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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 61051. |
\lim _ { x \rightarrow 0 } x ^ { x } = ? |
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Answer» thanks bro |
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| 61052. |
5 dn a regular hexagon ABCDEF, AB |EDI | the x-axis. What arethe slopes of its sides? |
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Answer» 1st 2nd |
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| 61053. |
. (a) If ABCDEF is regular hexagon then show thatAB+AC+ AD+AE+AF 3AD |
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| 61054. |
In Fig. 9, is shown a sector OAP of a circle with centre o, containing ABis perpendicular to the radius OA and meets OP produced at B. Prove that-1]the perimeter of shaded region is r tano + sec0 + 19180OAFigure 9 |
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| 61055. |
\lim _{x \rightarrow 0} x \csc x |
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| 61056. |
agiven-interest com pounded annualla Ann. Rs. 8ουο be ca me Rs. lo,580 akten 2 years'what was the yale interes? |
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Answer» A = P(1+r/100) ^ |
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| 61057. |
\lim _{x \rightarrow 0} x \sec x |
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Answer» Lim x tends to 0x/cosxnow putting limits0/cos00/1= 0 |
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| 61058. |
3. In Fig. 6.18, if LMCB and LN | | CD, prove thatAM ANNAB AD |
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Answer» LM || CBBy using basic proportionality theorem, we get,AM/MB = AL/AC ...(i)Similarly, LN || CD∴ AN/AD = AL/AC ...(ii)From(i)and(ii), we getAM/MB = AN/AD figure is this in this question |
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| 61059. |
(a) Determine P, so that the following equaticoincident roots : t2+ p 2 (p 1) t. |
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| 61060. |
arm eac aaenthits13.Iti finehedeMetea linde? Ä°S10cm, andbasera dius 3.sem, Find the fo fal sufake anca et tha rticle |
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| 61061. |
man donates 10 aluminum buckets to an orphanage. A bucket made of aluminum isof height 20 cm and has its upper and lowest ends of radius 36 cm and 21 cmrespectively. Find the cost of preparing 10 buckets if the cost of aluminum sheet is42 per 100 cm2. Write your comments on the act of the man. |
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Answer» Surface area of bucket = π(r1 + r2)l + πr12 l = √[h2 + (r2 - r1)2] = √625 = 25 cm ∴ Surface area of 1 bucket = 22/7 × 1866 cm2 Surface area of 10 buckets = 22/7 × 18660 cm2 Cost of aluminium sheet = Rs. 24631.20 Like my answer if you find it useful! |
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| 61062. |
A man donates 10 aluminum buckets to an orphanage. A bucket made of aluminum isof height 20 cm and has its upper and lowest ends of radius 36 cm and 21 cnmrespectively. Find the cost of preparing 10 buckets if the cost of aluminum sheet is42 per 100 cm2. Write your comments on the act of the man30/2 |
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Answer» i also want this answer Surface area of bucket = π(r1 + r2)l + πr1² l = √[h² + (r1 - r2)²] = √[20² + (36 - 21)²] = √625 = 25 cm ∴ Surface area of 1 bucket = 22/7 × 1866 cm2 Surface area of 10 buckets = 22/7 × 18660 cm2 Cost of aluminium sheet = Rs. 24631.20 The man is kind-hearted and values others needs. |
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| 61063. |
hcre is a reqular hexagon ABCDEF offnd the anca of hexagn |
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| 61064. |
2. Find the compound interest on 6,500 for two years at 9% per ann..2 find theand compound interest on a sum of 8.00 at 50%.. Int |
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| 61065. |
044.at K.MNOPQis a regular pentagon. The bisector of angle M meets side OPFind measure of MKO |
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Answer» thanks😁😁😁😁 |
