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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 65901. |
EXESolve the following pair of linear\begin{array}{l}{x+y=14} \\ {x-y=4}\end{array} |
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Answer» x + y = 14 ........(1)x - y = 4 ........(2) Adding (1) and (2)2x = 18x = 9y = 14 - 9y = 5 |
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| 65902. |
12. Why is it easier to pull a lawn mower than to push it? |
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Answer» The force applied to move a body depends upon effective force applied on it including its weight. As effective weight in the case ofpullingis lessthanin thepushing, less force is required inpulling please like the solution 👍 ✔️ |
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| 65903. |
\frac{2}{5}+\frac{3}{15}+\frac{7}{10} |
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Answer» thanks |
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| 65904. |
. The population of a town 2 years ago was 7,25,000. If the number of people decreases every-year at the rate of 5% per annum. Find itspresent population. |
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| 65905. |
ADWhat Did You Learn?Exercise 2.2Frame an equation and solve.A)Twice a number is 30 greater than its half. Find the number. |
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| 65906. |
nu ll-3y - 8. Shade the region boundeduy the lhes and the y-axis.In a class, one-third of students had gone to watch drama. Twice the square root of the students had gone to watchmagic show and remaining 12 students had gone to watch football match. Find the total number of students in theclass. |
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Answer» Let the total number of students in Class be XThus according to questionStudent went to drama = A = X/3Student went to magic show =B =2 root XStudent went to football = C = 12Thus X= X/3 + 2 √X + 122X/3 = 2 √X + 122 √X= 2X/3 - 12Squaring both sides4X = 4X^2/9 + 144 - 48X/34X^2/9 - 60X/3 + 144 = 04X^2/9 - 20X + 144 = 04X^2 - 180X + 1296 = 0X^2 - 45X + 324 = 0X^2 - 36X - 9X + 324 = 0X(X - 36) - 9 (X-36) = 0X = 36thus total Students = 36 |
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| 65907. |
A person incurs 5% loss by selling a watch for * 1140. At what price should the watch be soldto earn 5% profit? |
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Answer» Answer: The selling price of a watch that will earn 5% profit is Rs. 1260. Solution: Let the new selling price be x. (100 - 5) : 1140 = (100 + 5) : x 95/1140 = 105/x 95x = 105 * 1140 x = 1260 Hence, the selling price of a watch that will earn 5% profit is Rs. 1260. let the new selling price = X, ( 100 -5)/1140=(100+5)/x; 95/1140=(105)/x; 95 x =1140 × 105 ; 95 x = 119, 700; x = 1 1 9 7 0 0 / 95 = 1260 |
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| 65908. |
24. A horse is tethered to one corner of a field which is in the shape of anpu/ equilateral triangle of side 12 m. If the length of the rope is 7 m, find thearea of the field which the horse cannot graze. Take 3 1.732. Writethe answer correct to 2 places of decimal. |
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| 65909. |
Find the sum of the following series:13 + 33 +534.+to n terms. |
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| 65910. |
The angle of eltowards the tower, the angle of elevationfrom the foot of the tower. (3 1.73)of elevatlon of the top of a tower from a point on the ground is 459. On walking 30becomes 60°. Find the height of the tower and original dievati |
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Answer» Let ABC be the tower and D be the distance moved towards the tower. angle ABC= 45 degreeangle ADC= 60 degreeCD = 40mlet height of the tpwer be h metre and BD = x metrefrom triangle ABCtan 45 degree = P/B1 = h/40+xh = 40+x equation 1from triangle ABDtan 60 degree = P/Broot 3= h/ xh= root3x equation 2from 1 and 240+x=root 3x40 =root3x-x40 = x(root3-1)x= 40/root3-1put value of root 3= 1.732x = 40/ 1.732-1x= 40/0.732x= 54.64mput the value of x in equation number 1h= 40 + xh = 40 + 54.64h = 94.64 m (approximately) |
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| 65911. |
js¡Complete the following series:IF, JH, LJ, OL,(a) SN(b) RN(d) SM |
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| 65912. |
6. The length of the shadow of a tower is 20/3 metre. If the height of tower is 20 metrethen find the angle of elevation of the Sun at that time. |
