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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 66101. |
\frac { 1 } { 3 x + 1 } - \frac { 1 } { 2 x - 1 } + \frac { 3 } { 4 } = 0 , x = 1 [ x \neq \frac { 1 } { 2 } , - \frac { 1 } { 3 } ] |
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| 66102. |
\left. \begin array l l ( x %2B 2 ) ^ 3 = x ( x ^ 2 - 1 ) & \text (B) \quad ( x %2B 1 ) ^ 2 = 2 ( x - 3 ) \\ ( x - 2 ) ( x %2B 2 ) = 5 & \text (D) x ^ 2 %2B \frac 1 x ^ 2 = 2 \end array \right. |
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Answer» Option A is the answer to that questionक्योंकि यहां पर एक्स की घात 2 से ज्यादा है अतः द्विघात समीकरण नहीं है |
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| 66103. |
\left. \begin array l \text For some given data, if M %2B \overline x = 32 \text and \\ M - \overline x = 2 , \text then Z = \ldots \ldots \ldots \\ ( q ) 6 \quad ( b ) 21 \quad ( c ) 13 \quad ( d ) 19 \end array \right. |
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| 66104. |
e abscissa of the orthocentre of thetriangle formed by the lines y=m_{1} x+\frac{b}{m_{1}}y=m_{2} x+\frac{b}{m_{2}}, \quad y=m_{3} x+\frac{b}{m_{3}}1) b2) -b3) 2b4) -2b |
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Answer» 1 2 the answer is -b |
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| 66105. |
\frac \sqrt 3 - 1 \sqrt 3 %2B 1 = a %2B b \sqrt 3 \quad \text (ii) \quad \frac \sqrt 5 - 2 \sqrt 5 %2B 2 = a %2B b \sqrt 5 |
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| 66106. |
2.Draw the layout diagram of Electric Power Sub-station. |
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| 66107. |
Subtract the following rational numbers:83!! from-26) from 13(iii) from 2(ifrom-7-7(iii)713 |
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Answer» a)(13/7)-(8/3)=-17/21b)(-6/7)-(-4/13)=-50/91c)(-2/9)-(11/9)=-107/54 Subtract 4/7 from 9/7 |
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| 66108. |
Subtract the numbers |
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Answer» 0 is the easiest answer of maths |
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| 66109. |
Subtractfrom 13.13 |
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Answer» Subtract - 1/1/13 from 13 13 - (-1/ 1/13) = 13 - (-13) = 13 + 13 = 26 16 OK |
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| 66110. |
6 men can complete the electric fitting in 7 days. How many days will it take 21 men to do the job? |
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Answer» you have to make the fraction such that numerator is W and then the answer required will be the denominator |
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| 66111. |
-2*sqrt(161)*sqrt(7)/49*i^3*quad*text %2B 3 %2B sqrt(23) |
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Answer» (3 + V23)-V23 x ( 3+V23)+V23/3/(3+ V23)+V23= (3+V23)-V23)^2/3+V23-V23=(3+V23-V23)(3+V23-V23)^2/3=(3)^2/3=9/3=3 (ii) (3+√23)-√23 =3+√23-√23 =3 , a rational number(iii) 2√7/7√7 =2/7 , a rational number . 2V7/7V7× V7/V7=2(V7)(V7)/7V7 (7V7)=2(7)/7V7(7V7)=14/49(7)=14/343= |
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| 66112. |
\frac 1 3 x %2B y %2B \frac 1 3 x - y = \frac 3 4 \quad \text and \quad \frac 1 2 ( 3 x %2B y ) - \frac 1 ( 3 x - y ) = \frac - 1 8 |
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| 66113. |
_ 6. व्याख्या कोजिए कि 7» 11 13 + 13 और 7966 > 5 «4» 3:९2 » 1+5 भाज्य संख्याएँ क्यों हैं।B . ST St o & 5 |
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Answer» A composite number is a positive integer that has a factor other than 1 and itself. Now considering your numbers, 7×11×13+13 may be written as, 13x{(7x11) + 1} i.e. 13x(78). So other than 1 and the number itself, 13 and 78 are also the factors of the number. Further, 78=39x2. So, 39 and 2 are also it's factors. So this number is definitely not prime. Hence its composite number. Similarly, 7×6×5×4×3×2×1+5 can be written as 5x{(7x6x4x3x2x1)+1}, i.e. 5x(1009). So, other than the number and 1, it have 5 and 1009 as it's factors too. So it is also a composite number. |
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| 66114. |
( \text i) \quad ( x %2B 3 ) ( x %2B 3 ) |
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| 66115. |
Integral(f(a*x %2B b), x)=((quad*text)*Integral(f(t), t))/a |
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Answer» Hi, Here is the answer to your question. |
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| 66116. |
write the type of charge on a glass rod and silk cloth when they are rubbed with each other. |
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Answer» a glass rod when rubbed against a silk cloth acquires a positive charge and silk cloth acquires negative charge |
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| 66117. |
6. Which number should be subtracte numbers 13, 25 and 55 so that the resultingwould be in continued proportion?th(3 marksSolution: |
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Answer» suppose 5 is subtract from all three numbersso 13-5=8,25-5=20,55-5=5020/8=(5×4)/(4×2)=5/250/20=(5×10)/(2×10)=5/2 |
