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62851.

what is the magnitude of the angle formed between the two hands of a clock at the following times (a) 3 :30

Answer»

On first glance, this problem may seem simple in that the angle between the 3 and 6 on a clock is one quarter of a circle or 90 degrees. However, you must take into account that in the half hour that has passed from 3:00 to 3:30, the hour hand has moved half the distance between the 3 and 4. To find the degrees, simply divide the total number of degrees in a circle by 12 to find the degrees between each consecutive number, and then multiply that number by 2.5 because you have half the distance to the 4, and the the full distance to the 5 and the full distance to the 6. Thus,

360/12=30

30∗2.5=75

😀😀😀😀

62852.

water that runs into the sea per miHte is ln a shower, 5 cm of rain falls. Find the volume of water that falls on 2 hectares of ground(in m).

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62853.

In a shower, 5 om of rain falls. Find2 hectazes of groundthe volume of water that fals on

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62854.

1. Find the arithmetic mean of first five prime numbers

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62855.

A solid piece of metal, cuboidal in shape with dimensions 24cm, 18cm, 4cm is recast into a cube. Find the CSA of the cube.

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Volume of cuboidal metal= 24 cm * 18cm* 4 cm= 1728 cubic cm

Volume will remains same as the same metal cuboidal is recast into cube.

Volume of cube = 1728 cubic cm

Side of cube = cube root of 1728= 12 cm

Lateral surface area = 4 * side*side= 4 * 12 * 12= 576 sq. cm

Thanks

62856.

9. There were 1800 students in a school last year. There is 12% increase in the numberstudents in the school this year. Find the number of students studying in the school- - - -

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2016 students in the school now

62857.

\frac { 6 x - 8 } { 99 } + \frac { 3 x + 8 } { 33 } = \frac { 7 } { 3 }

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62858.

\operatorname { ct } \frac { 5 x } { 8 } \frac { 3 x } { 8 } =

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62859.

heE AND ITS ANt itif the ha the two bisectors isis tors or ths of a sight Iriangle meet at O, then the angtets of exterior angles at B and C of AARC meet at 0 Ir() 135() 90The bisaytsat O. IrtA-x", then(db) 00(a) 90°博(e) 1o" a(d) 1809-n AC " and aC is prodluced to a point D. If the bisectors of Ac anu(d) 75

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23.

62860.

\int \frac { 12 x + 8 } { 3 x ^ { 2 } + 4 x + 8 } d x

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thank u

62861.

A Welt drik ilabe kian with a rectangular tbase of esem sight 10on Whihcontainer has greaier ca

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62862.

What is the angle formed by the line of sight withthe horizontal, when the point being viewed isabove the horizontal level?

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The angle of elevationof the point viewed is the angle formed by the line of sight with the horizontal when the point being viewed is above the horizontal level, i.e., the case when we raise our head to look at the object.

62863.

In a shower, 5 cm of rain falls Find the volume of water that falls on 2 hectares of ground

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62864.

28-In a shower, 5 cm of rains falls. Find the volume of water that falls on 2 hectare of groun

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62865.

If their are n arithmetic mean between 3 and 17. the ratio between the last and first arithmetic mean is 3:1. find n.

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17n+3/3n+17 =3/1; 3(3n+17)=1(17n+3); 9n+51=17n+3; 8n=48;; 8n=-48; n=48/8=6

62866.

Find the area enclosed by each of the following figures7cm4cm18cm

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62867.

10) For a sequence, if , find nth term. Henceshow that it is a G.P. Also find the common ratio.find nth tI 5

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62868.

nth term of an A.P.

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to find nth term of an ap series we use formula tn=a+(n-1)d

tn = a + ( n-1 ) d is ans

62869.

23.) The mean marks of a class of 40 students are 50. If the mean of first 20 students are 56 and themean marks of last 20 students are 48, find the marks of the 20th student.

Answer»

Mean marks of 40 students = 50

∴Total marks of the class = 40×50 = 2000

Mean marks of the first 20 students = 56

∴Total marks of the first 20 students = 20×56 = 1120........(1)

Mean marks of the last 20 students = 48

∴Total marks of the last 20 students = 20×48 = 960...........(2)

Adding equations (1) and (2), we get

Total marks of the first 20 students + total marks of the last 20 students = 1120 + 960

⇒Total marks of 40 students + marks of the 20thstudent = 2080

⇒2000 + marks of the 20thstudent = 2080

∴marks of the 20thstudent = 2080 - 2000 = 80

Like my answer if you find it useful!

62870.

