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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 66551. |
( 05" ÂŽ oQ& |
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Answer» ∫cos⁴xdx=∫cos²xdx−∫sin²xcos²xdx=1/2∫1+cos(2x)dx−1/8∫1−cos(4x)dx=3/8x+1/4sin(2x)+1/32sin(4x)+C ∫ |
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| 66552. |
Complete the followinlete the following multiplication (x) table:Second Numberx4-5 52-20-1First Number |
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| 66553. |
\left| \begin{array} { l l l } { 1 } & { x } & { x ^ { 2 } } \\ { x ^ { 2 } } & { 1 } & { x } \\ { x } & { x ^ { 2 } } & { 1 } \end{array} \right| = ( 1 - x ^ { 3 } ) ^ { 2 } |
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| 66554. |
The diference betueen the sides at rightperimeter of the triangle4The area of the triangleiv 120 cmnd Caleolangles in a right- anged |
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| 66555. |
22+11+05= |
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Answer» 22+11+05=38answer ok |
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| 66556. |
oplal borrowed Rs 12650 from a cooperative socieRs 10381 and gave a buffalo to clear the debt. What is the cost of the buffalo?ty at 18% per annum. After 3 years, he paidRoout at 8% per annum. After 8 |
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| 66557. |
the collection of good cricket player of india |
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Answer» Sachin Tendulkar, Dhoni, Sourav Ganguly, Virat Kohli, Rahul Dravid, Kapil Dev, Sunil Gavaskar |
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| 66558. |
The collection of good cricket players of India. |
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Answer» Sachin Tendulkar, Dhoni, Sourav Ganguly, Virat Kohli, Rahul Dravid, Kapil Dev, Sunil Gavaskar |
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| 66559. |
ple 1: Construct a quadrilateral PQRS in which PQ = 4.5 cm, QR = 5.2 cm,RS = 5.5 cm, PS = 4 cm and PQR = 120°.an: |
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Answer» Steps of construction:Step 1: TakePQ= 4.2 cmStep 2:Make∠XPQ=120∘,∠YQP=60∘Make∠XPQ=120∘,∠YQP=60∘Step 3: Cut an arc of length 5 cm from pointQ. Name that point asR.Step 4: FromP,make an arc of length 6 cm. Name that point as S.Step 5: JoinPandS.Thus,PQRSis a quadrilateral. |
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| 66560. |
PLE 1. The equation of the circle which touchesX-axis at (3, 0) and passes through (1, 4) is given by2L 22 |
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Answer» here is a solution for a similar ques.- Find the equation to the circle which touches the axis of x and passes through the two points (1,-2) and (3,-4). |
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| 66561. |
vide the followin3/5/4(b |
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Answer» Write answer Thank you |
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| 66562. |
Vide &SNo betueen 3 |
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Answer» 1)2/6=1/32)1/63)2/6=1/34)1/65)1/6 perfect cube kada perfect square kada 4 is the only perfect square in the dice..so probability will be 1/6 perfect cube |
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| 66563. |
(जा दरग 9: विल सत कौजिए, : (0 729 01206... |
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Answer» hit like if you find it useful hit like if you find it useful |
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| 66564. |
vide:(a) 1.5 = 0.3(d) 125 = 1.25(g) 6 = 0.8(j) 12.8 + 0.05Divide: |
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Answer» (1) 5(2) 100(3) 7.5(4) 0 (:1:)=5(:2:)=100(:3:)=7.5(:4:)=256 a) 5b)100c)if any expression divided by 0 is undefined same d) also. (a) 5(b) 100(c) 7.5(d) 256 1=52=1003=7.54=256 |
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| 66565. |
\operatorname { log } _ { 9 } 3 - \operatorname { log } _ { 81 } 729 \text { Ans: } - 1 |
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| 66566. |
What is the significance of playing sports regularly? |
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Answer» Sportsboost your self-confidence. Theregularexercise that comes withplaying sportscan boost your confidence and improve your self-esteem. As your strength, skills, and stamina increase throughplaying sports, your self-image will improve as well. |
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| 66567. |
Exanipleple 9 : In Fig. 6.43, the line segment, XY is parallel to side AC of Δ ABC and itdivides the triangle into two parts of equalareas. Find the ratio AXABY' |
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Answer» bhai vo ba=√2 bx kesse hua |
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| 66568. |
