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If d= -4and 7 th term = a+6d= 4as Tn= a+(n-1)dso a+6(-4)= 4a= 4+24= 28First term will be 28

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Given:A right angled ∆ABC, right angled at B

To Prove- AC²=AB²+BC²Construction: draw perpendicular BD onto the side AC .Proof:

We know that if a perpendicular is drawn from the vertex of a right angle of a right angled triangle to the hypotenuse, than triangles on both sides of the perpendicular are similar to the whole triangle and to each other.

We have△ADB∼△ABC. (by AA similarity)Therefore, AD/ AB=AB/AC

(In similar Triangles corresponding sides are proportional)

AB²=AD×AC……..(1)Also, △BDC∼△ABCTherefore, CD/BC=BC/AC (in similar Triangles corresponding sides are proportional)

Or, BC²=CD×AC……..(2)Adding the equations (1) and (2) we get,AB²+BC²=AD×AC+CD×ACAB²+BC²=AC(AD+CD)( From the figure AD + CD = AC)AB²+BC²=AC . ACTherefore, AC²=AB²+BC²

This theroem is known as Pythagoras theroem.

Given data:Speed of the man = 6 km/hr = (3 x 1000) / 3600 = 0.83m/secTime = 2 min = 2 x 60 = 120 secArea of the square = ?Solution:As it is given that man crosses the diagonal of square with a speed of 0.83 m/sec.In 2 min or 120 sec, the man will go = 0.83 x 120 = 99.6 mThis means that the diagonal of the square field = 99.6 mWe know that,Diagonal of square field = Side square field x√ 299.6 = Side of square field x√ 2Side of square field = 99.6 /√2Side of square field = 99.6 / 1.4142Side of square field = 70.63 mArea of square field = (Side of square field)²Area of square field = (70.63)²Area of square field = 4988.59 m²Which shows that the area of the square field is 4988.59 m² ~ 5000m^2

any short cut

Solution

Length of diagonal = distance covered in 2 min= 3600/60 * 2 = 100 mArea of the field = 1/2 (diagonal)^2 = 1/2 * 100 * 100= 5000 m^2 = 50 ares

SP=880Loss 20%so CP=880/0.8=1100to gain 10% SP=1100×1.1=1210

Perimeter= 2(length+ breadth)80/2=(24+b)40-24= breadth16 cm = breadth

Let PQ and RS be the chords of the circle that touch the inner circle at M and N respectively.

PQ and RS are the tangents to the inner circle, and OM and ON are the radii of the smaller circle.

OM = ON

Thus PQ and RS are equidistant from the centre, therefore they are equal.

Hence PQ = RS.

2/5th of house in one dayhence to complete the painting work 2/5*X=1X=5/2 days required that is 2.5 days

Let PQ and RS be the chords of the circle that touch the inner circle at M and N respectively.

PQ and RS are the tangents to the inner circle, and OM and ON are the radii of the smaller circle.

OM = ON

Thus PQ and RS are equidistant from the centre, therefore they are equal.

Hence PQ = RS.

thanks

the correct answer is a

15/17 is right answer hai

correct answer is a.15÷17

option A is the correct answer.

15/17 is the right answer

√225/√289

The Answer of this question is 15/17

a option is correct answer

(a) 15/17 is right answer

option a is the right answer

Answer is option a) 15/17

√225/√289=√15×15/√17×17=15/17

Given:

Dimension of brick = l=22.5 cm, b=10 cm, c=7.5cm

Total surface area of a container= 9.375 m²

Total surface area of a brick = 2(lb+ bh+ lh)

= 2(22.5×10 + 10×7.5+ 22.5×7.5)

= 2(225 + 75 + 168.75)

= 2×468.75

= 937.5cm²

= 937.5/100×100 m²

Number of bricks that painted out of thiscontainer= total area painted by containers paint / total surface area of abrick

=9.375/ (937.5/100×100)

=( 9.375×100×100)/ 937.5

= 937500/ 9375= 100

Hence,100 bricks can be painted out.

thx

ans is 400

2/5th of house in one dayhence to complete the painting work 2/5*X=1X=5/2 days required that is 2.5 days

After allowing a discount of 25% on the marked price of an item, it is sold for rupees 240.find the marked price of the item.

Bhujangrao had to pay 2% cash. So, he got 98% of the selling price.Amount he got = 98% of (5200*15)= 98/100 * 78000= Rs. 76440

Volume of metal needed = (volume of full pipe) - (volume of inner cylinder)

Diameter of pipe = 12 + 2 = 14 cm=> radius of pipe = R = 7 cm

Radius of inner cylinder = r = 12/2 = 6 cm

Length of pipe = 100cm

=> volume of metal = pi * R^2 * h - pi * r^2 * h= pi * h (R^2 - r^2)= (22/7) * 100 * (7^2 - 6^2)= 4085.71 cm^3

bro plz tell in simple language

i)3/5 quintal costs 210so 1 quintal costs (210×5)/3 = ₹350,so

ii) cost of 0.4 quintal is ₹350× 0.4 = ₹140

Cost 3/5(0.6) quintal wheat is ₹ 210

i) Cost of 1 quintal wheat is ₹210/0.6 = ₹350

ii) Cost of 0.4 quintal wheat is

= 0.4 × ₹350 = ₹140

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Sp of 1 Quinta rice-₹924Profit=12%Cp=100/112*924=825Sp of 1 quintal wheat-₹924Loss=12%Cp=100/88*924=1050Total sp =924+924=1848Total cost price =1050+825=1875Cp>sp,so loss=>1875-1848=27

inner circumference= 440 mSo,2πr = 440 ,which gives r=70mSo, outer radius= (70+14)m= 84 mSo, outer diameter= 2*84 m= 168 m

Thank you for posting answer

2/5th of house in one dayhence to complete the painting work 2/5*X=1X=5/2 days required that is 2.5 days

1 quintal is 100kghence 100kg Costs 880 rupeeshence20 kg will be as 100/5=20hence880/5=176rupees

Volume of earth dug out = πr²h= (22/7)*2²*14= 176 m³. This volume is spread evenly in the field. Increase in height = Volume of earth dug out/( length * breadth)= 176/(10*4)= 440 m

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1 Quintal = 100 kg.18 kg wheat costs Rs 2161 kg wheat will cost Rs 216/18 = Rs 12100 kg wheat will cost Rs 12 × 100 = Rs 1200Therefore, 1 Quintal wheat will cost Rs 1200.