(iv)numbers in the following:missingtheла.,80, 880, 8880(b) 10,70, 130x 10, 4 x 10, 9 x 10,ITYinding number pattern using matchsticks

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62871.

99. Express (1.6 x 10°)x(5x10 %) in the form kx 10":(1 sk < 10)

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62872.

Example 2 Find the area enclosed by the ellipse r + )4ab ntab

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62873.

(40 + 5) * 4 (3 x 8 - 3+6)

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864 is the answer of the question

864is right answer 🤩🤩

864 is the right answer

672 is a right answer

(40÷5)×4(3×8-3+6)=(8) ×4(24-3+6)=(8)×4(24+6-3)=(8)×4(30-3)=(8)×4×27=8×108=864 answer

864 is the best answer

864 is the correct answer h

8×4(30-3)8×4×278×108864

672 this is right answer

(40+5)×4(3×8-3+6)=4860 answer

864 the right answer

Answer is 864 correct

=8x4(24-3+6)=32x27=864

864 is the right answer according to your question

864 it is the right answer

864 is the right answer.

864 is correct solution & should be solved with BODMAS rule.

After solving brackets 864 is correct solution.

42 is the right answer of this questios

(8)×4(24+6-3)=32×27=864 is right answer

864 is correct answer

( 40 ÷ 5) × 4 (3 × 8 - 3 + 6)= 8 × 4 (24 - 3 + 6)= 8 × 4 × 27= 864 ANSWER

(40+5)×4(24-9) = (45)×4(15) = 45×60 = 2700

864 is the correct answer

480 this is answer

480 is correct answer

864 is the right answer hai

(40÷5)×4(3×8-3+6)=864

864 is the right answer

864 is right answer okk fine

672 is a right answer

answer is the question 864

864 is the right answer for this question

4860 is correct answer

864 is the correct answer

864 is the right answer

(45/5)*4(3*8-3+6)8*4(8*3-3+6)32(24-3+6)32(27)864

864 it is right answer

864 answers your.correc

864 is the right ans of this question

864

This question of right answer is 771

864 is the correct answer h.

8×4(24-9)8×60=480 i hope this answer help you

864 is the right answer to your question

672 is right answer

864 is the right answers

(8)4(24-9)(8)4(15)=32(15)=480

864 is a right answer .......

8*4(24-3+6)8*4(27)8*108Ans=864

8×(12×32-12+24)=864 is the correct answer please like my answer

=(8) *4(24-9) =(8) *4(15) =(8) *(60) =480

672 is the right answer

864..................................

864 is the correct answer please like my answer

Right answer is 486 bro

(40÷5)×4(3×8-3+6)(8)×4(24-9)32×15=480

(40÷5)×4(3×8-3+6)8×4(24-3+6)32(21+6)32(27)32×27=864

864 is the correct answer please like my answer

(40÷5)×4(3×8-3+6) = (40÷5)×4(3×5+6) = 8×4(15+6) = 8×4×21 =673

(40÷5)×4(3×8-3+6)8×4(24-3+6)32×27864

480 is crrekt answer

8*4*(24-3+6)=32*24-3+6=768-3+6=765+6=771.

(40/5)*4(3*8-3+6)8*4(24+6-3)32(27)32*27864

864 is right answer the qusen

ans : 672 .

(40÷5)×4(3×8-3+6) 8. × 4(24 +3) 32×27 864 864is ✔️ right answer

480 is the answer of this question

40÷5=83×8-3+6=2727×4=1088×108=864the answer is 864

864 is the right answer..

(40+5)×4(3×8-3+6)=(45)×4(24-3+6)=(45)×4(30-3)=(45)×4(27)=(45)×108=4860

864 is right answerof this question

(40/5) *4(3*8-3+6) (8) *4(3*8+3) 32*27=864

this question ka 864 hoga

864 𝙞𝙨 𝙩𝙝𝙚 𝙛𝙞𝙣𝙖𝙡 𝙖𝙣𝙨𝙬𝙚𝙧

62874.

( x ^ { 9 } ) ( - x ^ { 10 } ) ( x ^ { 11 } ) ( - x ^ { 12 } )

Answer»

as negative x have even powers hence it will become positiveusing laws of indicesx^a*x^b=x^a+bhence x^9+12+11+10=x^42

62875.

The area of a rectangular field is 48m2 and one of its sides is 6m.How long will a lady take to cross the field diagonally at the rate of20 m/minute?

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62876.

A CCTV camera has to be placed at the top of a 12m high pole so that traffic beyond the line of sight distant 13 m can be seen. In this case find area of non-sight circle around the pole.

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62877.