dan gee-cot-9..dund theand .9.6、く90°ec 5e,then |
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Answer» Tan 9 a= cot atan 9a=tan (90 -a)9a=90-a10a=90a=9cosec 5×9cosec 45√2 |
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| 66569. |
PLE 1.Subtract:(0 9 from 4 |
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Answer» Subtract 9 from 4 hence 9-4=5 |
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| 66570. |
19 -linolkn2 77Cy-ă. Final, the height og teacy lin dan s Cy |
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| 66571. |
5. D, E and F are respectively the mid-points of sides AB, BC and CA of A ABC. Find thaeratio of the areas ofa DEF and Δ ABC. |
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Answer» Thnkq sir |
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| 66572. |
D is a point an vide BC such thae BD- BCPwe dhar |
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Answer» Like my answer if ypu find it useful |
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| 66573. |
Find the square root of (i) 7299ple |
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| 66574. |
from9. Alok borrowed t 7500 on 26 March 1999Cooperative Bank at the rate of 8% per annum siminterest. If he cleared the account on 7 June 1999, whatamount did he payple |
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Answer» iska??????????????????????????? nahi pata dur pagal yaar means year. |
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| 66575. |
? C Date-ae Ple |
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Answer» The value is (64)^1/2=√64=8 √64 = 8 is the correct answer of the given question |
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| 66576. |
4. If (x +2, 4) (5, y-2), then find thecoordinates of the point P(x, y). |
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| 66577. |
निफ़त मश्थाीरटनांज़ T I कर ्त R जोन? |
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Answer» 3/2 ÷3/2 ×2 +3/21×2+3/22+3/27/2 |
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| 66578. |
. Probability of getting an ace in playing cards is:(b) 52(c) นึ1 (d)13(a) į |
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Answer» Ans :- Option (c) 1/13 is correct. If only one card is to be drawn then the probability is 4/52. |
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| 66579. |
3, ITE, F G and II are respectively themidpoints of the siden AI, BC,CD and ADof a parallelogram ABCD, show thatarErG)AF(ABCD)uilutcrel do you get, if you join AAPM,ADPO, AOCN andADPO, AOCN and AMyou join ЛА PM, MpO), AC |
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Answer» Like if you find it useful |
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| 66580. |
ple 5. What principal will amount to Rs. 1,035 in 25 years at 6% simple interest |
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| 66581. |
ple 5: A trader has 2520 apples. If 45 apples are stored in one box, thenlow many such boxes will be filled? |
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Answer» There are total 2520 apples.There are 45 apples in each box. Boxes - 2520/45=56 Total no. of boxes = 56 |
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| 66582. |
ple 9: Multiply(i) (a + 7) and (b-5) |
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| 66583. |
Find the coordinates of the point which divides the join of (-1,7) and (4,-3)in theratio 2:31. |
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| 66584. |
1. Find the coordinatesof the point which divides the join of (-1,7) and (4, -3) in theratio 2:3. |
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| 66585. |
PPAOL1+de44-13होतो किसहैकराया |
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Answer» (1+x/144)½=13/121+x/144=(13/12)²1+x/144=169/144(144+x)/144=169/144144+x=169x=169-144x=25 ans 25 (1+X/144)1/2=13/121+144=169/14425 ans |
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| 66586. |
11. Δ DEF-aABC; If DE : AB = 2: 3 and ar(d DEF) is equal to 44 square units, then find thearea (AABC)in square units is |
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| 66587. |
tion 8(a) A total of 85,500 children visited a zoo last year.If equal number of children visited the zoo eachmonth, how many children visited the zoo in amonth? |
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Answer» total visitors last year=85500same visitors in each months are same total months are 12so visitors in each month=85500/12=7125 |
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| 66588. |
walking at 50% more than his uncal speee..a man reaches his office an hour earlies.How long does he usually take to reachhis ffice, |
