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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 62801. |
were found-İnell gible and .85% atvm elig becandiate belong ed to 9eneral categoy 2ncandidate belonged to othe categ ies nhow many candidates applied for the exami nat- |
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| 62802. |
17. Find the measure of all the angles in the Atriangle ABC60°B.55°502(60°90° |
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| 62803. |
From the top of a 36 m high building, the angle of elevation of top a tower hasmeasure 60 and angle of depression at foot of tower has measure 30. Find theheight of the tower. |
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Answer» Thank you so much for answering the questionsThis is for my brother |
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| 62804. |
¢20, 7 sind = दर है तो दिखाइए 3 ८054 -4 ८०57 4 ल01न का |
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Answer» By this right angled triangle we have, sinA=1/2 cosA=√3/2 so cos^3(A) = 3√3/8 substituting these values we get 3cosA-4cos^3(A) = 3*√3/2–4*3√3/8 =(3√3/2) – (3√3/2) = 0 And hence it is proved Like my answer if you find it useful! |
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| 62805. |
Pradnya had S dozen copies. She gave half of the copies to Anushka and 5 times ofcopies to Prajwal. How many copies are remaining with her ?(1) 60(2) 12(3) 18(4) 30 |
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Answer» Ans :- Option (c) is correct.18copies is remaining with pradnya Step-by-step explanation: total copies =5 dozen=5*12=60 copies given to anushka=60/2=30 copies given to prajwal=60*1/5=12 remaining copies with her=total-total given copies =60-(30+12) =60-(42) =18 so she is left with 18 copies |
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| 62806. |
The shadow of a tower is 30 m when the angle of elevation of the sun hasmeasure 30. When the angle of elevation of the sun has measure 60 m find thelength of the shadow of the tower. |
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| 62807. |
the measure of each angle.60°1008.In the figure alongside,ZS = 60°, ZR = 100°.The bisectors of ZP andZQ meet at O. Find anglePOQ. |
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| 62808. |
iesnces(C) Collective(D) descriptive14. If'A, B' is coded as '3,7', 'C, D' iscoded as '7, 11', 'E, F' is coded as'13, 17', then 'I, J' will be codedas â(A) 19,23 (B) 37, 41(C) 21, 27 (D) 21,25-95ere |
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Answer» I, j will coded as 21,25 |
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| 62809. |
9) One thousand muffins are sold at a loss of7520. If one muffin costs 10.50 to makefind the total selling price of all muffins. |
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| 62810. |
E and F are points on the sides PQ and PRrespectively of a Δ PQR. For each of the followingcases, state whether EF lI QR:A6) PE 3.9 cm, EQ3 cm, PF 3.6 cm and FR-2.4 cm(ii) PE 4cm, QE 4.5 cm, PF 8 cm and RF 9 cm(ii) PQ 1.28 cm, PR 2.56 cm, PE 0.18 cm and PF 0.36 cmchi |
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| 62811. |
2. E and F are points on the sides PQ and PRg Arespectively of a Δ PQR. For each of the followincases, state whether EF | QR0 PE 3.9 cm, EQ 3 cm, PF 3.6 cm and FR-2.4 cm(ũ) PE 4 cm, QE 4.5 cm, PF 8 cm and RF 9 cm(iii) PQ 1.28 cm, PR-2.56 cm, PE 0.18cm and PFs0 |
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| 62812. |
The sum of first n terms of an AP is (5n - n²). The nth term of the AP is(a) (5-2n)(b) (6-2n)(c) (2n-5)(d) (2n-6) |
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Answer» Given that sum of the first n terms of an AP is 5n - n² Sn = 5n − n² First term, a₁= S₁= 5(1) − (1)2= 5 − 1 = 4 Sum of first two terms = S₂= 5(2) − (2)2= 10 − 4 = 6. Second term, a₂= S₂− S₁= 6 − 4 = 2 d = a₂− a₁= 2 − 4 = −2 an= a + (n − 1)d = 4 + (n − 1) (−2) = 4 − 2n + 2 = 6 − 2n ∴ nthterm of an A.P = 6 - 2n |
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| 62813. |
The sum of two consecutive multiples of 7 is 161. Find these multiples |
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| 62814. |
2, E and F are points on the sides PQ and PRrespectively of a A PQR. For each of the following Acases, state whether EF IIQR:0 PE-3.9 cm, EQ-3 cm, PF 3.6 cm and FR 2.4 cm(ii) PE = 4 cm, QE = 45 cm, PF-8cm and RF-9cm(ii) PQ 1.28 cm, PR-2.56 cm, PE-0.18 cm and PF-0.36 cmFig. 6 |
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| 62815. |
