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63151.

If a transversal intersect two parallel lines and the difference of two interior anglesthe same side of a transversal is 20°, find the angles

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63152.

cross roads, each of width 5 m, run at right angles through the centre ofarectangular park of length 70 m and breadth 45 m and parallel to its sides. Findthe area of the roads. Also find the cost of constructing the roads at the rate of105 per m212. Two

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63153.

the pPath.Two cross roads, each of width 5 m, run at right angles through the centre of a repark of length 70 m and breadth 45 m and parallel to its sides. Find the area of tAlso, find the cost of constructing the roads at the rate of.105 per m2

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thank you

63154.

5. If two parallel lines are intersected by a transversal, prove that the bisectors ofinterior angles on the same side of transversal intersect each other at right angles.

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AB and CD are two parallel lines intersected by a transversal L. X and Y are the points of intersection of L with AB and CD respectively. XP, XQ, YP and YQ are the angle bisectors of ∠ AXY, ∠ BXY, ∠ CYX and ∠ DYX.

AB || CD and L is transversal.

∴ ∠ AXY = ∠ DYX (Pair of alternate angles)

⇒ 1/2 ∠ AXY = 1/2 ∠ DYX

⇒ ∠ 1 = ∠ 4 (∠ 1 = 1/2 ∠ AXY and ∠ 4 = 1/2 ∠ DYX)

⇒ PX/YQ (If a transversal intersects two lines in such a way that a pair of alternate interior angles are equal, then the two lines are parallel)...(1)

Also ∠ BXY = ∠ CYX (Pair of alternate angles)

⇒ 1/2 ∠ BXY = 1/2 ∠ CYX

⇒ ∠ 2 = ∠ 3 (∠ 2 = 1/2 ∠ BXY and ∠ 3 = 1/2 ∠ CYX)

⇒ PY/XQ (If a transversal intersects two lines in such a way that a pair of alternate interior angles are equal, then the two lines are parallel) ...(2)

From (1) and (2), we get

PXQY is a parallelogram ....(3)

∠ CYD = 180°

⇒ 1/2 ∠ CYD = 180/2 = 90°

⇒ 1/2 (∠CYX + ∠ DYX) = 90°

⇒ 1/2 ∠ CYX + 1/2 ∠ DYX = 90°

⇒ ∠3 + ∠ 4 = 90°

⇒ ∠ PYQ = 90° ...(4)

So, using (3) and (4), we conclude that PXQY is a rectangle.

In a rectangle all angles are 90°.

Hence proved.

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63155.

.Hind the aite of 70 per m2cm of the tablehanging all around the table, find the area of the table top.a garden is 120 m long and 85 m wide. It has an insidecoA tablecover 5 m x 3 m, Is spread on a meeting table. I 2

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63156.

1)72cm,(ii)2.4 m.12. The area of a square is 16200 m2. Find the length of its diagonal

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63157.

14. The area of a square plot is 6084 m2. Find the length of the wire which can go four timesalong the boundary of the plot.

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63158.

uare plot is 6084 m2. Find the length of the wire which can go four times asthe boundary of the plottA wire is in the shape of a squaro o a14. The area of a sqlengthtimes along

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63159.

Š find the greatest wo that raill aliviale,162] leaning semaine dus 4,5 ands.

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63160.

A number has two digits. The unit digit is four times than tens digits. It the differencebetween the number obtained by reversing the digits and the original number is 54, find theoriginal numberALDOC) 14(D) 41

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(a) 28unit digit is 4 times and the difference between number and reversed number is 54..

63161.

wo cubes have their volumes in the ratio 1 27. Find the ratio of their surface areas.

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63162.

A particle moves according to the laws =-61 + 91 + 15, find the velocity whent = 0.wo

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63163.

Hint. 1 hectare = 10000 m2Phe area of a square plot is 6084 m. Find the length of the wire which can go four tlines

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Given : Area of the square plot = 6084 sq m.Area of square = Side× Side6084 = Side²Side =√6084Each side of square plot = 78 mNow, for finding out the length of wire which can go along the boundary of the plot, we have to find the perimeter of the square plot.So,Perimeter of square plot = 4× Side= 4× 78Perimeter of square = 312 mNow,The length of four rounds of wire = 312× 4= 1248 mSo, the length of four rounds of wire is 1248 m

63164.