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| 61066. |
DLW JULUTL15km on toot. Find the5 tom in 3 hours, partly on foot at the rate of 5 km/h and aFind the total distance25. A boy covers a distance of 25 km in 3 hours partthe rate of 10 km/h. Find the distance covered on foot.kmh and party on beyekea |
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| 61067. |
10. A train at a uniform speed covers a distanceof 255 km in 15 hours. Find the speed of thetrain and the distance covered in 3 hours. |
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Answer» We know,Distance = speed * time Speed of train= 255 / 3/2= 85*2 = 170 km/hr Therefore,Distance covered in 19/5 hours= 170 * 19/5= 34 * 19= 646 km |
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| 61068. |
eaxe-e ax(9)limX0X |
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Answer» sinax is the right answer |
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| 61069. |
A cicalar Blower bed is of radius 3.5 m. If J kg of fentilizer is roquired for I square mtre anca, howmuch fertilizer will be required for the flower bed? |
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Answer» => Radius of the circular flower bed = 3.5 m => Area of the circular flower bed = π × r^2= 22/7 × (3.5)^2= 22/7 × 12.25= 22 × 1.75= 38.5 m^2 => Fertilizer required for 1 m^2 = 1/2 kg = 0.5 kg => Fertilizer required for 38.5 m^2 = 0.5 × 38.5= 19.25 kg= 19 1/4 kg |
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| 61070. |
was aann |
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Answer» Iwill be using A instead of theta we have , RHS=cosA+sinA=√2cosAsquaring both the sides =>(cosA+sinA)²=2cos²A=>cos²A+sin²A+2sinAcosA=2cos²A=>cos²A-2cos²A+2sinAcosA= -sin²A=> -cos²A+2sinAcosA= -sin²A=> cos²A-2sinAcosA=sin²Aadding sin²A on both the sides => cos²A+sin²A-2sinAcosA=2sin²A=> (cosA-sinA)²=2sin²A=> cosA-sinA=√2sinA L.H.S |
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| 61071. |
List things we use more than one litre at a time.Water for taking bath |
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| 61072. |
VRSS£TUS .JJ.L_ नि कि10 |
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Answer» 2 cos^2 67/cos(90-23) = 2 cos^2 67/cos 67 = 2 cos 67 Like my answer if you find it useful! |
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| 61073. |
2UUSUL05. Find the value of m, when (m+1)x=3ky+15=0 and 5x+ky+5=0 are coincident06 Ilan ann muntinligation method to solve ay+hysabb |
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| 61074. |
,Y1. It takes 77 minutes to fill 11 buckets of water. How much time willit take tofll 7 suchuaTeUHthesmartboardin class to do Exercise24buckets? |
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Answer» time taken to fill 11 buckets =77min.time taken to fill bucket =77÷11=7min.time taken to fill 1 bucket =7×7=49min |
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| 61075. |
0.28 A man donates 10 aluminum buckets to an orphanage. A bucket made of aluminam is of height 20em and has its upper and lowest ends of radius 36 cm and 21 cm respectively. Find the cost ofpreparing 10 buckets if the cost of aluminum sheet is Rs 42 per 100 cm2. Write your comments onthe act of the man. |
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Answer» Step-by-step explanation: Find the surface area of 1 bucket: Surface Area = π(R - r)√[(R - r)² + h²] Surface Area = π(36 - 21)√[(36 - 21)² + 20²] Surface Area = 375π cm² Find the surface area of 10 buckets: 1 bucket = 375π cm² 10 buckets = 375π x 10 = 3750π cm² Find the cost: 100 cm² = Rs 42 3750π cm² = 42/100 x 3750π = Rs 4950 |
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| 61076. |
of Poove thathumbes2 tus is an isrational |
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Answer» Let 2+√5 be a rational number. A rational number can be written in the form of p/q where p,q are integers. 2+√5 = p/q Squaring on both sides, (2+√5)² = (p/q)² 4+√5²+2(√5)(2) = p²/q² 4+5+4√10 = p²/q² 9+4√10 = p²/q² 4√10 = p²/q² - 9 √10 = (p²-9q²)/4q p,q are integers then (p²-9q²)/4q is a rational number. Then √10 is also a rational number. But this contradicts the fact that √10 is an irrational number. .°. Our supposition is false. 2+√5 is an irrational number. Hence proved. |
