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5701.

d) A jar contains 24 marbles, some are green andother are blue. If a marble is drawn at randomfrom the jar, the probability that it is green is 2/3.Find the number of blue balls in the iar

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5702.

The probability of selecting a blue marble at random from a jar thatcontains only blue, black and green marbles is . The probability ofselecting a black marble at random from the same jar is . If the jarcontains 11 green marbles, find the total number of marbles in the jar.4

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it will be 20as five blue11 green and 4 blackbecause probability is givenmeans 1out of totalso 1 out of 4 black1 out of 5 blueAnswer = 20

5703.

Abedket s in tre toofsis in the form of a frustrum of a cone of height is 30 cm with radi ofoffgits lower and upper ends as 10 cm and 20 cm respectively Find the capacitythe bucket, Aiso, find the cost of milk which can completely fill the containeratthe rate ofRu 25 per liter(Take %-314) 5yq("Oo-. A jar contains 24 marbles, some are green and others are blue. If a marble is

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Solution:-

Radius of the upper end of the frustum of cone = R = 20 cmradius of the lower end of the frustum of cone = r = 10 cmH = 30 cmVolume = 1/3πh[R² + r² + R*r]= 1/3*22/7*30*[20² + 10² + 20*10]= 660/21*[400 + 100 + 200]= (660*700)/21= 22000 cu cm or capacity = 22 litersNow, Slant height 'l' =√(R - r)² + h²l =√(20 - 10)² + 30²l =√10² + 30²l =√1000l = 31.62 cmSlant height is 31.62 cmSurface area =πR² +πr² +π(R + r)l=π[R² + r² + (R + r)*l]= 22/7*[20² + 10² + (20 + 10)*30]= 22/7*[400 + 100 + 30*30]= (22*1400)/7Surface area = 4400 sq cmCost of 1 liter milk = Rs. 25Total cost of 22 liter milk = 22*25=Rs 550

5704.

A jar contains black and white marbles. If there are ten marbles in thejar, which of the following could NOT be the ratio of black to whitemarbles?10.

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5705.

et ० कर हनन निजी “०0८०० S ot Qo= ot

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5706.

Ajay has 42 more seeds than Vijay000000OOOOOOOOOOOOOOOO000je vertically and subtract.5 - 425(2) 465 - 179(3) 542 - 3511 - 287(5) 500 - 365(6) 502 – 307- 100 = 300, solve 477 - 177. Write three subtraction problems with th200.buys a uniform worth *372 and a school bag worth *250. How muloes she spend on the uniform than on the bag ?uswer to an addition is 915. One of the numbers is 427. Which is the otr?swer to an addition is 915. Choose any number smaller than 800 asnumbers. Find the other number.the numbers 534 and 252, write a subtraction word problem and solveK23

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(2)465-179=286, (3)542-351=191, (5)500-365=135, (6)502-307=195

477-177=300; 915-427=488; 915-800=115; 534-252=282

5707.

-What number should replace the question mark?2784the question mark ?

Answer»

4 is repalace in the question mark box.please like my answer

4 is the correct answer of the given question.

4 is the following question answer

4 is the correct answer of the question correct answer question

4 is replace in the question mark box.please like my answer

4 is correct answer.

4 is right answer....

4 is the replace in the question mark box.please like and comment my answer

4 is correct answer.every three numbers makes sum of 19

5708.

Which number replaces the question mark?1329125

Answer»

253 is the right answer hope this helps you

5709.

MATHSSOLVE THE FOLLOWING PUZZLES.What number should replace the question mark?OOOO

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5710.

Which number replaces the question mark?41247422

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In 1st triangle (9+7)-4=16-4=12

In 2nd triangle(4+1)-1=5-1=4

Thus in 3rd triangle(6+5)-2=11-2=9

9 is correct answer for the sim

5711.

What will replace the question mark3, S. 13, 43, 177,5353in the follow

Answer»

The solution is:

if we notice the series, we can see that,after the 1st number, 2nd number is generated by:3*1 + (1+1) = 5then next after is:5*2 + (2+1) = 13So on and so forth, thus missing number becomes:177*5 + (5+1) = 891

5712.

What number should replace the questionmark?47X55 X638592 X997325

Answer»

47+8=55 and 55+8=63similarly, 85+7=92 and 92+7=99so, let the missing number be y and the term we need to add in it to make 73 be xso, 25+x=yy+x=73solve them to get, y=49( answer)

5713.

2.= 0, તો X = ..| 1 2 5|જો 1 x 5|3 -1 2(a) 2(c) 5.(b) -2(d) -5

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B) -2 is the correct answer

5714.

Which number replaces the question mark?3A. 7B. 5C. 9D. 11

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option C) 9 is the right answer

9 is the correct answer

option (C) is the right answer

5715.

