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By pythagorus theorem,

(breadth)² +(length)²=(diagonal)²

(breadth)²+4²=5²

breadth=√25-16

breadth=3m

Perimeter of rectangle=2(length+breadth)

=2(4+3)

=2×7=14m

area of rectangle=length×breadth

=4×3

=12 m²

per month interest = 3000*1*1/100

= 30 rupees

In 6 months = 30*6 = 180 rupees

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Sum of all observations /no. Of observations 400/8=50Mean score =50

Mean score = (58+76+40+35+46+45+0+100)/8= 400/8= 50

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(i) 40 as it is a isoceles triangle.(ii) 90.(iii) 50

45x/100 = 135

x = 13500/45

x = 300 marks

Oxygen creates a hard oxide surface on aluminium parts

We know that any positive integer is of the form 3q or, 3q+or 3q+2 for some integer q and one and only one of these possiblities can occur.

So, we have following cases:

Case-I:When n = 3q

In this case, we have

n= 3q, which is divisible by 3

Now, n = 3q

n+2 = 3q+2

n+2 leaves remainder 2 when divided by 3

Again, n = 3q

n+4 = 3q+4=3(q+1)+1

n+4 leaves remainder 1 when divided by 3

n+4 is not divisible by 3.

Thus, n is divisible by 3 but n+2 and n+4 are not divisible by 3.

Case-II:when n = 3q+1

In this case, we have

n= 3q+1,

n leaves remainder 1 when divided by 3.

n is divisible by 3

Now, n = 3q+1

n+2 = (3q+1)+2=3(q+1)

n+2 is divisible by 3.

Again, n = 3q+1

n+4 = 3q+1+4=3q+5=3(q+1)+2

n+4 leaves remainder 2 when divided by 3

n+4 is not divisible by 3.

Thus, n+2 is divisible by 3 but n and n+4 are not divisible by 3.

Case-III: When n + 3q+2

In this case, we have

n= 3q+2

n leaves remainder 2 when divided by 3.

n is not divisible by 3.

Now, n = 3q+2

n+2 = 3q+2+2=3(q+1)+1

n+2 leaves remainder 1 when divided by 3

n+2 is not divisible by 3.

Again, n = 3q+2

n+4 = 3q+2+4=3(q+2)

n+4 is divisible by 3.

Thus, n+4 is divisible by 3 but n and n+2 are not divisible by 3.

one dozen ball=rs.180so,one ball=180/12=15rsone score shuttle cock=rs.90so,one shuttle cock=90/20=rs.4.50

Now ratio of one ball to one shuttle cock=15/4.5=3.33.Ans

Bhaiya is ka answers pata chal

Find the selling price of 1 pen:

15% profit = 15% x ₹6 = 0.15 x 6 = Rs 0.90

selling price of 1 pen = 6 + 0.9 = ₹6.90

Find the selling price of 600 pens:

1 pen = Rs 6.90

600 pens = 6.9 x 600 = ₹ 4140

Answer; The selling price of all the 600 pens is ₹4140

6/7 is the correct answer

(b):-1/7

Cost of 2 pens = 2*12.25

= 24.5 rupees

all are irrational no is the correct answer of the given question

increasing order: 3, 4 , 5 , 8, 9median = 5

5 ihfd DJs usual isoseismal Harrison's

add all the number. 3+4+5+8+9. divide it by total digit number. 29 divide by 5. so median=5.8

1 score = 20 pencils.3 scores = 20*3 = 60 pencils

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Principal=Rs.2000(P)time=18 months=1.5 yrs.(t)rate=6% p.a(R)∴S.I=PRt/100=(2000×6×1.5)/100=Rs.180

Option b is correct.

cp of one pen=₹10number of pens sold=45loss%=1045*90/100=₹40.5 so sp of 1 pen=₹9

values are not correct shagufta

dear student b is the right option not a

43 is the mode of the given data because it has the highest frequency of 5p

Radius of wooden sphere = 10.5 cmSA of wooden sphere = 1386 cm²radius of cylindrical support = 1.5height = 7 cmso, CSA = 66 cm²and area of circular end of cylindrical support = 7.07 cm²area to be painted silver = 8 * (1386 - 7.07) = 11031.44 cm²cost of painting with silver = 11031.44 * 0.25 = RS.2757.86painting black = 528 * 0.05 =RS 26.40total cost = 2757.86 + 26.40 = RS. 2784.26

cost of 1 pen is ₹3cost of 10 pen is ₹3 × 10 = ₹30

as we know that...cost of one pen =3no.of pen=10cost of 10 pen=

10 ×3 = 30

1 pen = RS. 310 pens = ?

1/10 = 3/x

1×x = 3×10

x= 30

10 pens for 30 RS.

total price=₹85price of muffin=₹20price of 5 bars of chocolate=₹85-₹20=₹65each chocolate bar=65/5=₹13

but what is the shape

thanks