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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 65651. |
3. IP and TQ are the two tangents to a circle with centre O such that 2PO-110. Find themeasure of ZPTQ. |
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| 65652. |
o circles touch externally at a point P. From a point T on the tangent at P, tangents TQ anddrawn to the circles with points of contact Q and R respectively. Prove that TQ-TR.25. TwoP, tangents TQ and TR are4angent at |
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| 65653. |
Determihe we Toin ciIf thr roints A(4, 3) and Be, 5) are on the circle with centre 0(2, 4). Find the va |
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| 65654. |
Solve the following pair of linear equations by using corss multiplication methoox-3y-7-03x-3y-15-0 |
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Answer» hit like if you find it useful |
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| 65655. |
AOB is the diameter of circle with centre O. If LA = 40 ) , find LB00 |
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| 65656. |
, 3o pagve जैन, _2:2060 iamsus -V)ol fan |
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| 65657. |
| solveNtY = atbIañhty |
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| 65658. |
13. Kishore can run at 6 km/h while his son can run at3.6 km/h. They decide to race and touch a goal-poston the other side of a field. Starting off together, theson touches the goal-post 12 seconds after his father.How far was the goal-post from their starting point?(Hint: Convert their speed to m/s) |
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Answer» Speed of Kishore = 6 km/hr= 6*5/18 = 5/3 m/sSpeed of son = 3.6 km/hr= 3.6*5/18 = 1 m/s We know,Distance = speed*time Let goal post is at distance dLet time taken by Kishore = t Then, For Kishore d = 5/3 * t...... (1) For sond = 1*(t + 12).....(2) Now, 5t/3 = t + 125t = 3t + 362t = 36t = 36/2 = 18 Therefore, Distance of goal post from starting point = 5/3 * 18= 5*6 = 30 m Speed of kishore=6km/hr=6*5/18=5/3 m/sspeed of son =3.6km/hr =3.6*5/18=1m/s |
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| 65659. |
in figure first if TP and tq two tangents to a circle with Centre O show that angle poq equal to 110 then find the value of angle ptq |
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Answer» Like my answer if you find it useful |
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| 65660. |
3. The probability that Pedro scores a goal in any match is 2Calculate the probability that Pedro scores a goal in each of the next two matches. |
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Answer» Probability = (2/5)x(2/5) = 4/25. |
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| 65661. |
Osvoldo has a goal of getting at least 30% of hisgrams of carbohydrates each day from whole grains.Today, he ate 220 grams of carbohydrates, and 55grams were from whole grains.Did Osvoldo meet his goal? Why?grams of whole grainsyes / no., Osvoldo atemore / less than his goal. |
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Answer» 30 % of 220 = 66Osvoldo got only 55 gram from whole grains66 - 55 = 11 gramsHe got 11 grams less than his goal. I did thanks very much |
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| 65662. |
nty=16N-y=4Solve using cuessmultiplication |
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Answer» x+y=16; x-y=4; X+Y=16; X-Y=4/2Y=12; Y=6; X=16-Y:; X=16-6=10 x+y=16; x-y=4/2y=12, y=6; x+y=16; x=16-y=16-6=10, 10+6=16; 10-6=4 |
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| 65663. |
10. In the adjoining figure, TP and TQ are tangents to the circle with centre 0and POT = 550. Find the Measure of LPTQ |
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| 65664. |
Example 3: PQ iş a chord of length 8 cm of acircle ofradius 5 cm. The tangents at P and Qintersect at a point T (see Fig. 10.10). Find thelength TP |
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Answer» thanks |
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| 65665. |
He. 6 - (a) If the sums of n terms of two arithmetic progression are in the ratio(3n+8) :(7n + 15), find the ratio of their 12th terms.(5) |
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| 65666. |
= Z(X *30+1) || : oeneaq 10x °3o] |
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| 65667. |
the mid-paintline-sreging) 4 (.iie seament 3o |
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| 65668. |
s. If the sums of n terms of two arithmetic progressions are in the ratio 2n +5:3n + 4, thenwrite the ratio of their mth terms. |
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Answer» how could you know to replace 'n' with '2m+1' sorry ' 2m-1' |
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| 65669. |
240, 720 and lusu resPettively.28: The sums of n terms of two arithmetic progressions are in the ratio(5n +4): (9n + 6). Find the ratio of their 18th terms.OR |
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| 65670. |
Hence, the common dmeleitExampfe(6)The surn of n terms of two arithmetic progressions are in the ratio(3n + 8): (In +15). Find the ratio of their 12t terms.diference of the first |
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| 65671. |
16./inabasketballgame a field goal counts 2 points and a foul shot one point. Shreyash scored 14 pointsin a game. He made 3 times as many field goals as foul shots. On how many shots of each kind didhe score? |
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Answer» Number of foul goals be X. Then number of field goals is 3x.Then, 2(3x)+1(X) = 14=> 7x = 14=> X = 14/7=> X = 2. Please hit the like button if this helped you |
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| 65672. |
6 पड + 05०9६ST TP gl |
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| 65673. |
If the sums of n terms of two arithmetic progression are in the ratio(3n + 8) (7n + 15), find the ratio of their 12th terms. |
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| 65674. |
In an AP if Tp=q and Tq=p. Find Tp+q. |
