9 are replaced by 8 and14 respectively the new mean is:a)6(b) 8(c) 14(d) 16 |
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Answer» kese hua Complete steps provided |
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| 5416. |
Find mean of the following observations:X 50 52 77 82 854 |
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Answer» Mean = [ 5(50) + 7(52) + 6(77) + 3(82) + 4(85) ] / (5+7+6+3+4)= (250+364+462+246+340)/ 25= 1662/25= 66.48 thanks |
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| 5417. |
what will be the mode of the following observations?2,7,9,11,2,4,7,6,11,7,3,5,7,6 |
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Answer» If you find this solution helpful, Please like it. |
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| 5418. |
O.Ilcos-5/13findsin Θandtan θ,-,Mean of 12 observations is 7. If the mean of firstbservations is 6, find the mean of last 4.observations.8One vear ago the father was & times as old as his son Now his |
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| 5419. |
Vidyamandir Classes: Innovating For Your Success7. In a picnic there are boys and girls. Fifteen girls leave, then the boys and girls are left in the ratio of2: 1. Later 45 boys leave and the ratio changes to 1 :5. The number of girls in the beginning was: to(A) 40(B) 43(C) 29(D) 50to 1 nirrenf wark in 3 hours, He and his son together finish it in 20 hours. The son along |
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Answer» what if we take girls x and boys y answer is coming wrong then,,,,BTW Thanks |
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| 5420. |
Pooja receives three hundred rupees from her mother of which she is spend 1 upon 8 on a book and bye buy a dress with 3 upon 5 of the the money how much money is left with Pooja? |
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Answer» Answer: Step-by-step explanation: Money spends on a book = (1/8)*300=300/8=37.5 Money spend on her dress= (3*300)/5 =900/5 =180 Total money she spend=180+37.5=217.5 Money left with pooja = total - spend =300-217.5= 82.5 pooja left 82.5 rsplz like my answer Pooja spend total money 1 Pooja= 82.5plz like my answer she spent on book=300×1/8 =75/2 spent on dress=300×3/5 =180total spent=180+75/2 =(360+75)/2 =435/2=217.5 rs.money left=300-217.5 =82.5 rs. ans. |
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| 5421. |
LANKINGPooja ran(a) 33in a class Rakesh is gth frobe her rank from the last?(b) 35(c) 37(d) 34 |
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| 5422. |
Pooja n=35 Kaiser aya |
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Answer» Please post the question in english! |
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| 5423. |
6. in a test Minir scured T amu2700. Some of them gave? 300 towards the bill and some10 friends went for a dinner. The bill amounted togave 200. How many gave 200? |
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Answer» Let Total number if friends give Rs 200 =x Then , Total number if friends give Rs 300 = 10 -x From given condition we get 300 ( 10 -x) + 200x = 2700 3000 - 300x + 200x= 2700 - 100x = - 300 x = 3 Therefore, Total number if friends give Rs 200 = 3 |
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| 5424. |
4. Rakhi's mother gave her110.50 and herfathergave her 15.80. Find the total amount givento Rakhi by her parents. |
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Answer» thanks |
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| 5425. |
) I had? 200 with me. I gave? x to Anwar,. Find the amount I gave to Vidhu._ to Vidhu a2 |
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| 5426. |
6.8Three planes can carry 1185 passengers. How many passengers can be carried inplanes?7.2250 clips are equally packed in 18 packets. How many clips are there in 13 packets? |
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Answer» 3 plane carry 1185 passenger.one plane carry 395 passengersThen 8 plane will carry 395×8 passengerMeans 3160 passengers 2250/18 * 13=125*13=1625 |
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| 5427. |
emean of 26, 14, x, 25, 15, 13, 27, 18 is 18.75. Find the value of x.The mean of six numbers is 30. If one number is excluded, the mean is 29. Find the valwhich is excluded |
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Answer» thanks |
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| 5428. |
sean mode and median of the following frequency distribution:Find the mean,andFrequencyClass Interval50-7070-9090-11012132718,110-130130 150150-170 |
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Answer» Who is the speaker in the poem |
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| 5429. |
The ages of ten students of a group are givenbelow. The ages have been recorded in yearsand months:8-6, 9-0, 8-4, 9-3, 7-8, 8-11, 8-7,9-2, 7-10, 8-8(i) What is the lowest age?(ii) What is the highest age?(iii) Determine the range?Q.6 |
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| 5430. |
1)10) In a class, 8 students out of 28 have a dog as their pet animal at home, 6 students have acat as their pet animal. 10 students have dog and cat both, then how many students donot have a dog or cat as their pet animal at home?1.11 |
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Answer» there are 11 students 4 students do not have a dog or cat as their pet animal. |
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| 5431. |
The following table shows the number of students and the time they utilizeddaily for their studies. Find the mean time spent by students for their studies bydirect method.Time (hrs.)No. of students0-22-44-66-88-10181210 |
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Answer» please like my answer if you find it useful |
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| 5432. |
y utilizetable shows the number of students and the time thedaily for their studies. Find the mean time spent by students for their studies bydirect method.Time (hrs.)No. of students76-88-102-4180-24-61210 |
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| 5433. |
55. In a class of 49 students, the ratio of girls toboys is 4:3. If 4 girls leave the class, the ratio ofgirls to boys would be(A) 11:7(B) 8:7(C) 6:5(D) 9:8 |