Is (i) log 2 rational or irrational? Justify your answer.(ii) log 100 rational or irrational? Justify your answer.

Answer»

i)

Thank you

62878.

2. Find the 30th term of the 10, 7, 4,...

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Given:a=10; d=7-10=-3an=a+(n-1)da30=10+29(-3)=10-87 a30=-77

62879.

28=n(2a + (n-1)-290. Also, find its 30th term. Find the number of terms in the A.P. 10, 4,-2, 8,from the end.

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62880.

Example 1. Find the 30th and nth term of A.P. 10,7,4, ......

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thanka bro

62881.

fn A.M. 's are introduced between 3 and 17 such that the ratio of the last mean to theis 3:1, then the value of n is:(B) 8(A) 6(C) 4(D) none of these

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62882.

find area enclosed between curvesy=x+1 and y=x^2

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62883.

find area between the curves y=|x|-3 and y=3-|x|

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62884.

6.If Suresh walks 0.7 m with each step, how many steps will he take to walk 840 m?

Answer»

Steps taken = 840/0.7= 1200.

Please hit the like button below if this helped you

840/0.7=1200 this is the answer

62885.

5. A horse is placed for grazing inside a rectangular field40 m by 36 m and is tethered to one corner by a rope14 m long. Over how much area can it graze?(Take π = 22)(3)

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62886.

. Arectangularfield is 30 m by 40 m. What distanceis saved by walking diagonally across the field?

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To find the length of the diagonal you can use the pythagorean theorem: a^2+b^2=c^2

So:

30^2+40^2=c^2900+1600=c^22500=c^250 = c, the length of the diagonal walk

It 50m to walk diagonally, and 70 to walk width by length. so you save 20 feet.

62887.

2018-19Choose the correct choice in the following andjustify030th term of the AP: 10,7,4.i(A) 97(3) 77) 1Ith term of the AP:-3,2,is(A) 280-38

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62888.

i “W . )k: Sm A - XT i 91 = A5 - xg (M) LFn M=l + sTwrs=4A(m) I3t

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62889.

1062. Choose the coreet choice in the following and justity0 30th term of the AP: 10, 7,4,,, is

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a=10n=30d=7-10=-3hence an=a+(n-1)da30=10+(29)(-3)=10-87=-77

an = a+(n-1)da=10b=7-10=-3an= 10+(30-1)-3an=10+29×-3an=10-87a30=-77

62890.

20 %2B (10*40)/5

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(40×10)÷(5+20)=400÷25 =16

According to bodmas40*2+2080+20100

according to bodmas40*2+2080+20100

100 is the correct answer of the given question

= 40×10÷5+20= 40×2+20= 80+20= 100

62891.

15D.5164.method is suitable for purification of semiconductora. Liquationc. Zone Refiningb. DistillationRefiningion

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zone refining is the method for purification of semiconductor

62892.

See how many purification steps take placebefore drinking water reaches your publictap! Is it right to use this water for otherpurposes?

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62893.

A horse is tied with a rope 7 m long to one corner of a square fieldgrass that the horse can graze. (Take π =-)of side 17 m. Find the area of

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Length of rope tied to the centre of the Square=7 mSide of square=17 mTo find,(i) Area grazed(ii) Area ungrazedATQ,(i) Area grazed= Area of circle with r=7 m=πr²=22/7*(7)²=22*7=154 m²Now,Area ungrazed=Area of square-Area grazed=[(a)²-154] m²=[(17)²-154] m²=[289-154] m²=135 m²

62894.

p(x)=-a*e*f*i^3*l*m*o*p*s*t*text*u*(2*x %2B 1) - x %2B 4*x^3 %2B 4*x^2

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I don't know the answer sorry

62895.

10/ A horse is placed for grazing inside a rectangularfield 40 m by 36 m and is tethered to one cornerby a rope 14 m long. Over how much area can itgraze?

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62896.

iii. Ifx and y vary inversely and y-12, find x when constant of variation-210.

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62897.

15. If x and y vary inversely and x -18 when y 8, find x when y 16.

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62898.

14. Ifxx and y vary inversely and x-15 when y-6. tnd y when x -9

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62899.

18. In Fig. 10.140, X is a point in the interior of square ABCDAXYZ is alspr三3 cm and 47-2 cm, then BY-(a) 5 cmㄣˊgcm

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62900.

EXERCISE 10.2to choose the correct option and give justification.Fron a point O. the length of the tangent to a circle is 24 cm and the distance of Q fnhe centre is 25 em. The radius of the circle isiA) 7cmC) 15cm(B) 12 cm(D) 24.5 cnm

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