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all boys =6/10C3=6/10*9*8*3*2*1=1/720and all girls will be =4/10C3=4/10*9*8*3*2=1/10*9*2*3*2=1/1080

(3+x)/6-3/10=1

x = 24/5 =4.8 hours to fill the cistern after the outlet is closed.

If the outlet pipe were kept open, it would take 15 hours to fill the cistern

90hours

Oxygen in tank initially = 219 2/3 L

Oxygen in tank left = 219 2/3 - 32 1/3= 659/3 - 97/3= 562/3

Total capacity of tank = 245 3/8 L

Therefore, unused space in tank = 245 3/8 - 562/3= 1963/8 - 562/3= (5889 - 4496)/24= 1393/24= 58 1/24 L

tanks

As 1 cubic metre=

1000 litres

1-1/7=7/81/8×1hoursso 7/8×??1/8×7=7/8×?7 hours

wrong ans

An inlet pipe fills 1/8 part of tank in 1 hour.

Then, Time require to fill the empty tank = 8*1 = 8 hours

Shanghai became the hub of the new print culture, catering to the Western-style schools. By the 17th century, the print was no longer used just by scholar-officials in China. Merchants also started using print in their everyday life as they collected trade information. Reading became a leisure activity. The new readership preferred fictional narratives, poetry, autobiographies, anthologies of literary masterpieces and romantic plays. Rich women began to read and publish their poetry and plays. Wives of scholar-officials published their works and courtesans wrote about their lives. Western printing techniques and mechanical presses were imported in the late 19th century. From hand printing, there was now a gradual shift to mechanical printing.

42 cm^2

For perimeterperimeter of shaded part will beperimeter of square - perimeter of 4 quadrant14*4-(2*22/7*7)56-4412 cm

find discriminent :2x-2/2n+1=0

find discriminent:2×-2/2n+1=0

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answer should solved in linear equation method

If two angles are 45 each then according to angle sum propertySum of all angles =18045+45+x=180x=90Resultant triangle will be right angled triangle.

Thanks

3 ans 1kg 1000g4kg 4000g8kg 8000g4000/80002/41/2

750m long and 250m broad so area = 750×250 = 187500 sq. m. 16 per day100 sq.m. so total cost = 187500×16/100 = 30000

When ,(5m+1)(5m+3(5m+4) 5=5m(5m+3)(5m+4) + 1(5m+3)(5m+4) 5

=5m(5m+3)(5m+4) + 5m(5m+4) + 3(5m+4) 5={ m(5m+3)(5m+4) + m(5m+4) +15m + 12}/5 = {m(5m+3)(5m+4) + m(5m+4) + 3m + 12}/5

The remainder of 12/5 is 2, so the remainder of (5m+1)(5m+3)(5m+4)/5 is 2.

Let the Capacity of tank be x∴Sandeep filled 4x/7& Ramakant filled x/4Then Umesh used 3x/14∴Equation becomes 4x/7+x/4-3x/14x(4/7+1/4-3/14)x(17/28)Now x=560∴560×17/28=340 litres∴Required volume is 340 l

A tank is 3/5 full of water.It means that 2/5 of tank is still empty.To fill the tank completely, 50 litres of water is needed.

So, we can say that,To fill the 2/5 of tank, 50 litres of water is neede.

So,2/5 × Capacity of tank = 50Capacity of tank = 50 × 5/2Capacity of tank = 250 / 2Capacity of tank = 125.

So, tank can hold 125 litres of water.

Let present age of son = xPresent age of father = 2x

After 8 yearsAge of son = x + 8Age of father = 2x + 8

Given (2x+8)/(x+8) = 7/4 4(2x+8) = 7(x + 8) 8x + 32 = 7x + 56 x = 56-32 = 24

Present age of father = 2x = 2*24 = 48 yrsPresent age of son = x = 24 yrs

M = 2S(m+8)/(s+8) = 7/4(m+8)4 = 7(s+8)(2s+8)4=7(s+8)8s+33=7s+56s=56-33s=23m=46

no answer is wrong the answer is 48 and 24 years

your mistake is you have done 8×4 =33

Principal amount= 18000 ruppesTime = 2 yearsrate of interest= 10A= P(1+R/100)^2= 18000(1+10/100)^218000(110/100)^21.21*1800021780 ruppesThis will be the amountInterest = 21780-180003780 ruppes

Please like the solution 👍 ✔️

n(n!) = (n+1-1)n! = (n+1)n! -(1)n! = (n+1)!-n!

The terms will become

a1 = 2!-1! a2 = 3!-2! a3 = 4!-3!.... and so ona100 = 101!-100!

so, on summation it will be ,a1+a2+a3 ..... +a100 = 2!-1!+3!-2!+4!-3!+5!-4!..... +100!-99!+101!-100!

here all the negetive terms will cancel its precedding positive terms like 2!-2!, 3!-3! and so on 100!-100!

so, at the end the terms remaining will be 101!-1! = 101!-1

so, 101!-1 is the answer.

option 3

AB is a chord of circle with centre O as shown in figure.according to question, PQ passing through centre O. hence, PQ is a diameter of circle { as we know, a line segment passing through centre cut the circle at two points is known as diameter of circle }

so, PQ is diameter of circle and we know, half of diameter of circle is known as radius of circle. here POQ = 2AB , means Length of AB is equal to length of radius.

Let radius of circle is r then, AB = r from figure it is clear that OA and OB are the radius of circle .so, OA = OB = r

now, ∆OAB, OA = OB = AB = r . all sides of ∆OAB are same so, ∆OAB is equilateral triangle .hence, all angles of ∆OAB will be 60° hence, ∠AOB = 60°

Thanks

Maximum capacity = 560 litres .

Sandeep used 4/7(560) = 320 litres.

So water left after being used by sandeep = 240 litres.

ER. RAVI KUMAR ROY

Water used by Ramakant = 1/4(240) = 60 litres.

Water still left after used by Ramakant and Sandeep = 180 litres.

Water used by Umesh =3/14(180) = 270/7 litres = 38.571428 litres

So water finally left in the tank =141.42857 litres approximately.

In two weeks total number of days=7*2=14daysIn 16 hours water pumped=13450*16=215200litresHence in 14days=215200*14=30122800litres

Apply S.I here frndSI=PRT/100P=24000R=7.5%T=4So,SI=2400*7.5*4/100=720Hope it helps...

A+B+C = 180°A = 180° -(B+C)sin(A)sin(180° -(B+C))sin(B+C)(a) option is correct

option A is right

0(0-1)-1(0-1)+1(1-0)=1+1=2

0(0_1)_1(0_1)+1(1_0)=1+1=2is the correct answer