Which number replaces the question mark?36A. 31B. 13C. 12D. 21

Answer»

C) 12 the right answer

B) the correct answer

5716.

•Verityforthe pecoperty :la: 4 b = -8axcb+c) = caXb+com)-2

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5717.

8) In a triangle ABC, LA 120° and2B = 22C. Find <B and <C.

Answer»

In triangle sum of all angles is 180°

Given angle A = 120Let angle C = xThen angle B = 2x

Using triangle angle sum propertyx + 2x + 120 = 1803x = 180 - 120x = 60/3 = 20

Therefore,Angle B = 2x = 2*2*= 40°Angle C = x = 20°

5718.

5 ^ { - 3 / 2 } + 5 ^ { - 1 / 2 } + 5 ^ { 1 / 2 }

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ans 31/25

5719.

mount100 - 100100 100

Answer»

1 is correct answer.

1 is the correct answer

1 is correct answer...

1 is the correct answer

1/1=1 is the answer......

1 is the right answer

1 is a good answered

1 is a correct answer

1 is the correct answer of the given question

100÷100=1so 1/1= 11 is the correct answer

Your answer is 1Thanks for asking

100÷100/100÷1001/11 answer

1/1 is equal to 1 . so is answer

1 is the right answer

1 is the correct answer

1 is a correct answer

5720.

where is Mount Everest

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Mount Everest is located on the border between Tibet andNepalin the Himalayas in Asia.

5721.

2500 for 2 years at 10% per annum1. Find the amount and the compound interest oncompounded annually.

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5722.

17. In the given figure, BE is the bisector of 2B and CE is the bisector ofZACDProve that ZBEC·LA.CD

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5723.

uiu me get besides the greetingsOf the 5675 people in a village $448 are literate. What is the percentage of literacyin the village?

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Percentage of literacy= (Number of literates/Total No. of people )×100 =544800/5675 =96

5724.

PyZ uiu:’f A _dngudon cand phat 42 0हद कि G5 ou"j‘- जि 24. 2421:० N gfi”& LU .A_,,A.u’: Y. ana A g Q)किए 25.

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Like if you find it useful

5725.

40^{\circ} 37^{1} 30^{\prime \prime}

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thnks soo.much 😍😍😍

5726.

The leigur UIu(2) Sahil has12 less than three times what Sohan has. If both have a total of88, how many rupees each must have got ?Rooto The nresent age of

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hit like if you find it useful

5727.

17the given figure, BE is the bisector of B and CE is the bisector ofCACDProve that BEC-LA28

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5728.

2. 1 UUIU IILUL LOL$/ The product of two numbers is 504347. If one of the numbers is 317, find the other.umher the quotient is 189 and the remainder is 37

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other number = (504347) /(317) =1591 Ans

2nd number = (504347) /(317) =1591 Ans

let the other no. is XX×317=504347X=504347/317X=1591the other no is 1591

5729.

Find the lulal uIuand height 60 cm.. If the slant height of a cone is 18.7 cm and the curved surface area is 602.8 cm, find thevolume of cone. (T 3.14)2 then find the volume of sphere. (Take Tt #: 3.14)

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taking π = 3.14

5730.

ORSolve for x:(atb+x) a-+ bt x , I t

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5731.

Find the value of x where atb* *.+ + + ,

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1/a + 1/b + 1/c= bc/a +ca/b + ab/c=bc+ca+ab/abc=2abc/abc=2

5732.

Ex.9. 6 men can earn150 in 10 days. Howmuch money will be earned by 8 men in 7days ?

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5733.

What sum of money must be givenat simple interest for nix months at496 per nnum in order to earn Rs.150 interest ?

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150 = P×4×6/(12×100) P = 25×100×3 = 7500

5734.

* Kiran bought 1 kg plastic for Rs 10, but sold 1 kg plasticHow much money does she earn on selling i kgfor Rs 12.plastic? Rs

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5735.

(a) If a number is divisible by 4, then it is divisible by 2.inrim then it is odd number.

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yes if the number is divisible by 4 Sothe number is also divisible by 2.

the right answer is 16

yes,it is also divisible by 2 ofcourse

5736.

umber which is exactly divisible by 20, 25, 30est number which divides 630 and 940 leaving remainders 6 andrespectively.

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5737.

y uvides 81 and 117.umber to which if 7 be added, the number obtained be exactly divisible by 25, 45,5673. Find the smallest number to which163, 84.hor of 5 dicit

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the smallest number divisible by 24,25

is 600

if 7 is less than 600 then

593 is the number , wgich is smallest as he asked

5738.

