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Here a1/a2 = b1/b2 not equal to c1/c2

InconsistentNo solution

(a^2b^3c)^4.(abc)^3/(a^3bc^-1)^2= (a^mb^nc^p)^1/2

(a^8b^12c^4).(abc)^3/(a^3bc^-1)^2= (a^mb^nc^p)^1/2

(a^[8+3-3]b^[12+3-2]c^[4+3+2])= (a^mb^nc^p)^1/2

(a^8b^3c^9) = (a^mb^nc^p)^1/2

Since base is same powers are equal

m/2 = 8, n/2 = 3, p/2 = 9m = 16, n = 6, p = 18

Thereforem + n + p = 16 + 6 + 18 = 40

It is given that ,

x + 1/x = 8 ---( 1 )

Do the square of equation ( 1 ),

( x + 1/x )² = 8²

x² + 1/x² + 2 = 64

x² + 1/x² = 64 - 2

x² + 1/x² = 62 --( 2 )

Again do the square of equation ( 2 ),

( x² + 1/x² )² = 62²

x⁴ + 1/x⁴ + 2 = 3844

x⁴ + 1/x⁴ = 3844 - 2

= 3842

tkanks

sin2x / (1+cos2x) = 2sinxcosx/2cosxcosx = tanx

tan^(-1)(tanx) = x

It will be cos2x/2+c

No it has infinite many solution as there is no restrictions on variable x and y. so take any value of x we can find a corresponding y.

8x+5y=9; 3x+2y=4; 2(8x+5y=9)=16x+10y=18; 5(3x+2y=4)=15x+10y=20;/ x=2; 8x+5y=9; 8(2)+5y=9; 5y=9-16=-7; y=-7/5;;

Answer - (cos2x)/2 + cplease like the solution 👍 ✔️

first of all we will focus on these formulas.1= sin^2 x + cos^2 x ...............(1)sin 2x =2 sin x cos x .................(2)now put these values in question.sin^2 x + cos^2 x + 2 sin x cos x (sin x + cos x)^2 •.• [a^2 +b^2 +2ab]so the answer is (sin x + cos x)^2 .

1

2

4

derivative of e^x(4x^2+9)

Al2(SO4)3+ H2O this reaction will take place

Aluminum oxide react with sulfuric acidAl2O3+ 3H2SO4-------->Al2(SO4)3+ 3H2O

Aluminum oxide react with sulfuric acid to produce aluminium sulfate and water.

Please post complete information of the question.

Please post the complete question

angle between two lines in 2nd degree equation is given by

tan∅ = 2√h²-ab/(a+b). where 2h = 5 , a = 2 and b = 2

=> tan∅ = 2*√(25/4-4)/(2+2) = 2√(9/4)/(4) = 3/4

=>∅ = tan-¹(3/4)

So,

-3x + 5y = 7

(2p - 5)x - 3y = 1

For unquie solution

-3/(2p - 5) ≠ 5/(-3)

(-3) × (-3) ≠ 5 ( 2p - 5)

9 ≠ 10p - 25

34 ≠ 10p

p ≠ 34/10

If 18, a, b, - 3 are in AP

Then common differenced = a - 18 = - 3 - b

Then,a + b = 18 - 3a + b = 15

Raw data(sometimes called sourcedataor atomicdata) isdatathat has not been processed for use.

The derivative oftan−1xis11+x2(for "why", see note below)

So, applying the chain rule, we get:

ddx(tan−1u)=11+u2⋅dudx

In this questionu=2x, so we get:

ddx(tan−12x)=11+(2x)2⋅ddx(2x)

=21+4x2

Note

Ify=tan−1x, thentany=x

Differentiating implicitly gets us:

sec2ydydx=1, so

dydx=1sec2y

From trigonometry, we know that1+tan2y=sec2y

sodydx=11+tan2y

and we havetany=x, so we get:

Fory=tan−1x, the derivative is:

dydx=11+x2

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