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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 65101. |
\int _ { 0 } ^ { \ln 2 } \int _ { 1 } ^ { \ln 5 } e ^ { 2 x + y } d y d x |
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| 65102. |
\int _ { 0 } ^ { 1 } \int _ { 0 } ^ { 2 } ( x + 2 ) d y d x |
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| 65103. |
\int \frac{d x}{\sqrt{1+^{2}-x^{2}}}=\int \omega d t |
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| 65104. |
\int _ { 0 } ^ { 1 } \int _ { 0 } ^ { 2 } ( x + 2 ) d x d y = 5 |
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Answer» please the given question is wrong , answer will be 6 |
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| 65105. |
1.Examine the continuity of the following functions at gi(Sx – e2(1) f(x) = sin 3x= 1,forfor |
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| 65106. |
.. sindxlimâxâ0 $1N 2X |
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Answer» Like my answer if you find it useful |
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| 65107. |
a) lfcos (x-20° ) = sin (3x-10° ), then find the value of x.[1] |
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Answer» cos ( x - 20) = sin ( 3x - 10) sin (90-(x - 20)) = sin ( 3x - 10) 90 - x + 20 = 3x - 10 90 + 30 = 4x x = 120/4 x = 30° |
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| 65108. |
14Plen) : A city has two main roads which eross each other a the oenhse wlsae along the North South direction and Eas We |
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| 65109. |
41 in ΔABC and ΔΡQR ,ΔΑΒCAPQR is sim ilarityAC-6 then find PR.PQ 5 |
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| 65110. |
The lengths of 40 leaves of a plant are measuredcorrect to the nearest millimetre and the dataobtained is represented in the following table5Length 117.5 126.5- 135.5- 144.5- 153.5- 162.5- 171.5(in mm) 126.5 135.5 144.5 153.5 162.5 171.5 180.5Number of 3 594 cm, 5 cm and 6 cmr to it whose sides areg sides of the firston of the construction12 5 42LeavesFind the median length of the leaves. |
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| 65111. |
24. In the given figure, ABCD and PQRCare rectangles and Q is the mid-pointof AC, then prove that (i) DP PC(ii) PR- AC .[CBSE 2010]Answers |
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| 65112. |
integrate{(x-1)/3x²-4x + 3}dx |
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Answer» set derivative. then make perfect square then solve |
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| 65113. |
integrate X + 1 into DX |
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| 65114. |
\frac { \sqrt { x ^ { 2 } + 1 } [ \operatorname { log } ( x ^ { 2 } + 1 ) - 2 \operatorname { log } x } { x ^ { 4 } } |
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Answer» it is simplified as |
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| 65115. |
\int \{ \frac { 1 } { \operatorname { log } x } - \frac { 1 } { ( \operatorname { log } x ) ^ { 2 } } \} d x |
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| 65116. |
Evaluate the followings:Integrate (1/x²-9) dx |
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Answer» long questions 1/6 questions about |
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| 65117. |
6.31· 37すfr 6.27찌 Po ll BC, PR 11 AC, QS 11 AB.37例 6.27 |
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Answer» thanks you Ruchi thanks |
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| 65118. |
integrate sin^2 x/2dx |
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| 65119. |
Integrate the functions in Exercises 11, x sin x2. x sin 3x |
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Answer» Nice |
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| 65120. |
There is a negative error of 0.03 mm in amicrometer. If the micrometer gives a measurementof 40.53 mm then, what will be the correct reading?(a) 40.50 mm(c) 40.46 mm.(b) 40.56 mm(d) 40.59 mm1. Lock uut is used in a micrometer for- |
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Answer» Correct Reading = Observed reading - Error= 40.53 - (-0.03)= 40.56 mm Please hit the like button if this helped you |
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| 65121. |
(1).x cube log x + ex + ax . (2) 1/X+1/1/x-1+log2. (3).(X cube+5)7. (4).X square+a square/ X+a. Find the derivative works.r.t. x:---- |
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Answer» 1 2 Thanks sir |
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| 65122. |
\ text { give reason for the following statement }\begin{array} { l } { \{ 2,3,5,7,9,11 \} \neq \{ x : x \text { is a prime number, } x < 12 \} } \\ { \{ 1,64,125 \} \neq \{ x : x \text { is a perfect square and perfect cube, } x \leq 125 ] } \end{array} |
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Answer» 1) this is the collection of numbers those are prime and less than 122) x is a perfect square and perfect cube which are less than 125as 8*8= 64 and 4*4*4= 64 |
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| 65123. |
integrate Sin cube x dx |
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Answer» welcome |
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| 65124. |
The radius and height of a cylinder are both x cm. Then, the volume of the cylinder is.... cm cube .A. 4pie x sqB.pie x cube C.pie x sqD.pie x |
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Answer» volume of the cylinder = pie*r*r*h now r = h = x so volume of the cylinder = pie x cube |
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| 65125. |
Hence, PQRS is a rhombus.1 In the adjoining figure, ABCD andPORC are rectangles, where Q is themidpoint of AC. Prove that(1) DP = PC, (ii) PR ==AC.ulRILAR |
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Answer» aap up ke Mann Ki bacche ho to mujhe like karo the ans is (ii)option option (ii) is the correct answer |
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| 65126. |
uut ul papel, plastic, glass and metals, and send them for rQ.2. What would be the advantages of exploiting resources with short-term aims ?Ans. If the resources are exploited to the hilt with thort t |
