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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 64251. |
5. n If onetoot of the equation 2x2, 10x tep. 0 is 2, then find the value of p. |
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| 64252. |
9. A car moves at a uniform speed of 75 km per hour. How much distance will it cover in98 hours? |
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Answer» Speed=distance/timeDistance=75*98=7350km |
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| 64253. |
3. Obtain all other zeroes of 3x+6x-x-10x-5, if two of its zeroes are andN 3 |
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| 64254. |
\begin{array} { l } { \text { Evaluate each of the following without using } } \\ { \text { tables : } } \\ { \text { (i) } \log 5 + \log 8 - 2 \log 2 } \end{array} |
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| 64255. |
Obtain all zeros of 3x^4 +6x^3 -2x^2-10x-5.lf two of its zeros are -1 and -1. |
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Answer» Quotient is x2+2x+1 Compare the equation withax2+ bx+ c= 0 We get a = 1 ,b=2 c= 1 To factorize the value we have to find two value which sum is equal to b= 2 product isa*c=1*1 = 1 1 and 1 are required values which sum is1 + 1= 2 product is1 * 1= 1 So we can write middle term2x= x+ x We get x2+ x + x + 1 =0 x (x +1) +1(x +1) = 0 ( x + 1)( x + 1)= 0 x+1 = 0 , x+1= 0 x= -1 , x= - 1 so our zeroes are - 1-1 , √(5/3) and- √(5/3) answer is wrong Kindly go through the entire problem once again, the four zeroes are -1,-1, root 5/3 and - root 5/3. |
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| 64256. |
State the condition when the linear congruence ax= b (mod n) has a solution. |
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| 64257. |
rYcsf the syuore of a mom beadded to fhe op 28¡theiSresult is 180whiat te umbeynumbey1S SOS. |
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| 64258. |
etsQat hen divided by 128 aFindl the mom bex |
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Answer» Let the number be x divident = divisor×quotient + remainder x=128×27+5 x=3461 |
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| 64259. |
40. If three circles of radius a each, are drawn such that each touches theother two, prove that the area included between them is equal to 4[Take /3 1.73 and T - 3.14.]25 |
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| 64260. |
log xShow that the function given by f(x)-ben has maximum at x-e. |
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| 64261. |
35. (d) Given, y = log (sin(x²))On differentiating both sides w.r.t. x, we get |
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| 64262. |
7.Express ½ log(x+y)-2log(x-y) as single !gorithm? |
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| 64263. |
6.Given that log x = m + n and log y = m-n,express the value of log10and n10xin terms of m(ICSE) |
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Answer» thank you very much |
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| 64264. |
I1. Given logio 25 , log o 75 y, evaluate withoutusing logarithmic tables, in terms of x, y(1 log1o3,(ii) log102ICSE) |
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| 64265. |
convert 40km in metres |
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Answer» 1 km= 1000 m40 km=40×1000m 40000m 1km = 1000m40km=40x1000therefore 40km =40000m |
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| 64266. |
A car moves at a speed of 40km/h.how far it will travel in 40 minutes |
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Answer» Thanku |
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| 64267. |
13. Find the condition which must be satisfied by the coefficients of the polynomial)X3-px2 t qx-r, where the sum or its two zeros is zero. |
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| 64268. |
ABC and ÎDEF, AB-DE and BCEF (Fig. 9.19).Fig. 9.19What additional information is required to maongruence condition?ke the two triangles congruent b |
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| 64269. |
DESCRIBE The Rese-Beettle mom |
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Answer» http://www.e-reading.mobi/chapter.php/85610/6/Durrell_-_My_family_and_other_animals.html |
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| 64270. |
