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| 60951. |
12. In the given figure, prove that(i) Δ AOD Δ BOC(ii) AD BC(ii) ZADB LACB(iv) Δ ADB Δ BCA |
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Answer» What is the full form of V. O. A |
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| 60952. |
30. If tanθ + sin.-m and tanA-sinθn, show that m2-n2-4/mn |
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| 60953. |
In ∆ABC, AD L Bc and BE L AC. If BC=16 cm, AD= 6 cm and BE= 8 cm, then find AC. |
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| 60954. |
In the adjacent figure, AC-AE AB ADand ZBAD LEAC. Show thatBC = DE.B4 |
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| 60955. |
n, show that rna_ n24/mn.If tan θ + sin 0-m and tan θ-sin θ |
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| 60956. |
solve the pair of equation by reducing them to a pair of linear equation1/2x+1/3y=21/3x+1/2y=13/6 |
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| 60957. |
Q 26: Solve the equation: 2(r 3)+3(x - 2)(2x -3) 8(x+4)(x 4)-1 |
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Answer» 2(x^2+9-6x)+3[2x^2-3x-4x+6]= 8(x^2-16)-1 |
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| 60958. |
Find the measure of an angle which is onefifth of its supplement. |
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Answer» let the angle =x x=180/5x= 36°because two angles are supplementary when they add upto 180 |
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| 60959. |
(ख) सिद्ध कीजिए किm-n2 =4/mn यदि tane +sin e =m औरtane-sin e=n.चार्ट |
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Answer» pta nhi iska answer sayad ye trigonometry ha |
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| 60960. |
nd a number whose three-fourth of one-fifth is 60. |
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Answer» Let the number be x Given (3/4) (1/5)x =60 (3/4) (1/5)x = 60 3/20 x = 60 x = 60 ÷3/20 x = 400 |
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| 60961. |
e Crdova Smart Class Software on the smart board in class to do ExerciseAxYz,1. In AABCand AXYZ, AB2.6 cm, ะะก-3cm, BC-3.5 cm, XY3.5 cm, XZ-26 cm and YZh3.5cm3.5 cmre the two triangles congruent? If yes, write the congruence relation in symbolic form.2. In given figure AB = BD and CA-DC |
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Answer» Yes these two triangles are congruent. Three sides of the triangles are equal [ SSS congruency] Please hit the like button if this helped you out |
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| 60962. |
Find a number whose three-fourth of one-fifth is 60. |
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| 60963. |
s if thepernnetua wire of 440 m length is moulded in the form of a circle and a square turn-by-turn,find the ratio of the area of the circle to that of square,grtho aras of the square that can he inscribed in a circle of radius 8 cm. |
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Answer» Length of wire = 440 mSo, this will be considered as the perimeter for a square and circumference for a circle.So, according to the question.Circumference of circle = 2πr440 = 2*22/7*r44r = 440*7r = (440*7)/44Radius of the circle = 70 m.Now, area of the circle =πr²= 22/7*70*7Area of the circle = 15400 sq mNow,Perimeter of the square = 440 mEach side of square = Perimeter/4= 440/4Each side of square = 110 mNow,Area of the square = side× side= 110× 110Area of the square = 12100 sq mNow,Ratio of the area of the circle to that the area of the square.= 15400 : 12100Ratio = 14 : 11 |
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| 60964. |
3.33 g \text { into } cg |
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Answer» 1Grams =100Centigrams3.33g =3.33×100=333cg |
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| 60965. |
9Qo5 [Cg; (25â (.E_" )3 ' |
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| 60966. |
65 In thIn the given figure, find the area of theshaded portion with given measurements.14 cm |
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Answer» 154+154/2= 154cm^2 |
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| 60967. |
क) चित्र में, 400 1 80 हैं। सिद्ध कीजिए : AB? + CD? = BD? + AC? |
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Answer» if help then plzz like |
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| 60968. |
28. In AABC, m2BAC 90 AD L BC. Then from thefollowings which one is corredt(1) BC2 BD CD (2) BC2 AB AC(3) AD2 BD.CD (4) AD2 AB AC |
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| 60969. |
In the adjoining figure, AB = BC and AC = CD.Prove that : <BAD : <ADB = 3 : 1 |
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| 60970. |
2 In the adjoining figure, ABBC and ACCD.Prove that : ZBAD ZADB 3 1. |
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| 60971. |
JuIvE uRy two of the following sub-questions.)Find the value of m' for which the given simultaesolution.04iquee given simultaneous equations have unmx + 5y-11=0: 14x = 15-7y |
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Answer» From which book have you taken this question? Please tell us so that we can provide you faster answer. |
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| 60972. |
2Factorise: 212+ 3-22/2 2 3 |
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| 60973. |
((2^2*3^2)/((2^3*6^2)))^2 |
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| 60974. |
1. Complete the following activities to prepare simultanenring activities to prepare simultaneous equations frominformation : Write them in the boxes shown by arrows.the given(2 marks each)Equation 1Equation 22x + 2y =My perimeteris 90 cmI am a rectangle.My length is x cmand breadth is y cmMy length is3 cm lessthan twicethe breadthWrite the equationsin the form ax + by=c(ii)The cost of an apple is xThe cost of a guava isy |