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Answer» T(p)=a+(p−1)d=qT(q)=a+(q−1)d=p Subtracting 1st equation from the 2nd. d(p−q)=q−p d=−1 Now we will substitute d in the first equation a+(p−1).(−1)=q a=p+q−1 Now we will use the values of a and d in the equation stated below T(p+q)=a+(p+q−1)d =p+q−1+(p+q−1).(−1) =0 ans |
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| 65675. |
&9.TP OF MATTERDistinguish between heat and temperatare |
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Answer» Heat:Heat is the amount of energy in a body . It is the measure of total kinetic and potential energy contained by molecules in an object. It flows from hotter object to cooler object.Temperature:Total kinetic and potential energy contained by molecules in an object. It is the measure of average kinetic energy of molecules in a substance. It rises when heated and falls when cooled. |
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| 65676. |
ane 3o'.yo and n Find the vajue |
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| 65677. |
9. The sums of n terms of two arithmetic progressions are in the ratio5n +4:9n 6. Find the ratio of their 18th terms. |
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| 65678. |
the raExample 6 The sum of n terms of two arithmetic progressions are in(3n +8): (7n + 15). Find the ratio of their 12th terms. |
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Answer» Thanks alot |
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| 65679. |
Example 6 The sum of n terms of two arithmetic progressions are in the(3n + 8): (7n+ 15). Find the ratio of their 12th terms. |
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| 65680. |
5. Theweight of 7 containers of milk is 224 kg. Find the weight of 11 such containers |
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Answer» 7 containers= 224 kg 11 containers= ? 7/11= 224/x 7×x = 224×11 7×x = 2464 x = 2464/7 x = 352 litres of milk |
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| 65681. |
7, Coffee costing 250 per kg was mixed with chicory costing 75 per kg in thecertain blend. If the mixture was sold at 230 per kg, find the gain or loss pHint. Let 5 kg of coffee be mixed with 2 kg of chicory |
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| 65682. |
mple 6: Find the productsาว(a) 289 x 20 |
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Answer» 289× 20= (200+89) × 20= 4000 + 89× 20= 4000+ 1780= 5780 |
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| 65683. |
3.Howdohyd:ochloricacidandsodiumhydroxidereactwithzinemetai?Wsitethicbalar-equet.ons of the reactions involved? How will vou test ior tie sas evoved? |
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Answer» (a) Zn(s) + 2HCl→ZnCl2(aq) + H2(g) ZnCl2(aq)- Zinc chloride (b) Zn(s) + NaOH→Na2ZnO2+ H2 Na2ZnO2-Sodium Zincate |
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| 65684. |
mple 6 The sum of n terms of two arithmetic peogressions are8): (7n+ 15). Find the ratio of their 12 terms |
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| 65685. |
4. In a AABC, LA-2 <B = 3 <C, find each angle of the triangle. |
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| 65686. |
(3 n-5)(3 n+5) |
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| 65687. |
The ratio of zinc and copper in an alloy is 7:9. If the weight of copper in the alloy is 11.7 kgfind the weight of zinc in it.17. |
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| 65688. |
10. A circular park of radius 15 m has a path of10 m width around its outer side. Find thearea of the road03 |
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| 65689. |
The ratio of zinc and copper in an alloy is 7 : 9. If the weight of the copper in the allyis 11.7kg, find the weight of the zine in the alloy |
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| 65690. |
An alloy contains 40% copthe alloy18.per, 32% nickel and rest zinc. Find the mass of zuc in ane kg af |
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| 65691. |
$(3) If n (A), 15, n(AUB)29, n(An B)--7, then n(B)ะ๠|
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| 65692. |
An alloy contains 38% copper, 28% zinc and the rest is nickel. Find each quantity m gramsin a sample of I kg alloy2. |
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Answer» 380 GM copper280 GM zincand 340 GM nickel send steps you send me steps |
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| 65693. |
10 An alloy contains 36% zinc, 40% copper and remaining is nickel. Find the amount of each metalin a sample of alloy of mass 1 kg. |
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Answer» 36% zink40% copperso 24% nickelnow 1kg of alloyso 360gm zink,400g copper and 240gm nickel |
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| 65694. |
mple 6. The angles of a triangle are in A. P and its greatest angle is 75. Find theleast angle of the triangle in radian. |
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| 65695. |
In ∆ABC,if a=2,b=3 and sinA=2/3 Find angle B |
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| 65696. |
In triangle ABC, <C=90° and AC = root 3*BC. Find angle B |
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| 65697. |
In Fig. $ 6.32, $ if $ \mathrm{AB}\left\|\mathrm{CD}, \angle A P Q=50^{\circ} $ and \right.$ \angle \mathrm{PRD}=127^{\circ}, $ find $ x $ and $ y $ |
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Answer» x = 50° ( vertically opposite angle)y + 50° = 127° ( exterior angle theorem)y = 127° - 50°y = 77° |
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| 65698. |
(6Marks)Find the zeroes of the polynomial f (x) x3-5x2-2x+24if it is given that the product of its two zeroes is 12. |
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| 65699. |
If n (A) 15, n(AUB) 29, n (An B) 7 then n (B)? |
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| 65700. |
A circular path whose circumference is 616 m. has path inside the park whose width 15 14park. Find the area of park excluding the path and also find the cost of grassing on it at the faceper m. |
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Answer» 88 cm is the correct answer of the following question |
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