deProve that AB CD2A straight line is drawn cutting two equalcircles and passing through the mid-point Mof the line joining their centres O and O'.o'Prove that the chords AB and CD, which anted hy the two circles, are equal. |
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Answer» Draw OP⊥AB and O'Q⊥CD.Consider ΔOPM and ΔO'QMOM = O'M [Given]∠OMP = ∠O'QM [Vertically opposite angles]∠OPM = ∠O'QM = 90° [Construction]∠POM = ∠QO'M [Angle sum property of a triangle]So, ΔOPM ≅ ΔO'QM OP = O'Q [CPCT]⇒ AB = CD [Equal chords of same circle or equal circles are equidistance from the centers of the respective circles.]Hence proved. |
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| 64271. |
Draw two concentric circles of radii 3 cm and 5 cm. Construct a tangent to smaller circle from a point on the larger circle. Also measure its length. |
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Answer» 1 2 |
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| 64272. |
2,200 इक चतु्भुन है, जिसमें 0 « 80 और८ 9## # ८ (8 हैं (देखिए आकृति 7.17)। सिद्धऑीजिए किW SABD=ABACW BD=AC(i) £ ABD= £ BAC |
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Answer» Given, AD = BC - - - - - - - - - - - 1 (given) ∠DAB = ∠CBA - - - - - - - - - - 2 (given) AB = AB - - - - - - - - - - - - - - - 3 (common) 1)) ΔABD ≅ ΔBAC By C.P.C.T we can say that all angles and sides of a triangle will also be equal 2))BD = AC By C.P.C.T, we can say that BD = AC 3))∠ABD = ∠BAC By C.P.C.T, we can say that ∠ABD = ∠BAC |
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| 64273. |
लि. I ko é, 1562000 Laiks |
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Answer» 150 : 200 15 : 20 3 : 4 is the ratio in simplest form |
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| 64274. |
3.Given log x = m + n and log y =10xin terms of m and n.m-n, express the value of log- |
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Answer» log identities usedlog(ab) = log a + log blog(a/b) = log a - log blog(a^n ) = n log a-log(10x/y^2 ) = log(10x) - log(y^2 )log(10x/y^2 ) = log(10) + log(x) - 2log(y)log(10x/y^2 ) = 1 + log(x) - 2log(y)log(10x/y^2 ) = 1 + m + n - 2(m - n) = 1 + m + n - 2m + 2nlog(10x/y^2 ) = 1 - m + 3n |
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| 64275. |
16 Given that log xm+ 1n and log y -m-n, express the value of log10* in terms of2m and n. |
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Answer» log(10x/y²) = log10x - logy²= log10 + logx -2logy= 1 + (m+n) -2( m-n) = 1+m+n-2m+2n= 3n-m+1 |
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| 64276. |
1. State any two conditions The mandependiíessential for good health. |
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| 64277. |
(\cos x+\cos y)^{2}+(\sin x-\sin y)^{2}=4 \cos ^{2} \frac{x+y}{2} |
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| 64278. |
\cos x \cos \frac{x}{2}-\cos 3 x \cos \frac{9 x}{2}=\sin 7 x \sin 8 x |
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| 64279. |
40km ko meter me change |
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Answer» 1km [ 1000meter40km = 40*1000 meter= 4*10^4 meterPlease like the solution 👍 ✔️ 1 km ka matlab 1000 meter to 40 km ka matlab 40000 meter 1km =1000m =40*1000=40000m |
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| 64280. |
tivities, including calls on me-mbers of Congress, advertisi-ng, funding of thinktank rese-arch and efforts to get the at-tention of President Trump,whose on-again, off-again stre-ak of economic populism is ofparticular concern to thefirms. Last month, the indust- |
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Answer» an angle of measure 150 degree angle |
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| 64281. |
frame sentence of the following words.gracious |
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Answer» I am saved by God's gracious intervention on my behalf. |
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| 64282. |
frame the sentence of the following wordsincident |
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Answer» It was anincidentwhich did not change her plan. |
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| 64283. |
frame the sentence of the following wordsanimation |
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Answer» Theanimationfor the film took over two years to complete |
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| 64284. |
50 ko sabd me likhe |
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Answer» 50 को शब्द मे "पचास" कहते है। |