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| 65127. |
1. Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct theof tangents to the circle and measure their lengths. |
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| 65128. |
1. Drawa circle of radius 6 cm. From a point 10 cm away from its centre, construct the pairof tangents to the circle and measure their lengths. |
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Answer» thank you |
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| 65129. |
1.Drawacircleofradius6cm.Fromapoint10cmawayfromitscentre,constructthepairof tangents to the circle and measure their lengths. |
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| 65130. |
simplya=4r/√2a=? |
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| 65131. |
1. Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the pairof tangents to the cirele and measure their lengths. |
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| 65132. |
1. Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the pairof tangents to the circle and measure their lengths. |
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| 65133. |
3. Two parallel lines l andt be 12x- 8jP and (3x-71°.are cut by a transversal t. If the interior angles of the safind the measure of each of these angles.h that s is not |
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| 65134. |
3. Simply . sec2 θ cosec" θ2See |
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Answer» 1/secx = cosx 1/cosecx = sinx cos²x+sin²x We know that (cos²x+sin²x=1) = 1 |
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| 65135. |
simply (x+3)cube+(x-3)cube |
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Answer» x^3+9x^2+27x+27+x^3-9x^2+27x-27=2x^3+54x |
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| 65136. |
ful) 196 and 38220 |
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Answer» To find:HCF of 38220 and 196 Solution:38220 = 196 × 196 + 0 Hence HCF of 38220 and 196 is 196 |
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| 65137. |
1. Illustrate the judicial system formulated through East IndiafulCompany.2 |
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Answer» The Indian Judiciary was basically formed from the legal system set up by the British and other colonial powers. Since then, it has partly retained the main characteristics, though several modifications and amendments to the system, have been brought about. The Jury System was the first to go as it was found to be highly biased, when it came to the case of British or foreign subjects. It was abolished in 1958 by The Indian Law Commission. |
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| 65138. |
7. L and M, two parallel lines, are intersected by Another pair of parallel lines P [and C, show that Δ ABCΔ CDA. |
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| 65139. |
l and m are two parallel lines intersected byanother pair of parallel lines p and q(see Fig. 7.19). Show that Δ ABC Δ CDA. |
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| 65140. |
ranis age is 6timethe age of Keerthi write a linear equation in two variable |
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Answer» Let age of keerthu is x and age of ranis is yy=6x tell me full solution |
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| 65141. |
l and m are two parallel lines intersected byánother pair of parallel lines p and q(see Fig. 7.1 9). Show that Δ ABC Δ CDA |
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| 65142. |
28Construct a pair of tangents to a circle of radius 3 cm from a pointP.5cm away from its centre. |
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| 65143. |
Fig.7.18l and m are two parallel lines intersected byanother pair of parallel lines p and q(see Fig. 7.19). Show that Δ ABC Δ CDA. |
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| 65144. |
Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the pairof tangents to the circle and measure their lengths. |
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| 65145. |
1. Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the paiof tangents to the circle and measure their lengths.2. Construct a tangant t |
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| 65146. |
8. Two parallel lines l andm are intersected bya transversalp (see Fig.)Show that thequadrilateral formedby the bisectors of interior anglesrectangle. |
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Answer» Given l||m and p is the transversalTo prove: PQRS is a rectangleProof:RS, PS, PQ and RQ are bisectors of interior angles formed by the transversal with the parallel lines.∠RSP = ∠RPQ (Alternate angles)Hence RS||PQSimilarly, PS||RQ (∠RPS = ∠PRQ)Therefore quadrilateral PQRS is a parallelogram as both the pairs of opposite sides are parallel.From the figure, we have ∠b + ∠b + ∠a + ∠a = 180°⇒ 2(∠b + ∠a) = 180°∴ ∠b + ∠a = 90°That is PQRS is a parallelogram and one of the angle is a right angle.Hence PQRS is a rectangle. |
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| 65147. |
UL8 In the adjoining figure, AC = AE, AB = AD andBAD = ZCAE. Show that BC = DE.Hint. Join DE.Show that AABC = AADE. |
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Answer» what is your question take triangle ABC and triangle ADE,AB=AC ( GIVEN)AD=AE (GIVEN)angle DAC= angle DAC (COMMON)therefore triangle ABC is similar to triangle ADE Therefore BC=DE |
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| 65148. |
14. In the adjoiningD-7cfigure, ABCD is aparallelogram andE is the mid-pointof side BC. If DE-A-ㄧㄧㄧ-B -- ->Fand AB when produced meet at F,then prove that AF = 2AB |
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| 65149. |
11. In the adjoining figure, D and E are points onthe sides AB and AC of AABC such thatar(ABCE) = ar(ABCD).Show that DE|| BCint inside |
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| 65150. |
कक.लिन रा eN RGeS\ ee 6 AD3 Az 5B =&BF w2 ond e = AN Ane Pind ¥ |
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