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65001.

27.The order of rotational symmetry for an equilateral triangle

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65002.

(Mathematical C

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65003.

19,Á car takes 2 hour less to cover a distanuof 240 km, if its speed is increased by20 km/h than its usual speed. What is the20asual speed of the car?

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65004.

write the order of rotational symmetry of a square

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65005.

\begin{array}{l}{9 p^{2}+6 p-8} \\ {3 a^{2}+30 a+63}\end{array}

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65006.

O NN LDLD Oo~

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the answer of this question is 884

65007.

iv) If P(n, 6) 30 x P(n,4), then find the value1Vof n.

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65008.

30 minutes after 11:30 p.m.?

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11 h 30 min+30 min = 12 p.m.=0:00 a.m.

thanku whT a fantansic brain

65009.

\left(\frac{7}{11}\right)^{30} \div\left(\frac{7}{11}\right)^{10}

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here is your answer

here is your answer

65010.

Example 8.7 The brakes applied to a carproduce an acceleration of 6 m s2 inthe opposite direction to the motion. Ifthe car takes 2 s to stop after theapplication of brakes, calculate thedistance it travels during this time.

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hope this helps :)

v=u-atv=0 a=6 t=2secu=at=6*2=12m/ss=ut-1/2at^2s=12*2-1/2*6*4s=24-12=12m

v=u-atv=0 a=6 t=2secu=at=6*2=12m/ss=ut-1/2at^2s=12*2-1/2*6*4s=24-12=12m

65011.

|11. यदि|-sin 30°- tarie हो तो 8 का मान है-1+sin 30° ।

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65012.

3.nultiplied a number by 3.2 instead Ul o8e got is 10.24. What is the correcFind x° and y in the following figung figureA.50°y110

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thanks my friend ☺☺☺☺☺

65013.

Arrange the following fractions in descending order.3/9, 4/5, 6/30, 11/15, 3/6

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4/5 , 11/15 , 3/6 , 3/9 , 6/30

65014.

1) Eight kilograms of salt costsR96. How much does40 kg of salt cost?

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8kg costs rs 961kg costs rs 96/8=rs 12so 40kg costs= rs 12 *40 = rs 480

65015.

lgioup ubes not atfect the variance.Example 19 The mean and standard deviation of 100 observations were calculatd40 and 5.1, respectively by a student who took by mistake 50 instead of 40 forobservation. What are the correct mean and standard deviation?

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65016.

) Represent v2 pn a number line( )'-1 er-$2x-8then find the value of x.

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65017.

1. Ktraflic signat hoard, indicating 'SCHOOL AHEAD', is an equilateral triangle withside "a". Find the area of the signal board, using Heron's formula. If its perimeter is180 em, what will be the area of the signal board?

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Given, side of asignal whose shape is an equilateral triangle= a

Semi perimeter, s=a+a+a/2=3a/2

Using heron’sformula,

Area of the signal board = √s (s-a) (s-b) (s-c)

= √(3a/2) (3a/2– a) (3a/2– a) (3a/2–a)

= √3a/2 ×a/2× a/2×a/2

= √3a⁴/16

= √3a²/4

Hence, area of signal board withside a by using Herons formula is= √3a²/4

Now,

Perimeter of an equilateraltriangle= 3a

Perimeter of the traffic signal board = 180 cm (given)

3a = 180 cm

a = 180/3= 60 cm

Now , area ofsignal board=√3a²/4

= √3/4 × 60 × 60

= 900√3 cm²

65018.

3. Find the measure of an angle which isi. equal to its complementii. 14° more than its complementv. one-half of its complementvii. one-fifth of its supplement

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65019.

Questions1. Find the measurere of the angle which is complement of itself.angle, the complement of (90°-α).

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Sum of complementary angles is 90°.Let x be the required angle. x + x = 90° 2x = 90° x = 45°

65020.

10. Find the value of x in each figure:2r+303r- 2011. Find the magnitude of an angle, which is(i) 3 ofits supplement.(ii) İof its complement.12. An angle is equal to its complement. Find its measure.

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65021.

10. Find the value of x in each figure:2r+3011. Find the magnitude of an angle, which is(1) 3 of its supplement.(ii) 4 of its complement.12. An angle is equal to its complement. Find its measure.

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value of X1)as they are vertically opposite angleshence they will be equal2x+30=3x-20-x=-50°X=50°2)they are linear angleshence there sum will be 180°3x-10+2x-20=1805x-30=1805x=210X=42°

65022.

thetemperatureofapersonwasl03.2The normal temperature of a human being is 98.6°F. Ifhow much was it above normal?Bind the total length

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to find this subtract the temperature.103.2-98.6=4.6°F

65023.