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| 64285. |
Draw two circles passing through A, B where AB-5.4cm |
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Answer» Draw a line segment of length 5.4cm Draw the perpendicular bisector Taking A and B as centre's and AP & BP as radius draw 2 circles. thanks very much bro |
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| 64286. |
1. The volume of a cube is 343 cm3, find the length of an edge of cube. |
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Answer» If you find this solution helpful, Please give it a 👍 |
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| 64287. |
bf kare+ b and k-a-b, express log(-j in terms ofandE |
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Answer» thank you |
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| 64288. |
\frac { 1 } { x + 1 } + \frac { 1 } { x + 3 } = \frac { 2 } { x + 4 } , \text { find } x |
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| 64289. |
22cos x-sin x-1x +1-1is continuous at0, findx=0 |
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| 64290. |
Train A is 280 m in length and train B is 370 m in length. A has a speed of 40 km hr and B has a speed okim/hr. If they move in opposite direction, find the time A will take in passing B completely |
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| 64291. |
Dashmalw snkhya ko bhinn me saraltam roop me likho0.125 |
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Answer» 0.125 ka Bhinn roop 125/1000 = 5/40 = 1/8 To 0.125 ka bhinn roop 1/8 hai |
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| 64292. |
tanA+secA=x, to sidh kare ke sinA=x2+1/x2-1 |
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Answer» As we know that 1 + tan²A = sec ²A sec²A - tan²A = 1 (secA + tan A) (secA - tanA) = 1 (secA - tanA) = 1/(secA + tanA) secA - tanA = 1/x ( As givensecA + tanA = x) Now adding (secA + tanA ) + ( secA - tanA) = x + 1/x 2secA = (x² + 1) /x 1/cosA = (x²+1)/2x ( As we know thatsecA = 1/cosA) cosA = 2x/(x² + 1) Cos²A = 4x²/(x² + 1)² 1 - cos²A = 1 - 4x²/(x² + 1)² sin²A = (x² + 1 )² - 4x²/(x² + 1)²(sin²A + cos²A = 1) sin²A = [(x²)² + 2x² + 1 -4x²]/(x² + 1) sin²A = [(x²)² - 2x² + 1]/(x² +1)² sinA = √(x² - 1)² / √(x² + 1)² sinA = (x² - 1)/ (x² + 1) Hence proved. true |
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| 64293. |
Three cubes each of volume 343 cm^3 are joined end to end. Find the surface area andvolume of the resulting cuboid. |
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| 64294. |
3. The volume of a cube is 343 cm. Its total surface area is |
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| 64295. |
1Find x in the following figure :40c |
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Answer» x=100 degrees is the correct answer ∆ABC is an isosceles triangle.Therefore, AB = AC and <B = <CNow, In ∆ABC <A + <B + <C = 180° x + 40° + 40°= 180° [Given] x + 80° = 180° x = 180°- 80° x = 100° here the answer will be 100 AB=AC (Given)<B=<C (By theorem)40°=40°Now,In 🔼ABC<A+<B+<C=180°(Angle sum property of triangle)=x+40°+40°=180°=x+80°=180°=x=180°-80°=x=100° |
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| 64296. |
In the following figure, find the measure of other angles, if angle `1 = 50 |
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Answer» ANGLE at 1= 50° Opposite angles are equal at 2 = 50° So, Line AD is a straight line =180°-50° 3 =130°. Opposite angles are equal ,So, 4=130° 1)50°2)50°3)130°4)130° |
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| 64297. |
28. Find the area of the following figure |
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| 64298. |
Find the value of x in the following figure |
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Answer» x+70=90°( right angle)x=90°-70°x=20° thankyou for good bless you Sir its just easy just we can see it is a90 sngle so remaining is (90-20)=70 single false spelling that,s true spelling is angle OK |
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| 64299. |
Findfiverational numberI and 3betweennie, numbers between |
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Answer» n=5+1 = 61*6/5*6. 3*6/5*6= 6/30. 18/30 So,the 5 rational no. are-7/30,8/30,9/30,10/30,11/30 |
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| 64300. |
Find the area of rhombus whose one side is 6.5 cm and the altitude is 4cm. |
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