147lelogram ABCD, two points P and Q areonal BD such that DP BQ(see Fig. 8.20). Show that:i) AP CQ(iii) ΔΑQB Δ CPDIV(iv) AQ CP(v)APCQ is a parallelogramFig. 8.20

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correct

63165.

13. The area of a square field is hectare. Find the length of its diagonal in metres2Hint.1 hectare10000 m2ind the length of the wire which can go four tes

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63166.

12 cm,(ii) 2.4 m12. The area of a square is 16200 m2. Find the length of its diagonal.13. The a

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63167.

the area of Square is 16200 m^2. Find the length of its diagonal.

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a+b2222422445253321442

63168.

4(a)identily the transversal lines in the following figuret8. Int

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1) l,m,n

2) n

3) l

In geometry, a transversal is a line that passes through two lines in the same plane at two distinct points. Transversals play a role in establishing whether two other lines in the Euclidean plane are parallel

63169.

The area of a square field is 729 m2. Find length of its side.

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thanks

63170.

Do all the parts:(a)The area of rectangle acts reduced by 8 m2, whenits length is reduced by 5 m and its breadth isincreased by 3 m. If we increase the length by 3 mand breadth by 2 meter, the area is increased by 74m2. Find length and breadth of the rectangle. 4ma,

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63171.

3. A dictionary contains 2012 pages. A new version includes 1003 more pagesWhat is the total number of the pages in the new version

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total number of pages = 2012 +1003=3015 pages

63172.

Wo find the product of 7 and 2

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-12/15 * 8/10 = -48/75

-48/75 is right answer

63173.

42. The area of a rectangular field getsincreased by 25 m2, if its length isreduced by 5 m and breadth is increasedby 5 m. However, if the length isincreased by 2 m and breadth is reducedby 4 m the area reduces by 88 m2Find () length, breadth and perimeterof the field. (i) area of the field

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length = 5 m breadth equals 4m and area =478 sq m

63174.

The area of a square plot is 6084 m2. Find the lengthof the wire which can go four times14.onbont into a rectanle of length

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63175.

The area of a square is 16200 m2. Find the length of its diagonal.

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63176.

A parallelogram has height 5.6 m and area 70 m2. Find the length of its bats

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Area of parallelogram = base × height

Base × 5.6 = 70

Base = 70/5.6 = 700/56 = 100/8 = 25/2

Base = 12.5 cm

63177.

12. The area of a square is 16200 m2. Find the lengthofitsdiasonal.

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63178.

मूलधन 4000 रु., दर 5%, समय 2 वर्ष

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400 rs. ब्याज correct answer.

400₹ is the answer of the following

मूलधन रू दर 5% समय 2 वर्ष

P=4000 rs.R=5%N=2 years SI = PTR /100 = 4000×5×2/100 = 400 rsA = P + SI = 4000 + 400 = 4,400 rs.

63179.

Find the cube root of 8000.

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=20

63180.

Find the cube root of 8000

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20 is the cube root of 8000

cube root of 8000 is 20

63181.

4000+2000=

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63182.

- मूलधन =₹8000, दर = 8% वार्षिक, समय =

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SI=1600 is the right answer

si 1600 is the right answer

1704.448 it is right answer

simple interest--1600

correct answer for this question

1600is the correct answer

simple interest–1600 is the correct answer

1704.448 is correct answer.

63183.

मूलधन =₹8000, दर = 8% वार्षिक, समय -

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a year samaj to bahr hee

मूलधन *दर *समय /1008000*8*2.5/100=16000

मूलधन * समय * * 10 बटेसों

मूलधन * समय * दर बटा 100 ब्याज ज्ञात करने का सूत्र है इससे ब्याज ज्ञात करते हैं सोलह सौ आता है

1600 is the correct answer.

8000×8×5/100×2 मिश्र भिन को साधारण भिन में बदलेंगे tb 5/2 आएगा अब अगर solve करेंगे =40×8×5=1600 is correct answer

1600 is the correct answer

63184.

aveen reads a non-fiction book which contains 280 pages. If he has read 40% of the totalbook then find the number of pages left to be read) N

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40% of 28040/100*280=112 pages readleft=280-112=168 pages

63185.

a book contains 92 pages a page is chosen at random what is the probability that the sum of digits in the number is 9 ?