Let Us Do 2.31. Tthe Hamber nhach i disisible by 9 is(0 201(ii) 3556(ii) 3.206(v) 60126 9uy)99(00 992(iv) none of thesethe sum of its digits is divisible by 9the m of its digits is divisible by 1are div isible by a umber, then their is albo divisible by that numbersum(iv) all the aboveS The swn of two consecutive ol mmbers is ahways dirviuble by0 4(uo Stv) 12The smallest digat which cao replace to make 201 38 divisible by 1is0) 2228 27 425 62s1Q, 9u 2,100's 2624,12.15,6/%,6/92,14340,21,084ind the laggestbumbet is a primeprime momber requirad ho test as a divisoe to determine if the fotlow ingmomber Abo determine ir the mbe is aprime umber: 117, 1smmber219 21, 30 38 421, sA mmer divisle by 3 is also divisiNe by o(a) A mumber dvsble by Is sdhsue ty hech and

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2.999 because sum of all the digits of 999 is9+9+9=27which is divisible by 3

5739.

mid point therom

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The Midpoint Theoremstates that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

5740.

bisector therom of triangle

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theangle bisector theoremis concerned with the relativelengthsof the two segments that atriangle's side is divided into by a line thatbisectsthe opposite angle. It equates their relative lengths to the relative lengths of the other two sides of the triangle.

5741.

6. What is the role of saliva in the digrstion of food

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5742.

The tangent and normal at P(t), for all real positive t, to the parabola y2 4ax meet the axis of theparabola in Tand G respectively, then the angle at which the tangent at P to the parabola is inclined to thetangent at P to the circle passing through the points P, T and GisA) cott(B) cot 1t2Š tan-It(D) tan t

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5743.

PQ is a double ordinate of the parabola y2=4ax. Thelocus of the points of trisection of PQ is(a) 9y2=4ax(c) 9y2+4ax=0(b) 9x2= 4ay(d) 9x2+4ay=0

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5744.

Find this when yº = 4ax.

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Differentiation on both sides2ydy/dx=4ady/dx=4a/2yd^2y/dx^2=-4a*2*dy/dx/4y^2d^2y/dx^2=-2a/y^2*dy/dx

5745.

0 —4ax +ab - 4bx

Answer»

a(a-4x)+b(a-4x)(a-4x)(a+b)

5746.

8abatbx-4aX

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5747.

Derive the equation of parabola y^2 =4ax in standard form.

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Let S be the focus and the linelbe the directrix. Draw SZ perpendicular to the linel. Take O as the midpoint of SZ. Now take O as the origin. Take OS produced as X-axis and the perpendicular to OS at O as Y-axis. Let SZ = 2a. The OS = a. Therefore, S=(a,0)

Now let P(x,y) be any point on the curve. Join PS and draw PM perpendicular to the lineland PN perpendicular to x-axis

Then by definition of the parabola, PS = PM. By distance formula, PS = rt { (x-a)^2 + y- 0)^2} and PM = NZ = x + a

Hence squaring we have (x-a)^2 +y^2 = (x+a)^2 or x^2 -2ax + a^2 + y^2 = x^2 + 2ax + a^2 i.e., y^2 = 4ax

Hence the equation of the parabola is y^2 = 4ax

5748.

erive the equation of parabola y^2 = 4ax in standard for

Answer»

Let S be the focus and the linelbe the directrix. Draw SZ perpendicular to the linel. Take O as the midpoint of SZ. Now take O as the origin. Take OS produced as X-axis and the perpendicular to OS at O as Y-axis. Let SZ = 2a. The OS = a. Therefore, S=(a,0)

Now let P(x,y) be any point on the curve. Join PS and draw PM perpendicular to the lineland PN perpendicular to x-axis

Then by definition of the parabola, PS = PM. By distance formula, PS = rt { (x-a)^2 + y- 0)^2} and PM = NZ = x + a

Hence squaring we have (x-a)^2 +y^2 = (x+a)^2 or x^2 -2ax + a^2 + y^2 = x^2 + 2ax + a^2 i.e., y^2 = 4ax

Hence the equation of the parabola is y^2 = 4ax

5749.

) Write the subtangent of the curvey^2 = 4ax.) Define asymptotes.

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An asymptote is a value that you get closer and closer to, but never quite reach. In mathematics, an asymptote is a horizontal, vertical, or slanted line that a graph approaches but never touches.

5750.

11.The probability of selecting a red ball at random from a jar that contains only red, blue and1orange ball is 4. The probability of selecting a blue ball at random from the same jar is 3If this jar contains 10 orange balls, then what is the total number of balls in the jar ?

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a box contain 4 green balls, 6 red balls, and 5 blue balls. A ball is selected at random from the box. Find the probability of getting (a) red ball ( b) a blue balls