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81251.

3rd term7. The 1st, 3rd and 4th terms of a proportion are 12, 8 and 14 respectively 9lind tue lad

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81252.

A wheel has radius 42 cm.(a) Find the distance covered in 700 revolutions(b) In how many revolutions will it cover a distance of 3 km 960 m?

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Circumference will be the distance covered in one revolutionHence2πr=2*22/7*42=264cm^2a)Hence in 700 revolutions=700*264=184800cm^2Now 3km 960m=3000m+960m=3960mHence,Revolutions will be 3960/264=15revolutions

81253.

souravranjanrout 14 days agoHow many numbers less than 4500 when divided by 56 & 72 will leave a remainder of 39 In each case

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L.C.M of 56&72 is 504. So there are numbers multiple of 504 plus 39 but less than 4500. Now 504×9=4536 which is >4500. So there are 8 numbers which will satify the condition. Thus following are the numbers: 504+39=543,504×2+39=1047, 504×3+39=1551, 504×4+39=2055, 504×5+39=2559,504×6+39=3063, 504x7+39=3567 & 504×8+39=4071.

Ans: 8 numbers.

81254.

e. A farme llas enougfood last, if there were 8 more animals in his cattle?ent of 5011. A garrison of 900 men had provisions for 42 days. However, a reinforcement of sarrived. For how many days will the food last now?elhootrl 75 students had food provision for 24 days. If 15 students leave the hos

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81255.

A fort has rations for 180 soldiers for 40 days . After 10 days . 30 soldiers leave the fort . Find the total number of days for which the food will last.

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Let ration last for n days.

Then,180*40 = 180*10 + 150*n180*30 = 150*nn = 180/5 = 36

Ration last for 36 days

81256.

days?In a hostel, there were provisions for 300students for 45 days. After 31 days, 195 studentleave the hostel. How long did the remainingprovisions last for remaining students?

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81257.

4. A can finish a work in 24 days, Bin 9 days and C in 12 days. B and C start the work but are forced toleave after 3 days. The time taken by A to complete the remaining work is:(a) 8 days(b) 12 days(c) 7 days(d) 15 days

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81258.

Y 3y less than10. How much is x - 2y420 mreater than 3x12. What should be subtracted fromx2 - xy + y - x + y + 3 to obtain -x2 + 3y² - Axy + 113. Subtract the sum of 13x - 4y + 7z and -6Z + 614. From the sum of 3x2 - 5x + 2 and -5x - 3x +subtract 4x2 - 3x + 915. Fill in the blanks:a) The degree of expression 9 -5x + xy is _b) The degree of expression 7x + 4xy + 5x isc) The degree of expression 6 - x + xy? - 4x isd) The degree of expression 3x² + xy² + xise) The degree of expression 6 + x®y isf) The degree of expression 5 + 4x2 + xisg) The degree of expression 6x-1 is16. Solve:a) 536 * (-35) + (-536) * 65 =b) (-4) × (-2-8)=c) (-25) × 37 * 4 =

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answer of question 5 part 1 is 1

which question you want to solve

81259.

The order of the differential equation223d sdsdt3+4-O is:+ 31Sdt2

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order of the differential equation is 2

81260.

4) The angle subtended in a semi-circle is .......a) 180 b) -180 c) 90d)

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90° will be the angle subtended in a semicircle..

90°is the angle subtended in a semi - circle

angle substended by semicircle is 180°

81261.

Vhich of the following statements is/are True' or False'?(i) The sum of two angles which form a linear pair is always equal to 180°(ü) The complement of 90° is 90°The supplement of an acute angle is always an obtuse angle.(iv) The supplement of a right angle is also a right angle.(v) The sum of two adjacent angles is supplementary.(üi)

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5 is also True??

yes...The adjacent angles will have the common side and the commonvertex. Two angles are said to be supplementary angles if the sum of both the angles is 180 degrees. If the two supplementary angles are adjacent to each other then they are called linear pair. Sum of two adjacent supplementary angles = 180

okk..Thanks for telling..Now I got it!

truefalse truetruetrue

81262.

TQ.60 The measure of each angle of a convex quadrilateral isVA) less than 180° • (B) equal to 180° (C) greater than 180°

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Less then 180 answer ok like the answer

measure of each angle of a convex is less than 180° ...because sum of angle is 360°.

less than 180 is the right answer.

sum of angle is 360° in quadrilateralso,each angle is less than 180°

81263.

Newton's 3rd law of motion

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Newtons third law of motion : For every action ,there is an equal and opposite reaction.

81264.

9. In the adjacent figure, the bisectors of LA and LB meet in a point PIf LC 100° and ZD 60°, find the measure of ZAPB

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81265.

The radius of the wheel of a horse-carriage is 0.7 m. What distance will it coverin 250 revolutions?

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81266.

न. गा सन ड़ पान .1 14cos A(क) सिद्ध कीजिए: osec A — cot A sin AkRt ०, आर ही... च आ

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81267.

सजा ..' TNअर उरी. कीजिए . —_——(i) T T—snf " =3 s, e कक

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81268.