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Answer» Ratio is 4;3then girls will be 4/7× 49= 28now 4 girls left remaining = 24ratio = 24/21= 8/7 |
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| 5434. |
(D) 13: 1095. In a class of 49 students, the ratio of girlsboys is 4: 3. If 4 girls leave the class, the ratiogirls to boys would be(A) 11:7(B) 8:7(C) 6:5(D) 9:8 |
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| 5435. |
The internal measures of a cubical room are 12m x8m x4m¡Find the total costăwhite washing all four walls of a room, if the cost of white washing is 5 perm? Whawill be the cost of white washing, if the ceiling of the room is also white washed. |
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| 5436. |
The intenal measures of a cubical room are 12m x8m x4m Find the total cost ofwhite washing all four walls of a room, if the cost of white washing is 5permWhtwill be the cost of white washing, if the ceiling of the room is also white washed. |
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Answer» 2(l+b)h = LSA2(12+8)4 =2(20)4 = 40*4 = 160m²cost of whitewashing 4 walls =160*8 = Rs 1280area of 5 walls = LSA+ l*b = 160 + (12*8) = 160 + 96 = 256m²cost of whitewashing vd ceiling = Rs 1280 +(96*8) = Rs 1280 + 768 = Rs 2048 |
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| 5437. |
ता3% जा5st =cos™ £17 - 85 |
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Answer» We will use following trigonometric formulas in this solution - sin^-1(x) - sin^-1(y) = sin^-1{x√(1-y^2) - y√(1-x^2)}---------(1) sin^-1(x) = cos^-1{√(1 - x^2)}---------(2) {We have to prove that,} sin^-1(3/5) - sin^-1(8/17) = cos^-1(84/85) LHS = sin^-1(3/5) - sin^-1(8/17) {Using formula (1) in LHS} LHS = sin^-1{ 3/5 × √(1 - (8/17)^2 - 8/17 × √1 - (3/5)^2 } => LHS = sin^-1{ 3/5 × √(289-64)/17^2 - 8/17 × √8/17 × √(25-9)/25 } => LHS = sin^-1{ (3/5 × √(225/289) - 8/17 × √(16/25) } => LHS = sin-1 { (3/5 × 15/17) - (8/17 × 4/5) } => LHS = sin^-1 (45/85 - 32/85) => LHS = sin^-1(13/85) {By using the formula (2) now} LHS = cos^-1{√(1 - (13/85)^2)} => LHS = cos^-1{√(7225-169)/7225} => LHS = cos^-1(√7056/7225) => LHS = cos^-1{√(84×84)/(85×85)} => LHS = cos^1(84/85) = RHS {HENCE PROVED} convert sin in terms of tan we get in the formula tan A-tan B/1+ tanA.tanB so we can get the solution |
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| 5438. |
L 3cos55° - __4 cos 70° cossec 20’e - sin35° 7 tan5° tan25° tan 65 tan 85 |
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Answer» hit like if you find it useful |
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| 5439. |
5. A washing machine is marked at 8500. The shopkeeper allows discounts ot 20%What is the selling price of the washing machine? |
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Answer» discount on marked price of 8500 is 20% = 0.2*8500 = 1700rs so, selling price will be 8500-1700 = 6800rs |
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| 5440. |
EXERCIS E 14.11. A survey was conducted by a group of students as a part of their environment awarenesprogramme, in which they collected the following data regarding the number of plantsin 20 houses in a locality. Find the mean number of plants per house.Numbar of plants 0-2 2-4466-8 8-10 10-12Numberof houses1Which method did you use for finding the mean, and why?12-14 |
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| 5441. |
Hin Order Thinking Skills (HOTS)8. Find the absolute value of :1-- 15-5-5Remember. Operate from left to right |
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Answer» 5 is the correct answer -125 operate from left to right 5 is the correct answer 5 is the correct answer 5 is the correct answer of the given question 5 is the right answer of the following |
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| 5442. |
High Order Thinking Skills (HOTS)8. Find the absolute value of :-1 1 - 15 -5 -5Remember. Operate from left to right |
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Answer» -125 the correct answer of the given question |
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| 5443. |
High Order Thinking Skills36. Factorize (256x16 - 1). |
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| 5444. |
High Order Thinking Skills (HOTS)20. Simplify:It on-MT14om-n |
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| 5445. |
High Order Thinking Skills (HOTS)23. Find: y10 y2+108+v154 V225 |
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Answer» Please hit the like button if this helped you |
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| 5446. |
The selling price of 12 articles is equal to the cost price of I5 articles . the gAin Persent is . |
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| 5447. |
20 girls and 15 boys in a class.what is the ratio of number of girls to the number of boys?s the ratio of number of girls to the total number of students in the class |
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| 5448. |
6. There are 15 boys and 10 girls in a class. What is the percentage in the class o(a) girls(b) boys? |
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Answer» Total no. of students in a class = 15 + 10 = 25 Percentage of boys = (15/25)*100 = 60% Percentage of girls = (10/25)*100 = 40% |
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| 5449. |
1. There are 20 girls and 15 boys in a class.(a) What is the ratio of number of girls to the number of(b) What is the ratio of number of girls to the total numin the class? |
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Answer» (a) 4/3 and (b) 3/4 Ratio = number of girls/number of boys =20/15 (a) =4:3(Ans) Total number of students =20+15=35 Rato=number of girls/Total no of students =20/35 (b) =4:7(Ans) Ratio = number of girls/number of boys =20/15 (a) =4:3 now as given Total number of students =20+15=35 Ratowill be number of girls/Total no of students =20/35 (b) =4:7(Ans) |
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| 5450. |
Find the value of x, if the mean of 18, 5, 3, 12, 17, 10, x, 6, 6 is 9.n The mean attendance of a school for the first. four days of the week was 780 |
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Answer» 18+5+3+12+17+10+x+6+6/9 = 9 77+x = 81 x = 81-77 x = 4 Like my answer if you find it useful! |
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