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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 63951. |
\left. \begin{array} { l } { \operatorname { sin } ^ { - 1 } \frac { 4 } { 5 } + 2 \operatorname { Tan } ^ { - 1 } \frac { 1 } { 3 } = \frac { \pi } { 2 } } \\ { 4 \operatorname { Tan } ^ { - 1 } \frac { 1 } { 5 } + \operatorname { Tan } ^ { - 1 } \frac { 1 } { 99 } - \operatorname { Tan } ^ { - 1 } \frac { 1 } { 70 } = \frac { \pi } { 4 } } \end{array} \right. |
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| 63952. |
\left. \begin{array} { l } { 5 x + 3 y = 9 - - - - ( I ) } \\ { 2 x + 3 y = 12 - - - ( \Pi ) } \end{array} \right. |
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Answer» Subtracting equation 2 from 1x=-1 and put the value of x in y..then y=14/3 5x+3y=9- 2x+3y=12(-) (-) (-)____________3x=-3x=-3/3x=-1 5x+3y=95×(-1)+3y=93y=9+5y=14/9 subtract equator your answer will come |
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| 63953. |
\begin{array} { l } { \text { Prove that: } } \\ { \text { 1. } \sin ^ { 2 } \frac { \pi } { 6 } + \cos ^ { 2 } \frac { \pi } { 3 } - \tan ^ { 2 } \frac { \pi } { 4 } = - \frac { 1 } { 2 } } \end{array} |
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| 63954. |
16. A man sells an article at a loss of 10%. If he had40 more he would have gained 10%. "Thesold it for Rs.cost price of the article is:- |
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Answer» SP = CP - CP*10/100SP = CP(1 - 1/10)SP = CP*9/10 SP + 40 = CP(1 + 10/100)SP + 40 = CP(11/10)CP(9/10) + 40 = CP(11/10)CP(2/10) = 40CP = 40*5CP = 200 Cost price is RS. 200 |
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| 63955. |
16. A man sells an article at a loss of 10%. If he hadsold it for Rs.40 more he would have gained 10%. Thecost price of the article is:- |
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| 63956. |
IRS133The nltitude of ล right triangle is 7 ebase. If the hypotenuse is 13 emo sides.find the |
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| 63957. |
A man sold an article at a loss of 20%. If he soldit for 12 more, he would have gained 10%. Thecost price of the article is |
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| 63958. |
17.D) केवल 1 का पालन होता है। (Only 1 follow)नीचे दिए बेन आरेख में कौन सा स्थान उन लड़कियों का प्रतिनिधित्वकर रहा है जो एधलीट है लेकिन अनुशासित नहीं है?In the below Venn diagram which number spacerepresents the girls who are athletes but not discipline ?O|→ Boys→ GirlsAthletics1→Discipline110| 1 c) >OLaa,(B)(D)8.4र होता है। |
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Answer» 4 is right ans bcz vo circle m bhi and triangle m bhi h bus or kisi m bhi nhi h ans= 3 options A |
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| 63959. |
\frac { \operatorname { cos } ( \pi + x ) \operatorname { cos } ( - x ) } { \operatorname { sin } ( \pi - x ) \operatorname { cos } ( \frac { \pi } { 2 } + x ) } = \operatorname { cot } ^ { 2 } x |
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| 63960. |
& A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl irs5 cm. Find the outer curved surface area of the bowl. |
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| 63961. |
\operatorname { sin } ^ { 2 } \frac { \pi } { 6 } + \operatorname { cos } ^ { 2 } \frac { \pi } { 3 } - \operatorname { tan } ^ { 2 } \frac { \pi } { 4 } = - \frac { 1 } { 2 } 2 \cdot 2 \operatorname { sin } ^ { 2 } \frac { \pi } { 6 } + \operatorname { cosec } ^ { 2 } \frac { 7 \pi } { 6 } \operatorname { cos } ^ { 2 } \frac { \pi } { 3 } = \frac { 3 } { 2 } |
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Answer» 1) 2) |
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| 63962. |
tan(acot(3/2) %2B asin(3/5)) |
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Answer» tan(tan^-1(3/√5^2-3^2+tan^-1(2/3))tan(tan^-13/4+tan^-12/3)tan(tan^-1(3/4+2/3/1-3/4*2/3)tan(tan^-1(17/6)=17/6 |
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| 63963. |
acot(x) %2B asin(1/(sqrt(5)))=L*(pi/4) |
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Answer» X= 3 is the answer to the question |
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| 63964. |
2 \sin ^{2} \frac{3 \pi}{4}+2 \cos ^{2} \frac{\pi}{4}+2 \sec ^{2} \frac{\pi}{3}=10 |
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| 63965. |
5) Stickers are bought at 11 for 10 and soldat 10 foräš11, Find the profit per cent. |
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Answer» Cost price of 11 stickers = Rs10 Cost price of 1 sticker = Rs 10/11 Therefore cost price of 10 stickers = Rs 10/11 x 10 Selling price of 10 stickers = Rs11 Therefore profit = SP -- CP = Rs 11 -- 100/11 = (121 -- 100) /11 = 21/11 Therefore profit per cent = P/CP x 100 = 21/11 ÷ 100/11 × 10 = 21 % |
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| 63966. |
______he does not quit smoking, he will getcancer. |
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Answer» Unless he doesn't quit smoking, he will get cancer.2) if he doesn't quit smoking, he will get cancer. any body he does not quit smoking he will get cancer |