ANTSURFACE AREAS23The front compound wall of a house isdecorated by wooden spheres of diameter 21cm, placed on smail supports as shown in Fig13.32. Eight such spheres are used for thispurpose, and are to be painted silver. Eachsupport is a cylinder of radius 1.5 cm and height7 cm and is to be painted black. Find the costof paint required if silver paint costs 25 paiseper cm? and black paint costs 5 paise per cm2Fig. 13.32 |
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| 62816. |
. 2,€Da+b=>5a b= TAE TR (I एव 840(27+ 00) = 624e |
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Answer» a + b = 5.........(1)a - b = 1.......... (2) Add eq(1) and eq(2)2a = 6a = 6/2 = 3 Put value of a in eq(1), we get3 + b = 5b = 2 Therefore, value of8ab(a^2 + b^2)= 8*3*2(9 + 4)= 48*13= 624 |
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| 62817. |
if the price of 12 books is Rs189 ,then each book costs |
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Answer» Your correct answer is Rs 15.75 12 books of price=189 then1 books of price=189/12ans=15.75 each book cost Rs15.75 cost of 12books=rs.189cost of 1book=189/12 =rs.15.75 |
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| 62818. |
है कम MM 2:2५. e 101. 00616. 0,1.5 .6 fl.&_m_m___%_m Wamaol tae srmollesk eqmodd Hak Aoof KL M_QM_E_B_._.«&M-_M-' |
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| 62819. |
The Conceptum publication sold 500 copies of bookat a profit of 24%. If a book costs him Rs.15 find theselling price ofbook |
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| 62820. |
2EXERCISE 8.1.1. Is it possible to find ratio between the following quantities. If yes, find it in the simplestform :(1) Cost of 2 books and cost of 3 notebooks, where one book costs * 28 and I notebookcosts 20. |
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| 62821. |
Calculate Break-even Point:Units of outputFixed CostsVariable CostsSelling Price |
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Answer» In economics, fixed costs, indirect costs or overheads are business expenses that are not dependent on the level of goods or services produced by the business. They tend to be time-related, such as interest or rents being paid per month, and are often referred to as overhead |
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| 62822. |
indspeedo10. As observed from a point 60 m above a lake, the angle of elevation of an advertisingballoon has measure 30 and from the same point the angle of depression of theimage of the balloon in the lake has measure 60. Calculate the height of the balloonabove the lake. |
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| 62823. |
5. Evaluate1 +i2+i4 +16+i-2n...-...+j-2rn |
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| 62824. |
3 a real number.3)Find the value ofii) i+i2 + i3 + i4 |
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| 62825. |
I416. The sum of the squares of two consecutive multiples of 7 is 1225. Findthe multiples.65 |
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Answer» Let the first multiple is 7*k and next multiple is 7*(k+1)therefore 49*k^2 + 49*(k^2 + 2*k + 1) = 122549*(2*k^2 + 2*k + 1) = 12252*k^2 + 2*k + 1 = 25k^2 + k -12 =0k = 3 or -4(rejected)k=3 k+1 =4therefore 21 and 28 |
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| 62826. |
ample Paper (va Shudying)SECTION-BThe raional nmer ies between\frac{3}{7} \operatorname{ard} \frac{2}{3}and isi4 |
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Answer» 3/7=3*3/7*3=9/212/3=2*7/3*7=14/21now the option are4/7=4*3/7*3=11/21which lies between 3/7 and 2/3 answer not matched with options |
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| 62827. |
1. The maximum length of a pencil that can be kept in a rectangular box of dimenstons12 cm × 9 cm × 8 cm, is(al 13 cm |
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Answer» thanks... |
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| 62828. |
6. A well is 7.2 m deep. The cost of cementingr dmt is11,880. Determine the radius of the theits inner surface at 75 paise pese21wall. |
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| 62829. |
ज्ञात कीजिए | Al 2, 7,12, i) W श्रेढ़ी 9, 13, 17, 21, ..... |
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Answer» 1) a=2 d=5T10 = a + 9d = 2 + 9(5) =47 2)a=√2 d=2√2T18= a + 17d =√2 + 34√2 =35√2 3) a=9. d=4T24= a + 23d =9 + 92 =101 |
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| 62830. |
(al61. (72 + 2)* x (36x6) = (6) x (12960 +10) में प्रश्नचिह्न (?) कामान है(a) 12(b) 13(c) 11(d) 14 |
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| 62831. |
find mean of first five prime number |
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| 62832. |