The mean and standard deviation of 100 observations were calculated as 40 and 5.1 respectivelyby a student who took by mistake 50 instead of 40 for one observation what are the correct mean astandard deviation

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65024.

e) Mr Sharma pays the house rent as Rs 2,496 per quarter ofa year. What is the annual rent paid by him?

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QUARTER means 1/4 year or 3 months.number of quarter in a year = 4Annual rent paid by Mr. sharma = 2496*4 = 9984 Rs.

quarter rent =2496 ,annual rent=2496*4=9944

quarterly rent 2496 annual rent 2496*4-9984 is the ri8 ans

65025.

89.The length of the chord intercepted by theellipse x2 +2-4 on the normal at theellipse x+2y-4 on the normal at thepoint (R1) is3/62/61)2)7/656/63)4)

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65026.

The water acidity in a pool is considered normal when the averagedaily measurements is between 72 and 7-8. If the first two pH readings arfind the range of pH value for the third reading that will result in the acnormal.

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65027.

A traffic signal board, indicating SCHOOL AHEAD', is an equilateral triangle withside 'a'.180 cm, what will be the area of the signal board?Find the area of the signal board, using Heron's formula. If its perimeter is

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65028.

1. A traffic signal board, indicating SCHOOLAHEAD', is an equilateral triangle withside 'a Find the area of the signal board, using Heron's formula. If its perimeter is180 em, what will be the area of the signal board?12.3 A

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Solution:

Given, side of asignal whose shape is an equilateral triangle= a

Semi perimeter, s=a+a+a/2=3a/2

Using heron’sformula,

Area of the signal board = √s (s-a) (s-b) (s-c)

= √(3a/2) (3a/2– a) (3a/2– a) (3a/2–a)

= √3a/2 ×a/2× a/2×a/2

= √3a⁴/16

= √3a²/4

Hence, area of signal board withside a by using Herons formula is= √3a²/4

Now,

Perimeter of an equilateraltriangle= 3a

Perimeter of the traffic signal board = 180 cm (given)

3a = 180 cm

a = 180/3= 60 cm

Now , area ofsignal board=√3a²/4

= √3/4 × 60 × 60

= 900√3 cm²

Hence , the areaof the signal board when perimeter is 180 cm is 900√3 cm².

================

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65029.

arhird (Take π to be .)Aase isplacdfor grazing inside recomerbyarope 21mlong. How muca rectangular field 70 m by 52 m and is te. How much area can it graze?teth52 mm2170m

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thank u

65030.

9. Which interchange of signs will correct the following equation?

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Given,35 + 7 * 5 ÷ 5 - 6 = 24

Therefore,Correct equation is given by35 ÷ 7 + 5 * 5 - 6 = 24

65031.

vi. one-eighth of its complement te

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X=1/8 of 90-X. On solving for X, we get X =10.

65032.

\begin{array} { l } { \text { 1e allowed: } 3 \text { hours } ] } \\ { \text { Attempt five questions in all, Q.No. one } } \\ { \text { If } y = x + \frac { 1 } { x } \text { , show that } x ^ { 2 } \frac { d y } { d x } - x y + 2 } \\ { \text { Evaluate the integral } \int \frac { 1 } { x ( 1 + \log x ) ^ { 2 } } d } \end{array}

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65033.

1. A traffic signal board, indicatingSCHOOLAHEAD', is an equilateraltriangle with side 'a. Find the area of thesignal board, using Heron's formula. If itsperimeter is 180 cm, what will be the areaof the signal board?

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65034.

perature, the temperatureIn 8 hours duration, with uniform decrease in tedropped 24ยบ. How many degrees did the temperature dedid the temperature drop each hour2

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time taken = 8 hr.decrease in temprature = 24 degree.

ER. RAVI KUMAR ROY

each hour decrease = 24/8 = 3 degree ANS...

65035.

1- sin' x3 cos xif x <Letf(x) =If f(x) is continuous at x =find a and b.NEUENb (1-sin x)| (A-2752Tencendo 1

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hii dudGiven:f(x)=⎧⎪ ⎪ ⎪ ⎪⎨⎪ ⎪ ⎪ ⎪⎩1−sin3x3cos2x,ifx<π2a,ifx=π2b(1−sinx)(π−2x)2,ifx>π2fx=1-sin3x3cos2x,ifx<π2a,ifx=π2b1-sinxπ-2x2,ifx>π2