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| 60975. |
If cot x (1 + sin x)4 m and cot x (1-sin x) = 4 n , prove that(m2-n2)-mn.22. |
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| 60976. |
Find a number whose three-fourth of one-fifth is 60 |
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| 60977. |
subtracted from one-fifth oftribeted from one-fifth of a number gives 1 Find thehalf of a number, the result is double the number. Find the number |
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| 60978. |
One fifth of a number is 7. |
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Answer» Suppose that number is xthen1/5 th of x = 7x/5= 7x= 35That number is 35 thankyou |
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| 60979. |
5. lf 0 < x < π , and if y.+1y+111 + sin χ|1 + sin x, then y is equal to(a) cot(b) tan(c) cot 7 + tan(d) cot -tan222 |
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| 60980. |
\int \frac{(1+\cot x)}{(x+\log \sin x)} d x |
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| 60981. |
If $ y=\sin ^{2}\left[\cot ^{-1}\left(\frac{1}{\sqrt{\frac{1+x}{1-x}}}\right)\right] $ then find $ \frac{d y}{d x} $ |
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| 60982. |
7 In the given figure,ABC75. Find LADO |
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Answer» in cyclic quarilateral opposite angles make sum of 180°soangle b+ angle d = 180°angle ADC = 180-75°115° |
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| 60983. |
In the given figure, ABC and DBC are two triangleson the same base BC. If AD intersects BC at Othen prove that:-18area (ABC) AOarea (DBC) DO |
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| 60984. |
In the given figure, ABC is a right-angled triangle at C. Provethat ΔABC-AADE and find the lengths of AE and DE |
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| 60985. |
20.In the given figure, O is a point in the interior of a triangle ABC, OD LBC, OE 1 AC andOF AB. Show thatORIn the given figure, ABC and DBC are two triangles on thesame base BC. If AD intersects BC at O, show that arasCGA0ar(DBC)DO |
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| 60986. |
\frac { d } { d x } \tan ^ { - 1 } \left( \frac { \sqrt { 1 + \sin x } + \sqrt { 1 + \sin x } } { \sqrt { 1 + \sin x } - \sqrt { 1 + \sin x } } \right) = |
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Answer» tan-1√1+sinx/1-sinsx^ = tan-1√(cos^2x/2 + sin^2x/2 + 2*sinx/2*cosx/2)/(cos^2x/2 + sin^2x/2 – 2*sinx/2*cosx/2) =tan-1√(cosx/2 + sinx/2)^2/(cosx/2–sinx/2)2 =tan-1(cosx/2 + sinx/2)/(cosx/2–sinx/2) =tan-1(1 + tanx/2)/(1–tanx/2) (by dividing the numerator & denominator by cos x/2) =tan-1(tan(pi/4) + x/2) =(pi/4) + x/2 Henced/dx tan-1√1+sinx/1-sinx = d/dx [(pi/4) + x/2] = 1/2 Ans: 1/2 |
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| 60987. |
24. In the given figure, ABC is a triangle in which LA : ZB : <C = 3 : 2 : 1and AC 1 CD. Find the measure of LECD |
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| 60988. |
AlgeWrite down the algebraic expression whose terms are:(1) 5a, -36, (ii) x² – 5x, 6 (iii) x²y, xy, - xy?.4. Write all the terms of each of the following |
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Answer» 5a-3b+c x²-5x+6x²y+xy-xy² the correct answer of the given question |
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| 60989. |
2121: The product of ( and 2 3)(1) +102y+3y(3) 6x+10r'y +3y |
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| 60990. |
i. From the given determinants, form two simultaneous equations and solve them.3 21=9; 1-1 21 |
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Answer» Which one of the following is not a quadratic equation? |
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| 60991. |
A. Write an algebraic expression for each1. 2 subtracted from the sum of x and phe l |
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Answer» Sum of x and p is x+p 2 is subtracted from it Therefore, (x+p)-2 |
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| 60992. |
6.x is multiplied by itself and then added to the product of x & y.( Write in algebraic expression) |
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Answer» like the answer if it helps you |
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| 60993. |
\cot ^ { - 1 } \left\{ \frac { \sqrt { 1 - \sin x } + \sqrt { 1 + \sin x } } { \sqrt { 1 - \sin x } - \sqrt { 1 + \sin x } } \right\} |
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| 60994. |
. The sides of a triangle are in the ratio 3:5:7 andits perimeter is 600 cm. Find the area of the triangle. |
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| 60995. |
s. Write the algebraic expressions for the following statementOne fifth of n multiplied by difference of x and y. |
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Answer» i) expression will be(1/5 × n )(x-y)(x-y)n/5 |
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| 60996. |
\cot ^{-1}\left(\frac{\sqrt{1-\sin x}+\sqrt{1+\sin x}}{\sqrt{1-\sin x}-\sqrt{1+\sin x}}\right)= |
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| 60997. |
1), In figure, LB < 90° and ADL BC. Prove that :AC2 = AB" + BC2-2BCBD |
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| 60998. |
ute were recordede wer choosing a suitable method.ned in a hospital by adoctor and the number of hear beats perd summarised as follows.Find the mean heart beats per mimute221for these womenrt beat 65-68 68-71 71.74 14-.Namber of heartper minuteNumber of women |
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| 60999. |
. In âłABC, ADIBC and point D lies on BC such that 2DB =3BC. Prove that |
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| 61000. |
3.Find the measures of x,y and z in the figure, where I ll BC→7 |
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