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| 66118. |
7*(text*(x*(b*y))) %2B 2*x %2B 7*(quad*(text*(x^4*(D*(i*(v*(de*i))))))) - 3*x^2 - 1 |
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| 66119. |
The sde of the square is St. If the perimeter of the square is 72 |
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Answer» Please post the complete question. apply the formula here |
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| 66120. |
A circular track has an outside circumference of 484 m. The width of the track is 7 m. What is the inside circumference? |
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| 66121. |
th25. If a 3n - 5n what would be the 13h term?a. 484b. 442c. 508d. 16 |
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Answer» n=13 put in expressionhence it will be3(13)^2-5(13)=3*169-65=442hence option b |
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| 66122. |
one o the 2eesihe square quadmagrutu de but, opposites sign%hen furo! the valuc. az k |
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Answer» Letα andβ be the zeros of the polynomial 4x²-8kx-9It is given thatα=-βThen,α+β=0-b/a=0-(coefficient of x)/coefficient of x²=08k/4=02k=0k=0 |
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| 66123. |
3. A man wishes to have a rectangular shaped garden in his backyard. He has 84 feet of fencing with which toenclose his garden.a) Write an expression for the perimeter of the garden.b) The area of the garden is A - I'w. Use the perimeter equation from part(a) to write the area in terms ofjust one variable.c) Find the dimensions for the largest area garden he can have if he uses all the fencing. |
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Answer» let length of gardan= lbreath = b2(l+b)=perimeter2(l+b)=84l+b= 42b= 42-larea = 1^°wl(42-l)=1^°w |
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| 66124. |
17. The value of à mac? 160000, what was its value last year?An alloy contains 40% copper, 32% nickel and rest zinc. Find the mass of zinc in onthe alloy18.,2% of proteins, 25% of fats and 63% of carbohydra |
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| 66125. |
hisson'sage14. The total sum of the ages of father and son is 55 years. If the father was to ive tiliequals his present age, the total of their ages would be 93 years. Find their present ages. |
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| 66126. |
10^2/484 |
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| 66127. |
15Hn(c)The population of a town increases by 5% every year.the present population is 9261, the population 3 yt agowas(a) 8000 (b) 7500 5700 6000d) 18 min2. |
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| 66128. |
1 : Is 484 a perfect square? |
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Answer» yes 484 is perfect square .it is square of 22. 22 is the perfect square yes ...the square of 22 Yes 484 is a perfect square. Square root of 484 is 22 yes ,it is a square of 22 22 is the answer for this question 484 is the perfect square of 22 484 is perfect square of 22 |
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| 66129. |
The perimeter of a square is 26 cm, while theareaof another square is 121 cm?. Find the ratio of thelengths |
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Answer» not 121 it's 121 square What do you mean? |
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| 66130. |
n Q. 1. Define vector space. |
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Answer» A vector space is a set V on which two operations + and. · are defined, called vector addition and scalar multiplication. The operation + (vector addition) must satisfy the following conditions: Closure: If u and v are any vectors in V, then the sum u + v belongs to V. |
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| 66131. |
Derive the equation of the line in a space passing through a point andparallel to a vector both in vector and Cartesian form. |
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| 66132. |
The perimeter of a square is 26 cm, while the araof another square is 121 cm. Find the ratio of thelengths. |
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Answer» sorry but your ans is wrong |
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| 66133. |
Divide the following(1) 4) 484 |
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Answer» Please hit the like button if this helped you out |
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| 66134. |
14. Find the third term to make the LHS of theequation m2-3m = 1 a perfect square. |
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| 66135. |
, A pole broke at a point but did not separate. Its top touched the ground at a distanceof 5 m from its base. If the point where it broke is at a height of 12 m from the ground,what was the total height of the pole before it broke? |