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Answer» Height of the tower = AB = 20 m Length of the shadow = BC = 20√3 m the altitude of the Sun = <ACB tan <ACB = AB/CB = 20/20√3 = 1/√3 tan <ACB = tan 30° <ACB = 30° |
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| 65913. |
1 Sides of a triangular field ar 15m, 16m and 17m. With the three cormersof the field a cow, a buffalo and a horse are tied separately with ropes oflength 7m each to graze in the field. Find the area of the field, whichcannot be grazed by the three animals? |
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Answer» Let ABC be the triangular field with sides Ac = 15 m, AB = 16 m and BC = 17 mAnd,Let the place where the cow, the buffalo and thehorse are tied, are three sectors i.e. sector ADE, sector BFG and sector CHIThe area of triangular field by Heron's formula =√s(s-a)(s-b)(s-c)s = (a+b+c)/2s = (15+16+17)/2s = 48/2s = 24 m√24(24-15)(24-16)(24-17)√24*9*8*7√12096Area of triangular field = 109.98 sq mArea of the grazed part = Area of the triangular field = Area of the sector ADE + Area of sector BFG + Area of sector CHI= π*7²*∠A/360 + π*7²*∠B/360 +π*7²*∠C/360=π*7²(∠ A + ∠ B + ∠ C)/360= 22/7*7*7*180/360= 154/2Area of the grazed part = 77 sq mNow, the area of the field which cannot be grazed by these animals= 109.98 - 77= 32.98 sq m |
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| 65914. |
132).Fig. 15.110a triangular field are 15 m, 16 m and 17 m. With the three corners of the fieldowa ind the area of the field which cannot be grazed by three animalsSies buffalo and a horse are tied separately with ropes of length7 m each to graze inINCERT EXEMPLARIANSWERS |
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Answer» Solution:- Let ABC be the triangular field with sides Ac = 15 m, AB = 16 m and BC = 17 mAnd,Let the place where the cow, the buffalo and thehorse are tied, are three sectors i.e. sector ADE, sector BFG and sector CHIThe area of triangular field by Heron's formula =√s(s-a)(s-b)(s-c)s = (a+b+c)/2s = (15+16+17)/2s = 48/2s = 24 m√24(24-15)(24-16)(24-17)√24*9*8*7√12096Area of triangular field = 109.98 sq mArea of the grazed part = Area of the triangular field = Area of the sector ADE + Area of sector BFG + Area of sector CHI= π*7²*∠A/360 + π*7²*∠B/360 +π*7²*∠C/360=π*7²(∠ A + ∠ B + ∠ C)/360= 22/7*7*7*180/360= 154/2Area of the grazed part = 77 sq mNow, the area of the field which cannot be grazed by these animals= 109.98 - 77= 32.98 sq m |
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| 65915. |
Fig. 13.110, triangular field are 15 m, 16 m and 17 m. With the three cornets of the felddes or buffalo and a horse are tied separately with ropes of length 7 m each tocowi the field. Find the area of the field which cannot be grazed by three animaa cow, a[NCERT EXE MPLAR) |
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Answer» Like if you find it useful |
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| 65916. |
National Animal. Their number decreases every year.w 3% annual decrease. According to the census ofnal Tiger conservation Authority, there were 1700tigers in Indiar20i1. if thetrend continues, how many tigers would be there inTriger is our2016? |
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Answer» A = P*[1-(3/100)]^5= 1700*(97/100)^5= 1459 tigers. Please hit the like button if this helped you. |
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| 65917. |
of 20 boys and 10 girls, 5 boys and 3 girls are honest. If two persons are selectedm from the group, find the probability that either both are girls or both are honest.at rando |
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Answer» No. Of possible outcomes= No. Of girls + No. Of honest persons= 10 + 8 = 18 No. Of total outcomes= 20 + 10= 30 Probability = possible outcomes / total outcomes= 18/30= 3/5 |
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| 65918. |
III.Answer the following:35.Find the sum of first twenty terms of Arithmetic series2+7+ 12 +...using suitable formula. |
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Answer» Given series is in AP with first term a = 2, common difference d = 7 - 2 = 5 Sum of n terms of an AP isSn = n/2[2a + (n-1)d] Therefore,Sum of first twenty termsS20 = 20/2[2*2 + 19*5] = 10(4 + 95) = 10*99 = 990 |
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| 65919. |
Centre C6 At a point on level ground, theelevation of a vertical tower is foundthat its tangent istowards the tower; the tangent of the anglefound to be. Find the height of theis found to he. On walking 192 metre1234tower |
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| 65920. |
9 121810 25 3520.b) s02503503(c) 250350 |