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Number of pages of the book = 92

Which are from 1 to 92

Number of possible outcomes = 92

∴ Number of pages whose sum of its page is 9 = 10

i.e. 9, 18, 27, 36, 45, 54, 63, 72, 81, 90

P(E) = 10/92 = 5/46

63186.

4000t His porsentigs woin the Manks

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please post clear image with proper light.

Please post a clear image with proper lighting. We cannot provide a solution without a clear image of question.

ok

63187.

Solution :For 4, ' 3'Product of extremes Produc83-4Product of extremes = 4 × 8Product of means 7x 5Hence, the numbers are in propor3EXERCISE 8.3Are 12, 18, 8, 12 in proportion?

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yes they are in proportion

63188.

calculate the pressure exerted by a force of 100N on an area of 20m2

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If F is theforceacting normal to the surfaceareaA,then thepressureP is given by : P = F/A, Newtons/square meter or P = F/A Pascals.

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the correct answer is 5 Pascal

the right answer is 5 Pascal

force=load/areaf=1000/20=50 n/m2

63189.

,.Two-fifths of a number is 8. Find the number.

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Let the required number be x.

=>(2/5)×x=8=>x=8×5/2=20.

:. the required number is 20.

63190.

Total surface area of a cube is 1014 m2 Findlength of the side of the cubethe

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63191.

totalsdiagonal. 46 em, JdilTotal surface area of a cube is 1014 m2. Findlength of the side of the cube. 13em

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Given total surface area = 1014 m sqFormula : Total surface area of cube= 6 a^2Solution: 1014= 6 a^2a^2=169a=13Therefore Side of the cube = 13 m

63192.

Fig. 10.3nFig. 10.39, A, B, C and D are four points on acircle. AC and BD intersect at a point E suchthat BEC = 130° and ECD = 20". FindВАС.130lu 10.39

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63193.

ही. wihthey #e o व. =LU 5 6 4,]%, AP'WLP

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63194.

1815. The dimensions of a cuboid are in the ratio of 1:2:3 and its total surface areais 88 m2. Find the dimensions.

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63195.

19. An aeroplane, wien flying at a height of 4000 m irom the ground passes vertically above anotheraeropiane at an instant when the angles of eluvation of the iwo planes from the same point on theground ate 60 and 45 respectively. Find the vertical distance betveen the aeroplanes at that iristant(lake 3 1.73)| an 6?" İn erms of trio onntnetic ratios of angles between 00 and 452epmetric rafios of augles between)o arZ 10cin 57,

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63196.

d. 935A Book contains 320 Pages, vishal roadsof the book. How many the has stillto readP

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it's not a good day at 🏫 tomorrow and I don't know how to get free products from shop and I don't know how I was going to get the money I don't know

320-192=128 pages still to read

No. of pages read by vishal=3/5 × 320=3×320/5=960/5=192/1 [on cutting]=192 pages

No. of pages still left to read=320-192=128Hence,128 pages are still left to read.

No. of pages read by vishal=3/5 × 320=3×320/5=960/5=192/1 [on cutting]=192 pages

No. of pages still left to read=320-192=128Hence,128 pages are still left to read.

128 pages are left to read

128 is the correct answer

63197.

A dealer buys an article marked at Rs. 25000 with 20% and 5% off. He spends Rs 2000 onits repair and sells it for Rs 25000. What is his gain or loss percent?

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Price of article after 20 % discount= 25000(1-20/100)= 25000(4/5)= 20000

Additional 5% discountPrice of article at which dealer get=20000(1-5/100)=20000(15/20)=15000

CP of article = 15000 + 2000= 17000SP = 25000

Gain%=[ (sp-cp)/CP]x100= (8/17)100= 47%

63198.

2000+4000+4000

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10000is the most correct answer

10000 is the most correct answer

63199.

lI in the blank) 4000-10008000- 10006000- 4000

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4000 -1000 =30008000-1000 =70006000-4000 =2000

63200.

Vishal gets 60 marks and fails by 20 marks in a Mathematics paper where the maximum marks are 200 Find the pass percentage

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pass mark = 80

pass % = 80*100/200

= 40%

pass marks =60+20=80TOTAL marks=200Percentage of pass marks=80÷200×100=40%