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| 61077. |
.ance of 20.25 km in 2.5 hours. What is the average0.25 km in 2.5 hours. What is the average4A car covers a distance of 20.25 km in 2.5 hoursdistance covered by it in 1 hour? |
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Answer» ln 2.5hours distance covered=20.25In 1 hour distance covered=20.25/2.5 =2025/(25×10) =81/10 =8.1 km |
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| 61078. |
कहत है।न 6. प्रोकैरियोटिक कोशिकाओं में डी०एन०एनर-प्रोकैरियोटिक कोशिकाओं के कोशाद्रव्य में डीको पीढ़ी दर पीढ़ी पहुँचाता है। कोशिका की उपापबहुविकल्पीन 1. मनुष्य में गुणसूत्रों की संख्या होती है-(044,i) 45,न 2. पुरुष में लिंग गुणसूत्र होते हैं-(O Xx,(ii) XY,न 3. निम्न में कौन-सा आनुवंशिक पदार्थ है।(i) आर०एन०ए०, () डी०एन०ए०,न 4. केन्द्रक बना होता है-() प्रोटीन से,ii) आर०एन०ए० (R.N.A.) से,15. डी०एन०ए० (D.N.A.) अणु में-G-T,(iii) |
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Answer» (1) 45(2) xx(3)DNA(4) RNA a. 45b. xxc. DNAd.RNA is the |
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| 61079. |
10. In the adjoining figure, find the value of x.125ann anca Find the probability of getting |
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Answer» value of x is 55. please like my answer give me best 55 is the correct answer. |
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| 61080. |
\tan 48 ^ { \circ } \tan 23 ^ { \circ } \tan 42 ^ { \circ } \tan 67 ^ { \circ } = 1 |
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Answer» tan42=tan(90-48)=cot48 tan23=tan(90-67)=cot67 tan48tan23tan42tan67 = tan48cot67cot48cot67 = 1*1 = 1 Thanks |
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| 61081. |
A tank is full of 300 L of water. How much water willbe filled in 25 tanks? If 15 buckets canone tank of water, how many buckets in all can befilled with the water in 25 tanks?be filled with |
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| 61082. |
2. Show that:(i) tan 48° tan 23° tan 42o tan 67° 1 |
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Answer» tan 48° tan 23° tan 42° tan 67° = tan (90° - 42°) tan (90° - 67°) tan 42° tan 67° = cot 42° cot 67° tan 42° tan 67° = (cot 42° tan 42°) (cot 67° tan 67°) = 1×1 = 1 |
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| 61083. |
कि MITEUL 46 नtan 48° tan 23° tan 42° tan 67° = 1 |
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Answer» = tan (90° − 42°) tan (90° − 67°) tan 42° tan 67° = cot 42° cot 67° tan 42° tan 67° = (cot 42° tan 42°) (cot 67° tan 67°) = (1) (1) = 1 |
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| 61084. |
17.—X—+6 9 9(a) 044(c) 04952 26iका सरलतम रूप है® 032( 036 |
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Answer» The correct answer is option a 0.44 |
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| 61085. |
4. Anar can walk 52 km in 1 hour. How much distance well he covered in 24 hours? |
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Answer» Distance covered by Sharda in 1 hour =253253km225hours=(2×5)+25=125hours225hours=(2×5)+25=125hoursDistance covered by Sharda in125hours125hours= Distance covered in 1 hour×125×125⇒⇒Distance covered by Sharda in125hours125hours=253×125=20km |
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| 61086. |
a man completed a trip of 136 km in8 hours some parts are covered in 15 km/hr and some in 18 km/hr find the part of trip covered in 18 km/hr |
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Answer» Let the trip covered at 18km/hr be x = x/18. ------------------ (1) So, Part of the trip covered at 15km/hr is (136 - x) = (136 - x)/15 -------------- (2) On solving (1) and (2), we get (136 - x)/15 + x/18 = 8(Given 8 hours) (2448 - 18x + 15x)/ 15 * 18 = 8 2448 - 3x = 2160 3x = 288 x = 96km. |
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| 61087. |