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Answer» H.C.F. of 9,12,18=3L.C.M. of 10,25,35=350so answer is 3/350 |
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| 65921. |
Balance the following chemical equations.(a) HNO,+ Ca(OH, Ca(NO,+ H,O(b) NaOH + H2SO4 â Na,SO4 + H,0(c) NaCl + AgNO, AgCl + NaNo,(ds BaCl +HSOBaso, +HCI |
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| 65922. |
14. If 37 % of a number is 93.75, find that number/a. 200b. 250c. 180d. 160 |
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Answer» 37 1/2 % *x =93.7575 x /2 *100 = 93.75,x = 93.75 * 2 *100/75 ,=250 |
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| 65923. |
02: If α β and γ are the zeroes of a cubic polynomial+ cx + d, then α(1 + βγ) + β + γ is equal to:-2c8:2dCe-dD: |
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| 65924. |
CHAPTER NPERCEN6.If 16-% of a number is added with itself thenresult becomes 4956. Find the original number.यदि किसी संख्या में उसका 165% जोड़ा जाए तो प्राप्त संख्या4956 हो जाती है। संख्या ज्ञात करें।(a) 4248 (b) 4125 (c) 4215 (d) 14587of a number is subtracted from itself thenresult becomes 5670. Find the original number.यदि किसी संख्या में से उसका 65% घटाया जाए तो 5670 प्राप्तहोता है। संख्या ज्ञात करें।(a) 7015 (b) 8102(c) 6075(d) 5012If 11% of a number is added with itself thenresult becomes 900. Find the original number. |
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Answer» x=4248 is a correct answer |
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| 65925. |
a solid sphere of radius 6 cm is placed in a hollow of height 10 cm .find the volume of empty space |
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Answer» volume of solid =4/3×pi×r3=4/3×22/7×216=905.14cm3 R of cylinder=6 H=10 V=pi×r2×h=3.14×36×10=1130.4cm3 Remaining space = 1130.4-905.14=225.26cm3 volume left Like my answer if you find it useful! |
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| 65926. |
120. Find the missing number.5( 63)4172331(a) 26(c) 28(b) 25(d) 22 |
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Answer» the correct answer is C C.is the right answer.. A is the correct answer 26is correct answer option D is the correct answer 28 is the right answer... 26 is the right answer 26 is the best answer 26 is the missing number 26 is the right answer 26 is missing number a is the correct answer Option D is correct answer 26 is right answer of following question 26 is the correct answer |
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| 65927. |
488।। fhी0 ,है। शो A का 2 से1.। |
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Answer» D, A ka nana hoga! it's the correct answer yahan par D se A ka father ka sambandh hain d a ka nana hoga is right |
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| 65928. |
9. Find the missing number in the following series 12, 9, 17, 13, 22, 17,27,21, 32, 25,a7.2a) 42b) Ao 28 |
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| 65929. |
money does Mohan have Hwd) After spending some amount from 500, Mita found that she was left with323.20. How much did she spend? |
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| 65930. |
Shoan takes 9 hours to mow a large lawn. He and Mohan together can mow it in 4 hours. How long will Mohan take to mow the lawn if he works alone |
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| 65931. |
25% of Rs. 488 ?a) Rs. 122 b) Rs. 250c) Rs. 48 |
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| 65932. |
( 64 ) ^ { - 1 / 4 } \times ( 16 ) ^ { 1 / 4 } |
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| 65933. |
4) 25ο Α.t.\ A. and A, aro G,M. 's G', G) and ty, o ll. M.'s lli, l, are inserted bet" een any Inon-perw positive mambers thenM, 11G, G+ AA, + AA) GG2)3) |
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Answer» please post the question again. it is blurred. ek naav das ghante se pratikul prabhav se 30 kilometre AVN anukul pravah se 44 kilometre karti hai aur nav pratikul prabhav se 40 kilometre Tak tatha anukul pravas se 55 kilometre duri Tay karne mein tera ghanta samay lete hain shant jal manav ko kya kya hai |
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| 65934. |
Questionamber 712y 2 lilQ7 Given that V2 is irrational, prove that (S +32) is an irvätioumiเว |
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Answer» Given:root2 is irrationalNow,let us assume that 5 +3root2 is rationalSo,5+3root2 = a/b3root2 = a/b-5 =a-5b/bRoot2 = a-5b/3b But we know that root2 is irrationalSo, our assumption was wrong.Hence 5+3root2 is irrational. Hence proved |
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| 65935. |
