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144.6 is the answer of the following

144.6 is the correct answer

The right answer is 144.6..

eaten rice=2/5left rice=1-2/5=3/5left kg of rice=3/5*145=3*29=87 kg if u satisfied with the ans then like or cmmt ✌️

this is the correct answer ok

Total rice=145kgEaten=2/5 th of 145=2*29=58kgLeft=145-58=87kg

Converting Cot(π/24) into degrees by multiplying the angle by 180/π we can get

Cot(π/24)= cot 7.5

cotA= (1+cos2A)/sin2A

We can write

Cot (15/2)= (1+cos15°)/sin15°……………(1)

Now

cos15°= cos (45°-30°)

=cos45.cos30+sin45.sin30

=1/√2.√3/2+1/√2.1/2

=> cos 15°= (1/4) (√6 + √2)

Similarly sin15° = (1/4) (√6 - √2)

Putting these values in eq. (1)

Cot (15/2)= [1 + (1/4) (√6 + √2)] / [(1/4) (√6 - √2)]= (4 + √6 + √2) / (√6 - √2)

On rationalisationCot (15/2)= [(4 + √6 + √2) * (√6 + √2)] / [(√6 - √2) * (√6 + √2)]= (4√6 + 6 + 2√3 + 4√2 + 2√3 + 2) / 4= (4√2 + 4√3 + 8 + 4√6) / 4= √2 + √3 + √4 + √6.

x^2=(2+√2)^2=4+2+4√2=6+4√21/x^2=1/6+4√2*6-4√2/6-4√2=6-4√2/36-32=6-4√2/4hencex^2+4/x^26+4√2+6-4√2=12

The breadth of the rectangular hall b m.

then the length of rectangular hall will be ( 3b -4 ) m.

b is the greater value when compared to o and a

b is the greater value of the answer

Cube=side^3Henceside will be cube root of (2.197)=1.3mHence side length is 1.3m

thank u for the answer

S. I=(500*4*15)/100=300, then Ramesh should be return to Sumit Rs (500+300)=800

tq

thanks

-370---------. =0.41900

11/5 is the correct answer

11/5 is correct answer

2.2 is the correct answer

-2/5+2/5_-3/5×1/6-2/5+2/5+2/52/5

11/2 is the best answer

11/5 is the correct answer.

11/5 is correct answer.

Area of verandah = 29*19 - 25*15= 551 - 375= 176 sq m

very very thank

please like my answer if you find it useful

Let the length be ltherefore breadth=l-3area=l(l-3)the area of isosceles triangle = 1/2×(l-3)126(l-3)given:l(l-3)-4=6(l-3)l²-3l-4=6l-18l²-9l+14=0l²-2l-7l+14l=0l(l-7)-2(l-7)=0(l-2)(l-7)=0l=7or 2and the breadth is 4since breath cannnot be negative.

l = b + 8A = 240l × b = 240(b + 8) × b = 240 b^2 + 8b - 240 = 0(b - 12)(b + 20) = 0b = 12, b = -20Since length cannot be negative, b = 12 is the solution.

l = 20 mb = 12m

let breath = xlength= x+8area= 240x(x+8)=240x^2+8x-240=0x^2+20x-12x-240=0x(x+20)-12(x+20)=0(x+20)(x-12)=0either x+20=0, x= -20 (impossible because length never be in -ve)so x-12=0x= 12so breath = 12mlength= x+8= 12+8=20 m

length of park=20m , and breadth of park= 12m please like e my answer

Let the Length of the Park be X m

Then Breadth of the park = ( X - 7 ) M

Perimeter of Rectangle = 2 × ( L + B )

Perimeter Given = 1034 m

So we have ,

2 × ( X + X - 7 ) = 1034

2 × ( 2X - 7 ) = 1034

(2X - 7 ) = 5 17

2X = 517 + 7

2X = 524

X = 262

〰Length of plot is 262 m

〰Breadth of plot is 255 m

भावना की अंक x हो तो(x + 10) + x + (x - 5) = 170 3x + 5 = 170 3x = 165 x = 55ईशा के प्राप्तांक = x - 5 = 55 - 5 = 50

(1)-let ABCD be a rhombus in which diagonal are intersecting at point O and circle is drawn while taking side CD as it's diameter we know that a diameter subtends 90°on the arc.(2)-thus,angle COD=90°(3)-Also, in rhombus,the diagonal intersect each other at 90°(4)-angle AOB=angle BOC= angle COD= angle DOA=90° (5)-Clearly,point O has to lie on the circle. please like and comment my answer is wright or not

Let the length be ltherefore breadth=l-3area=l(l-3)the area of isosceles triangle = 1/2×(l-3)126(l-3)given:l(l-3)-4=6(l-3)l²-3l-4=6l-18l²-9l+14=0l²-2l-7l+14l=0l(l-7)-2(l-7)=0(l-2)(l-7)=0l=7or 2and the breadth is 4since breath cannnot be negative.

so answer will be +8 as given that both are real and positive.

sinA/1-cosA =1 +cosA/sinA

L.H.S=sinA/1-cosA

=sinA(1+cosA)/(1-cosA)(1+cosA)

=sinA(1+cosA)/1-cos^2(A)

=sinA(1+cosA)/sin^2(A)

=1 +cosA/sinA

=R.H.S

1.

x² + y² = 4

Differentite wrt x

2x + 2y dy/dx = 0

dy/dx = -x/y

For 64 cubes the placing will be :8 cubes with 8 rows.

For every small square: area = side^26.25 = side^2side= 2.5

therefore side of chess board without border: 8 x side = 20

therefore size of the chess board with border is: 20 + 2= 22cm

Give any two real-life examples for congruent shapes

sorry i didn't understand the question sorry.please like

The altitude passes through point B.

We can get coordinates of point B by solving eqn of line AB and BC. y - x = 2x + 2y = 1Therefore B is (-1,1)

Also, the altitude through B is perpendicular to side AC. => Slope of altitude = -1/Slope of AC= -1/(-3)= 1/3

So, we now have a pt. (-1,1) and slope of the line 1/3.Hence required eqn of the line (y - 1) = 1/3 (x +1)which is 3y - x = 4 (Ans)

Area= breadth x length= 93/5*26/3161.2m^2

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For example volume is height x length x weight

so, height x length x width = .6 cubic meters

h x 5 x .4 = .6

h = .6/(5 x.4)

h/thickness = .3 m or 30 cm or 30/2.54 in or 11.8110 inches

one day work of A = 1/21B is 40 % more efficient than A which means that A will take 40% more days than B because efficiency and number of days are inversely proportional to each other.

=> 21 is 40% more than B’s days.

=> 21 = (140/100)*B’s days

=> B’s days = 21*(100/140) = 15 days