We have(LHLatx=π2π2) =limx→π2−f(x)=limh→0f(π2−h)limx→π2-fx=limh→0fπ2-h

=limh→0(1−sin3(π2−h)3cos2(π2−h))=limh→0(1−cos3h3sin2h)=13limh→0((1−cosh)(1+cos2h+cosh)(1−cosh)(1+cosh))=13limh→0((1+cos2h+cosh)(1+cosh))=13(1+1+11+1)=12=limh→01-sin3π2-h3cos2π2-h=limh→01-cos3h3sin2h=13limh→01-cosh1+cos2h+cosh1-cosh1+cosh=13limh→01+cos2h+cosh1+cosh=131+1+11+1=12

(RHLatx=π2π2) =limx→π2+f(x)=limh→0f(π2+h)limx→π2+fx=limh→0fπ2+h=limh→0(b[1−sin(π2+h)][π−2(π2+h)]2)=limh→0(b(1−cosh)[−2h]2)=limh→0(2bsin2h24h2)=limh→0⎛⎝2bsin2h216h24⎞⎠=b8limh→0(sinh2h2)2=b8×1=b8=limh→0b1-sinπ2+hπ-2π2+h2=limh→0b1-cosh-2h2=limh→02bsin2h24h2=limh→02bsin2h216h24=b8limh→0sinh2h22=b8×1=b8

Also,f(π2)=afπ2=a

Iff(x) is continuous atx=π2π2, thenlimx→π2−f(x)=limx→π2+f(x)=f(π2)limx→π2-fx=limx→π2+fx=fπ2

⇒12=b8=a⇒12=b8=a

⇒a=12andb=4

65036.

If $u=\log (y \sin x+x \sin y)$ Then find $\frac{d y}{d x}$

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give me answer

65037.

m long. 9 m wide, and 6 m high Water is beine pamglitres per minute. Inh9 mr s pered onentall recte. In how many hours will the reservoit beater reservoir is 1ne day was 6 cm. Find the volume of water thataare

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65038.

Xiampie JEvaluate S_ \x3 – X| dx

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65039.

dyFind dx for the following functions:01. y loge111where x = π/3

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65040.

8. Mr Sharma bought a house for Rs 15,00,000 in 1996.In 1998 the price of houses in that area increased by20%. By 2000, the price had risen by 20% of the1998 price. Calculate the price of the house in 2000.

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65041.

Counting by two's, write the numerals from:(1)1996

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1. 2561, 2563, 2565, 2567, 2569, 2571, 2573

65042.

topofa80mhightree.Fromapointontheground,theangleofA bird is sitting on theelevation of the bird is 45° The bird flies away horizontally in such a way that it remainedat a constant height from the ground. After 2 seconds, the angle of elevation of the birdfrom the same point is 30° Find the speed of flying of the bird (Take 3-1.732).

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Like my answer if you find it useful!

65043.

1. A traffic signal board, indicating SCHOOL AHEAD', is an equilateral triangle withside 'a'. Find the area of the signal board, using Heron's formula. If its perimeter is180 cm, what will bethe area ofthe signal board?

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65044.

1. Atraffic signat board, indicating SCHOOL AHEAD, is an equilateral tiangl wiside a'.Find the area of the signal board, using Heron's formula. If its perimeteris180 cm, what will be the area of the signal board?

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65045.

from a point on the30°. Find the speed of flyingA bird is sitting on the top of a tree, which is 80 m high. The angle of elevation of theground is 45. The bird flies away from the point of observatioground is 45°. The bird fies away from the point of observation horizontally and reb2 seconds, the angle of elevation of the bird from the point of observation becomes 3e a constant heiof the bird.

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In triangle OAC tan 45=AC/OA=1

AC=OA=80

IN TRIANGLE ODB

tan 30=BD/OB=1/√ 3

OB=BD√ 3-AC√ 3(since ac=bd as bird remains constant height)

AB=OB-OA=AC√ 3-AC=AC(√ 3-1)=80(√ 3-1)

NOW FOR 2 SEC

80(√ 3-1)/2=40(√ 3-1)

=29.2M/SEC

65046.

on a horizontal plane, finds a bird flying at a distance ofAmit, standing200 m from him at an elevation of 30°. Deepak standing on the roof of a50 m high building, finds the angle of elevation of the same bird to be 45Amit and Deepak are on opposite sides of the bird. Find the distancethe bird from Deepak

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65047.

ne :-2 /2 hourste:- Attempt all the questions.1 What comes before.)78

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77 comes before 78. 77 78 79

65048.

Short Answer Type Questions (SLAB-DSum of twonumbers is 35 and their difference is 13.Find the numbers.1.te fottr ti

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x+y= 35and x-y= 13adding these 2x= 48= x=24and y = 24-13= 11

65049.

derivative of dy/dx =(x3+x+5)3

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What is your question

65050.

dydx3. If y=-+ ethen findsin x

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y = cosecx +e^x

dy/dx = -cosecxcotx +e^x