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Answer» Let the point where it broke be B.the base be C.the fallen top be A.ABC form right triangle where angle c is 90.AC is 5m.BC is 12 m.by pythagoras theorem,AB2 = BC2 + AC2AB2 = 12square + 5squareAB2 = 144 + 25AB2 = 169Ab = 13total height of pole before breaking = 12m + 13m=25m |
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| 66136. |
14. Divide 20 pens between Sheela and Sangeeta in the ratio of 3:2 |
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| 66137. |
Find out median.Age (in years)101-200201-300301-400401-500501-600601-700No. of Patients1015 |
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Answer» Answer is 306.06 |
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| 66138. |
। समीकरण sec-2x =1- tan2x का मुख्य हल और व्यापक |हल ज्ञात कीजिए।Find the general solution and principal solutionof the equation sec-2x = 1- tan2xc . |
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| 66139. |
r A seel wire when bent in the form of a square encloses an area of 121 cm2. The same wire is bent in the formof a circle. Find the area of the circle. |
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| 66140. |
A steel wire when bent in the form of a square encloses an area of 121 cm*. If the samewire is bent in the form of a circle, find the area of the circle. |
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| 66141. |
A copper wire, when bent in the form of a square, encloses an area of484 cm2If the same wire is bent in the form of a circle, find the area enclosedby it. |
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| 66142. |
A man purchased some eggs at 3 for R 5 and soldthem at 5 forき12 Thus, he gained 143 in all.How many eggs did he purchase ? |
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| 66143. |
Root / solution ofthe equationEqationLHS2x = 102x10x +4=123 |
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Answer» y=5*3=15x=15-4=112x+1=9=2x=8=4 tq |
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| 66144. |
Water flows through a cylindrical pipe of internaldiameter 7 cm at 36 km/hr. Calculate time in minutesit would take to fill a cylindrical tank, the radius ofwhose base is 35 cm and height is Im. (ICSE 1993)Hint. See Solved Ex. 17 |
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Answer» Speed of water = 36km/hr = 36000/60 m/min. = 600 m/min. Converting into metres, Diameter of base of tank = 2 x .35 = 0.7 m. Volume of tank= Pi/4 x d square x h = Pi/4 x 0.7 x 0.7 x 1 cubic.m. Let Length of pipe for equaling volume of cylinder be h Pi / 4 x 0.07 x 0.07 x h = Pi/4 x 0.7 x 0.7 Hence h = 100 m Time taken to cover 100 m of pipe = 100/600 min. = 1/6 min. Like my answer if you find it useful! kuch question ke answer nhi a rhe |
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| 66145. |
1) Shripati sold a land for Rs. 2,50,000 to Mr. Sadashiv through a brokeBroker received 2% brokerage from both. Find the total brokerage receiveby the broker. |
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Answer» Brokerage = brokerage from Shripati + Brokerage from Mr. Sadashiv= 4% of 250000= 4/100 * 250000= 4*2500= Rs. 10000 |
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| 66146. |
5. Sangeeta lent40,960 to Amar to purchase a shop at 12.5% per annum. If the interest iscompoundedsemi-annually, find the interest paid by Amar after 1years. |
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| 66147. |
s a trapezium in which AB Il CD and(see Fig. 8.23). Show thatC(see r': o. LA=<Bdiagonal AC diagonal BIDFig. 8.23Hint: Extend AB and draw a line through Cparallel to DA intersecting AB produced at E.] |
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| 66148. |
0. The ages (in years) of 6 males of a family are 11, 48, 37, 90, 25, 54. Find the median age ofthe males. t2. |
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| 66149. |
what is trial balance?state any four function of a trial balance |
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Answer» If a statement is prepared with debit balances in one side/column and credit balances on the other side/column, the totals of the two sides/columns will be equal. Such a statement is called as ‘Trial Balance.following are it's functions :1Helps in finding and correction of errors2Helps in preparation of final accounts3Helps to prove the accuracy of Books of Accounts4 It helps in the preparation of the final accounts i.e., Trading a/c. Profit and loss a/c and Balance Sheet. |
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| 66150. |
do spores remain viable during unfavourable conditions? |
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Answer» The spores remain viable during the unfavourable condition because of the presence of the sporopollenin in the pollen grains. It is the polymer of carotenoids. When it comes Sporopollenin, it is a major component of the exine of pollen and spores. It is highly resistant component available in this organic world. Also, it is resistant to the non-oxidative enzymes, chemicals and other chemical reagents. |
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