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| 63967. |
key |
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Answer» key is to remove lock key is remove the lock key is remove and replace to lock |
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| 63968. |
11, An article was sold at a profit of 7%. If it had beensold for 276 profit, he would have gained 10%.Find the cost price. |
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| 63969. |
2) Observe the Venn diagram and write following sets.A, B, C, An B,AuB,An BnC101 12 |
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| 63970. |
Which of Venn diagram represents set A -(Bn C)is(C) A(D)A |
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Answer» option B is the correct answer how????? A-[Bnc] = [A-B] U [A-C]So here [A-B] Means only A except B So Dont minus the part of A, only minus the part of B. Hence the answer is B/A. Because the given Picture is not clear!!! Just make it clear. |
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| 63971. |
theta*asin(x) %2B asin(2*x)=pi/3 |
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Answer» sin^-1(x)+sin^-1(2x)=π/3 First, it is helpful if we rewrite this expression parametrically:a+b=π/3a=sin-1(x)b=sin-1(2x) In turn we can solve the second and third equations for x:x = sin(a)2x = sin(b) And then substitute sin(a) into 2x = sin(b) for:2sin(a) = sin(b) Now we have a system of two equations with two variable we can solve:a+b = π/32sin(a) = sin(b) Isolate a in the first equation:a = π/3-b And substitute:2sin(π/3-b) = sin(b) Use identity:sin(α-β)=sin(α)cos(β)-cos(α)sin(β) where we will use α=π/3 and β=b. This will change our expression to:2(sin(π/3)cos(b)-cos(π/3)sin(b) = sin(b)2((√3/2)cos(b)-(1/2)sin(b) =sin(b) √3cos(b)-sin(b)=sin(b) √3cos(b)=2sin(b) √3=2sin(b)/cos(b) √3/2=sin(b)/cos(b) tan(b)=√3/2 b=tan^-1(√3/2) Convert to inverseb≈.713724379 Since we already know that 2x=sin(b), we plug it in and get x≈.327326835. |
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| 63972. |
a Δ ABC, if3<A = 42B = 62C, calculate the angles. |
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Answer» angle A = x then angle B = 3x/4 and angle C =x/2 Sum of all angles of triangle = 180 degrees =>x+3x/4+x/2 = 180 => (4x+3x+2x)/4 =180 =>9x = 720 => x = 80 degrees angle A = x = 80 degreesangle B =3x/4 = 60 degreesangle C =x/2 = 40 degrees=> 9x =720 => x =80 |
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| 63973. |
Find ะบ, if3 is a solution of 3x2 + (K-3)x + 90 |
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| 63974. |
acos(15/17) %2B asin(3/5)=asin(77/85) |
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| 63975. |
y=asin(x) %2B asin(sqrt(-x^2 %2B 1)) |
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| 63976. |
asin(1/3) %2B asin((2*sqrt(2))/3)=pi/2 |
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| 63977. |
3 Harish sohavebeeld a bicycle at 8% gain. HadÄŤt been sold for Rs 75 more, thegan would14%Find the cost price of the bicycle. |
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| 63978. |
key word of lungs in 1mark question |
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Answer» Ans :- Lungs: The lungs are a pair of breathing organs located with the chest which remove carbon dioxide from and bring oxygen to the blood. |
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| 63979. |
17. Draw Venn diagram of a) (A-B) b)AnB. |
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Answer» you are a given N that the property that every next digit N is greaest thab the previousdigit,now multiply N by 9,what is the sum of digits of the resulting number? |
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| 63980. |
11 Naresh sold a bicycle at a profit of 10%. Hadhe sold it for 150 more, the profit would havebeen 15%. Find the cost price of the bicycle. |
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Answer» 10/100(150) 150cost price 10/100(150) 150 cost price 10/100(150) 150 is the cost price cost price is 1000 is the best answer cost price of bicycle is 1000 15%=150₹then 1%=10₹so, 100%=10×100 =1000₹ cost price of bicycle is ₹1000 cost prise of cycle = rupee 1000 10/100(150) 150 cost price is the best answer think total amount is rs."X"x-(x*10%)+150=15%x-10x/100+150=15%100x-10x+15000/100=15/10090x+15000=1590x=15000-15x=14985/90 =6106.50 226 rupees is the right answer 10/100(150) means 150 is the cost price cost price ofcycle =rupees 1000 ₹150 is cost price of bicycle answer of this question is rs 3000 |
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| 63981. |
cos 55°-sec A cosec A35°) cos 35°tan A- A) cos (90-A) 1+tan2A1 then 28o |
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Answer» 🙏🙏 |
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| 63982. |
Factorise the following using a962) 200 |
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| 63983. |
A = 4 , \text { check whether } \frac { 1 - \operatorname { tan } ^ { 2 } A } { 1 + \operatorname { tan } ^ { 2 } A } = \operatorname { cos } ^ { 2 } A |