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Answer» take answer Let original speed = sLet original time taken to reach office = t Distance travelled by man = d Then,At original speed s time taken to reach office = d/s For 50% more than original speed time taken to reach office = d/s(1 + 1/2) = 2d/3s As per given condition d/s - 2d/3s = 1(3d - 2d)/3s = 1d = 3s Therefore, Usually time taken to reach office = d/s = 3s/s = 3 hours |
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| 66589. |
Anupam Kher, who has experimented (a) ..different film genres (b) an actorand director, feels that the quality of scripts,cinematography and screen plays in Hindi filmshasn't gone down (e)..... actually improvedover the years. "I don't think Bollywood is goingda bad phase. Instead, I think it is inits golden time right now," said Anupam."A lot of films are released in India.e.are some good and some bad. It is just like areporter's article. (.. article can't be good,"the actor saidseseeCOO99E |
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Answer» (a) with(b) as(c) which(d) under(e) There(f) All |
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| 66590. |
c) There are Tou students in Ă ostel. rood promore students join the group?d) Factorise the expression and divide 12xy(4Each question carry 4 marks eacha)Factorize at -b4 |
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Answer» a^4 - b^4=(a^2 - b^2)(a^2 + b^2)=(a-b)(a+b)(a^2 + b^2) |
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| 66591. |
T3I ) मगाधान कानों : tani(x + 1) + tan ! (x — 1) = tan 5 |
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Answer» Like my answer if you find it useful! |
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| 66592. |
A hostel had rations for 60 days for 500 students. After 12 days, 300 more students join the hostel. Holong will the remaining rations last ? |
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| 66593. |
w.r.t. x.PLE 51-tan x11+tan xDifferentiate |
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Answer» / 1- tanx/ 1+tanx= \ 1-sinx/ cosx/1+ sinx/ cosx= \cosx- sinx/ cosx\ cosx+ sinx/ cosx=\ cosx-sinx/ cosx+ sinx: cosx+ sinx=u, du/ dx=sinx + cosx; = cosx-sinx; du= cosx-sinx= \1/u dx= ln/u/ +c: = ln( cosx+ sinx)+c /1- tanx/1+tanx =/1- sinx/ cosx\ 1+ sinx\ cosx =cosx-sinx/ cosx/cosx+ sinx/ cosx = cosx - sinx/ cosx+ sinx; cosx+ sinx=k; dk/ dx cosx-sinx_/ cosx-+sinx:; dk cosx - sinx /1=1/k dx; 1n( cosx + sinx)+c |
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| 66594. |
\frac{\sin 5 x+\sin 3 x}{\cos 5 x+\cos 3 x}=\tan 4 x |
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Answer» (sin5x+sin3x)/(cos5x+cos3x)=(2sin4xcosx)/(2cos4xcosx)=sin4x/cos4x=tan4x |
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| 66595. |
5 \operatorname { tan } ^ { 4 } x - 1 = 4 \operatorname { tan } ^ { 2 } x |
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| 66596. |
11) The mean weight of 8 students is 455 kg. Two more students having weights 41.7 kgand 53.3 kg join the group. What is the new mean weight? |
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Answer» Mean weight of 8 students = 45.5 kg Total weight of 8 students= mean weight * no. Of students= 45.5*8 = 364 Total weight of 10 students= 364 + 41.7 + 53.3 = 459 Mean weight of 10 students= 459/10 = 45.9 kg |
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| 66597. |
Express 275 in pla forcewhere 820 and q-2). |
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| 66598. |
6. Name an animal in which the exchange of gases during respiration takes pla |
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Answer» Earthworms and amphibians, such as frogs, breathe through their skin. They belong to a group of animals which live on land and have a skin thin enough for gases to pass through. These animals are capable of breathing through their permeable skin, which needs to remain moist. Earthworms remain below ground in the moist soil, while amphibians live in or near water. Animals that can breathe through their skin have moist skin and have tiny blood vessels or capillaries that lie close their skin surface. These tiny vessels transport oxygen to their various tissues and carry carbon dioxide to the outer skin layer. Like my answer if you find it useful! |
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| 66599. |
of (R-1) is factoryPla de 44 anti-find valg a |
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Answer» p(1)= (1)²+4a(1)+5 0 =1+4a+5 0 =6+4a -4a =6 a = -6/4 a = -3/4 |
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| 66600. |
130 St बड़े लि v Ry 27w e 8 RP e s whase s a1 ad 112 i ecly |
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Answer» Let the two numbers be X and Y. Given:-x+y=27--------(1)xy=182---------(2) |
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