in the figure, shows the shape of a solid copper piece (made of two pieces) with dimen-sions as shown. The face ABCDEF is the uniform cross-sectionAssume that, the angles atA, B, C, D, E and F are right angles. Calculate the volume ofthe piece.в 22cm.8 om3 cm |
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| 62833. |
cannot bun im tae2 |
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Answer» I think it needs a specific temperature so that it may react with oxygen and burns. Burning something is combining a fuel with oxygen.If you burn hydrogen gas (H2) then you get 2 H2+ O2--> 2 H20. H20 is |
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| 62834. |
A book costs price thrice of a pelcost of book and penThe sum of a number and 13 is 46. What is the number?.from from thrice a number, the answer is 105. w |
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| 62835. |
ind ihemeasure of each angle of the trianglet. If one angle of a triangle is equal to the sum of the other two, show thatthe triangle is right angled.60 |
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| 62836. |
The side BC of a triangle ABC is produced on both sides.Show that the sum of the exterior angles so formed is greater than angle A by two right angles. |
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| 62837. |
12. In the given figure, shows the shape of asolid copper piece (made of two pieces)with dimensions as shown. The faceABCDEF is the uniforrm cross-section.Assume that, the angles at A, B, C, D, E andF are right angles. Calculate the volume ofthe piece.5 cm8 cm03 orn |
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Answer» Volume of first piece.V1 = 22*5*2 = 220 cm^3 Volume of second pieceV2 = 22*8*3 = 528 cm^3 Total Volume of given piece= V1 + V2= 220 + 528= 748 cm^3 |
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| 62838. |
Find mean of first five prime numbers.. |
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| 62839. |
A rver 2 m deep and 45 m wide is lowing at the rate of 3 km/h. Find the quantity of wäterthat runs ito the sea per minute. |
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| 62840. |
............ is the mean of first five prime numbers. |
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| 62841. |
2.Find the range of first five prime numbers |
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Answer» Numbers are 2,3,5,7,11range - (11-2) = 9 |
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| 62842. |
find the mean of the first five prime numbers |
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| 62843. |
find the range of first five prime numbersA. 2B.7C.9D.11 |
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Answer» The first 5 prime numbers are 2,3,5, 7 and 11. So, the fifth prime is 11. thanks😀😁😂 |
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| 62844. |
Find the range of first five prime |
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Answer» Numbers are 2,3,5,7,11range - (11-2) = 9 |
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| 62845. |
An are forms an angle of 30° at the centre ofthe cirice. What is the angle formed by it atany other point of the circle ? |
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Answer» angle on arc=1/2 × angle at centre=1/2 x 30=30/2=15° |
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| 62846. |
al 13. In a shower, 5 cm of rain falls. Find the volume of water that falls on 2 hectares of land. |
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| 62847. |
water thai tusto tae se Pe nteIn a shower, 5 em of rain falls. Find the volume of water that falls on 2 hectares of ground(in m3). |
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Answer» how 20000 came there |
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| 62848. |
Jtlpelmnuteis(inm)in a shower, 5 cm of rain falls. Find the volume of water that falls on 2 hectares of ground3(in m). |
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| 62849. |
triangle12. Find the angle formed by the bisectors of two acute angles of a right-angled |
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Answer» angle A= 90 degreeangle B= 60 degreeangle C= 30 degree Now bisecting angle A and angle BBisector meet at point D Then angle D A C= 15degree angle D C A =180degree - 30degree - 45degree =135degree |
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| 62850. |
if two straight line intersect each other in such a way that one of the angle formed measure 90degree show that each of the remaining angle measure 90degree |
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