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Answer» cotA=4/3so tanA=3/4 so cosA=4/5 sinA=3/5L.H.S.=(1-9/16)/(1+9/16)=7/25R.H.S.=16/24-9/25=7/25=L.H.S.Hence Proved. |
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| 63984. |
8.If3 cot A = 4, check whether-tan2A-COS2A-sin2A or notcos' A-sin-A or not.1 tanos |
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| 63985. |
1- tan2 A8. If 3 cot A 4, check whether + tanCOS Asin'A or not.- cos? A sin A or not. |
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| 63986. |
draw the diagram of lungs |
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| 63987. |
2. A bicycle was bought for 2470 and sold at a gain of340. Find the selliprice of the bicycle. |
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Answer» Cost price of bicycle=2470rsProfit=340rsSelling price=cost price +profit =2470+340 =2810rs |
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| 63988. |
Rsshopkeep er sold pricy ofthe bicycle.10% for(for( ((161nd S.PPRs.450. Find the cost price of the bicycle |
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Answer» 10 percentage loss means 100-10 = 90 percentage= 4501 percentage= 5100 percentage or cost price= 5*100= 500 rupees Cp=(100/100-10)*450CP=(100/90)*450CP=₹500 three solid cubes are 6cm, 10 and x cm are melted to form a single cube of edge 12, cm, find the value of x |
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| 63989. |
3 822(AV)) 3R tanA= 34— sec A &1 T &M |
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Answer» sec²A=tan²A+1tanA=4/3sec²A=(4/3)²+1sec²A=16/9 +1sec²A=(16+9)/9sec²A=25/9secA=5/3 |
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| 63990. |
how to draw venn diagram?((aUb'Uc) |
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Answer» * The first step to creating a Venn diagram is deciding what to compare. Place a descriptive title at the top of the page.*Create the diagram. Make a circle for each of the subjects. Every circle should overlap with at least one other circle.*Label each circle. Near or inside of each circle place the name of the topic or item which the circle represents. Avoid writing the titles inside neighboring circles in order to maintain clarity. It may be useful to distinguish the titles from other text by placing them in a box or altering their font or color.*Enter the differences. Inside each circle place characteristics that are unique to that specific item or idea, and are not true of any of the other topics.*Enter the similarities. If two or more subjects have a feature in common, place that feature in the section in which all such shapes overlap |
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| 63991. |
3 cmThe larger of two supplementary angles exceeds the smaller by 20 degrees. Find the angles.cos 55o cosec 357 cos 700 3 |
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Answer» Let the angle be xother angle (it's supplement) =( 180-x)x+18= (180-x)2x = 162x = 162/2 = 81other angle(its supplement) = 180- x => 180-81 => 99 |
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| 63992. |
eis en5, 8, 17,(A) 2537,48(B) 13(C) 24(D) 20 |
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Answer» the sequence is written as 5,8,17..... 37,48 notice the pattern is following as 5 = 2²+1 8 = 3³-1 17 = 4²+1 .... = 5²-1 = 24✓37 = 6²+1 48 = 7²-1 so, the value in the blank should be 5²-1 = 24. |
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| 63993. |
s N g हक ४... R2 (10°0) +¢.C : Thile hE 3R18(2¢8) - |
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Answer» 1/2^3+1/√0.01-(3^3)^2/31/8+1/0.1+9= 0.125+10+919.125 |
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| 63994. |
now that:se × height12 cmenyFig. 12.1 |
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Answer» area of ∆ = 1/2*(12*5) = 1/2*(h)*(13) => 12*5 = h*13=> h = 60/13 |
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| 63995. |
1- tan2 AIf 3 cot A4, check whether- cos A - sin A or notINCERT1 + tan? A |
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| 63996. |
ग g PRI १1४ ' हे 2109 13k १ 0 न ENY दर कक 2): 9| |
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| 63997. |
be in your notebook the chgs you foced wilesxinming or eny lhts from the web toleiraingLeorsing BicycleChollenges |
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| 63998. |
Find them.(ii) The larger of two supplementary angles exceeds the smaller by 18 degrees. Findthem.d 6 halls for 7 3800. Later, she buys 3 |
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Answer» thnx man |
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| 63999. |
7. It is given that in a group of 3 students, the probability of 2 students not having thesame birthday is 0.992. What is the probability that the 2 students have the samebirthday?allo ond 5 hlack halls. A ball is drawn at random from the bag. |
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| 64000. |
AYNA VE AV ALAMUA UVUDUL28. The mass of a brick is 2g. What is the total mass of 14 such bricks?11 |
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