4 शिलि ] e Al 0\“ 0 % fi'\_b []J‘flg“fi‘ \rं्ल््ण्फ L ४00: ठ्न्ठै रू 0800 ५. लि'i eO&UJJ om Re रण 0 141 oHon रण |
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Answer» Here, AB = Length of rodBC = Length of shadow. So 1 : √3 = AB/BCq/√3 = AB/BC We know that AB/BC = tan theta So, tan theta = 1/√3tan theta = tan 30°theta = 30° |
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| 61088. |
| 1 2 1|प्रश्न 2. 729 का -+-X1-=3 32 |
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Answer» 25 |
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| 61089. |
6 044+1) = (a? + 1), a0 |
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Answer» i think the book u are following is ml aggarwal...i also follow it...if u r having trouble. search in internet ......thk u....like plz |
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| 61090. |
Today, I got The form of CBSE Board, There was less space in column, So instead of Physical Education, I filled Physical Edu. Is it ok? |
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Answer» Yes, It is okay. There is no problem in it. |
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| 61091. |
: elim, 2 e |
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Answer» x² + 3lim -------- x-->2 x - 1 So putting x = 2, x² + 3 -------- x - 1 2² + 3--------- 2 - 1 7/1 = 7 |
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| 61092. |
If f(x) = 27x® and g(x) and g(x) = x1/3, then gof(x) is : |
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Answer» when f(x)=27x3 and g(x)=x1/3 then gof(x) =3x 27x is the correct answer 3x is the correct answer 3x is right answer hoga 3x is the correct answer. 3x is correct answer 3x is the right answer 27x³=(3³)⅓=3 correct answer |
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| 61093. |
Find lim 2-a-x→0 |
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| 61094. |
tan 2x48) Evaluate lim2 |
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| 61095. |
LOXI. & X122 (0.005 X 10 2² X2X10 |
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Answer» 0.062363 is correct answer. |
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| 61096. |
l, lind the weight ofRolid ylinder ol tadiue İD5cm and height uhmif the material of the cylinder weighs 5g per cm |
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Answer» Volume of cylinder =22/7×r2×h=22/7×10.5×10.5×60=20790cm3Weight=20790×5=103950gm |
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| 61097. |
MathieWorksheet -21Measurement (Length)Mathsdistance of 48 kmA person drives his car and covered G750 m from hishome. He has to cover 60 km, how muchdistance, he has to cover more?Sonu's house is 4 km 500 m andMonu's house is 6 km 250 m away fromtemple. Whose house is far from templeand by how much?Maithili3.Maithili requires 4 m 50 cm cloth forsuit. She already has 5 m cloth. Aftertaking out cloth for suit, how much will itbe with her ?4Michael covered 18 km 52 m on oneday and 23 km 500 m on other day.How much distance he coveredaltogether?5.Yuvi purchased 11 m 75 cm white string:24 m 50 cm green string and 5 m 25 cmblue string. Find the total length ofstring, he purchased.Roses are planted in a garden along a laneof 200 m. If roses are to be planted 5m apart from each other, how many roseplants are required?Activities - 4Grade:21Date:Signature: |
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Answer» 1) 60.000-48.750=11.250; 2) 10.000-4.500=5.500; 1) 60.000-48.750= 11.250;210.000-4.500=5.500 |
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| 61098. |
x1x22x 1 |
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Answer» hit like if you find it useful |
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| 61099. |
51 (0 | 17 ९0८28SN 26 |
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Answer» cos2A=2cos^2A-1and sin2A=2sinAcosAhence1+cos2A/sin2A=2cos^2A/2sinAcosA=cosA/sinA=cotA |
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| 61100. |
) lim (-2)X1 |
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Answer» thankz |
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