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50° and 60° as they are congruent the two angles of the triangle are equal to x minus 5 is equal to 45° show the value of x will be if 50 degree and the X + 5 is equal to 21 degrees show the value of x will be 25 degree..........

Total surface area of right circular cone = π r ( l + r )

▪ On putting the values , we get :-

==> π r ( 13 + r ) = 90 π cm^2

==> r ( 13 + r ) = 90 cm^2 ( both sides r divided by π )

==> 13r + r^2 = 90

==> r^2 + 13r - 90 = 0

On solving , we get

==> r^2 + 18r - 5r - 90 = 0

Taking common :-

==> r ( r + 18 ) - 5 ( r + 18 )

==> ( r - 5 ) ( r + 18 )

==> ( r - 5 ) = 0 , ( r + 18 ) = 0

==> r = 5 and

==> r = -18 ( can not be negative )

__________________________

Hence , it's radius is 5 cm.__________________________

ques. = 2 ( To find it's volume )

We have ,

● Radius = 5 cm

● Slant height , l = 13 cm

● height = ?

☆ h =√ l^2 - h^2

On putting values ,

==> h =√ 13^2 - 5^2

==> h = √ 169 - 25

==> h = √ 144

==> h = 12________________________

Volume of the cone = 1 / 3 π r^2 h cm^3

==> 1 / 3 * 3.14 * 5^2 * 12

==> 1 / 3 * 3.14 * 25 * 12

==> 3.14 * 25 * 12 / 3

==> 3.14 * 25 * 4

==> 3.14 * 100

==> 314 cm^3.

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If we consider photon corresponding to any colour and find its energy using E=hv.its value will come out less than 4.4 eV. so visible light cant eject electrons in copper

The area of a circle of radius r is π r2and thus if the hemisphere is meant to include the base then the surface area is 2 π r2+ π r2= 3 π r2.

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cot 45 is correct answer

cos45= sin45 = 1/√2so 1/√2/(1/√2)= 1 is the answer

sin45/sin45=1is the ans of your question

cos45/sin45=cot45=1

cos 45°/sin 45°cot 45°1

sin 45/cos 45cot 45=1

cos45/sin451/11is correct answer

cos45/sin45=1/√2×√2/1=1

sin45°/cos45°=1 answer

6/10 9/1512/2015/2518/3021/35

6/109/1512/2015/2518/3021/35

6/109/1512/2015/2518/3021/35

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150 *surface area of hemisphere +surface area of golf

Ali = 2 * Fatima (Ali-5) = 3(Fatima-5) Ali - 5 = 3*Fatima - 15 2*Fatima = 3*Fatima - 10 Fatima = 10 Ali = 20

1/2 b/w 1 and -1. !

let alpha= p, bita =qx^2-3x-2p+q= 3pq= -2sum of given zeros= 2p+3q+3p+2q= 5p+5q=5(p+q)= 5×3= 15product of given zeros(2p+3q)(3p+2q)= 6p^2+4pq+9pq+6q^26(p^2+q^2)+13pq= 6{(p+q)^2-2pq}+13(-2)=6{(3)^2-2(-2)}-26=6(9+4)-26=78-26= 52polynomial =x^2-x(sum of given zeros)+product of given zerosx^2-x(15)+(52)x^2-15x+52

let alpha=p and bita = q; p+q =3; pq=-2; sum =2p + 3q +3p + 2q = 5p + 5q =5( p + q) 5(3)=15; product (2p + 3q) (3p + 2q) (2p(3p))+(2p(2q))+3q(3p)+3q(2q)= 6p^2+4qp+9pq+6q^2 = 6(p^2+q^2)-13pq. =6((p+q)^2-2qp)+13(-2) =6((3)^2-2(-2))-26= 6(9+4)-26=6(13)-26=78-26=52; x^2-15x+52=0

Divide 4.55 kg by 7

Bcoz 7 days r in weeks

So, ans is

4.55÷7=0.65

Divide 4.55 kg by 7 Because 7 days are in weeks So,4.55÷7=0.65 ans

0.65 kg is the right answer

0.65 is the answer to your question

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Dry Iceis the common name for solid carbon dioxide (CO2). It gets this name because it does not melt into a liquid when heated; instead, it changes directly into agas(This process isknown assublimation).

To find 10 rational number between 0 and 1

Divide and Multiply 1 by 11

Now,10 rational numbers between 0 and 11/11 are 1/11, 2/11, 3/11, 4/11, 5/11, 6/11, 7/11, 8/11, 9/11, 10/11

Find 10 rational no. between 0 and 1divide and multiply 1 by 11now,10 rational no. between 0 and 11/11 are 1/11,2/11,3/11,4/11,5/11,6/11,7/11,8/11,9/11,10/11

l is parallel to m so angle A = angle supplement xx = 180° - 50° = 130°( linear pair)y = 30° ( Alternate angle)

Cost of 50 gm of Almonds =Rs 50

Cost of 500 gm of Almonds= Rs 500

Therefore, Cost of 1 kg or 1000 gm of Almonds = Rs 1000

100p is the answer of this question

cost of 50 grams almonds = ₹50cost of 01 gram almonds = ₹01so, cost of 1kg (1000grams) almonds = ₹(1×1000) = ₹ 1000

hence, cost of 1kg almonds are ₹1000.

3/5 = 0.6 4/5 = 0.8 numbers are 2/3 , 17/25 , 69/100 ,7/10 ,18/25 ,3/4

Let his original salary= ₹100020% of his original salary, (20/100)*1000=₹200

Salary after reduction=₹1000-₹200=₹800

Now,₹200 should be added to his salary in order to get back his original salary

Therefore, percentage of salary needed to be added= (200/800)*100%=25%

2asint/2 answers because of i will try this model questions

these 4 are in proportion so34/(25-x)=102/(59-x)2006-34x=2550-102x68x=544so.x=8

let unkown number be x(59)10=x×2x=(59)10/2x=590/2x=295

Let quantity of tea sold at 5% loss is x

Then,5% of x =3% of 405% of x = 1.2x= 1.2 * 100/5x = 24

Therefore,Quantity of tea sold at cost price = 40 - x = 40 - 24= 16 kg

lets take age=x so and z is the average of age.so table will be like following:x z no.of persons10-19 14.5 820-29 24.5 830-39 34.5 1040-49 44.5 1450-59 54.5 2860-69 64.5 12

so mode =(14.5*8+24.5*8+34.5*10+44.5*14+54.5*28+64.5*12)/(8+8+10+14+28+12) = 44.75

and bahulak is the number which one is appear frequently or more no. of times so here 8 is appearing more than any number so bahulak is 8.

R = 28 cmr = 21 cmLet height of frustum be h cm

∴Volume held by bucket = 28.490 litres = 28490 cm³Also,

Volume of frustum = π(R²+Rr+r²)h/3=> 28490 = 22*(784+588+441)*h/(3*7)=> 1813h =28490*21/22=> h = 27195/1813 = 15cm

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Let the polynomial to be added be Z. Then, (2x²-3x-8)+Z = (3x²+X+6)=> Z = (3x²+X+6)-(2x²-3x-8)=> Z = x² +4x+14.

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