2c+3p=1(a-b)x+(a+b)y=3a+b— 2

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81269.

Dy ] = 2—-l

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At x= 1/2p(x) =1/2*2+1=2

81270.

A can do a work in 25 days while B in 30days. They started working together.After how many days shouldA leave thejob to Make the work complete in 18days.

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81271.

What is the measure of (G) a right angle? (ii) a straight angleSay True or False(a) The measure of an acute angle < 90°(b) The measure of an obtuse angle < 90(c) The measure of a reflex angle > 180°(d) The measure of one complete revolution 360°(e) If maZA = 53° and m<B = 35°, then mLA > mLB

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a)TRUEb)FALSEc)TRUEd)TRUEe)TRUE

thanks

81272.

c) 3DT5. The supplementary angle for 120° isa) 180°b) 60°c) 90°d) 40°El-500- 40° than the

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area of rectangle L into b

b option is correct 60

60° is the correct answer

60° is the right answer

the supplementary angle for 120 is 60

Answer b which is 60

option b 60 degrees.

supplementary angle=180-120=60

20 degree angle for supplementary angle 120

180 (supplementary angle.) - 120 = 60

180-120=60 so,v option

60° is correct answer

option 'b' is correct

(b) The supplementary angle for 120 is 60

is answer 60° the supplementary angle for is 60°

60° is the correct answer of the given question

180-120=60 I hope you're understand it

The supplementary angle for 120° is 60°

60 is the write answer

60°supplementary angle = 180°so , 120°+ x = 180°x = 180° - 120° = 60 °

sum of supplementary angles=180let another angle =xx+120=180x=180-120x=60

60 is the coorect answer

60 c is right answer

120°-180°=60°b 120°-60°=60°c. 120°-90°=30°d. 120°- 40° = 80°ans

b option is right 60

angle 60 is correct answer

supplementary angle for 120 degree60 degree

b option correct angle 60 degree

option b =60 is the correct answer

60 B option is correct

60 , option B is correct because supplementary Angeles is 180 degree

the supplementary angle for 120 degree is 60 degree PLEASE HOPE THIS ANSWER PLEASE LIKE THIS ANSWER &COMMENT THIS ANSWER

60 is the second angle

you have doubt in maths you please ask me

b option is correct 60

60 is the right answer

supplementary angle =180answer=b 60

b option is correct answer

60000000000000489911m

let the supplementry angel of 120 be x then atq. 120 + x = 180x= 180_120 = 60

The supplementary Angle for 120° is 60°

supplementary angle =180°-120°=60°

b right answer is this question

option (b) i.e. 60

Answer of this question is 60

60° is the right amswer.

60 Degree is correct answer

60 angle for supplymentry angle

81273.

Perpendicular lines meet each otherat an angle ofA. O degree B 180 degreeC. 270 degree D 90 degree

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180 b is right......

....

180 right h bhy ok b option

answer::::::::::d)90 degree

perpendicular lines meet each other at an angle 90 degree

D) 90 degree is the correct answer

Perpendicular lines meet at 90 degreeoption D

81274.

A&B) Solve the following. (Any 2)In AABC, LABC= 90°seg BD 1 seg AC,AD = 8, BD = 12then find DC.ao

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as BD is perpendicular to AC from right angle ABC Therefore, BD^2= AD × CD 144=8DCtherefore, DC=18

81275.

Given: AD diameter of Circle P2If triangle ABD were drawn, the measure of angle B would equal90180100

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81276.

(c)2.5 cm(d) none of theseU) 2.2 em33. The area of a circle is 1386 cm3, then the radius of the circle is(b)22 cm(d) none of these(a) 21 cm34. The radius of a circular wheel is 8 m(c) 28 cm

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Area of circle=πr^2=1386cm^23.14×r^2=1386r^2=1386/3.14r^2=441.4r=√441.4r=21cm

81277.

17.20MATHEMATICS-ind the area of a quadrilateral ABCD in which AD- 24 cm, BAD -90 ad Bforms an equilateral triangle whose each side is equal to 26 cm.2.68. Find the area of a quadrilateral ABCD in rhich iDA 34cm

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81278.

28 cm12 cm21 cm

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Apply pythagoras in both triangles28^2 + 21^2 =x^2 - 12^2784-441=x^2-144343+144=x^2487=x^2x=22cm

I don't understand your solution

81279.

InIn AABC, AB 26 cm, BC 28 cm and the altitude AD 24 cm. Calculate AAABC, AB 26 cm, BC 28 cm and the altitude AD24 cm. Calculate AC.

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it is given that in a triangle ABC,

AB=26 cm,

BC=28 cm,

altitude(height)=24 cm

then AC value can be calculated by,

let AD the altitude be a median which divides BC into half so,

BC=DC + BD

DC = 14 cm

now we get two right triangles ABD and ADC

IN A RIGHT TRIANGLE ADC we have,

AC^2 =AD^2 + DC^2

AC^2 = 24^2 + 14^2

AC^2= 576+196

= 772

AC = square root of 772

= 27.8 cm