Worksheet 2In the following tables, a and b vary inversely. Fill in the missing val28 |
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Answer» if a and b vary inverse a= k/b => 7 = k/b = k/8 => k = 7*8 = 56 so, when b = 4 => a = 56/4 = 14 when a = 28=> b = k/a = 56/28 = 2 |
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| 65936. |
0 (Pot OI TZ_/~ ÂŽ= =(6S1-6) s 1oy, g 09500 )ÂŽ (9)FE e e e i |
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Answer» tan theeta x (1/2)= √3/2 tan theeta= √3theeta= 60°sin( 60-15)= sin45° = 1/√2Option-(a) please like the solution 👍 ✔️ 0.76×0.76+2×0.76×0.24+0.24×0.24 |
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| 65937. |
to 628.488 becomes 900.Mohan spend 16.50 for buying a pen and 2.25 for pencil. He gave 20 to the shopkeeper. How muchamount will he get back?14. |
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Answer» Mohan's bill = 16.5+2.25= ₹ 18.75Amount shopkeeper will give back = 20-18.75= ₹ 1.25 Please hit the like button if this helped you out |
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| 65938. |
4Mohan spend 16.50 for buying a pen and 2.25amount will he get back?for pencil. He gave? 20 to the shopkeeper. How much |
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| 65939. |
Findthenumberwhichwhenadded to 628.488 becomes 900.13.amount will he get back? ing a pen and 2.25 for pencil. He gave 20 to the shopkeeper: How much |
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| 65940. |
ufind the other.4. The product of two fractions ione of the fractions is 9 -Олthe number of |
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| 65941. |
Exercise 2d1. Maria thinks of a number and subtractsfrom it. She multiplies the result by 8.now obtained is 3 times the same number she thought of. What is the number?52 |
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Answer» thanks thanks |
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| 65942. |
(f) Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, shewill get 8. |
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Answer» 21 is the answer to your question 21 is the correct answer of the given question Yes 21 is a correct answer |
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| 65943. |
ko. The product of two fractions is 59. If one of the fractions is 8. find the other..72. |
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Answer» Let the 2nd fraction be x(74/9)*x=296/5X=296*9/74*5=2664/370=7.2=72/10=36/5So 2nd fraction=36/5 Let the 2nd fraction be x(74/9) ×x=296/5X=296×9/74×5=2664/370=7.2=72/10=36/5So 2nd fraction=36/5 |
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| 65944. |
161. The product of two fractions is 9If one of the fractions is 9. And the other |
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| 65945. |
llIterttHeiriu.tis 12In the given figure, find the length ACthetops.17 |
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Answer» thanks plz answer my questions brother for my studies i am always thankful to U |
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| 65946. |
Segment: A line segment is a ponit has a definite lenengthine segmea singlesan be rnumbers (variables)literal numherCotae seフー(ヘ1 人 |
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Answer» 0.5x = 25 x = 25/0.5 = 25×10/5 = 50 |
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| 65947. |
Ll pon e eot bp p 5 o S |
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Answer» Formula used - 30h−5.5m=±18030*5-5.5m= ±180m negative नहीं हो सकता अतः150-5.5m= 1805.5m = 30m= 30/5.55.45time 0.45*60= 27 secondअतः टाइम5.05.27सेकंड होगा |
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| 65948. |
If the circumference of a circle increases from 4 Ďto 8n, then what about its area? [Delhi 2013] |
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Answer» Old circumference=4Π=4Π 2Πr=4Π2Πr=4Π r=4Π2Π=cmr=4Π2Π=cm Old area=Π(2)2=Π(2)2 =4Πcm2=4Πcm2 New circumference=8Π=8Π 2ΠR=8Π2ΠR=8Π R=8Π2Π=4cmR=8Π2Π=4cm New area=16Πcm2=16Πcm2 (∵∵area is quadruples) |
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| 65949. |
15. The radius of a circle is increased by 1%. Find how much % does its areaincreases? |
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| 65950. |
There were 3 pencils with Samira. She gave 1 pencil to herfriend. How many pencils are left with Samira now ? |
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Answer» she has 2 pencils after the giving 1 pencil she has 3 pencilsshe gave 1 pencilspencils left=3-1=2 2 penciles left after geving |
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