Explore topic-wise InterviewSolutions in .

9 + 2*2 = 9 + 4 = 13 13 + 3*3 = 13 + 9 = 22 22 + 4*4 = 22 + 16 = 38

For the sequence to be proportion, we need to ensure that

term1/term2 = term3/term4 ...

Define x:

Let x be the number that we need to add to each number

Solve x:

Sequence = 10, 18, 22, 38

(term 1 + x) /(term 2 + x) = (term 3 + x) / term 4 + x)

(10 + x) / (18 + x) = (22 + x) / (38 + x)

(10 + x)(38 + x) = (18 + x) (22 + x)

380 + 10x + 38x + x² = 396 + 18x + 22x + x²

380 + 48x + x² = 396 + 40x + x²

48x - 40x = 396 - 3808x = 16x=2

Here segment APB is a minor segment so area of minor segment will be

TYPING KEYS:-Although the phrase refers totypingwithout using the sense of sight to find thekeys- specifically, a touch typist will know their location on thekeyboardthrough muscle memory - the term is often used to refer to a specific form of touchtypingthat involves placing the eight fingers in a horizontal row along the keyboard.

in 5! ways =5*4*3*2*1=120 ways

Atma Sethi the answer is 1/2*4!

Let Vishal monthly income be x

As he spend 80% of his income and save 20%

Hence,(20/100)*x = 15000x = 15000*100/20x = 75000

Therefore, Vishal monthly income is Rs 75000

d = 2-(-1/2)= 5/2

11th term = a + 10d= -3 + 10(5/2)= -3+25=22

We know sum of three angles of a triangle is 180°

Let third angle is x

Then,51 + 113 + x = 180x = 180 - 164x = 16

Therefore, third angle is 16°

correct because I have also solve to check whether it is right or not

36 student are passed

no. of students= 45 , there will be 9 groups of 5 students , every one student fails from a group so there will be 40 students who has passed

iuaqov,w9gql7H0z0qn sind9K

36 students are passed

36 students are passed in the class.

there are 9 students passed

36 students are passed

36 student Passe and this is bast answer

40 students who has pass

36 students passed in a calss room

36 is the correct answer of the given question

36 students are passea

35 students are pass in the class

35 students are in the class

No.of student=42No.of fail=42/6=7So,no of fail=42-7=35 students

35 are in the pass in a c

35 are pass in the class

Base area =πr² = 38.5 cm²

Volume = (1/3)πr²×h = 77 cm³

so,

77 = (1/3)×38.5×h

⇒h = (77×3)/38.5

= 6 cm

4m 92cm + 3m 77cm=4.92+3.77=8.69

Let the radius of circle = r cm

According to the question,

Area of sector =77cm^2

(θ/360°)×πr^2=77 =>(45°/360°)×πr^2=77

=>r^2=77×7×8/22=> r=14 cm

hit like if you find it useful

Net area to be covered=2(lb+bh+hl)-lb=2(55*35+35*12+12*55)-55*35=6010-1925=4085cm^2Area of tarpaulin=length*width4085=length*70Length=58.35cmFor 150 suitcases, 150*58.35=8752.5cm

bhaiya 5.25 m kaisa nikla

A desktop computer is a personal computing device designed to fit on top of a typical office desk. It houses the physical hardware that makes a computer run and connects to input devices such as the monitor, keyboard and mouse users interact with.

Total Computer purchased=45Cost of 1 computer=14,670 rs.cost of 45 computers=45*14670 =6,60,150rs.

total computer=45cost1computer =14.670cost 45 computer= 45*14.670 =660.15

Very helpful

each student requires 1/2 a computer 24* 1/2=12

For AP 3, 8, 13, 18....a = 3, d = 8 - 3 = 5

nth term of an APTn = a + (n - 1)d

Let mth term of given AP is 78Then,78 = 3 + (m-1)*578 - 3 = 5m - 55m = 80m = 80/5 = 16

Therefore, 16th term of AP is 78

{25*16÷(60÷15)-4*(77-62)}

= {25*16÷(4)-4*(15)}

= {25*4-4*15}

= 100-60

= 40

1344

m = 22 + 18 = 40cm = 77 + 54 = 131

As 100 cm = 1 mThen, 131 cm = 1 m 31 cm

Therefore,Total sum = 41 m 31 cm

the ANSWER IS ACCORDING TO ME EXACTLY

41.31

Volume=4/3πr^3henceVolume=4/3*22/7*343=1437.33 cm^3

Volume =4/3πr^3hence volume = 5/3*22/7*343=1437.33 cm^3

150.72 is the CSA of conr

radius is not r.. diameter is r

Radius=7cmV=4/3πr^3=4/3π×(7)^3=1437 1/3cm^3ii. 0.63mV=4/3πr^3=4/3×22/7×(0.63)^3=1.0478cm^3

this is a answer